0 喜歡 1 不喜歡
17.1k 瀏覽

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[練習] Coding (C) - 最新提問 分類:Chapter 5: Selection Statements | 用戶: (5.2k 分)
ID: 28934 - 從幾時開始: 2017-10-26 18:00 - 到幾時結束: 無限制

重新開放 用戶: | 17.1k 瀏覽
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 個回答

0 喜歡 0 不喜歡
內容已隱藏
#include <stdio.h>
* * * * **** * ***
int main()
{
** * ** ** * ** ** ** ***** ** ** ** * * *
*** * ** * * **** ** ** ** * %f * * ** * * * ** ** * *
* * * * * ** ** = (b*b-4*a*c);
**** ** * * ** ***** * = (-b + sqrt(D))/(2*a);
* * * * ** * *** * * = (-b - sqrt(D))/(2*a);
*** * * ** * * * **** **** ** = -b/(2*a);
** *** * ****** * * * * =sqrt(-D)/(2*a);
* * * * * ** ** * *** **** *
***** ** ****** ** *
** * ** **** ** **** * * * * * * * * * * ** * *** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and * ** * * * * *
* **** ** * * ***** * * ********* * * *** * * ** *** * = %.2f\nx2 = %.2f",x1,x2);
** * ** ** ****

* *** * *** * ** * * * if(D==0)
* * ** * ** * ** ****
* * * * ** ** * ** *** * * * * * ** * ** * * * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * * ******* * *** ***** ** ** ** **** * ** **** ** = x2 = %.2f",x1);
* ** *** *** * * *** * *
* *** ** ** **** ** * *****
*** * ** * * * *** * **
* * ** * * * *** *** * **** * * * ** * *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * *** * ** * * **
*** * ************** * **** * *** * ** * ** ** = * * * * ** * *** ******** **
** **** *** * ** ** * * ** * * ** * * * * * * *** * ** * * * = ***** ** * * * * **** *
*** * ** ** * ** * * * *
* * * *** **** * * * 0;
}
最新回答
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 喜歡 0 不喜歡
內容已隱藏
#include * ** * *

int main()
{
** ** ** ** * ** ** n, i;

** * * *** *** *** ** *** ** * * &n);

* * **** * *** * * * * = 1; i <= n; ++i)
** *** * * * * *
**** * **** ** *** *** ** ** * * ** **** *** * *** % i == 0)
* **** * ** *** * ***** *** ***** * * * ***** * * * **** * * * ", i);
* * *** ** ****

*** ** ** ** 0;
}
最新回答 用戶: (-284 分)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
** * *** ** ** *
* * * * * ** **

int main()
{
*** ****** * * *** * * ** * ** ** **
* ** * * * *** * *** *** * * * *** * * * ** * ** * * **
* * *** ** * * *** * *** * = * **
*** ** *** ** * *** * *
********** *** * * *
*** ** * * * * ** ***** ***
** * * * ** ** ** * * = -b /(2*a);
**** * * *** * * * ** * ** * ** *
***** * ** **** ** **** * * * = (-b)/(2*a);
* ******** ** ** ****** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = **** ******** **** ** *
** * * * * * ***** *
*** * ** ** * *** * * * * if(D==0)
** ** **** * *
** * *** ** ** = (-b + * * * *
* **** **** * * *** *** = (-b - * ** ****
* * *** * **** ** * * * * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = *** **** ** * * *
* ** * * **** ** *
* * ** ** * ** **** * if(D>0)
* * * **** ** ******
* * ***** *** * **** = -b/(2*a);
****** * *** ** * ** ***** = (-b + * **
*** * * ** ** * = (-b - *** **
* ** * ** ** * ** * * ***** * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * ** * ** **
****** * **** * * *
** * * * ** * * ** 0;
}
最新回答 用戶: (-323 分)
修改於 用戶:
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 喜歡 0 不喜歡
內容已隱藏
#include * ** * * * ***
#include ** * ***
int main()
{
* ****** *** * *** * ** a,b,c;
** * *** *** ** * * * * *** * *** ** * ** * *** ** *
* * * *** ** **** * * *
** *** * * * ** ** * * ** * **
** * ** ****** * ** ****
* * * ** ** *** *** *** ** *** *** **** *** ** * **** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ** * ** * *** * + ** * ** *** * - * *******
* * ** * *** * *** *
* * ** *** ** *** *****
*** ** * ** ** * * ** * if (b*b-4*a*c==0)
** ** * * ** * ** *
** * *** * * * *** *** * * ** ***** *** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** * *** * + * **** * **
** * ** * * * * ***
* * *** * * *** * * *
* * **** ** ** ** **
********* * ** ** **
** * ** * *** **** ** * ** ** * ****** **** *** * ** *** ****** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * *** * * * ** * ** * * * * **** * * * * * * * ** *** *
* ** * *** * * *****
* * * *** ***** * * ** 0;
}
最新回答 用戶: (-127 分)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 喜歡 0 不喜歡
內容已隱藏
#include ** ** * *****
#include * **** * ***
int main()
{
* * * ********** **** * * * a,b,c;
* *** *** * ** * ** * * ** ** *** * * ** ** **** *
** * * * * ** **** *
* *** * ***** ** ** * * * *
** * ** * * * *
* ** *** *** *** ** ** * ** * * * * * ** ** * ***** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * * * * * * * + * * * * *** - * * * *
* * ** ** * * ****
** * * **** **** *
**** *** * ** * ** ****** * * if (b*b-4*a*c==0)
* * *** ** ***** * **
* ** * ** * * * ** * ** * *** ** ** * * ***** ** * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * ** ** * ** * + ** * * ****
* * ** * ** ** ** **
** * * *** * ******
*** **** * * ** * ** * *
** * ***** * * ** *****
* * * * * * * * ** * ** * * * ***** * * * **** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= *** ** ** ** * * * * * * ****** *** * ** **** * ** ***********
* *** *** * *
* ** * * * * * **** 0;
}
最新回答 用戶: (-127 分)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 喜歡 0 不喜歡
內容已隱藏
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
* ******* ****** ** * a,b,c,d,x1,x2;
* * ******** * ** ** * * * **** **** ****** *** ** * **** ** ***
* * * ** *** *** ** * ** **** *** **
* ** ******** *** *** * ** ***
* * * * * * * * * * ***** * *** *
** * **** * ** ** * ***** **
**** ***** *** ** *
** * ** *** * * ** *** ** *** ** * * *** *** ***** * of %.2fx^2 + %.2fx + %.2f = 0 are real and * * ** **
* ** *** * *** * * **** * *** ** **** * *** * *** ** = %.2f\n",x1);
* * ** ** ** * * ** * * ** * * ** ** **** * ** * = %.2f",x2);
* *** * *** * ** * ***** *
* *** * *** * ** * * **** if(d==0)
*** * *** * ** * * ** * *** *
*** *** **** * *** * *** ***** * * **** * * * **** ** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
******* *** * *** ** ** * * * * ** * * *** * * = x2 = %.2f",x1);
** ******* ** ** ** ** **
**** * ** ** * * ***
*** **** * ** * * *
* ** ******** * * ** *** ** **** * * ** * ** * * **** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * ** * **
*** * * * *** ******* ** * * * *** *** * ***** ** * = *** * **** ** ****
* *** ** *** **** * * * * * * ** * * ** *** * ** * = *** * * * * *** * * **** *
** * * ** ** **
* * * * * * ***** 0;
}
最新回答 用戶: (-214 分)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 喜歡 0 不喜歡
內容已隱藏
int a, b, c, D, spD, x1, x2;
* * * *** ** * * *** * ** * * ** * * * * * *** * *** ** ** * aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
* * * * ** * ** * ** * ** * * ******* * - (4*a*c);
* ***** **** * * ** * * * * * *** *** ***
**** * * ***** * **** * * * ** * * * **** * *** ** ** *** *** ** * ** **
* *** *** **** * ** ********** * * ** * * * * * * ** * * ** (-b+spD)/(2*a);
* * * ** *** * **** * ** ** * * * * * * ****** ** ** * ** * (-b-spD)/(2*a);
* * ***** ** *** * * ** ** ** ** * * * * * * *** ***** ** *** ** (x1==x2){
**** * ** **** *** ** * * *** ** ** ** * *** * * * * ****** ** ** * * * * ** ** **** ** * * * * ***** **** * *** * X=%d\n", x1);
** * * * ** *** ** ** * ** * * ** * * ** ****** ** *** *** ** *
* * * *** ***** * * *** ** ** * * ***** ** * * ** ** ** * * * ** ***** ***** {
* ** * * * ** * * * * * *** * * *** *** * *** ***** * ** ** * ** ** * *** ** * * * * ** ***** *** ** *** X=%d或%d\n", x1, x2);
* * * * * * ** * * ** * * ** * * ** ** * * * * ****
        }
* ** * * * * *** * * ***** * * * ** ** if(D==0){
*** ** *** ** *** * * ** * **** * **** * ** ** * * * * * * ** (-b)/(2*a);
* * * * * **** *** *** * ***** ** ** **** ** * ***** * ** ****
*** * ** * * * *** ** * **** * **** ** * * * ** * *** ****** *** *** ****** *** **** ** ****** ** * X=0");
* **** * * *** * ** ** * ** * *** * ** ** ** * * * ***
* ** * ***** ** * *** * ** * ********* *** **** * * ******
* * ** * * * ** *** * * * * * * * **** ** ** ** *** * ** ** ** ** * * ****** * *** * * * * *** X=%d\n", x1);
** * *** ** **** ** * * * * ** * * ** * ** * *** * **** **** ** * * * *
        }
* *** * ** ***** ***** * * * * * * * *
*** * * ** ** ** * * *** * * * ** ** ** * ** ***** * ****** *** * **** * * * * * * * * * * * ** * ** ** **
**** * *** ** * ****** * ** * ** * * * ** *** * **
    }
** **** * * ** * * * *** * * ** ** * * ***
    system("PAUSE");
    return 0;
}
最新回答 用戶: (-32 分)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 喜歡 0 不喜歡
內容已隱藏
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
** * ** * *** * ** * a,b,c,D;
*** ***** * * * ** * x1,x2;
** * * ** * ** * * * *** *** ** * %d ** ** * * * * ***

* * * ** **** * * *
* * * * **** *** * * * * **
* * * ** * * ** ***** ****** *

** ** ** * ** * ** ** * * A,B,C;
*** ** * ** * * ** ***

** *** ** * *** * * *
* * * * * * **** *** **** * **** ** * ***** ** * * of %.2fx^2 + %.2fx + %.2f = 0  are real and *** ** * * * *
* **** * * ** * * *** ***** *** * ** * ** *** ** * ** * = %.2f\n",x1);
*** * * ** ** ** * * ***** ** ** *** * *** * ** * *** = %.2f",x2);}

* * * ** ** ** * ** if(D==0)
* ** * ** * ** *** *** * ** ** * * *** ** * ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
* * *** ***** ** *** **** * ** *** ** * * * ******** ** * * * = x2 = %.2f",x1);}

** * * * * ***** * * if(D<0)
* * * * ****** * **** ** ** ****** ***** * * * ** * ** of %.2fx^2 + %.2fx + %.2f = 0  are complex and * ** **** * ****
** ****** **** ** *** ** *** * *** * ** bb,d,dd;
* * * ** ** ** ** ** * * ** * * * ** *** *** ***** * * * * *
* * * ** * * * *** ** * * **** * * * ****** *** * * * * ** *
* ** ** *** * **** *** * *** ** *** **** *** ** ** = * * ** **
*** * * * * *** ** *** * *** * * * * **** *** *** ** * = ** * * *** *** * **

* * ** **** * ** ****** ** 0;
}
最新回答 用戶: (-16 分)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 喜歡 0 不喜歡
內容已隱藏
#include <stdio.h>
* * ***********
int main()
{
**** * * * * ** ** * ** ** * *** **** **** *** *
* ** ** * *** ** ** ** * ** %f ** * ** *** * * * ****
*** ** ***** * *** * = (b*b-4*a*c);
***** * * **** ** = (-b + sqrt(D))/(2*a);
* ** *** *** ** ** * ** * = (-b - sqrt(D))/(2*a);
***** ***** * * * ******** = -b/(2*a);
* * * *** * ** ******** ** * =sqrt(-D)/(2*a);
* * * * * ******** * ****
**** * *** * ** * ***
** * * * ** ***** * * *** ** * **** * * * * * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and * * **** * * ** *
* * ** ** * * *** ** * * * * *** * * **** ** * * *** * *** = %.2f\nx2 = %.2f",x1,x2);
* *** ** * *** **

* ** * ** ***** **** ** if(D==0)
*** * * * ** * * *
* **** * * ***** * * * * ** *** ** * * ** ** ** ********* * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ***** * ** **** * *** * * ** * * * ** * * * ** **** ** *** * = x2 = %.2f",x1);
* * *** **** * * ****
* *** ** * **** * *
* **** * **** * * * * ****
* *** * * ** ** * ***** ** ** * * **** * ** * * * * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** ** ** ***** ****
* * * *** *** ***** * **** * *** * ** ** * ** * * ** = * * * *** * *** ** * **
*** * * * * ** * ****** * * * ** *** ** * ** ** **** * * * = ** **** * ** * * ** ** ***
* * * * *
** ** * **** **** ****** 0;
}
最新回答
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 喜歡 0 不喜歡
內容已隱藏
#include <stdio.h>
** * * **** * *
int main()
{
* * * ** * *** ***** ** * * * ** * ** *
**** ** *** ** * ** ** * %f * * ** * * ** * **** *
**** * * *** ** * ** = (b*b-4*a*c);
* * * ** * ** * * = (-b + sqrt(D))/(2*a);
* *** * ** * * * * * * = (-b - sqrt(D))/(2*a);
** * ** * * ****** **** * ** = -b/(2*a);
* **** * * * *** **** * * * * =sqrt(-D)/(2*a);
* * * ****** * ** *** *
* ** *** * * * * ** **
* **** * ** * *** ***** * ** * * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and ** * ** * ** **** *
* *** * * **** ** ***** *** * **** ***** * ** * * = %.2f\nx2 = %.2f",x1,x2);
* * ** **** ** * *** *

* * * * **** ** **** * * * if(D==0)
* ** * ** * *
* ** ******** * **** * * * ** * * ** **** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** * * * **** ** * * ** * *** * * **** * **** * * = x2 = %.2f",x1);
** * ** **** ** * *** **
* *** * ***** **
* *** ** ** **** **
* * ** * *** * * *** * * * *** ** * *** ******* of %.2fx^2 + %.2fx + %.2f = 0 are complex and * ** * *
* * * * * ** **** * ****** * ** ** * **** * = **** ******* ******* ****
* *** ** *** *** * * **** * * **** * ****** * ** * **** * ** * = *** ** * ** * *** **
*** * **** * * * ** ***
* *** **** * * ** 0;
}
最新回答
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.95
©2016-2026

沒有找到相關問題

12,783 問題
183,442 回答
172,219 留言
4,824 用戶