0 like 1 dislike
7.6k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 7.6k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
* * * * **** **
int main()
{
** ****** * * * **** *** ** * ** ** ****
** * * * * * * ** ** *** * *** %f * **** * ** **** * * ** * *
*** ** * * * *** * *** = (b*b-4*a*c);
** ** ** * * * * * * * ** * = (-b + sqrt(D))/(2*a);
**** * * * ** ** ** * = (-b - sqrt(D))/(2*a);
* * * ** ** * * *** * *** = -b/(2*a);
* ** **** *** * * *** ** =sqrt(-D)/(2*a);
* ***** * * *** ** **** * **
** ** * * * * * ** ** * **
** * *** * ** * ** * * ** **** ** ** ** * * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and **** * * * *
* * **** ****** * *** *** ** * *** * * * **** = %.2f\nx2 = %.2f",x1,x2);
*** * * *** *** *** **

** *** * ** * *** * * if(D==0)
* * * **** * * * **
* **** ** * * * * * **** ** * * * * ** * * ***** * *** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ** ** ** * * ** * ** * ** * ** ** ** * *** = x2 = %.2f",x1);
* * ** * ** *
** ***** ** **** ** *
** ** * **** * ** ***
* * * * ** * * * * *** ** *** * ** ** * **** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * *** ** **********
** * * * ***** ** * *** * **** * * **** ** ** **** * = * * ** * ** **** ** **
**** ** * ** * * * ***** *** ** * * ** * * *** **** * ** = ** * *** ** **** **
*** * *** * * * * ***
* *** *** * * * * * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** * * *** *

int main()
{
*** ** * ** *** n, i;

***** **** *** * * * ** * * ** * ** &n);

* * ** * **** * * **** *** = 1; i <= n; ++i)
**** **** ** * *** * *
** ** ** ** *** *** **** ** ** * % i == 0)
****** * *** * ** ** * * * * **** ********* * * ****** ***** *** * ** ", i);
* ** ***** **

* ** ** * ** * 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * *** *** **** *
* *** *** *

int main()
{
** * * * *** * ** * * * * * ** **** ****** *
* ******** * * **** * * * * ** ** ** **** ** * * * * ** ** *
** * *** ** * * ** ****** = *** *
** * ** ** ** * ** * ****** *
*** * * *** * ****** *
**** ** * * ** *** * * * * * ***
* * * **** ** * *** = -b /(2*a);
* ** ** * * ** ** * * ** * * * * ***
**** * * * * * * * * = (-b)/(2*a);
*** **** ** * ** * * * * *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * * ** * *** * **
* * * * ** * * ** ***** * **
**** * * * *** ** * if(D==0)
* ** * * * * ** * * *
*** ** ** * * * * * = (-b + * * *
* *** ****** ** ** * ** = (-b - * *** **
** * * * * ** *** * * ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** ** ******
** * * * * ** * * *
***** ***** * ** ** if(D>0)
* **** * ** * *
*** **** ** * ** * ** * * * = -b/(2*a);
*** **** ** ** * * * ** = (-b + * ***
* * **** * * * * * = (-b - ** **
* * *** ** * *** * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * *** * * * *
* * ****** ** * ** *
** **** * * ** ** * * ** 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include *** * * *
#include *** **
int main()
{
** * *** ** * * * * a,b,c;
***** * *** ** * **** *** * ** * ** * * ** ** *** ** *** * * **
** *** ** ** *
** * **** *** ** * * ** * * ** ***
**** * *** ** * * **
* ** * *** * *** ** * * ** ** * ** * ** *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ****** * ** + ** ** * * * * - * ** ****
* * ** *** * * *
* *** **** * ****
**** *** * * *** * * ** ** if (b*b-4*a*c==0)
** * *** ***** * * * * *
** * ** **** ** * ** ** * ** ** * * * * *** ** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** ** * + * * * **
******** * * ** ***
* ** * * **** * * *****
*** * * * ** ** ** *
** * **** * * ** *
* * * * * * * ** *** ** ** **** * *** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * ** ** * *** **** * *** * ***** ** * * ** * *
******** * * *** * *
** ** ***** * ** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * * ** *
#include **** ** **
int main()
{
*** * * ** **** * ***** ** ** * a,b,c;
* ** ** * *** * ***** **** *** ** **** **** * * ***** ****** * * *
** *** *** ** * *
** * * ** ** * * * ** * *** * * *** ***
** * * * * * *** **** * * **
** * **** * * * * ***** * * ** **** * *** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = *** *** ** ** + * *** * *** *** - * *** *** * ***
* ******* * * * * * * ***
** *** ** * * **
* **** * * ** **** if (b*b-4*a*c==0)
* ** * **
** * * * * * ** **** ** * ** **** * * ** *** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = *** *** *** + * * ** ****
** * ** ** * ** ** *
** ****** * * *** *
** ** * ** * ******
** ** ** ** * * *** **
** * **** **** ** ** * * *** ***** ***** **** ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= * ** ** *** * * * ** *** * ** ** *** ** *
*** ** * ** * * *** *
** ***** ** * * * ** * **** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
** * ** * **** ** * **** * a,b,c,d,x1,x2;
*** * * ** ***** * ****** ** ***** ** * ** * ** ** *
*** * * * * ** ***** * **
****** * ***** * * * * * ***** **
* *** * *** * ** * * * ** *** **
*** * *** * * *** **** * ***
** ***** * * *
*** * * ** ******** * * ** ** * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and *** ***** * *
** ** ** * *** * *** * ****** ** * ** * ** * = %.2f\n",x1);
*** * * * * *** * * *** * * * * * ** * ** ** ** * = %.2f",x2);
* * ** * * *** * *
* **** * * * ** *** if(d==0)
* * * **** ** ****
*** * *** ** **** ** * * * * * ***** * *** * *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** * * *** ** * ** ***** ** * * ** ** *** * * **** * **** * = x2 = %.2f",x1);
** * ** ***** ***** *
** * * * * ** * *
* ******** * ** *****
* * * * * ** ** * * ** * * ** ****** * ** **** ** ** **** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * ** ** ***
* *** * * * * * ** ** * * ** * ***** *** *** * * ** = ***** ** *** *** * ** * ***
* * * * * ** ** *** *** ** ** * ***** * * *** = **** ** *** *** **** *
**** * *** * * * ***
* * * * ** ** * *** * 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
*** * ** * * ***** ** * * * *** ** ** * * ****** * aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
* ** ****** *** ** * * *** ** * *** * ** *** * - (4*a*c);
* ** ** *** * ** * * * ** * **** **** * * * ***
**** * * *** * ** * * ** *** ** ** * *** *** *** ** *** **** **** **
*** *** * ** *** *** * * * *** * * ** **** * *** * **** * ** * * * (-b+spD)/(2*a);
* * * ******* ** ***** ** ** * ****** ** * * * ** * * ** ** ** * *** * (-b-spD)/(2*a);
** * ** * * * * * * * ** **** ** * * * * ** ** * ** **** * (x1==x2){
** *** * ** * * * ** * * * *** *** ** * * *** * **** ** ** ** ** ** ** * * *** ** * *** * ***** ** * * * ** ** *** * * X=%d\n", x1);
** * *** *** ** *** * * * **** * * **** **** * * * * * * *
* * *** *** * * ** ** * *** ** ** **** * * ** * ****** *** * * {
** ****** ****** * *** ** *** ***** *** *** *** * *** *** ** ** * * ** *** ** * * * * *********** ****** **** *** *** * * * * * ** * * X=%d或%d\n", x1, x2);
* ** * ** * ** * * * * * * * * **** ** * ***** * * * ***** *****
        }
* ******** ***** *** * * *** * * ** ** * ** if(D==0){
* ** **** * ** *** ** *** * * * * * ** * ** * * **** ** **** (-b)/(2*a);
*** * * ****** * * *** *** * ** **** * ****** **** * * * * * * * * * ****
* * *** ** * ** **** * * ** * ***** *** * * *** *** * *** ** * ** * ** ** * *** ** *** X=0");
* * **** ** * *** ** * *** * * ** *** ** *** ** * * ** **** * ***** **
* * * * * *** ** ** ** * ******* * * ** *** * * ** * * * *
* * * **** * * * * * ** * * *** * ** **** * ** * * * * * * **** * ***** **** *** * ** ** * * * ** * X=%d\n", x1);
* ******** * * * ** * * *** **** * * * * * *** ** **** ** ** * *
        }
* * * **** ******** ****** *** * *
* ***** * * * * ******* *** * ** *** **** *** * * ** * ** ** ** * * **** ** * * *** * ** ***** * ** *
** ** *** * * ** * * ***** *** * *
    }
* ***** ** ****** ** * * **** * * ** ***** *** *
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
***** * ** ** * * * a,b,c,D;
** *** * ** * * * ** x1,x2;
** *** **** * * * *** ** ** *** * %d ** ** **** *** **** *

* * *** **** * * *** * * *
*** * * ** ****** * ** ***** *
*** ** * *** ** * ** * **

* *** ******** * ** **** ** A,B,C;
*** * ** **** *** ** * * *

*** ** * * * * ** ***
*** * ****** ** *** * ** **** * ********** * * ** of %.2fx^2 + %.2fx + %.2f = 0  are real and * **** * * * * *
* ** * * * ***** **** ** * * * * * *** * ** * * * **** * ** = %.2f\n",x1);
** ** * * * * ** * * ****** ** ** *** * ** ******* * *** = %.2f",x2);}

*** ** * ** *** ** * * if(D==0)
* * ******* * * *** *** ** ** * * ***** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
* ** **** * * * *** ** * *** ** * *** ** * *** * * * * ** * ** ** = x2 = %.2f",x1);}

*** ** ** **** * * *** * * * * if(D<0)
** * **** * * * ** * ** * ** * ** *** ** * ** ** of %.2fx^2 + %.2fx + %.2f = 0  are complex and ** ** * *
** ** ***** * * *** *** *** *** **** * ** *** bb,d,dd;
* **** * * ************* * * * ****** ***** * ** ** * * * * **
** ** * * ****** ** * ** **** **** * * ***** *
**** * * * **** * * ** * ** *** * * * *** *** ***** = * ** ** * * * * *
* **** * **** * * ** ** ** * * ***** * ** **** * * * = **** ** **** ***

** * * ***** * ** * ** ** 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
*** *** ** * *
int main()
{
* * * * * ** ** * * * *** ** * ** *
** * * * ** ** * **** * **** * %f ***** * * * **** ** **
**** * *** ** ** * * * ***** = (b*b-4*a*c);
** ****** * ********* * * = (-b + sqrt(D))/(2*a);
* ** ** ** * * ** = (-b - sqrt(D))/(2*a);
** * ** * ***** **** * * * * = -b/(2*a);
*** * ** ** ***** * * =sqrt(-D)/(2*a);
* *** ** ** ******* **** **
* ** * ** ** * * *
* * * ** *** ** ** ** * ** * *** ** **** ** * * * ** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and * **** * * *
* * ** **** * ** * ** * * ** ***** ** **** * ** = %.2f\nx2 = %.2f",x1,x2);
** * ** ** * * * ** **

* * * * * ** **** * if(D==0)
* * * * * ** ** * *
* ****** **** * * * * * *** * ** ***** * **** *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ** * * ** ** * ** *** *** ** * ****** * * ** **** = x2 = %.2f",x1);
* * * * * ** * ** **
* * ** ** * ***
* ** * * * ***** ** **
** * * * * *** *** *** * * ** **** * * ******* ** *** * ***** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * *** ***** ***
* * * ** * *** * * * ** * ** * * * ****** * * ** * = ** * ** * * * **** *
* ** *** * ** ** * * * *** * ** * ** ** * ** * = * * ** ** ** ** ** *
** * * * * * *** * ** *
* * *** ****** * * ** **** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* *** ** ** **
int main()
{
** ***** ** * * *** * * * ***** *** * * *** * * *
* * ** * ** ** * *** ** %f * ********* ** * * ** * *
*** * * * *** ** * *** * = (b*b-4*a*c);
** **** * * **** * * = (-b + sqrt(D))/(2*a);
** ****** * ** ** = (-b - sqrt(D))/(2*a);
* ** * *** * ** ** *** ** * = -b/(2*a);
*** ****** ** * ** =sqrt(-D)/(2*a);
* ** * * ** ** ***** ** * ***
*** ** * *** ** **** * ****
**** * ** ** * ** * * * * * * * * ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and * ** * * ***
** *** ** ** ** * *** **** * ** ** ***** * ******** = %.2f\nx2 = %.2f",x1,x2);
* * ***** ** *****

* * * * **** * ** * if(D==0)
* *** ******* * ** * * *
** ** **** * ** * * ** * * ** * * *** * ***** * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ****** ** * * *** ** ** ** ****** ****** ** *** = x2 = %.2f",x1);
* ** *** * * * *
* * *** * *** ***** * * * **
** * * * *** * * * *
* ** ***** **** ** *** ** * *** **** * * * ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * **** *** **
** * * * ** * ** * ** ** ** * * * ** * * ** = ** ***** * ******* *
* ** *** ** * *** ** * ** ** *** * * * ** ** * *** * = * * * * **** *** ***
* ****** ** ** ** * *
* * ** *** ***** * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.107
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users