0 like 1 dislike
8.5k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 8.5k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
*** * *** * *
int main()
{
* * * *** **** * **** * * ** * ** *** * ***
** ** * ** * * * **** ** * * %f * * * ** * ***
*** * ** ** * **** **** = (b*b-4*a*c);
* ** ** * ** *** *** * = (-b + sqrt(D))/(2*a);
** ***** ** * **** = (-b - sqrt(D))/(2*a);
* ** * * *** **** * * = -b/(2*a);
*** * *** ** * * * **** * * * =sqrt(-D)/(2*a);
*** * ** ** * ******** * *
******* * **** *
* * * ** * * *** **** * * ****** * **** * **** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * ** ** *** * *
*** * ** *** ****** *** * * * * ** *** * * ** *** = %.2f\nx2 = %.2f",x1,x2);
** *** ** ***** * *

** * ** * * *** * if(D==0)
* ** ***** * *** *
*** * * ** *** * * * ** * ** ** * * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * **** *** *** ***** * * ***** **** * ** * * * *** *** = x2 = %.2f",x1);
* * *** ** * **
*** **** *** **** * ** **
* * ** * * * * ***
* * * * ** **** **** * ** **** * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** * ** * *
** ** *** *** *** **** * ** * * *** * * **** ***** = * * * * ** * *****
* ** ** * *** * * * * * ** ** * **** * * *** * * * ** * * = *** * * *** ******
* *** * * ** ** * ****
* *** * *** * *** ** * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * * **

int main()
{
* ** ** *** ** *** * ** * n, i;

** * ** ** * * * * *** * * ** * ** * &n);

*** * ** * * * * ** * * = 1; i <= n; ++i)
* ** * ** * * * *
*** ***** * ** * * *** * ** * ** ** * *** % i == 0)
** ** ** * * * * * ** ** *** * ****** ** * *** * *** **** **** * *** * ", i);
* * * ** * *** * ** ***

* * ** *** ** ** ** ** 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * * *** * ****
* ** *** * * **

int main()
{
**** * ** * * ** ** ***** ** ***** **** ** *
** * ** ***** * ** * *** * * * * * * **** ** *
* ** **** * * ** *** * = ** * * * **
* * ** * * ***** **** * *
** * * * *********
* * * ** * * ** ***** ** **
* ** * * * * * ** = -b /(2*a);
* **** * **** * ** * ** *
*** * ** * *** * = (-b)/(2*a);
* * ** * ** *** * ***** * * ***** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = ** * * ** ***
* ** *** ***** ** * ** **
**** * ** ** * * ** ** **** * if(D==0)
* **** ** * * * ** *
* ** * * * * ** * * = (-b + * * ** * *
* ** ** * * * * * * = (-b - * **
*** ********* ** * *** ** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * **** **** *
***** *** ** * ** *** *
** * * ** * *** ** if(D>0)
* ***** **** ** ** **
** * *** ** ** ** * ** * **** = -b/(2*a);
* * * ** *** = (-b + * *** **
* ** ** * * ** = (-b - * ** * * *
* *** ** * ** *** * ** ** * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * * * **** *
* ** *** ** ** *** * *
* * * *** ** ** * *** 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** ** * * ****
#include * * * ** ***
int main()
{
* * * * ** * **** a,b,c;
* ** * * * * ** * ** * ** ** * **** ** * ** ***** **** * **
*** ** *********
** ** ** **** * ** ** * * ** **
**** *** **** * ***** *
** **** * * * * ** ** *** * ** ** * * * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ** * * * ** * + **** * **** - *** **** * ***
* ****** * * * * *
** * * * ** * * ****** *
** *** ** * * * * if (b*b-4*a*c==0)
* ** ** ** * **** * *
***** * *** * ** * * *** *** * *********** * ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * ** * *** + *** * **
* **** * ** * * ** *
** ** ** **** *
* ** *** ****** ******* *
* ** ** * ** ** * * **
* * ***** * ** ** *** **** * *** **** *** * ****** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * * * * ** * ** * * *** *** ** *** *** ***** ** *** * *
*** * ** * *** *
* * *** * *** **** * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** ** * **
#include * * ** ******
int main()
{
* * *** ** * ***** * a,b,c;
* *** * * * * ** * * ** * ** * ** * **** * ** * *** * * ****
** *** * *****
** * *** *** * ****** * ** *
***** * ****** * ** ** * * *
* * * ***** * ** * *** **** *** ** ** ** * * ** *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ** *** *** * * + ** * * ** * - *** * * ***
** * * **** ***** ****
* * * * * **
* * * * * * * ** ** * * ** if (b*b-4*a*c==0)
****** * * ** * **
* * * ***** * ** * ** * ** **** * * * ***** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = *** ** * * + *** *** ** *
* **** ***** * ** * ******
* * ** ***** ** * *** ***
*** ** ** *** ** **** **
* * ** ** **** ** * ** * **
** ** * *** **** ** * *** *** ****** ** * ** * * ** *** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= * ** **** * * *** *** *** ** ** *** * ** *
** * ** ** * ** ***** *
** * ** *** * * ** * **** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
** * * ******* * **** * a,b,c,d,x1,x2;
* ** ******** * * * * * * *** * * * ** * * * *
* * ** *** ** *** * **** * ** *
** **** * * *** ** * * ********
*** ** *** * ** * * * *** **
* * * ** ** * *** ** ** * ***
* * ** *** * * **
** * ** * * ** * **** ** * * * ***** * ** ***** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and * **** * ***** *
**** *** *** * * *** * * * *** * ** *** * ** * = %.2f\n",x1);
* * *** **** * ** *** *** * ***** ** * ** ** = %.2f",x2);
* ***** ** **** ** **
** * *** *** * ***** * ** if(d==0)
*** * * * *** * * ** ***
* ***** * * ** * ** ** ****** * * * ** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * * *** * * * ** * *** *** ***** * ** ** ** = x2 = %.2f",x1);
*** **** * * * * *****
** * *** * ** ** ** * * *
** *** *** **** * * **
** * *** * ** ** * * * ** * * ** * * * *** ***** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** * ** *** *
**** * ** ** * ** ****** ** ** ** * * **** * * ** = ** * * * ** * ** * *** ** **
*** * ** * ** ** * ** * ** **** * * * * ** *** * *** * = *** * * ** *
* * ** ********* **** * *
** *** **** *** ** * 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
*** * * * *** * * * * *** * * ** * ** * ******* ** * *** *** * aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
* * ** *** *** * * * ** *** * ** ** * ** - (4*a*c);
*** *** ** ** * **** *** ** * *** * * * ** * *
*** * *** * * * * *** *** * * * ****** ** * * * * * ** * *** ** * *****
* **** * *** **** * ** ** ** ** * ** ** * ** * * * **** ****** ** *** ** (-b+spD)/(2*a);
*** *** **** * * * ** ** * * * * * ** * ** * * * * * * *** (-b-spD)/(2*a);
* * ** * *** * * ** **** ******* ******* **** ** * * ** * *** (x1==x2){
*** ******** *** * ** * * * ** * * **** ** * *** ** *** * ** ** * * * *** * ** ** * *** * ** ****** ** * ** ** ** * * * ** X=%d\n", x1);
* * ** * * **** * * * * ** ** *** ** * *** ** * * * * ** *** * * *** **** ** *
** * *** * * * **** * * * ** ** * * * * ***** * * * {
** * ** ** * **** *** * * * * * **** * * ** * * * ** ** ** * * *** * **** **** * **** * *** ****** ** ** * * ** ** *** **** ** **** X=%d或%d\n", x1, x2);
* ** ************ *** * * *** ** * ** ** * **** **** ** ** * * ****
        }
** ** ** ** **** ********** ** ** ** ** **** ** if(D==0){
* *** ** * *** * **** * * * * * * *** *** ** * * ** * ** ** (-b)/(2*a);
*** ** ******* * * * * ** *** ** ** * *** *** * * ** * ** * **** **** *
* * * ** ** **** * *** **** * * ** ** ** ** * * ** ** *** *** * * * ** * *** ** ** X=0");
* ** * ********* * * *** * **** ** ** *** * ** *** * * * ** *
* * ** ***** *** **** * **** * ***** * **** * ** * **
** * ** ** * ** * * * * ** ** *** *** * * * ** *** * * * * ** * * * * * *** * *** X=%d\n", x1);
* * *** ** **** * * *** ***** * * * ** *** ** ** ** * * *
        }
* ** ** ** * ** *** ** ** * ** ** **** * ***
*** * ** ***** ** * ** * ** ***** ** * * **** ** * * * *** ** **** * ***** * ** ** * * ****
* **** *** * * * * ** * * * * ** *** * ****
    }
* * ** * *** ******* ** ** ** ** * ** ** * * ***
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
* ***** ** * * * a,b,c,D;
***** *** * ** ** * * * *** x1,x2;
***** ** *** *** * **** * * * ** ** %d * **** * * *** * * ***

** ** ******** ** * * *
**** * *** * * **** ****** * * *
* * * * * ** * * * * ** **

** * **** * * * ** * * * A,B,C;
** ** ** ** *** * ** *** *

* ** ** * ******* *** ** * *
** *** ** * ** ** * * * ** *** ** ** **** * * * * *** ** of %.2fx^2 + %.2fx + %.2f = 0  are real and * ***** ****** *
*** * **** * * * ** ** ** *** * * *** * * **** ** * = %.2f\n",x1);
** * * * **** **** * * * *** *** **** * **** *** ** * * * * ** * ** = %.2f",x2);}

* ** ** **** * if(D==0)
* *** * **** * **** * * *** * ** * * **** ** **** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
****** *** * * ********* * ** * * * ** ******* ** **** * * ** = x2 = %.2f",x1);}

*** * ** * * ** ** * if(D<0)
*** ** * * * * ** **** ** * ***** * ** ** ** ** * ** ** ** * * of %.2fx^2 + %.2fx + %.2f = 0  are complex and **** * *** * * *
** * * * ** ** *** ***** *** *** ****** * ** * ** * bb,d,dd;
* ****** ** ** * * ** *** * *** ** * * ** * * *** ** *
* * * * * * **** ** * ** ** * * **** * ** *
* ** * * * * ** * *** ** * *** * * * *** **** ** *** = * **** * * ** *
* ** *** * ** * ** * *** ** ***** * ******** ** *** = ****** * * *** *

* * **** ** * ** **** * * 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* * ** ** **
int main()
{
* *** ** **** **** * * ** ** ** *** ***** ** *
*** ** ** *** * * ** *** ** ** *** * %f *** * * * ** * *** *** * **
***** * * ** *** *** = (b*b-4*a*c);
** * * ***** * ** * = (-b + sqrt(D))/(2*a);
* * ** * *** * ****** ** = (-b - sqrt(D))/(2*a);
* *** *** * * * * * * = -b/(2*a);
* *** * ** * * * *** * * =sqrt(-D)/(2*a);
** * **** * ** ** * * * *
* ** ** * **** * *** *
* ** * *** ** **** * ***** *** ** * * * *** **** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and *** * * * *
** ** * * ****** *** ***** *** * * ** ** ** * * *** **** * = %.2f\nx2 = %.2f",x1,x2);
**** ** * * * * *** ***

* * ** ** ***** * ** * if(D==0)
**** ** ** * * *
*** * * ** *** **** ****** * *** * ** * * ** ** ***** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
**** ** ** * **** *** ** * * * * **** ** * = x2 = %.2f",x1);
* * * * * *** *
* ** * ** ** * ** * ***
** ** * * *** * * *
* * ** **** ** **** **** * ** *** * **** ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** * *** *** ***
** ** ** * * ** ***** * * * ******** * ** * ** * = ** * * * * ** *
* * ** ** ** ** ** ** *** * **** *** * ** ** * ***** = * * * *** * * * * *
** * ** ** *** ***********
**** *** * * * ** **** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* * ****** ******
int main()
{
** * ** ** **** * * * * * * * * * ***** *
* * **** * ** ** ** * ** ** * * * %f * * * * ** * * ** * ** *
* * * * * * * * = (b*b-4*a*c);
****** * * ** * ** * = (-b + sqrt(D))/(2*a);
** * ** ** ** * * ** ** = (-b - sqrt(D))/(2*a);
** * ********* ******** * * = -b/(2*a);
* ** * *** ** ** *** * ** * * * =sqrt(-D)/(2*a);
* ** *** ****** ** *
** * *** ** * ** **** **
** * ** * ** ** *** ****** ** ******* * ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and *** ***** * **
* * * * * * * **** * * ** * ** * * **** * * *** * * * * * = %.2f\nx2 = %.2f",x1,x2);
**** * **** * *

*** ** ******** * ****** if(D==0)
* * * ** * **** * * *** ** *
** * ** *** * ****** * * * ** * ** ** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* *** * * * * ** ** ** * * * ** *** ** * * * * = x2 = %.2f",x1);
** * * *** * ** **** *
* ** * * *** ** ***
**** ** ** *** * * * * *
*** **** * *** * ** * * ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** ** * **
* * * * *** * ** *** * * * * ***** * * ** * ****** = ** ** *** * ********** **
** **** * * *** * * * *** * * * * ** **** *** ** * = * ** * **** * **
** ** ** *** * ****
* * **** * * * * * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.255.69
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users