0 like 1 dislike
13.7k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 13.7k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
***** * *** * * * *
** *** ** *

int main() {
* *** ** ** ** ** ***** * ** *
* ** ** ** ** * * * ** * *** %f ***** *** &a, &b, * * **
*** ****** * ** * ** ** *
**** * ** ** *** ** **** * * {
* * ** *** * ** **** ** * * * **** **** ** * **** ** * * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * = ** **** = * *** a, b, c, (-b)/(2*a), ** *** * (-b)/(2*a), ** *
*** * * *** * * *
** ** * *** * * * * if(d==0) {
* * * * ** ** ** **** **** ** ** * **** *** * **
* * * * ** * *** *** ******* * ******** * * ***** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * ** a, b, c, x1);
* * *** ** *** * *** ** * **
** * * ** ***** * * * * * {
*** *** * * * * * ** * * ** * ** ** * *
* * ** * ** *** **** ** * * *** ***** * ** ** **
** * **** * * *** *** * ** * ***** ** ********** ** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** * * ** = %.2f\nx2 = * ** ** * a, b, c, x1, x2);
** ** ** *** * * ** ****
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** * * *
** ** ******
#include * * * * *

int main()
{
*** ** * **** *** ***** * * * ** *** **
*** * ** ** *** ***** ** ** %f ** *** * * * * ** ** **
* * * ** * *** * * ** ** *
** * * ** * *** * * * * *
* ***** **** * ** **** *** ** *
** ***** * * * *
* **** * ** * * ** *** * *** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and *** *** * = %.2f\nx2 = ** * * *
* ** ** * ****** ** ****** ** if(D==0)
** * * * * **** ** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = *** * * *
** *** ** **** **** *
* * * ***** * * * ** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ***** **** = ** * ** = ** * ** ** * * * **** * * ** **
**** * * * *** * * ** ** * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** * * *
** * ** * * ** *
* * * * * * *

int main()
{
** **** ** ** * * * ** *** * * * * *
* * * * *** * *** * ** ** %f * **** * *** * * * *** *
* ******* * * * ***** * * **
* ** ** ** ** * * ** * ****** *
** * ** * * * * ** **** * ** ***
* * * ** *** ** * ***** * *
*** ***** * * * * * **** *** *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and * * *** = %.2f\nx2 = * *** * * * **
* * * * * **** * * * * **
* * **** * ** ** ** * *** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * ** ****
* * * * * ** *** * ** **
***** ** ** ** *** ** *** *** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * = %.2f + * = %.2f - * * * * *** * ** ** **** *** *
* * * ** ** * *** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
* ** * * ** ***** ** * *** a,b,c,x1,x2,D;
** ** * ** * * * ***** *** *** %f * ** * ** **** * ***
** * * * ** * * ** ** **
** * ***** * ** * * = (-b + sqrt(D))/(2*a);
* ** * * * *** *** * = (-b - sqrt(D))/(2*a);
** ****** ** ** * * * * * * **
** * * ** ** * *** * * ** * * * ** * *** ****
* *** * ** *** *** ** ***** *** *** * * **** * * ****** * * * * * ******* * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\n",a,b,c);
* * * * **** * * *** * * ** * * ** ** * ** *** * * * ** *** ** = %.2f\n",x1);
* ** * *** * * * ** * * ** * * *** * ** ** * **** * * ** * ** * * * = %.2f",x2);
* ** * **** * * ***** * **** ***** ** ** ** * ** *
**** * **** * * ** * *** * if(D==0)
* ** ** * * *** ** * * ** * * * ** *** ** * *
* * * ** *** * * *** *** * * *** *** * * * * * * * *** * * *** **** **** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
***** ** * *** * *** **** * **** *** ** *** * ** *** * *** **** * *** ** ** *** = x2 = %.2f",x1);
* * * * ** ***** ** * ** *** * *** ** ********
* * * * *** ***** ** * * *
***** *** ***** ***** * ***** ** **** * * * * **** *** *
** ** * * ** ** * ** ******** *** * *** ** ** ** * **** * * * *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\n",a,b,c);
** **** * * ** * ** * ** ** * * ** * ** ** ***** * ********* * ** ***** = ** ** * * * * *
* *** ***** * **** * * ** * ** * ** * ** **** * * ** *** * * * * * = **** *** * * * *
** * * * * *** ******* ******** * * **** * * ***
*** ** ** **** ** * * * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
* * ** **** * * * * a,b,c,x1,x2,D;
** * * * *** * ** ** *** * %f ** * * * *** ** * *
* * * **** ** * * *
* ** ***** * ** * * = (-b + sqrt(D))/(2*a);
**** ** * * * * * = (-b - sqrt(D))/(2*a);
* *** ** ** ** * ** * *
* * * ** * ** * ** * ***** ** **** * ***
* *** * ** * ** * ** * ***** * * ** * * * ** ** ** ** * *** of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
*** ** * * * *** ** * * * * * ** * * * ** ***** ******** * * * *** * = %.2f\n",x1);
*** * * ** * * **** * *** **** * * * * * * ** * * * * * ** * = %.2f",x2);
** * * * *** * * * * ** * * * * *** *
*** * * ** *** **** ** *** * if(D==0)
* *** * * *** ** *** *** ** * * *** ** *
** ****** **** * * * **** ****** * * * ** * * **** * **** ** * ** of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
*** ** ** *** * * * **** ******* **** **** * * * * * * * ** ** * **** = x2 = %.2f",x1);
* *** ** **** * ****** * ** ** * * * ** ****
* ** * * * *** * * *****
***** *** * * * ** * ** * ** ** ** * *** * * * * **
* * * *** * * ** * * ****** ** ****** ** ***** * ** ****** ** * ** * * * * * of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
* ** ** * *** ** * * *** * ** * * * *** ***** ** * ** * *** ****** * * ** ** = * ** ** * ** * **** *
* * ** * ** * ** ** ***** * * * * * *** * *** * * * ** * *** * = * ******** ** ****** ** *
** ** *** *** ** **** * * * * ** * ***
** * ** * * ***** ** * 0;
}
answered by (-258 points)
0 0
prog.c: In function 'main':
prog.c:13:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:19:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:24:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
0 like 0 dislike
Hidden content!
* ** ** ** *
* ** ** * *
int main()
{
* ****** * * * * ** a,b,c,D = 0,x1 = 0,x2 = 0;
** **** * * * * ** ****** ** * * * *** * * ** ***

* * ***** * * * ** * * * ** * * ** * of %.2fx^2 + %.2fx +%.2f = 0 ** * ** **
** ***** * * **** * = (b*b-4*a*c);
*** ** * ** * * ****** (D < 0)
* * *** * **** * ** * * **
* ** ** ** ** * * ** * *** complex and ** * ******** *
* ** ** * * **** * **** ** * * = * * ** *** * * ** ***
**** * ** ****** * * * *** **** * = ** * ***** * ** ** * *
** * ***** * * **
*** * * **** **** * * (D > 0)
* * * * * *** * * * ***
****** * ** ** *** * real and * ** ** ***
* ** ***** **** ** *** ** ********* = *** * ** ** + sqrt(D))/(2*a));
* * *** **** * * **** *** * * ** = %.2f",(-b - sqrt(D))/(2*a));
*** ****** *** ** **
* ** *** ***** ******* (D == 0)
** ** *** * ** * ** ** *
******* * *** * ** * ** * *** real and same\n");
* **** * ** ** * *** ****** ** *** = x2 = %.2f",(-b + sqrt(D))/(2*a));
* * * ** *** * * *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
your output lack of 1 space at line 8 when print out "Roots of ..."
0 like 0 dislike
Hidden content!
** * * ** * * * ****
* * ****** * *
int main()
{
* * ***** * * * ****** a,b,c,D = 0,x1 = 0,x2 = 0;
* * ** *** * * ** * ** * * ** ** **** ** * *** **

* *** * *** * * * * * ******** of %.2fx^2 + %.2fx +%.2f = 0 * * * ** **
** *** * * * **** * * = (b*b-4*a*c);
* **** ** * * * * * (D < 0)
** * * ** * * * * *** *
* * * * * * * * * * *** ** * complex and * * * * ** * *
* *** * * * * **** * * *** * = * * ** * *** * ** *****
* ** ** **** *** * * ** * * ** = *** ***** * ** * * * * * *
** * * ** **
* * * **** ** * ** * (D > 0)
** * * * *****
* ***** ** ** * * ****** * ** * **** real and ** * * * **
* * * * * * * * * *** ** = **** ** ** ** * + sqrt(D))/(2*a));
** * ** *** * * * * = %.2f",(-b - sqrt(D))/(2*a));
** ** * * * ** ** **
* ***** *** * * *** **** (D == 0)
* ** **** ****** * * * **
* ***** ****** * ** ** *** * ** real and same\n");
** ** * * * * * * ** *** = x2 = %.2f",(-b + sqrt(D))/(2*a));
* * * ** * *** * * ***
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
*** ** * **** **
** * **** * ** **
int main()
{
* ** * *** * a,b,c,D = 0,x1 = 0,x2 = 0;
*** * * * * ** ** *** *** **** ** *** ** *** * **

* * * * * * ** * * ***** * of %.2fx^2 + %.2fx +%.2f = 0 * **** * **
** ***** * * * * **** * = (b*b-4*a*c);
*** * * * **** *** ** * (D < 0)
** *** * * * *** **
* * ** * * * * ** complex and **** ** ***
* * * * * * * * *** * = * * * ** *** *** ******
* ** ** ** * * * ** ****** * = ** * ** *** * * * **
* ** * *** * *****
*** ** * ** * * * ** (D > 0)
* * * * * * * * ****
* **** *** * * ** ** * ** ** real and * * *** * * **
* *** ** * * ** * ** *** = * ** ** *** + sqrt(D))/(2*a));
*** *** * *** ** ** ****** * * *** *** = %.2f",(-b - sqrt(D))/(2*a));
***** ** ***** ***
* *** * *** ** ** * (D == 0)
***** * * * * ** * **
** *** * ** * * * * * ** real and same\r\n");
** * ** * ** * *** ** *** = x2 = %.2f",(-b + sqrt(D))/(2*a));
**** * ** ****** **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * * *** *
** **** **** * * * *
int main()
{
* * * ** ** ** a,b,c,D = 0,x1 = 0,x2 = 0;
* * * *** **** ** * ** * ***** * * ** * * * * * * *** * ** * ***

**** * * * * ** * * * * * ** of %.2fx^2 + %.2fx +%.2f = 0 *** * *
** *** ** * ** ** * = (b*b-4*a*c);
** * * *** ** ** * (D < 0)
*** * **** *** ** *
** * ** *** **** * **** ** * complex and *** ** ****
*** * ** * * * *** * * *** * = * ** ** *** ** * **
** ****** * * * *** * ** * **** ** * * = * ** * * *** *** * *
** *** *** * * ** **** **
** *** * * * ** * *** (D > 0)
* * *** ** * *
*** * * * *** ** * * ** * *** real and * * ***** ** * * *
*** **** * ****** *** * * * = ** *** * * * + sqrt(D))/(2*a));
*** ** * ** *** **** * * * ** = %.2f",(-b - sqrt(D))/(2*a));
* *** * *** * * * *
* * ** * *** * * * ** * * (D == 0)
* ** *** **** ** ** * *
* * **** * * * * ** ** *** * ** real and same\r\n");
* *** ******* * ** * * * * * *** * = x2 = %.2f",(-b + sqrt(D))/(2*a));
** * **** * * * ** * * *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** ** ** ** * **
* * * * ** * ** ** *
int main()
{
*** **** * * * *** a,b,c,D = 0,x1 = 0,x2 = 0;
* * * * * *** ** ******* ** * * * ** * * * ** * *

** *** ** * ** ** * *** * * ** of %.2fx^2 + %.2fx +%.2f = 0 are",a,b,c);
** ** *** ** * * * * = (b*b-4*a*c);
*** * * * ***** * **** * * = (-b + sqrt(D))/(2*a);
**** **** * * * ** * = (-b - sqrt(D))/(2*a);
** ** * * *** * * * *** * * (D < 0)
* * * * ** * *** * *
* * * * * * * * * complex and * * * * * *
* ** * * ** *** * *** ** *** ** * = * * * * ** *** ** * *
* * * ** ** * *** * * ** ** * = *** ** * *** **
*** *** ** ** **
* * **** * *** * ** * (D > 0)
** *** * *** ****** *
* ***** * * * * * ** *** * real and * **** ** * **
* * ******* * ***** **** * * = * ** * **
** ** ** * * * * * * * * *** * * = %.2f",x2);
** *** ** * ** * * * * * *
* ** ** **** ** * * * * (D == 0)
* * *** * ** * * *
* **** ** *** * * ** * ** real and same\r\n");
* **** * *** * ** * * *** * * ** ** * * = x2 = %.2f",x1);
* *** * ** *** ** ** *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.165
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users