0 like 1 dislike
7.6k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 7.6k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
* * * ** * **
* **** ** ** *** *

int main() {
* **** *** * ** * * * * **
**** * *** *** * *** ** **** %f * * &a, &b, * ***
* ** * * * ** ** *********
***** * * *** ** * * *** * ** {
** * ****** ** * * * * ** * * * ** * * * ***** ** *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** ** * = * ** * = ** *** ** a, b, c, (-b)/(2*a), * * *** (-b)/(2*a), * * **
* **** **** ** * * ** * * *
* * * *** * * if(d==0) {
* ** ** * ** *** * ** * * *** * ** ** ** ***** ** **
** *** * * **** * ** * *** * ** *** * * ** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * * * a, b, c, x1);
* **** ****** * ****
* * * * * * * * * ** *** *** {
* ** * ** **** ** ** *** *** * * ****** * ** * * * ***
* * * ** * * * * * * ** *** * * *** ** * * * ** *******
* ** * * ** * *** ** *** * * **** * ******* ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** ** = %.2f\nx2 = * * * *** a, b, c, x1, x2);
** * *** * ****
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * **** *** *
* *** ** ** *
#include * ***

int main()
{
***** ** ***** ** * ** *** ** * * **
** * * *** *** * * ***** * * ** %f * * * ******** * *** * **
*** * ** * * * ** * *
***** * * *** *** * ** * * **
** ** **** ** * **** *** **
** ***** *** ** ** * * *
* * ** * ****** *** * *** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * * = %.2f\nx2 = ** * * ** ***
* * * * * * * *** ******* if(D==0)
* * * * ** * * * * *** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * ** ** **** *
** * * ****** ** *** *
* **** *** * * * ** ** * **** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * ** * = * **** = * *** * * * ** * ***** ** *** *
* **** *** * * * * **** * * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * **** * * *
* * ** ** ** * * *
* ** * * *

int main()
{
* ** ******* *** * ** * ******
* ** ** ** * ***** ** ********* ** **** %f ** *** ** **** ** *
* * * * * * ** ** * **
* *** * * ** * * * ** **
** ** ** * * *** ** *** * ****
******* * **** * * ** * * **
* *** **** **** * * *** **** of %.2fx^2 + %.2fx + %.2f = 0 are real and ***** * ** = %.2f\nx2 = * * * * * **
*** * ** ** * * ** *
* * * * * ***** * * *** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ***** * * *** *** *
** ** ****** ** * **
** * * *** * * * **** *** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and *** = %.2f + * = %.2f - ** *** ** ********** * * * *** ** * ****
** *** * *** ****** * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
******* ***** * * * * * a,b,c,x1,x2,D;
* ** ** ** * * ** ******** ** * %f * * * * * ** *
** ** ** ** **** * **
* * ** *** * * ** *** = (-b + sqrt(D))/(2*a);
*** * * ** ********* = (-b - sqrt(D))/(2*a);
** * * * * ** * * * * ** **
* * *** ** * ********* * ** * ** * * * * * * *
******** * **** * *** ** * * * * * * *** * ** * * **** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\n",a,b,c);
*** *** * * * * * *** ** * ** * ** ****** ** ** *** * *** ** *** ** * * ** * = %.2f\n",x1);
* * *** * * * * * * * * **** ** **** ** ** * ** ** ** * * *** = %.2f",x2);
* ** **** ******** **** ** * * ** * * * * ** * ** *
* * * ** ** ** * *** if(D==0)
* ** * * * * *** ** * * * *** * ** * **
*** * **** ** * ** * * * ** ** ** ** ** * * ** * * * ** **** * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
*** ** ** * * ** * * ** ** ** **** * ** *** * * * * ** *** **** ** * ** * = x2 = %.2f",x1);
* *** * ** * * *** ****** *** * **** **** * * * * *
* * ** ****** * * * ** ***
* ** *** * * ** * * * * * ****** * * * ** **
** * ******* * * * *** * * **** * * * ** *** * ******** * **** * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\n",a,b,c);
* ** * *** * *** ** * **** ** ** ** *** *** *** * *** **** * * * * *** * * * = * ** * ***** * **
** * * * *** * * * ** **** **** ***** *** * * * ** ** * ** ** * * **** = ** * * * *** * * ** * ** *
* ***** ** ** **** * *** **** ** ** * * **
**** ** * ** * * * * * * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
* * * ** **** ** * * * * a,b,c,x1,x2,D;
* *** ** *** * * *** ** * * * %f *** ***** ** ** ** *** ***** *
* **** *** *** *** *** * * *
***** **** *** ** * * *** ** = (-b + sqrt(D))/(2*a);
*** ***** * ********** = (-b - sqrt(D))/(2*a);
* * *** ***** *** **** *** **
** * * **** * * ** **** ** ** **** *
* ** * * * * ** * * * * * * ***** * ** ** * ** * * *** ** *** * **** * of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
*** ******* **** * ** * ** ***** * ** ** * * * **** **** * ** **** ** * = %.2f\n",x1);
** * *** ** * ** ** ** **** ***** * ** *** * * ** * *** * *** = %.2f",x2);
* ** * * ** ** *** ** ** ** * ***** * *
** * ** * ** ** * * if(D==0)
******** * * * * *** * **** ***
* * * *** ***** ** ** * * * * * ** ** * ** * *** ***** ** * ***** of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
** * ** *** *** ** * ** ***** * *** *** ** *** * * ******* ** = x2 = %.2f",x1);
**** * *** *** ** * * * * * * ** * *** *
* ** * * * * * * *** *
* * ** *** * *** ** * *** * * * *
* * * ******** *** * * * * ** * * * * *** * * ** ** *** * ** * **** of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
* * * * * * * ** ** ** * * ** * * **** ** ****** * * *** ** = ** * * ******** ** *
***** * *** * * ***** *** ***** * ** ******* *** **** ** * ** ** * * ** = * *** ** *** *
* * * * * **** * * * ** * * ** *** ** *
*** * ** **** ***** * ** *** 0;
}
answered by (-258 points)
0 0
prog.c: In function 'main':
prog.c:13:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:19:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:24:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
0 like 0 dislike
Hidden content!
* * ** * * * *
* ** *** ** * * **
int main()
{
* *** ** * * * * * ** a,b,c,D = 0,x1 = 0,x2 = 0;
*** *** * **** ** ** ** * * * ** ** * * * ** ** *** * * * * *

***** * ** ** * ** **** * * ** * * * of %.2fx^2 + %.2fx +%.2f = 0 ** * * *
* ** ** ** *** * ** = (b*b-4*a*c);
** * **** * * * * (D < 0)
** ***** * *** * *
* **** *** ******* **** complex and ** ** *
* * **** ** * * * * ** ** ** = ** * ** * * * * * * **** *
***** ** * ** * ** * *** ****** = * * *** * ** * * * ****
* * * ** ** *** *** ** **
* * * **** * *** * * * (D > 0)
** * **** * ** * *
** ***** ***** ** ******* *** ** real and * **** * **
*** *** ** * * * *********** *** * = ** * *** * + sqrt(D))/(2*a));
**** * * * **** * ** * * * ***** = %.2f",(-b - sqrt(D))/(2*a));
**** * ** * * * * *
*** * ** * * ** * * (D == 0)
* * * * * * ****** *
* * ** * * ** **** * ** real and same\n");
* * *** * * ** * *** ** ** = x2 = %.2f",(-b + sqrt(D))/(2*a));
* * * * * ** *** * * *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
your output lack of 1 space at line 8 when print out "Roots of ..."
0 like 0 dislike
Hidden content!
* * * * * * *
*** **** *** * ***
int main()
{
* ** * ** * * ** ** a,b,c,D = 0,x1 = 0,x2 = 0;
* * * * * ** * * * * * * ** **** * ** * * ** *** * ** *****

* * ** * ***** * ***** *** *** ** of %.2fx^2 + %.2fx +%.2f = 0 * * * *** **
** * ** ** * *** ** * = (b*b-4*a*c);
*** **** *** * ***** ** (D < 0)
* ** * ** *** *** *
** * * * *** * ** * * ** complex and ** ***** *
* * ** * ** **** ** ** ** * **** ** * = * * * ******** **** * * * * *
**** ** * ****** ** * * = ** **** * * ****
** ** ** * * * ****
* ***** * * *** * * (D > 0)
** ***** ** ******** **
** **** * ** *** * * *** real and ** **** **
* *** *** * * *** ** * * * * * * *** = ** ***** + sqrt(D))/(2*a));
*** * * *** * ****** *** *** * = %.2f",(-b - sqrt(D))/(2*a));
* *** * ****** * *** ***
* ** * ** ** * * *** * (D == 0)
* *** ** **** *** *
** ** ** * ** * ** real and same\n");
* ** * * * ** *** ** * * * = x2 = %.2f",(-b + sqrt(D))/(2*a));
*** * *** * **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
*** * *
* * ** * * *
int main()
{
****** * * ** ** * a,b,c,D = 0,x1 = 0,x2 = 0;
* * * **** * *** * ** ** ** ****** * * ***** ****** *****

* * ** * * * * * ** ** * * **** of %.2fx^2 + %.2fx +%.2f = 0 ******* * **
**** * * * * * ***** = (b*b-4*a*c);
* * ** ** * **** ** (D < 0)
* **** ** * * * ** * ***
* * ** * * * ** *** **** * *** complex and ** * *** * ** **
*** * * * * * * *** * ** * * = *** * * * * *** ** * ** *
** **** * ** * * * * *** * **** = * * * ** ** ***** * * * * *
*** * ** *** ** * * *
** * **** * * ** (D > 0)
** * ***** ***** * ** * *** *
* * * *** *** * * *** real and **** * ** * * *****
* ** ** * * **** * ***** * * = **** *** ** + sqrt(D))/(2*a));
**** ** * * ** * ** **** * = %.2f",(-b - sqrt(D))/(2*a));
* **** ** ****** * * **** **
** ** *** * ** * ** (D == 0)
* **** * ** * * * **
*** * *** * *** * * *** * *** real and same\r\n");
* * * * * ****** ********** *** = x2 = %.2f",(-b + sqrt(D))/(2*a));
* * ** **** * * ****
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** * ** *
* * ** ****
int main()
{
* * ** * ** **** * ** *** * a,b,c,D = 0,x1 = 0,x2 = 0;
* ******* * ** * ** * * * **** **** * ** ** * ** ** ***

* * ** * *** * * **** * of %.2fx^2 + %.2fx +%.2f = 0 *** * *** ** *
*** ******* * * * * = (b*b-4*a*c);
*** * **** * ** * **** (D < 0)
****** * ** *
* **** * ** ** *** ***** * *** complex and * * * ** ** *
***** * * * * ** * *** * *** = ** * ***** *** ** **
** * * ***** ** ** ** **** * = *** * * * * * ******* * **
** * ** * * * *
* *** ** * ** * * * (D > 0)
*** *** *********** *** ***
**** * * * ** *** * real and ** *** ** *
* ***** * * **** ** * * = **** ****** * + sqrt(D))/(2*a));
***** * * ** * * ** * ** * = %.2f",(-b - sqrt(D))/(2*a));
** **** * * * *** * **
*** *** * ** *** *** * (D == 0)
*** * * ** *
** * ***** ***** * ** * * real and same\r\n");
* * *** ** * * * * * * = x2 = %.2f",(-b + sqrt(D))/(2*a));
** ** * ** *** ** *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * * **
** ** * * *
int main()
{
* ** * * * ****** ** *** *** a,b,c,D = 0,x1 = 0,x2 = 0;
**** * ** * * ********* ** **** ** **** * ** * ****** ** ***

*** *** * ** * * * * * **** *** ** of %.2fx^2 + %.2fx +%.2f = 0 are",a,b,c);
* ***** ** * = (b*b-4*a*c);
* *** * * * * *** * ** = (-b + sqrt(D))/(2*a);
* * * ** * * * * = (-b - sqrt(D))/(2*a);
** **** ** * * **** * (D < 0)
* * ** ***** ** *
* * ** * * *** ** ** * * * ** * complex and * * * *** *
*** * * * ** ***** *** * * ** = ** * * **** * * * * * *
** ***** ** * * * * *** * ** ** * = ***** ** ** ** * * **** **
** *** * * ** **
** *** ** *** ** * ** (D > 0)
** * * ***** * * **
** *** ** ** ** ** ****** * ** real and * ** * ****
* *** ** *** * ** ******* * * = * ** *
* *** ** ** *** ** * = %.2f",x2);
* **** **** * * **** * **
* *** ** * * * ** **** (D == 0)
**** ** *** * * * * * * *
* * * ** ** ***** * * * * ** real and same\r\n");
************* * * ** *** ** ** * = x2 = %.2f",x1);
* *** * ***** * * * * *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.162
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users