0 like 1 dislike
20.6k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 20.6k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
** * * * *** * ***
** ** ** * * * *

int main() {
*** *** ** ** ** * * * ** * * * *
** * ** * * **** ** ** * ** * %f ** * &a, &b, ********
** ****** * ** *** * * ** ** ***** **
* ** *** ** * **** * ** ** * ** {
* * * * * ** * * ** ** * * * ** ** *** ** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * * * ** = ** * ** = *** * ** ** a, b, c, (-b)/(2*a), * *** (-b)/(2*a), ** ** *
* *** * * * * **** *
*** ***** * * ** * *** if(d==0) {
* ** * * ******* ** * *** *** * * ** * ** * * * * ** * * **** *
* * ** ** ** * * * * ** * ***** * * * ** ** * * ** * * * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * a, b, c, x1);
*** * ** *** ** *** **
** ** ***** * ** ** * ** ** * ** {
* * ** *** * * *** * ** * *** * * ** * * * ** *******
** * * ** ** ** * *** *** **** ***** ** ** ** ******* **
** * * *** ******* *** * * ** ** * * ****** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and * ** = %.2f\nx2 = * * ** * a, b, c, x1, x2);
** ** * * ** * ** *
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** * * *
* ** * * * ** * *** **
#include ** *** * *

int main()
{
*** * **** * * **** * *** * *
* **** ** * ****** * ******* *** %f ** ** ** * ** * **
*** ****** * * * * * * ***
* * * ** * ** *** ***
*** * ** ** * ** **** *** * *
** ** ********* * * ** * * ** *
** ** * * **** * * * ** * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and *** ** * = %.2f\nx2 = * **** *** ****
** * * * * ** * * ** * *** * if(D==0)
** ***** ** * **** * *** **** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * ** *
** * *** * ** ** ***
** * *** * *** ** *** **** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** **** = ** ** **** = * * ** *** ****** * ****** **** *****
** ** * ** ** ** * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * *** *** *
* ** *** * * *
* *** ** *****

int main()
{
* * ** * * ** *** *** ** ** *
** * *** * ** * * ** ** %f **** * * ** *** * * * *** *
** * * ** * * * *
** * ****** *** * ** **** *
** * * *** * ** ******* ** *
** * * ** * *** ** ***** ***** ** ** *
* * *** * * * **** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * ** = %.2f\nx2 = **** *** **
* **** *** ***** * * * ***
*** *** **** * ***** ** ** ***** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = **** * **
*** ****** *** * * * **
** ** ***** * * *** ** * * **** *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and *** = %.2f + ** ** = %.2f - * **** * *** **** *** * * * ***
* *** ** **** ** *** ** * ** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
***** * ** ** ** * * *** * * a,b,c,x1,x2,D;
***** *** * * * ****** ** *** * * %f ** * **** * * ** * * * * ***
** ** ** ** * * ** * *
** ** * ** ** **** * = (-b + sqrt(D))/(2*a);
* *** * ** ** ******* = (-b - sqrt(D))/(2*a);
* *** ** * * ** * * * ** *
*** * ** * ** **** * * * ** * * *****
** **** * * ****** * **** * * * * *** ** * *** *** ** *** ****** ** **** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\n",a,b,c);
** * * * ** ** ***** * *** * *** ** ** * ** * **** * **** **** * * * * * = %.2f\n",x1);
* * *** *** * ** * * *** ** *** * * * * *** * ***** *** * * ** = %.2f",x2);
** * ** * * * * * * * * ** *** ** * ** **
* ** * ** ***** * * * if(D==0)
* * **** ***** ** ** *** *** * * * ** ** *
* *** * * **** **** *** * ** * ** * * ** ********** * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** * *** * ** * * * * **** * ************ ** **** ***** * ****** ** **** * * * = x2 = %.2f",x1);
* * * * * * * *** * * * * ** * * ******
****** * ** ** * ** **
* ** **** * * ****** *** **** ** * * ** ** * * ** *
*** * ** * ** ** * ** ****** ** * ** ***** *** ***** *** * * * * *** **** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\n",a,b,c);
* ** **** ** ** * * * ** * ******** * * * ** * * ** * *** = * ** ***** * * * * *
****** * **** * ** ** *** * * * * * ** * * * * * * ********** ** = ** ** ** * * ** * **
** * ** * * ** * ** * * ** * ** ***** ****
* * ** ** ** ** * ** ** 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
*** * *** * *** * a,b,c,x1,x2,D;
** *** ***** ** * * ** ** %f *** **** **** ** ** *** ** ** ***
* * * ****** * *** * ** ***
*** ** **** * * ** ** = (-b + sqrt(D))/(2*a);
*** ** * ***** * = (-b - sqrt(D))/(2*a);
***** ** ** * * * * * * * **
*** ** * ***** * * **** * * * ***** *
**** ** *** * * * **** * * * ***** * ** * * * ** * ** * * * **** * * ** ** of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
**** *** *** * * *** **** * **** * ** * * *** * *** * ** * *** ***** * ** * = %.2f\n",x1);
* * ****** * * * ** * ** * ***** ** * ** *** *** ** * ** ** * ** * * ** * = %.2f",x2);
* ** * **** **** * * *** * ** ** * * * * *
** * * * * * ** * if(D==0)
* * **** * * ** ** ** * ** * * ** ***
** ** ** ** * * **** * * * * *** * ** * ** * * * *** *** **** ** * * ** of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
** * ***** * * * ** ** * **** * *** * ** ** *** ****** * * * * **** * ** ** *** = x2 = %.2f",x1);
**** * **** * * * ***** ** * * ***
**** * *** ** * ** * *
* * * **** ** ** * ** ** *** ** ** **
*** * * * ** *** * * ** * * ** ** * * ** * * *** * * * * ** * ******** * of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
* * * * * *** * ***** * * * ** * ** ** ** ** ** ** ** * ** ** * = * ** ** **** * ****
* **** ***** * *** ** ** * * **** ** * * * * * *** *** ** *** * = * ** ** ********** ***
** ** *** ****** * * ** ******* * *** * *
***** *** * * ** * ******** 0;
}
answered by (-258 points)
0 0
prog.c: In function 'main':
prog.c:13:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:19:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:24:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
0 like 0 dislike
Hidden content!
*** * ** ** *
* ** *** ** * * ** **
int main()
{
* *** ** ** ***** ** ** a,b,c,D = 0,x1 = 0,x2 = 0;
* ** ** ** * *** * * * ** ***** ** *** * * **** * * **

* * ** ** ** * ** ** ** ** **** of %.2fx^2 + %.2fx +%.2f = 0 ** * ** *
* *** *** *** ** ** *** = (b*b-4*a*c);
* * **** * * (D < 0)
* * ** * * * **
*** ***** ** ** * **** * * * complex and * * * * *
*** ** ** * ***** ** * ***** * = ** * ** * * *** * *
* ** ** ** * * * ** ** * * ** = ** ** * * ** *** *** *
* *** *** **** * * ****
* ** * * ** *** *** * ** (D > 0)
*** * * * * * *** ****
*** *** ** ** * * **** * ** real and * *** *
* **** * ** ** ***** ** * *** ** = ** * ** * + sqrt(D))/(2*a));
* ******* * * **** * ***** * **** * = %.2f",(-b - sqrt(D))/(2*a));
* * ** ** * ** ***
* * * * ***** **** (D == 0)
*** * * * ** **
* **** * * ****** *** * real and same\n");
** *** * *** * ** *** **** ******* = x2 = %.2f",(-b + sqrt(D))/(2*a));
* * *** * ** * **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
your output lack of 1 space at line 8 when print out "Roots of ..."
0 like 0 dislike
Hidden content!
** * * ****** *
** * * ** ** * * *
int main()
{
* ** * ** * * ** ** * * a,b,c,D = 0,x1 = 0,x2 = 0;
* * ** * * * ** * ** *** **** **** ******** ** * * ********* ****

* * *** * ** ** * ** * * of %.2fx^2 + %.2fx +%.2f = 0 ** * * ** **
******* *** **** **** * = (b*b-4*a*c);
* *** * * * * **** ** (D < 0)
***** * * * **** ** *
** ** *** *** ** ***** complex and * *** **** *
* * * * ** * * * ** **** = ** * *** ***** * * * ***
** ** **** * * * ** ** ** *** * **** * * *** = *** * *** * * * * * *
*** ** * ** ** *** **
*** *** * * ** (D > 0)
*** ** * ** ** **
** * * * * *** ** * * real and ** **** ** **
* * ***** ***** * * **** ** ** = ** * *** + sqrt(D))/(2*a));
** ** * * *** * **** * * ******* = %.2f",(-b - sqrt(D))/(2*a));
* **** * *** ******
*** ** * * ** ****** ** (D == 0)
** * * **** * * ****
*** ***** ** * ** * * * * * * real and same\n");
* * ** * * * * * ** *** *** = x2 = %.2f",(-b + sqrt(D))/(2*a));
* ** * * *** * *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * ***** *
* ** ** **** ***
int main()
{
* * ** ** * * ***** * a,b,c,D = 0,x1 = 0,x2 = 0;
*** * ** * * *** * * ** * *** ** *** ** ***

* * *** * *** * * ** * *** of %.2fx^2 + %.2fx +%.2f = 0 * ***** **
* * ** ** *** * *** ** = (b*b-4*a*c);
*** ******* * ** * (D < 0)
*** * * ******* ****
*** *** * * **** * * * * * complex and ** * *
** * ** * * ** *** *** * ** ** * * = **** ** * ** * * * * *** **
** **** ** * *** ******* * = **** * * *** *** ***
* *** * ** **** ** *
** **** ** *** ** (D > 0)
** * ** * ** ****** **
** ** * * * ** * ** * **** ** * ** real and * **** ***
******* ** *** * * * **** = * * *** * * + sqrt(D))/(2*a));
** * * * ** **** * * * * = %.2f",(-b - sqrt(D))/(2*a));
** * *** * * * * **
* ***** * *** ** * ** ** (D == 0)
* * * * * * ** * *
** ** ** * * * * ** * **** real and same\r\n");
** * ** ** * *** ** ** *** **** * = x2 = %.2f",(-b + sqrt(D))/(2*a));
* * * *** ** ** * **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* **** *** *** **
** * ** *
int main()
{
* * * * ** * ***** ****** a,b,c,D = 0,x1 = 0,x2 = 0;
* ** **** * **** * *** *** * ** * *** ** ***** * **** *

* *** * * * * * ******* ***** of %.2fx^2 + %.2fx +%.2f = 0 * ** * *
* ** ** * * * **** ** = (b*b-4*a*c);
* ** ** **** * ******* (D < 0)
* ** * **** * * ***** *
** * ***** ** * * * ** ** *** complex and *** * *** * * *
*** * * * ** * ** = * * **** * *** * **** * * ****
* **** * ** ** * * * * = *** * * ** *** **
*** *** * * * * * **
** * * * ******* ** (D > 0)
**** ** * ***
**** * * * ** ** * *** * *** * real and *** ******* * *
* * **** ** ** * ** * * ** * ** = *** * * ** + sqrt(D))/(2*a));
* * * *** *** ***** * * * = %.2f",(-b - sqrt(D))/(2*a));
* *** * ** ** * ** *** **
** ** * * ** **** **** (D == 0)
****** *** * * * * * **
* ** * * ** ** * ***** * ** * real and same\r\n");
* ** * * **** * ********* * ** * * = x2 = %.2f",(-b + sqrt(D))/(2*a));
* **** *** ** * * *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* **** * * *
**** ** *** * *** *
int main()
{
* * **** * **** ********* a,b,c,D = 0,x1 = 0,x2 = 0;
* **** * *** **** ** * ***** *** ** **** * * ** *

******* ** * * * ** * ** * ** *** of %.2fx^2 + %.2fx +%.2f = 0 are",a,b,c);
* * ****** ** ***** * * *** = (b*b-4*a*c);
* ****** ** *** * **** ** = (-b + sqrt(D))/(2*a);
*** ******* * * * ** * * = (-b - sqrt(D))/(2*a);
* * ** ** ***** * ** * (D < 0)
*** ** *** *** *
*** ** ** * ***** ** * * * complex and *** ** ** *
* * **** * * * ** * ** ** * * * = *** * * * * * * ******* ** *
**** * ** **** * ** * ** ** * = * * *** * *** * ** *
* * ** * ** **
** *** **** *** ** *** (D > 0)
*** * * * ** ** *** **
** ** *** ** ** * **** * * * real and ***** * *** **
***** *** **** * * ** ** **** * * ** = * ** * * *
* ***** *** * ** ** **** * * **** ** ** = %.2f",x2);
** * ** ** * * * * * ** **
* *** * ** * * * * ** (D == 0)
** * * * * * ****** *** *
* * * *** ****** * * ** * * * ** real and same\r\n");
***** *** * ** *** *** * = x2 = %.2f",x1);
* * ** ** ** * * * * *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.94
©2016-2026

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users