0 like 1 dislike
14.5k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 14.5k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
*** * * *** * *
int main()
{
**** **** * * ** * ** * * ***
** * ** * ***** ** * * %f * * * ****** * * * * *** ** *
* * * **** ** *** = (b*b-4*a*c);
* **** *** * ** *** * * = (-b + sqrt(D))/(2*a);
* ***** ******* ** * * = (-b - sqrt(D))/(2*a);
* ** *** * *** * * ** = -b/(2*a);
*** **** * **** * ** =sqrt(-D)/(2*a);
****** * ** ** * * * * ***
** ** * * ** * * *
* * * * ** * * * * * * *** * *** * ** * ** ** ***** * of %.2fx^2 + %.2fx + %.2f = 0 are real and ** * * * **
** *** * ***** * * * **** * ** *** *** * ** * * * * ********** = %.2f\nx2 = %.2f",x1,x2);
* * ***** **** ****

**** *** * ***** * *** * if(D==0)
* * ** ** * * * ** ** *
* * ***** * * ***** *** * * * * * ** ** * ** ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ** * * * ** * * **** * * **** *** *** *** ** * = x2 = %.2f",x1);
**** ** * ***** *** * *
** *** *** **
* *** * ** * ** ***
*** * *** * *** * * ****** ** * *** * * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * ** ** * * *
* ** * ******** ** ** ** ********* **** **** * **** ****** * = * ***** *** *** ** * * * * **
* **** *** * ** * *** * ** * *** * * ** * ****** * = * * *** * * ** ****
* ***** *** * *** * ***
*** ** ** ** ** * * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * **** ** **

int main()
{
* *** * ** * * ** * *** * n, i;

** * * ** * *** *** ***** ** ** * &n);

* *************** * = 1; i <= n; ++i)
**** * *** ** * ** * **
* *** * *** * *** * ** *** ** **** * ** ** % i == 0)
* **** ** * *** ** * * * *** * * ** * * * * * ** ** ** ** *** ** ", i);
** * *** * * * * **

******** * * * **** * * 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
*** * * ** **
** ** * ** **

int main()
{
* * * * *** * **** * * **** ** ** *
*** ** * * **** * ** * ** ** ** * * **** * * **** ** *
** * * *** * * **** **** = * *
* ***** ***** ** *** ** *
*** *** * **** ***** * * ** *
** * * * ** * ** ** **** * ** * *
** * * * * * * * * = -b /(2*a);
** *** ** *** * *** *** ** **** * * **
* * *** ** * *** * = (-b)/(2*a);
**** ****** * *** ** * * * * *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * * ** * ** **
* * * * *** * * *** *
* * * ** * * *** * ******* if(D==0)
* * * ** ***** ** * *
* *** ** * * * **** * = (-b + **
* ** ** ** * *** * ****** = (-b - * ******
* * * * ** *** *** * ** ** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * *
**** ** ** * * *
* * *** ** ** * * * if(D>0)
**** *** * ** * * * * * *
** ** *** * *** * * = -b/(2*a);
***** * * * * * = (-b + * *
****** *** * * ** * = (-b - **** **
* * *** *** *** *** * ** ** ** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * * ****** * *
* * * ** **** ** ** * ** *
* ** * * * * ** ** 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** **
#include ** *****
int main()
{
* ** * * * *** * * a,b,c;
** *** * * **** ** * **** * *** ** * * * * * * **** * *** ** * *** *
*** * ** * * * *** ***
** * ** * ** * * * * *
*** * * * * **** * ***
* *** *** ***** * ** * * *** ** * ****** * ** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * ** ** * ** + * *** *** * * - * * * *
** ** * ** * ** **
* * * *** **** * ** **
* * * * ** * *** * * ** * * if (b*b-4*a*c==0)
* * * * *** * **
* ** *** * ** **** * * * *** ** *** * ***** *** * *** * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** ** ** * + * * * * *
* *** * *** * * *
** ** * * *** *
* * *** ** *** * ** * **
** ** * * *** * * * ** *
***** ** ** * * * * * *** *** * * * ***** * * **** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * ** * *** *** *** ** *** * ** * * * * **** * ** * * ** *
** *** * * * * ***
* ****** **** *** * ** * * * * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** ***** *
#include * * * ****
int main()
{
* *** ** * **** * *** a,b,c;
* * **** * ** **** ** * ** ** ** **** * *** * ** ** *
* ** * * * **** * **
* * *** * * * ** ** ***** ******** **
*** * ** * ******
*** * *** * * * * ** ****** **** ** * *** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * * *** * * * + * * **** * * - *** * * * * *
* * ** * **** * ** * **
** ** * ** * * **
****** * * * ** *** * * * * if (b*b-4*a*c==0)
* * * *** ** **** * *** *
* **** * * ** ** ** * * ** ** * * * * * ****** * * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * ** * ** + * * * * *
** ** ********* ** ** *
**** * *** * ** *
* * * * * * ** ** *
* ** ** ** * * * *
** **** ** ** * *** * * ** * * ** *** ** ***** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= * * ** ** *** * *** ** ** * * ** ***** ****
**** * ** *** **** * *
** ******** *** * * * * * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
* *** ** ** ** **** * * * * a,b,c,d,x1,x2;
* ** * * * ** **** * *** * * ** *** * ** *** * * * * *** *
*** *** ***** ** ** * **
* * * ** *** ** * * ** * *
** *** * ** * ** * ******* *
* * * ** ** * **** * * * * *** ** *
****** **** ** ** * * * ** *
* * ***** * ** * ** * **** ** * ** * **** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * ** *********
* ** * * ** * ****** *** ** * ** ** ** ** *** *** = %.2f\n",x1);
* * * * * * **** * * *** * * ** ** *** * * ** * = %.2f",x2);
* ** * * ** * ** * **
* * *** * *** **** *** * if(d==0)
* ** * ** *** * *** **
** * * * * ** ** ***** *** * ** * ** ** * * * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
*** *** * * * * * **** * * * * * * ** = x2 = %.2f",x1);
* ** ** ** * ** * * * *
* **** * * * ** ** ** **
*** ** * ** * ** * ** * **
* ** * ******** ** **** *** ** * * ** * **** *** * *** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** * * ** ***
* * ** * * * *** *** * * * * ** ** **** * * * * ** = ** * * *** * * ***
*** *** * **** * * * * * * *** ********* *** = *** * ** ** * * ** * ****
***** ** * * * * * * *
* ** * ** ** * * ** 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
* ** ** *** ** **** *** ** * * ** * * * * *** * * ** * aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
** **** * * * * ** * *** ** * * * * ** - (4*a*c);
*** **** * ** *** **** * * * * ** ** * * ** ******
* * *** * ** * * * *** * ** **** * ** *** *** * ** ** ** * ****
** * ** * * *** ** ** * ** **** * * *** * * * *** * * *** * * (-b+spD)/(2*a);
*** * * * * * ** ** * ** **** ** ** * * * **** *** **** (-b-spD)/(2*a);
*** ** * * * * * *** ** ** * * *** *** ** ** (x1==x2){
* ** * * * ****** ***** * *** * * * *** * ** ** * ****** ** * * * * * *** * ** * ** * ** * ** * *** * ****** * *** * * * X=%d\n", x1);
* * **** **** * * * * *** * *** * * * ** * **** ** ** *
* * * * *** ** ****** **** * ** * *** ****** * ** * * {
* * * * * ** * * *** ** * ** * *** ** **** **** ** * ** *** ** * * * * * * * * * *** *** ** * * * * ** ** X=%d或%d\n", x1, x2);
** *** ** * * * ** * ** * ******* ** * * **** ** * * * *****
        }
*** * ** ** * ** *** ******* * * ** * * if(D==0){
* ****** * * *** * * ***** *** * **** *** * * *** * * * * ** * ** * **** (-b)/(2*a);
****** ** * ****** ***** ***** ******* * *** ** *** ** **** * * * ** *
** ** ** * * * * * *** * * *** * * * * * * ** * *** * *** **** *** *** * * * *** ** ** * * **** * X=0");
*** ******* * * ** ** ****** ** * * ***** ** * ** *** **** ****
* * ******* **** *** *** * ** **** ******* ** * ** * *
* ** ** ** * * ** **** *** * ** ** ** ***** * * * * * * ** ** * * * * ** * * * * * ** * * X=%d\n", x1);
* * * ** * *** * ** * ** * * * ** * ** * * * *** * * * *
        }
* ** ** **** ** * * * ** ** * * *
** ***** * * **** *** * * **** * **** * * ** *** ***** ** *** ** * * ***** * ** * * ***
*** ** * ******** ** ** * ** *** ** *
    }
** ** * ** * * *********** * * ****** * * * *** ****** * ***
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
* **** * **** * **** a,b,c,D;
* ** *** * * ** * x1,x2;
* *** ** * ** *** * * ** %d ** * * * **** ** *** *

** * ******** ****** ** *** **
* ** * ** * * ** ***
**** ** ** * ** * * * ** ** ****

* * * * *** *** **** *** A,B,C;
** *** *** **** *** * * ** *

**** * * *** * * * * * ** *
* * * * ** * * * ** ** ** **** ** ** *** * * * * * * * * of %.2fx^2 + %.2fx + %.2f = 0  are real and * *** ****** ** *
** *** * * *** * **** **** ** * * ***** * ** * * ** ** = %.2f\n",x1);
* * **** * * * ** * ** *** * * ** ** ** ** * ** ** ***** ** * = %.2f",x2);}

***** **** * * *** * if(D==0)
***** ** **** * * *** * * * ** * ** * ** ** * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
** ** * * ** * * * ** ** ** *** * ** * * *** * ** ** * * = x2 = %.2f",x1);}

*** * ** * * ****** * * if(D<0)
* **** * ** * * ******* ****** ***** ** ***** * * * * * of %.2fx^2 + %.2fx + %.2f = 0  are complex and * * ** * *** *
* * ** ** ** ****** **** ** ** * ** * * ** **** * * * bb,d,dd;
* * * ** ** *** * * * * * * ** * *** *** * **** * *
* * ** *** ** ** ** **** * * * * ****** *** ***** **
* * * ** * ** ***** * * * **** * * ***** *** ******* *** * = * ** * **** *
********* ** ** * ** * *** ** * * * *** * * *** * **** ** = ***** ** ** ** ****

*** **** ** ** * * * * * 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
*** *** ** *** **
int main()
{
* * * * * ** **** * * * ** * * * * * *
* * * ** ** ** ** * ***** * %f ** * * * * *** ****
* *** * * * *** * = (b*b-4*a*c);
*** * *** * *** ** *** *** = (-b + sqrt(D))/(2*a);
* *** * *** * * = (-b - sqrt(D))/(2*a);
* **** *** ** ** *** *** = -b/(2*a);
**** ** * **** * ** =sqrt(-D)/(2*a);
** * *** ** ** * *** * * **
* * ********* *
** * ** ** * **** **** *** * *** * * * * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and *********** *
**** * * * ** ** ** * * * ** * **** * * * ** * * * = %.2f\nx2 = %.2f",x1,x2);
* * * ** * ** * * *

** * *** * ** * * * ** * * if(D==0)
*** * *** * ** * *
* * * * ** * * * ** *** * **** ** * * * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ** * ** ** * * * ** **** * * ** * = x2 = %.2f",x1);
** * ** * ** *** *
* ** ** * *** *
*** ***** * * * * *** *
**** * * * ** * * * ** * * * ** ** * * ** ***** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * * * * *
* * * ** * *** ** * * ** * * ** **** * ** * * * *** = ******* ** * * * **** **
* *** * ** ** ****** * *** ** * *** ** ** ** * = * * ***** ** ** * *
* * **** ** ****
**** * * ** ** *** *** * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
** * ** ****** *
int main()
{
**** *** ***** ** * ** ** ** * * * **
* * ** * * * * * * %f ** * ** ** *** ****
** * *** * ** * *** ** * = (b*b-4*a*c);
* * ** * ** * * ** = (-b + sqrt(D))/(2*a);
****** ****** * ** ** = (-b - sqrt(D))/(2*a);
** *** ****** * * * * *** = -b/(2*a);
* ***** * * * * * * ** ** * ** ** =sqrt(-D)/(2*a);
* ****** ** * *** *** * * ** *
* *** * * ** * **
* * * ** * ** * * ** ******* * ** * **** * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** * ** *
****** * * * * ** ** *** ** ** ** ****** *** **** = %.2f\nx2 = %.2f",x1,x2);
*** * ** * * *** * ****

***** ** * *** **** * ** if(D==0)
* ** ** *** * * ****
* ***** ** * * ** ****** * * *** * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
*** **** * ** * * * * **** ***** ** * *** ** * * * = x2 = %.2f",x1);
** ** ***** * * * * *****
*** ** * ***********
*** * *** * **
** ** *** * * * * * *** *** ** * ** ** ** * ****** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** ** ** ** * **
** ** * * * * * ** * ** * * ** * = *** * * ** * * * *
***** * ** ** * * ***** ** * ******* **** * * * * ** ***** = *** * *** ** * *** **
** ** * * * ** * ***
* ** **** ***** * * **** * ** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.50.50
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users