0 like 1 dislike
17.3k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 17.3k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
* * * * * * **
int main()
{
*** * * * * * * * ******* * *** * *** * ** ** **
* ** * ** * * * ** * *** * * * %f ** * * * * *** *
* * ** * * ** *** = (b*b-4*a*c);
*** * ** ** * ***** * = (-b + sqrt(D))/(2*a);
* * * ** * * * = (-b - sqrt(D))/(2*a);
* * ** ** ** * *** * = -b/(2*a);
* * * * ** * * ***** * ** *** =sqrt(-D)/(2*a);
*** ** ** * * ** ** ***
* ** * * *
***** **** *** * * * * * *** * * ** * * * **** of %.2fx^2 + %.2fx + %.2f = 0 are real and * ** *** * * **
**** *** * *** * ** * ** * * ** **** * ** * * * * = %.2f\nx2 = %.2f",x1,x2);
*** ** ** * ***** **

* *** ***** * ** * if(D==0)
**** * * * ** ***
** * * * * * ** * * ****** * * ** ***** ** *** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
*** ** * ** ** * * *** *** ** *** * ** *** ** * = x2 = %.2f",x1);
** ** * ** * ** * ** **
** *** *** **** ** **
* *** ** *** ** * ** **
* ** ** ** *** ** * ** * ** * * * * ** * ***** * * * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * *** ***** *
* * ** * * ** * * ** * ** ** * ** * ** ** * ** * * ** * * = **** * ** * ** * ** ** *** *
** ***** * **** * * *** * * * * ** * ** ** ** ** = ** ** ***** *** *** *
** * ** * *** ** **
* * *** *** * * ** *** * ** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** * * * *

int main()
{
* * **** * *** ** ** *** n, i;

** ** * ** * * *** ** **** * ** *** * **** &n);

*** ** ** ** * * * * * = 1; i <= n; ++i)
** * * **** ** ****
* * * * ** ** * **** * * * ** * * ** % i == 0)
*** ******* ** ** ** ** * * ** * * *** * * * * * ** ** * *** * *** ", i);
** * ** ** * ** ****

* *** ** **** ** *** **** 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * *** * ** ** * *
* ** * * * * *** *

int main()
{
**** * * ***** *** *** **** * ** *** ** * * *
**** * * * ** ** * ***** ** * * *** ******* * * **
* * * * * * ** ** * = *** ** **
* * ** * **** * * * ** *
* * ** *** * * *
* * ***** ** **** ****** * ** *** *
* * **** ***** * * ** * * = -b /(2*a);
*** * ***** * ** * * *** * **
* ** * * **** ** = (-b)/(2*a);
* * * * * ****** ** ** ** *** * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * * ******* ** **
* ** * * ** * *******
* ** * * * **** * *** * if(D==0)
** * * * * * ** *** *
* * * ** ***** * *** * = (-b + **** *
* * ** ******** * * *** ** = (-b - ***
**** **** ** *** *** ** * *** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * ** ** ** *
* ** * **** * ** ***
** * * * * * * * * * if(D>0)
** * * * * *** * * * ***
* * * ** ** ***** * *** ** * * = -b/(2*a);
** * **** ** *** = (-b + *** **
** * * ** ** **** * **** ** = (-b - ** * ***
* ** **** *** * * * * **** * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * * ** *** *
* ** **** ** ** *** ***
** **** * **** ** * ** * 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * **** *
#include **** * * *
int main()
{
* *** ****** ** * ** * a,b,c;
*** ** * ** * * **** **** *** ** * ** * * * * ** * * ** *
** ** ** * * ****
* *** * * * ** ** ***** ** ***
*** *** *****
* * * * ** * ** * *** * * ** *** **** * **** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ** * *** * * + * * * * * ** ** - *** ** **
** * * ** **** *
* * ** * ** ** * * *
** ** ***** * * * ****** if (b*b-4*a*c==0)
* ****** * * ** * *
* ** ** ******* * ** * * * * *** * *** *** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = *** ** *** * * * + ** * * *
* **** * ** ** ****
* * *** **** **** ***
* * ** ***** ** * ****
*** * * * * ** *
* *** * * * *** *** * ** * * ** * * **** ***** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = **** **** ** * * *** * ** *** * * * ** * * *** ***
*** ** * * * **
* * * * ** ***** * ** ** * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * *** ** * * **
#include * ** **
int main()
{
**** * * **** **** a,b,c;
***** * ** * *** *** ***** * *** * **** ** * * **** **
*** ** * *
* * * ** ***** * * ** *** ** * * ** * *
* ** * ** * **
** * * * ** * ***** * * ** * * ** * * ** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ****** **** * * + * ** ** *** * * - * * * *
*** * * * ** ****
* * * * ***** **** ** **
* ****** * * * * * ** * * if (b*b-4*a*c==0)
* * * **** *** * ** * *
** ** * **** * ** ** * * * ** ** * **** ** * ** **** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * ** * **** + ******* **
** * ****** **** *** * * *
* *** * ***** *** *
**** * * * *** * **** *** *** **
* * * ** * * * **
** * * ** ** **** ** * ** ** * ** *** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= *** ** ** * * * * * * * * * * * *
** * ** *** ****** **
**** ** ** *** *** ** * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
** * * * ** ** * * a,b,c,d,x1,x2;
* * ** * ** ****** ******* * ***** * ** * * *** * * * *
******* * ** **** **** *
* * *** ** ** *** ** ********
* ****** **** ** *** * *** ** *** *
* * * * * * * * ** *** **
** **** *** * * ** ***
* ** ** * ** ** * * ** * * *** * **** of %.2fx^2 + %.2fx + %.2f = 0 are real and *** ** * * * *
* *** * ** * * * ** ** *** ** * * ** ** = %.2f\n",x1);
* * *** * **** * *** ** * * *** *** * ** = %.2f",x2);
* * *** ** * ****
**** * ** ** ** **** *** if(d==0)
** * * ** * * ** * **
* ** * * * **** * * *** * * * ** * ** *** * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ** *** ** ** ** ****** * *** ******* ** * * * * = x2 = %.2f",x1);
**** *** * * * *
* * * * ** * **** *
** * * * * **** *
** * ** **** *** ** * ***** ** * ** * * ** ****** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * *** ** * * ** * *
* **** * ** *** *** * * ** * * * ** * *** *** = ***** * * * * ******* * * *
* ***** ** * **** * * *** *** * *** ** * **** **** * ***** * * ** = * *** * **** ** * * * ***
**** *** * *** ** ** **
* **** ** * * ** 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
*** ** *** * *** * * *** * ** * * *** ** * *** ** * ** ** aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
**** * *** ** * **** * * * *** * *** * * * ** - (4*a*c);
* ** * * * **** ** * * ** * * * * * *
* ** ** *** * * * ** * * *** *** ** * * * * * * ** * * * ** *
** * ** ***** * * * ** ******* *** * ** *** * *** * * * * (-b+spD)/(2*a);
* * * * *** ** ******** ** **** * * *** * *** * *** * ** * *** (-b-spD)/(2*a);
* * *** ** ** * * * ** * ** * * ***** * ** * * * * *** ** ** * * (x1==x2){
****** ** * ** * * ** ** **** ** * ** *** *** * *** ** ** * ** *** * *** * ** * * * * ** * ** *** ** * * ** *** *** *** * * ****** X=%d\n", x1);
* ** ** *** * **** ** * ******* *** * * ** * ** * *** *** **
**** * ** * ** ******* ** ** * ** * ** ** * * * ** * * * *** **** * {
* * * * * * * * * ** * * * * **** * * * ******** ****** * **** * * *** * * * * * **** *** * * *** * ** ** * * ** *** * ** * * X=%d或%d\n", x1, x2);
* **** ** * *** * * ** * *** * **** *** **** * *** *** * * **** *****
        }
** * *** ** * * * * *** * ** * if(D==0){
***** * ** * * ** * ** ** * * * **** * * * **** ** ** ** ** *** * (-b)/(2*a);
**** * * * ***** ** * * * * * * * ** ** *** * * * * * *
* *** ** * *** * * * * ** *** * ** ** *** * *** * ** * ** *** ***** ** ** * * *** ** * ** * X=0");
** * * *** *** * * ** * * ***** ** *** * * * ** *** *** **** ** *** * ****
** ** * **** * ************* * ** *** **** * ** ******** ** * *** *
*** * *** * *** *** * * ** * * * * *** ** * *** * * * * * **** ** ** * *** * *** * *** ** *** ** * * X=%d\n", x1);
* * * * ** **** * *** *** * ** * * ***** *** * **** ** **** ***
        }
*** ** * * * * * * * ** * ** * *** ****
*** *** * * * * * * * * * ** * ******** * ** * ** * * * * * **** * * *** * ***** ******** *
* ** ** ***** * ** * * **** ** * * * * *
    }
*** * ***** ** * ** * *** *** * * *** *
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
** *** * *** * *** ******** a,b,c,D;
* ** *** *** **** * ** x1,x2;
** * * * ******** ** * * * %d * ** ** * ** * ** ** ******

**** * * **** * ** * * ** ****
* ** * * * ** ** * *** *** * * **
* * * * * * * * * **** **

* * * *** ** ***** * A,B,C;
*** ********* * ** * * * *

** ** **** **** * * * **
***** * ** * ** * * * * ******* ** * ** * *** ** * * *** * of %.2fx^2 + %.2fx + %.2f = 0  are real and ** ** * ***
* ** **** *** ** ** *** * * *** ** ** ** ** *** ***** * **** *** = %.2f\n",x1);
* *** *** * * *** * * ** * * * * * ** ** **** * **** * * = %.2f",x2);}

**** * * ** * ** *** * * if(D==0)
* *** * **** ** * * ** ** *** ** * * *** ** ***** *** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
** * * ** * * ** * **** * ** **** * * ** * * * ** = x2 = %.2f",x1);}

* * ************ * * ** if(D<0)
***** * * * ******* * * ** *** * * * * * ** of %.2fx^2 + %.2fx + %.2f = 0  are complex and * ** *** *** * *
* * * **** * **** * * ** * **** *** *** **** * ** * bb,d,dd;
* ****** *** ** *** * * ** *** * * **** ** * *
**** * *** * * ***** * * **** * * * ** ** ** ** *** **
**** ******* * * ******* ** * ** *** ***** * * ** = ***** * ** * *** **
****** ** * *** * *** * ** ** * * * *** * *** * * ** = *** * * * *

* ** * * *** *** *** * * 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* * **** ****
int main()
{
* ** ** * ** * *** ** * * ** * * * ** * **
***** * * *** **** * ** ** * %f * *** * * *** * * *
* ** *** ** * * = (b*b-4*a*c);
* * *** * * ** * * * **** * = (-b + sqrt(D))/(2*a);
* * * ***** ** *** = (-b - sqrt(D))/(2*a);
* * ** * ** ** * * ** **** ** = -b/(2*a);
* ** ******* ** *** ** **** * * =sqrt(-D)/(2*a);
* ******* * * ** **** **
* * * * ******** **** * ***
*** *** * * * ***** * ** ** * * ***** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and * * * * **
*** * * * * ** *** * * ** *** * * **** * *** ** ** = %.2f\nx2 = %.2f",x1,x2);
* * ** ** **** ****** *

******* *** ** ******* * ** if(D==0)
****** * **** * * * *
* ***** ** * * * * ** ** * * ** ** **** * *** **** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
*** * * * * * * * *** ** * *** ** * * * = x2 = %.2f",x1);
* * * ******** **
* ** *** ** * * **** *** *
** * * * *** * ******
* **** * ** * * ** *** *** ** *** ***** ***** * * ** ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** *** ** *
******* * * *** * *** * *** * * * * ** ** * * = * *** * * * ** **
*** * **** *** ** **** **** ****** ** * = * * * ***** * * * *
** * *** * **** * * * **
*** ** * *** **** ** * * *** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
*** * * ***** * * **
int main()
{
* ***** * * *** * *** *** ** *** ** * * * *
** * * * * * ** *** * * **** * *** * %f ** *** **** * * *** * * **
* ** * * ** ****** * = (b*b-4*a*c);
*** *** ** * * * * ** = (-b + sqrt(D))/(2*a);
********* * ** ****** = (-b - sqrt(D))/(2*a);
****** ** * * * ** ** = -b/(2*a);
** * *** **** ** ** * ** =sqrt(-D)/(2*a);
**** * * ** * * ** ** * *
* * ***** * ** **
* *** * ** * *** ** ** *** * *** * ** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and *** * ***** ******
** ** * * * * ****** * *** **** *** * * * **** = %.2f\nx2 = %.2f",x1,x2);
* * * * * ****** * **

* * **** ** ***** ** if(D==0)
* * * * * * ** ******** **
* *** ****** *** **** * * * ** *** * * * * ** **** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** **** * * * ** * *** ** * * * * **** ******* *** *** = x2 = %.2f",x1);
* * ** * ***
** * ** ***** ** * * *
* * ******** * * * ** **
**** ** ** ***** ***** ** * * ** * * * * * * * * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * **
* * *** * ** * * ** * * * * ** * ** *** = **** * ** ** * *****
** ** * ** * ******* * ** ***** ** * * *** *** * * ** * = ** ******* * * ***** *
** * ** * * * ** ** *
**** * * **** *** ** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.126
©2016-2026

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users