0 like 1 dislike
5.4k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 5.4k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
**** *** ** *
int main()
{
* *** * * * *** * * *** ***** *
** *** * ** * * ** %f * *** *** **** * * * **
** ** * * *** ** = (b*b-4*a*c);
* * *** ****** ** ** * = (-b + sqrt(D))/(2*a);
* *** * *** * **** * * = (-b - sqrt(D))/(2*a);
** *** * *** * * * = -b/(2*a);
* * *********** * ** ** * =sqrt(-D)/(2*a);
* ** * *** * **** *
* **** * *** * **
*** * * **** * **** * ** ** ** ***** *** ** ***** *** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** * * ** ** *
* *** * * ***** *** * **** *** * **** ** ** **** ** = %.2f\nx2 = %.2f",x1,x2);
** * * * ***** ** *

* ****** ** * * ** ** if(D==0)
***** *** * * ******
* * * ****** * * * ** ** **** * * * * **** *** ** ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** * ** ** * * ** **** * *** * ***** * ** ** * * ** ** *** = x2 = %.2f",x1);
** ** ** * ***** *
*** ****** * ** * * * *
** ** * * * *
* * ** * * * * * * *** **** * **** **** ** * *** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * ********** * * *
* *** *** *** ** **** * * * **** ** * * * = * * * * * ***** ** **
* ** * * * * ** ** ** * * **** * * * * *** = ******* * *** ** * *
*** ** * * * *
*** * * * * ** *** * * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** * * ***

int main()
{
***** * * ******* * ** n, i;

****** ** * *** * * ** ***** &n);

** ** * ** * ** * = 1; i <= n; ++i)
**** ******** * ** * * *
*** * * *** * * ** ** * ** * * ** *** * % i == 0)
* * **** * ******* **** * ** ** * * ** * * * *** * * ** **** ** ******* ", i);
*** *** *** *** *

******* ** * ** * ** 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * ** * * **
* * * ** ** * * *

int main()
{
** * * * * * * * * ** * *** **
*** ** * ** ** ** * ** * * * **** ***** *** * * * * ** *****
* ** *** ** ** * = * ** **
* ** * *** * * ** *** ****** *
* ** **** ** * *** * *
** * *** ** *** * * * *** * * * *
* ** ** *** *** = -b /(2*a);
**** ** * ** *** * **** *** * * *
** *** *** ** ** *** *** = (-b)/(2*a);
*** * *** ***** * * * * * ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * * ** **** * ** ***
** ****** ****** *****
* * ** ** ** ** * if(D==0)
* ** * ** * ** *** ** ***
* * * * * * ** * = (-b + * * *
** * ****** ** ** * * **** = (-b - * * * *
* * ****** *** * **** ** ***** ** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** *** ** ****
* *** * * ** ** * **
*** ** * ***** ** ** if(D>0)
* *** ** *** * * ** *
** * * ** ** *** ** * = -b/(2*a);
* ** * * ** ***** * = (-b + *** *
****** * * * * * * * ** = (-b - * **
* ***** *** * * ***** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * * * * *** *
** ** * * * ***** * * *
*** * ***** * ** 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** ** ****
#include * * **
int main()
{
*** * * ** * *** * **** a,b,c;
** * ** *** * * * * ** * **** * * ** **** ****** * * ****
**** ** * ** *** *****
***** * ** **** * * * * * *
** ** **** ** ** *** ** *** *
** * **** * * ** * * * ***** *** *** ** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ** *** * * + * * * * * * - * *** * * *
* **** ***** * * * *****
** *** ***** *********
* ***** *** * ** if (b*b-4*a*c==0)
** ** * * ** * *** **
* * ** * * * *** * ** *** * *** ** * * ** *** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * ******* * + * *
*** * * * ** ** * ***
* * * ** *** * * * *
* * * *** ** *** ***
***** *** ** * * ****
*** **** * ** ** * * **** ** * * * **** ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = ********* * ****** **** *** *** *** ** * ***** ***
* * ** * ** *
*** * **** ** * ** * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * **
#include * ** ** ***
int main()
{
** * * * ** * *** * **** a,b,c;
* * * * * * ** ** * ** ** **** * * **** *** ****
** * * * * *** ** *
***** * **** * ** * ****
* * **** * * * * ****
* ** **** ** * * ** * * *** * * * ** * * ** * * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = *** ** * * + * * ***** ** * - * *** * ** * *
* ** ** ** * * * * *
* * ** ** **** * **** * **
* * ** ** * * ***** ** * * if (b*b-4*a*c==0)
* * * * *** ** *** * *
*** * * * ** * * * ***** * * *** * ***** ** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** * * ** + * * *** * * * **
* ** * *** * ****
** ** * ** ** **
* *** * * * *** * * *
** ** * ** ** **
***** * ******* *** ***** ** * * * * * * * * ** *** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= * ** * ** * *** * ** ***** * * ** *** * *
*** ** ** * * ** * ** *
*** ** ******** ** * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
* *** * ** ** * * * * * a,b,c,d,x1,x2;
**** * * * ** * ** * *** ** ** *** * ** ** ** ****
* * * * * ** * * * * *
* ******* * ** **** * *** ** * * *
* ** *** ** *** * * * * *** * ** *
*** ** * *** *** * **** ***
* *** * *** * * ** ** * *
* **** ** * * * * *** *** **** * * * *** * * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and ** * * ** * ** ***
** * *** ***** ** ** *** ** * * ***** *** *** * **** * *** * * = %.2f\n",x1);
* ** ** * ***** * ** *** * * * ** * * ** ***** * ** = %.2f",x2);
* ** * * ** ****** * *
* * **** *** * ** ** if(d==0)
* ** ** **** **** * *
*** ** * * ** ******* ******* * ***** *** * **** ****** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * * * ** **** * ** ** **** * ** * ** * = x2 = %.2f",x1);
* * * *** * **** ** ** *
** * * * * * * * *
***** * * **** * * *
** ** * * ** ** ** * * * ** ** * * * *** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ***** *** **
** ** *** * * ** ***** * * * * * * *** *** * ******* * * ** * = ** **** * * *** *
* *** * * **** * *** * **** ** * ** * * * **** * = * ** * * * ** * * * ***
*** * * * ** **** ** *
*** **** ** * *** * *** * 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
* **** ******** *** * * ** **** * * ** ** * ** * *** * aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
*** ** ** * ** ** * * * ** ** * * ** * *** * ** - (4*a*c);
* * * * ** *** *** **** ** ** * ***** * * *
* * ** ***** ** * * ** ** ** * *** *** *** * * * ** * * *
** *** ** * ** ** * * ****** *** ** * **** *** * * * * ** * (-b+spD)/(2*a);
*** * *** *** * * ** * * * ** *** *** * * * * *** * **** **** * ***** * (-b-spD)/(2*a);
* * * ***** * * ** * * *** ** * *** ** * *** * *** * ** * ** (x1==x2){
* **** **** ** * * *** ** * ** * ** ** * * *** * ** ** * * *** ***** * * ******* *** * ** * *** ******* ** **** *** * X=%d\n", x1);
* * ** * * ** * * * * ** * *** * * * * * * ** * * * *** *** **
*** ** **** **** *** **** * **** *** * * ** * * ** * * ** * {
**** * ** * ** ** * * * ***** * **** * * ** * **** * * ***** * * * *** **** * ** * ** ** ** *** **** * *** ** ** * ** ****** * *** X=%d或%d\n", x1, x2);
* ***** * ** *** * ** * **** * *** *** **** * **** **** * *** * * ** ** *
        }
* * * * * *** *** *** *** ** ** * * * * if(D==0){
* * * * * *** * ** **** ** * ** * **** ** * * ***** * * * (-b)/(2*a);
*** **** ** ** * * *** ** *** **** * * * ** *** * * * * *
* ** * * ** **** ** * *** * ***** * * ** * * ** * ** * * * ** ** ** ** * * *** X=0");
* * ** * * * * ** * ***** * * * * *** * ** *** * * * * **
* * * ** * ** ****** * ** * * * ** ***** * ** * * * *** ***
* * * * * ** *** ** * ** *** ** * * *** * * ***** *** * * *** * * *** * ** * * **** ** * * * ** ** ** * * * X=%d\n", x1);
** * * ** ***** * ******* * * **** * **** ** * **** ** ***
        }
** * *** ** ** * ** *** ** ** ** ** ****
**** * ** ******* ** *** * **** ** * * *** ***** *** ** * ** ** **** ** *** * ** ** ** ** ***** ** ****
*** * *** ** *** * * * * * * **** **
    }
** * * *** ** ** * * ** *** **** * *** * *** *** *** * * *
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
* ** * *** * * * a,b,c,D;
*** ***** **** * ** *** x1,x2;
** * * ***** *** ** * * ** * * %d * * * ******* ******* **

***** * ** * *** ** * *
** * * *** * *** **** * ** * * *
* *** ** * *** * * *******

** ** ** * * * * ** ** ** A,B,C;
* * ** * **** * *** * * * ** **

** ** * * ** **** ** ***** **
** * * * ** * * ** ** * ** ** *** * * *** * **** ** of %.2fx^2 + %.2fx + %.2f = 0  are real and * * * * *** ** **
**** ** ** ** ***************** * ** * * * * * = %.2f\n",x1);
* **** * ** * ** * * **** *** * ** * ** *** * ** * * *** * * = %.2f",x2);}

* * *** * * ****** *** if(D==0)
* ******* ***** * * * ** *** *** * ** * * * * * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
* * * **** *** * * * * * * ** * *** * * * ** * ** * ** = x2 = %.2f",x1);}

* * * **** * * ** * if(D<0)
* ** * * * ** * * * ** * * * * * ** ** * *** * * * of %.2fx^2 + %.2fx + %.2f = 0  are complex and *** *** * **
* * ** * * *** * ** ** * ****** * *** bb,d,dd;
****** * ** * **** ** ***** * * * * ***** *****
* *** **** * * * * * ********** *** * ** *** * * *** ** **** * *
*** * * ** ** **** *** ** ***** ** ****** * * * = ** * * ** ** *
* * **** * * ** ****** * * ** ** ** * * * * **** **** = *** * ** * *** ** *

*** * * ** **** * * * ** * * 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* * *** *
int main()
{
** ****** * * ** * ** ** * ** * ** ** **** * *
* * ** ** ** ** * * %f ** ** ***** ** * *********
* ****** * * * ** *** * = (b*b-4*a*c);
**** *** ** * ** * * * * *** * = (-b + sqrt(D))/(2*a);
***** * ** * ***** *** * = (-b - sqrt(D))/(2*a);
* * *** **** ** ** * = -b/(2*a);
* * * * *** ** ** * * *** =sqrt(-D)/(2*a);
***** * ** * ** * * *** ** * ** *
* *** ** ***** ** *
*** * * **** ** ** ** * ** ** ** *** * *** ** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and *** * * * **
** * * * * * * *** ** * **** * * * * * * * ** * = %.2f\nx2 = %.2f",x1,x2);
*** *** ***

*** * ***** ** *** * * if(D==0)
** * * ** * ** ** * *
* **** *** * ** *** ** * *** ***** ** ** ** *** * * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
**** ** *** ** ** *** * * *** * * *** * * ** * ** = x2 = %.2f",x1);
* ** * * ******
* * * * ***** * * **
** *** *** * * * ****
* * * **** * *** * ** * *** ** *** * * *** * **** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * ** * *
** * ** * * ** * ** * * * ** * ** * ** = * *** * * ** ****** ****
** * * *** * *** * * *** * ** * ******* * = * ** *** * * *** * *
** * ** * ** ** * *
* * * * * * * ** **** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* * * ***** *
int main()
{
** ** ***** * * * ** ** *** * *** ** *
** * *** *** **** * %f **** * ** * * ***** * *
******** ** ** ******* ** = (b*b-4*a*c);
** ** ** ** ** * ** * ** = (-b + sqrt(D))/(2*a);
* ** *** ** * * * = (-b - sqrt(D))/(2*a);
*** * ** *** ** **** ** = -b/(2*a);
* * * *** * * * * * ** =sqrt(-D)/(2*a);
* * * * * * **** * * * * * ***
* **** **** * * * *
* *** * * * *** * *** ** * ** ** ** * * ** * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** * ******* * * ** **
* **** ** ** ** * * **** *** * *** ******** ** * = %.2f\nx2 = %.2f",x1,x2);
** * * ** * ****

* ****** * * ** if(D==0)
***** ***** ** **** * ****
** ** ***** * * * *** * ** ******** * * ** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ******* * * * ** *** *** ** ****** * ****** ******** **** = x2 = %.2f",x1);
* * ** **** * *
* *** * * *
* * ** ** * *** * ** *
* ** * ** ** * * * * **** ***** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * ***** * *
*** * * *** ** * * * * *** * *** ***** * * * * *** * * * = ***** *********** ********
* **** * * ** *** ** * * ** * ** **** * *** = ** * * ** * *** * **
*** * ** * * ** ** ****
*** * ** ** * **** ** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.238
©2016-2024

No related questions found

12,783 questions
183,443 answers
172,219 comments
4,824 users