0 like 1 dislike
6.7k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 6.7k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
**** ** * * ****
int main()
{
***** * *** * * * * * * * ** ** *** *
***** * * * ** ** * ***** * * * * *** %f ** ** * ** * ** * ***
* * * * * * * ** ** = (b*b-4*a*c);
* * * * *** *** * = (-b + sqrt(D))/(2*a);
** * * * *** ** ** * * * = (-b - sqrt(D))/(2*a);
* ** ****** * ** * * * * = -b/(2*a);
* * * ** * ** * * * * * * * ** =sqrt(-D)/(2*a);
* * *** * * * * ** ** * **
* ** ****** ** ** *
** * * * *** *** * * * * * *** *** * * * **** ****** of %.2fx^2 + %.2fx + %.2f = 0 are real and * * **
* * * ****** *** * **** *** * ** * * ** * * ** = %.2f\nx2 = %.2f",x1,x2);
** * * * * * * * * **

* *** * * * * * ** ** ** if(D==0)
*** ** * ***** **
********* ***** * ** * * * *** ** * * ** ** * * *** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** * * * * * * ** * ** * ** ** ***** **** * * ** *** * = x2 = %.2f",x1);
** *** ** * * ** ** *
** * * * * ** * *
**** ** ** ****** * * *
* * ** ** ****** * **** ** * * * ** *** ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** ** * ** *
** * * * ***** ** ** * ** ** ***** * **** ** ** * = ** * * * ** ** * * * * **
* ** ** * * ** * * * * ** ******** ** *** ** * = ** * * * ***** * **
* ***** * ** * *** *
* * * ** * ** *** ** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * ** *** *

int main()
{
* ******* *** ** * * * n, i;

*** * * * ** * ** ** * ** &n);

*** **** * ** ** * ******** = 1; i <= n; ++i)
*** * * ** * * *
* ** ** ** * * * * * * *** ** ** * % i == 0)
* * * *** * ** ***** ** **** * **** * ** * ***** * ** **** * * *** ", i);
****** * * *** * *

* * * ** * * **** * * * 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** ** * ** * *
*** ** * ****

int main()
{
** ***** ***** ****** * *** * * ** *
** ***** * * ** ** ** **** * * * * ** ** **** * *
*** **** * **** * = ** *
** *** *** ***** * *** ** * *
* * * * * ** * * *
* *** *** ** ** ** **** *** **
*** ** * ***** ** ** = -b /(2*a);
* * ** * * * ** ** ** ** * * * * *
* ** * ** ** * ****** = (-b)/(2*a);
* *** ** *** ******* * ** *** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * * *** ** * * * *
* ** ***** * * ***
** * * *** ** * * *** * * * if(D==0)
* * **** ** * *** *****
* * *** ** * * * ** = (-b + *** *
*** ** * * **** * ** * = (-b - ****** *
* * * **** * * * *** * * ** ** *** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * ** * *
* * ******** * * * *
* *** * * ******* * *** *** if(D>0)
** *** * * * *** * *
* **** ** * *** *** = -b/(2*a);
* ** * * * ** ** ** ** = (-b + * * ** * *
** ** ** * *** ** * * = (-b - * **
* ** ******* * ** * * * **** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ** ** ** ** ** * *
** **** * *** ** ** **
* ** ***** ** * ** * ****** 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * * * ***
#include *
int main()
{
****** * * * * * ** * ******* a,b,c;
** **** * ******* * ****** * **** * * ** *
* ***** **** * * ** **
*** * * ** ** ** * * * **
** *** ** * * ** **
** * * ** ** * ** ** * ** *** * *** *** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * * * **** + * **** ** *** - * * ** ** *
*** * * * ****** * *
* * * *** ** * * * *
* * * **** ** * *** ** if (b*b-4*a*c==0)
*** * ***** * ** * ***** *
** * * * * * ** * * * * * *** * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * *** + * * ** * **** *
* * ****** ***** * **
** * ** * ** ** *** *
** * *** * ** ** ****
*** ** * ** * ** *
* ********* ******* ** ** * * ** * ** * ** * *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * ** **** ** * * * *** * *** ** ** * * * * **
* ** ** * ** ** * * *
**** * * * **** * ** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * * * *
#include * ** **
int main()
{
** ** **** *** * * ** a,b,c;
* * * **** ** * ** ** ** ** ** ** * ****** * * * * *** **
****** ** * ** **
**** ** ** ***** ** * ** * *
** * ** *** **** ** ****
** * **** * ** * ** * ***** ** * *** * ** * ******* * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = **** * * * + ******* **** - ** ** * *
***** ** * * ** * **
***** * ** * * ** *
* **** * * * * * ** * if (b*b-4*a*c==0)
* ** ** * *** * ***
* * * * * * * * ** ** ****** * **** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = **** **** * + * * ** * ***
* * *** ***** * * * **
* * * * * * ** * * *
** ***** * * ** *** *** *
**** * * *** * *** ** *
* * *** ** ** * ***** * * **** * * * * *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= * ** ** * * *** ** ***** * * * * ** * ** *** *
* *** **** * * *
* * * * ** **** ** ** * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
* *** *** * *** ** ** * ** a,b,c,d,x1,x2;
* * ** * *** * * ** ** * * ***** * *** * * * ***** * * * * *
* * ** * * ***** *** ** * ** * *
* * ** ** ** ** * ***** ** ***
* * * * * ** **** ** ** * * * ** **
* *** ** * * *** * *
* ****** * * ** * **
** * *** ** * * * **** * * ** * ** * ** ** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and * * * * * ** ***
** * * ** * * *** * ** * * * *** * ** * * * * * ** * = %.2f\n",x1);
* *** *** **** * ** * * * * * ** ** * *** ***** ** = %.2f",x2);
* * * * * ** *
*** ** * *** ** * * if(d==0)
*** ** * ** **** *** *
*** * * *** ** * *** * ** **** * **** * ******** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ** ** * * ******* ** * * ** **** * ******* = x2 = %.2f",x1);
*** * * ** * ***
**** *** * ***** * ***
**** * * * ***** ***
** * * **** * *** * ** *** **** * ** *** * ** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * **** *
* * ** * * * * ** *** ****** * * * * * = **** * * * * ** ** ** *
** ** * * *** * * *** * *** * * ** *** * * * * * * = ** *** ** *** *****
** *** * * ** **
*** **** **** ** ** *** ** ** *** 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
** * *** * * ** ****** * ** ** *** * * * * ***** * *** * * aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
* * ** *** ** ** ***** * ** *** * * * * ** - (4*a*c);
** * * ** ******** *** *** * * *** * **** ** * **
* ******* *** **** * ** *** * ** * * **** ***** ** * * **** ******* ****** * *
* ** * * *** * * * * * **** ** ** * ** *** * **** **** *** (-b+spD)/(2*a);
** * * * ** ** * ** * * ** ** * ** * *** ** ** ****** ** * * * * * (-b-spD)/(2*a);
* * * ** * ** * ** ***** **** * * * *** **** * ***** ** * ** **** **** * * (x1==x2){
** * **** * *** ** * *** *** * **** **** * **** * * *********** * ** ** * * ** * *** * * *** **** * ** * ** *** ** **** ** * ***** * X=%d\n", x1);
** ** ** * * * * ** * *** ** * *** *** *** ** *** ** *** ** **
**** ** ** * *** * * ** * ** ** ** *** * **** *** *** ***** {
** * *** ** * * * **** * * ** * ** ** * ** **** ** **** ** * * * *** * * * * * * *** *** * *** *** ** * * * ** ** X=%d或%d\n", x1, x2);
**** * ** * *** *** ** * **** * ** * ** * ***** *** * *
        }
* * ** *** * *** * ** * * * * *** * ** * if(D==0){
*** ** ** ** * ***** * ******* * * ** ** ** ***** *** * ** * (-b)/(2*a);
****** * * * ** ***** **** ** * * * ** * ** * * ** * * * * *** *
** * * *** **** * * * *** * *** * ** ** *** * * ** * * * * *** * * ** *** * * * * * * X=0");
* * *** * * ** * ** **** * * *** * * ****** * ** *** ** * ** **
** ** ***** * * ***** * * *** * ********** * * * *** * * * ****
*** * * * **** ** * * *** *** * * * * **** * *** ** * * ** * * * * * ** ** ** * * *** * * * ********* X=%d\n", x1);
* *** ** **** ****** * ** ** * *** ** ** * ** * * ** **** *
        }
*** * * *** * *** * * ** ** **** * ** * *
** * * * **** ** * * **** * * * * * * * * *** **** * **** * ** * * **** ** ******* * * **
* **** *** ** *** * * ** * * * * * * * * **
    }
* ** ************ ** * ** ** * *** * * ** ** * **
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
*** ***** ** ** * a,b,c,D;
* * ** * ** *** ***** ** x1,x2;
*** *** ********* *** **** *** %d *** ** **** *** ** * *

*** * * ** * *** * * *
* * * * * * * **** * * * * ** ****
* **** **** ** **** * * ** **** *

** * ** *** ** *** A,B,C;
* * ** ** * * * * *** *

** * **** ****** **** *
* * ** ****** **** * *** * * * * *** * * * ** * * of %.2fx^2 + %.2fx + %.2f = 0  are real and ***** * * *
** * * *** **** **** * * ******* ** * * ** **** * *** * = %.2f\n",x1);
*** * ** * * ***** * * * **** ** * *** *** * ** **** ** *** * = %.2f",x2);}

* ** *** * ** ** ** * if(D==0)
********** * ** ***** * * * ** * *** * *** * ** ** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
* * * * *** *** *** ** * * ****** ** * * * ****** * = x2 = %.2f",x1);}

***** *** *** * * ******* * if(D<0)
** ****** ** * ****** ******* * ****** ** * ** **** ** * of %.2fx^2 + %.2fx + %.2f = 0  are complex and ******** *
* * *** ** * * ** ** * ** * *** * * ** ** * bb,d,dd;
**** ** *** * * ** ******** *** ** * * * ** * **
* * ******* ** * * ** * ** * * * ** * * *** * ** * * *
* * ** *** *** ** ** **** * *** * * * * ** * **** * *** * ** = ** * **** * ** ** ** *
***** ******** ** ** *** * * *** * ** * *** ** * * *** * * ** * = ***** * *** * *

** * * *** ***** ** 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* * * *** * **
int main()
{
*** **** * * ** * **** *** * * * *** *
** *** * ** * ** * * ** %f * * * *** ** ** ** * *
***** * **** **** = (b*b-4*a*c);
**** * ** ** * ** = (-b + sqrt(D))/(2*a);
* * ** * * * * * *** * = (-b - sqrt(D))/(2*a);
***** * **** * ** *** * * = -b/(2*a);
** ** **** * * * * *** =sqrt(-D)/(2*a);
* ****** **** * *** ****** * *
* * ** * *** ** * *
* * * * *** * * * ** * * ** * ***** ********** **** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and *** ** *** * * *
*** * ** ** ***** * ** ** ** ** **** * * * * * * = %.2f\nx2 = %.2f",x1,x2);
* * * **** * * *

* ** ** ** * ** * **** ** if(D==0)
*** * ** *** * * * *
* ** ** * ** * * ** * **** ** ** **** * ** ** *** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * * ** ** * * ** * * * * * ***** *** * ****** = x2 = %.2f",x1);
* ** * * * ** ** * **
* * * ** * *** *** * **** *
****** * * * ** * * ***
** * * * * * * * * ** * ******* *** ** *** **** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** * * * * * *
**** * * ****** *** * * ** **** * ** * ** *** = * * ** * * ** ****
** ** * * * ** * *** **** *** *** * ** *** ** * * ** * = * ******* **** * ** *
** *** * * * * * **
** * * *** ** ****** *** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
** * ******* *
int main()
{
* * * *** ***** * * **** * ** *** * * ** *
** ** * *** * ** *** *** * * ** %f * ** *** * * ***** * **
* * ** *** ** ** * ** = (b*b-4*a*c);
* ** *** * ** ** * ** * = (-b + sqrt(D))/(2*a);
** ****** * * ** * ** * = (-b - sqrt(D))/(2*a);
* * * * ** ** *** *** * = -b/(2*a);
* ***** ** * ** * **** * * =sqrt(-D)/(2*a);
*** **** * ** * ***
*** *** * ** **** * **
* ****** ** *** ** * **** * **** * * * *** ** ** * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * *** ** *
* * ** ** **** * * **** * **** ****** ** *** * * ** = %.2f\nx2 = %.2f",x1,x2);
* ** * * * **** * * *

* ** ** ** * * * **** ** if(D==0)
***** * * **** ** * *
* * **** ***** ** ** * * * **** **** * *** * * * ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ** *** * ****** *** * ** *** * ** * *** * **** ** *** ** = x2 = %.2f",x1);
** *** * ****** * * * *
** *** * * ** * * ** * * *
* * * * *** *** ** * ** ***
* ** ** *** * * * * * ** ****** ** ** *** ** **** **** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * * ** * ****
* * * * * ** * * * ** * ** * ** *** ** * * *** * * = * * *** ** ******* * * * * **
** * **** * * ** * * ** * *** *** * * **** ** * = **** ** * *** *** *** *
* ***** ** ** * *** * ** *
*** * ** ** * * * * **** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.100.84
©2016-2025

No related questions found

12,783 questions
183,443 answers
172,219 comments
4,824 users