0 like 1 dislike
5.2k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 5.2k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
* * ***** * * *** *
int main()
{
** * *** * * *** * ** *** * * * *** *
** * *** ** *** * * * * ** ** * * %f * * * * *** ****** ******
** * * ** ** * ***** * * * = (b*b-4*a*c);
* * * *** ** **** ** = (-b + sqrt(D))/(2*a);
**** ** *** * ** * = (-b - sqrt(D))/(2*a);
* * * ** ** ** * * * ** = -b/(2*a);
** **** * *** ** ** * * **** * =sqrt(-D)/(2*a);
* ** ***** ** * ** * **** * *
** * ** *** * *
* * * ** ** ** * * *** * * ** * * *** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and ** *** * ** *
** *** ** **** ** * **** ** * * * **** ** * * ******* ** * = %.2f\nx2 = %.2f",x1,x2);
** ** * ** * ***** **** *

** **** * * *** *** * * if(D==0)
* **** * ** * ** * * *
* * *** * ** *** **** * ** **** * ** **** ** ****** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ** ** * ** * ** *** **** ***** ** * * * ** ** = x2 = %.2f",x1);
* * * ** *** * ** *** *
* ** * ** * * * * ***
** * *** ** ** ******
***** **** *** *** ** * *** * * ** ** ******* of %.2fx^2 + %.2fx + %.2f = 0 are complex and ***** * *** *
* * ** ***** ***** * *** *** * * * ** * ** **** = * ** * * * * ** **
* ****** * * *** * *** * * ** ** ** * **** ** * *** * * * ** = ** *** * * * ***** ***
** * * * * * **
*** * * * ***** ** ***** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * * * *

int main()
{
** ** ** * * * * ** n, i;

* *** * * * * *** * ***** * * ** **** * &n);

* *** * * * *** * * * * * = 1; i <= n; ++i)
* * * * * * ***
* * ** * ** * ** *** *** * ** * ** * ** ** % i == 0)
* ** ** * * * ** * * * * ** *** * *** * ** * * * * * **** * ** * ", i);
* ** * * **** * *****

* * * * * * * ** ** * ** ** ** 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** * * * ** ** **
* ** ***** * *

int main()
{
* *** *** ** * *** ****** * * * * * ***** **
** **** * ** * * ****** *** ** ** * **** * *** ** ** *
* * *** * ***** * * = **** ***
***** * ****** * ** *** * *
* *** ** ** *
*** * **** *** *** *** *** *
* ** ** * * *** *** = -b /(2*a);
* * ** * * * *** ** *** ***** ** **
* ** * * * * * * *** = (-b)/(2*a);
*** *** ** * ** * * * * * ** **** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * *** * ** *** *
** * * **** *** * ** ***
******* ***** * * * if(D==0)
** * ** * ** * *
* * * * ** **** * ** = (-b + ** * *
* *** *** * * **** = (-b - ** *
* ** ** ** *** *** * * ** *** ***** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = **** *****
* ** ** * * ***
* ***** ** ** ** * if(D>0)
* * **** * * *
* *** * ** * * ** *** * * * = -b/(2*a);
* ** * ** * * ** ** * = (-b + * * ****
** * ** * * ** * ***** * = (-b - * **
**** * **** * *** *** ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ** * *** *** *
*** * * * * **** * ** * *
* ** * ** * ***** ** *** 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** * * ** *
#include * *** ** ***
int main()
{
**** * ****** * * * a,b,c;
***** *** **** ***** **** * ** **** ** * ** ***** *** ** *
* * * *** ** * * *
* ***** * * * * ** ****
* * **** * ***** ** **
** * ** * ** * ** ** * ** * ** * * ** ** *** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * ** ** * * + ** * * * *** - * **** *****
* *** * ****** * ** **
** * ** ** * ** *****
* * ** ********* * *** if (b*b-4*a*c==0)
*** * **** *** * *** * * *
*** * ***** * **** *** *** * * *** ** * * ** * ** ***** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** * **** + * * ***
**** ***** * * * * * * **
****** * * * **
* **** * * ** * * *
* * *** * * ** **** * * ***
*** ***** ** ***** * * * * * *** ** ** ** * *** ****** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * * ** ****** ** ** ** ** ** * ** * * * ** * **
****** * * ** * * *** *
* ** **** ** * ** ** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ***** * *
#include * ****** **
int main()
{
*** ** **** * **** *** a,b,c;
* **** * * * * ** ** * *** ****** ** * * * * ** * * * * ** **
* ** * ** *** * * *
* * * *** *** * * ** ** * * * * *
* ** * * **** ***
**** ******* *** * ** * ** * * * * ** ** * *** ***** * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = *** ** ***** *** * + *** * ** ** * - * *** * ****
* * **** *** * **** **
** * **** ** * ****
* *** * * ** * * * * if (b*b-4*a*c==0)
* ** * * *** ** * * ****
** *** * * * ** ******* * *** ** * ****** * * * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * ** * *** + * **** **
** *** *** * **** ** * *****
* ***** * ** **
* * * ** *** * * *** **
***** ** * * ******* *
** * *** * ** **** *** ** ** * * *** ** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= ** *** * * * **** ****** * ** * **** ***** * *** *
* * ** *** ** ****
* * *** * ** ** * ** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
* *** * ** *** ***** ** * a,b,c,d,x1,x2;
* ***** *** ** ** *** ** * ** ***** * ******* **** ***
* * ** * ******** ** * *** *
*** * * * * **** * * * * *** ** *
* *** **** ****** * *** ***
****** ** ****** ******** * ** * * **
* **** *** * * * * * * *
** ** ** * ** * * * * ** ** * ** * * **** * * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and * * ** ** * * **
*** * * *** * **** * * ***** * ** ** ** ***** ** = %.2f\n",x1);
* ***** *** * * * ** * ** ** ** * * * * * ** *** *** = %.2f",x2);
**** *** ** * **
** * ** **** **** ** * if(d==0)
***** * * ** *** * *
** ** * *** ** **** ** ** *** * * **** ***** ***** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * * *** * * * *** * **** * **** ** ** * = x2 = %.2f",x1);
** * * ** * * ** ***
** *** ** ** ** ***
** * * * * **** * * * **
* ** * * * * ** **** ***** ** *** * ****** * ** *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * **** ** * * *
** ** ** *** * **** * ** * * ** *** * * * ** ** = * ***** *** ** * ***
* * * *** ** * * * * *** * ** *** * *** **** * *** * = * * * * * ** * **** *
* **** ** ** * * ** *
* * ***** ** *** * * * 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
* ** ** ** ** *** * * * **** ** ** ***** * ** ** * ****** * ** aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
* **** * ** * ** * ******* * * * **** - (4*a*c);
*** * ** * * *** ** * * ** *** *** *** * * *** * *
** * ** ** * *** * * **** * * * * * * * * * * * **** * ****
** * * *** * * ** * * ** * ****** * *** * * ** *** **** * *** *** (-b+spD)/(2*a);
** * * * * * ** ** ** * * **** * ****** **** ** *** ** * ** * (-b-spD)/(2*a);
** ** * *** * * ** * * * ** ** ***** * ** ** * ************* (x1==x2){
* * ** * ** * *** *** *** *** * * *** ** ** * * *********** ** ****** * * * **** *** * *** **** * ** ** * ** X=%d\n", x1);
** *** ***** ** * * * **** *** *** * * ******* * * ** * ** * **
*** * * * * ***** **** *** * **** ** **** **** ** * ** * {
* * ** * * * * * **** * *** **** ** * ** ******* * * ** ****** *** * ** * *** * *** * *** * * * *** * ** X=%d或%d\n", x1, x2);
*** ** * * * * ** ** **** ** * * * *** ** * * * * ******
        }
* ** ** * * * ** *** * * ** ********* * * * * if(D==0){
***** * * * * *** *** ***** ** ** * ** ** *** * ** * ** * (-b)/(2*a);
* * * * * ***** *** ** *** * * * ** * * * *** *** **** ** * *** *** *
*** * * ***** * * * * * * ** * *** ***** * * ** * ** ** *** ** ** * * ***** ** *** * ******* X=0");
**** * ** ** ** * * ** ** * ***** ** **** * * * ** * ******* ** * **** *
** ** * * ** * * ** * **** ***** * ** *** ***** * *** * *
**** * * ** *** * * ** * ** ** ** * **** * * ***** * * ** ** ** * * * * ** * * * **** X=%d\n", x1);
** * * * ** * * ** ** * * * * *** ** ** **** *** * * * **
        }
* * * * * ** ** ** *** *** **
*** *** * * ******* ** * * ** * ** *** *** ** * ** * ** * ** ** * * * ** ***** *** ** ** *** **
** ** * * ** ********** * * * ** *** **** **
    }
* ** * *** * * *** * ** * ** * *** ** * *** ** * *** * ** ***
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
*** ** ** * *** ** **** ** a,b,c,D;
* ** * * *** * ** ** x1,x2;
* * ** * ** ** * ** ** *** * %d * * * * * ***** ** ** **

* ***** * ** * * ** * ****
* * * * *** * * ** *** * *
*** *** ** ** ** * * *** * *

* ** * *** ** *** * * * * ** A,B,C;
** * ***** **** ** * *** ***

* ** * ** **** * **** * *** **
* ** * * * ** *** * * * * * * * *** ** ** of %.2fx^2 + %.2fx + %.2f = 0  are real and ** *** ***** **
** ************* ***** * * ** * * ** **** * ** = %.2f\n",x1);
* ** * ** * * ** * ** **** ** * *** * ****** * * * ***** = %.2f",x2);}

**** ***** * * *** * ** *** if(D==0)
* ** * **** ****** * * ** *** * * ** ** ** **** **** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
* ** * * * * *** ** * * * ** **** * * **** * * * * *** * = x2 = %.2f",x1);}

* * **** * *** * ** if(D<0)
* ** * * * * * *** *** * * ** * ** * ***** of %.2fx^2 + %.2fx + %.2f = 0  are complex and **** *** * * ** **
*** * ****** *** ** ** * * ** * * * * *** ***** * bb,d,dd;
***** ** **** * *** *** ** ** ** ** *** * *
* * ** * * ** ** ** ** * ** * ** * *** * * * ** *
* ** * * *** ***** * * ** * **** *** * * ** ** * ** * * **** = ** ** * ** *
* ** ** *** * * ** ** * **** * * ** **** ** * * * * * * = **** * * * * **

** *** * * *** *** * ** * *** 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
******** ** *
int main()
{
**** * * *** * * ** * * ** * * * ***
* * * ** * * * * ** ** %f * *** * * ** * ** * * *
* * * * * ** * ** * * * * = (b*b-4*a*c);
**** ***** * * ** * = (-b + sqrt(D))/(2*a);
* * * * *** **** = (-b - sqrt(D))/(2*a);
********** * * *** * * = -b/(2*a);
** *** ** ** * * * * * **** * ** =sqrt(-D)/(2*a);
**** * ***** *** *** * * ** * * *
* * * ***** * ** * *
****** * * * * *** ***** ** * ***** ** ** *** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** * * * * * *
** * * * ****** **** ** ** ** **** ** * * ***** = %.2f\nx2 = %.2f",x1,x2);
****** * * * * ** ** *

* ** * **** * * * if(D==0)
** * * *** * ** *** ** *
* ** * * * * *** ***** * * ** * * ** *** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** *** * ** * *** ** * ******* *** * * *** * = x2 = %.2f",x1);
**** ** ****** *** * *
*** *** * ** *
** ** * **** ** ** **
* * ** ** * * * * * * ** ** * * * *** * *** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and *** * *** ** **
***** * ** *** * ***** * * **** **** * *** ** * = * * * * ** ** * **** *
*** ***** ** * * *** * ******** * * ** ** ** ** ** * = * ** * * **
* *** * * ** * ** * **
** ****** ***** * **** * * *** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
******* * * * *
int main()
{
*** * * ** *** ** ****** *** ***** ***** *
** *** * *** **** *** * *** * %f * * * * *** ** ** *
* * * * * * * *** * ** ** = (b*b-4*a*c);
* ** * * * ***** ** * * = (-b + sqrt(D))/(2*a);
* * ** * * * ** ** * = (-b - sqrt(D))/(2*a);
**** * ** * ** *** * ** = -b/(2*a);
** * * * * ** * =sqrt(-D)/(2*a);
* *** **** ** *** ** *** ***
* ** * * **** * * ****
* * *** * * *** ** ** ** ** **** * ** ** ** ********* of %.2fx^2 + %.2fx + %.2f = 0 are real and * * ** *
* * * ** * *** * * **** ** * * ****** ** * ****** **** ** ** = %.2f\nx2 = %.2f",x1,x2);
****** * * * * * ** *

*** * **** ** * *** if(D==0)
**** * * * * ****** * *
** * ***** * * ** * * * * * ** ** ** * ** *** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * ** *** **** ** * *** * ** *** * * * * ***** * ** = x2 = %.2f",x1);
* * * *** * **** ******
**** *** * ***********
**** *** **** **** *
*** * ** * *** ****** * ** *** * ** ** *** * ** *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and ********* *** * **
* ** * * * * ** * * * *** * * * * * *** = * *** * *** *** * *
***** * * * **** *** * ** ** ** ** * * **** * * * ** = ** * * **** * * * *
** * ** *** ** ** *
** * ** ** * * ** *** *** * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.179.60
©2016-2024

No related questions found

12,783 questions
183,443 answers
172,219 comments
4,824 users