0 like 1 dislike
17k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 17k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
* * ** ** *** ** * **
int main()
{
* * *** *** *** * * *** * * ****** ** *** * *
* ** * * ** * * *** *** * *** *** %f * * ** ** * * * * * * * *** **
* * ** ** ** * ** * * = (b*b-4*a*c);
* *** ****** * * ** = (-b + sqrt(D))/(2*a);
**** * * * * = (-b - sqrt(D))/(2*a);
* ** * * ** *** * = -b/(2*a);
* ** * ** ** ** * * =sqrt(-D)/(2*a);
** **** *** * * * * * *******
**** ** ** ** * * ** *
** ** * ** *** * ** * * * *** **** * ** ** ** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * * * * * ***
* ** * ** * * * * ** * ***** * ** **** *** * ***** = %.2f\nx2 = %.2f",x1,x2);
**** * * * **** *** ** * *

* ***** **** *** * * **** * ** if(D==0)
* * ** **** * * *******
* ****** ** ** * * * * * *** *** *** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * **** ***** * **** * **** ** * ****** *** * * = x2 = %.2f",x1);
** * ** ****** * *
*** * ** ** ** **
* *** * ** ** * *** *
** * * * ** * * * * * * ***** ** * ** ** * * ****** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * ** **** **
* * * *** ** *** * ** * **** ** * ** * *** * * ******* = * * * * ***** *** *
* ** * * * **** * ****** * * *** * ** *** ** * = * * ** ** * *
** ** *** * *** * ***
* * ** ** ********** ** * * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include **** * ***

int main()
{
*** * ** ***** * ** **** * n, i;

** * * * * * ** **** ** * ** * &n);

* * * * ** ** * * * = 1; i <= n; ++i)
* * **** * * * *** * *
* ** ***** * ** ** * * ** * * * * ***** * ****** ** % i == 0)
** * *** * ******* * ***** **** *** **** *** ***** * ** * ** * ** ***** * *** * * ** ", i);
* * *** * **** *** * ** ***

*** * ** * * * *** *** 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** **** ** ** *
* * ** * ** * **

int main()
{
** * * ** ***** * ***** ** **** * * ****** *
* **** *** ** ***** *** * ** ***** * * ** * ** ***
* **** ** * ** *** = * * ****
* ************* ***** * * *
* *** * ** * ** **
* * *** **** * ** ** ** **
*** ** ** * * * = -b /(2*a);
** * * ** ** * * * *** * ***
*** **** * * * ** * * * * = (-b)/(2*a);
** ** ** ** * ** * *** * * * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = ** ** * * ** * *
*** * *** * * * * * * *
* ** * **** ** * ** ** * if(D==0)
* * * ** *** * **
** * ** * * * *** = (-b + ***********
** ** * *** * * * * = (-b - ** ** *
* *** * * * * * *** * * * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** * ** * *
* * *** * ** ** ** ** *
* * ** *** *** * if(D>0)
* ** * * * ** *** ***
** * * ** * ** * * = -b/(2*a);
* * ** ** *** * ** = (-b + * *** ***
* * ** * * ** ****** **** ** = (-b - *** *
*** * *** ******* *** ***** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ** *** * **
* * * * *** ** * **
* ** * * **** * * * ** * ***** 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** ***** *
#include * ** ** **
int main()
{
*** **** * * **** ** * **** a,b,c;
* * **** *** * ** * * * * * * ***** *** ** **** ****** *
* ** *** **** **
**** * * * ** * ** * * * ******
**** *** ** ** ** **
* * * * ******* ** *** * **** *** * * * * * * * * ** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * *** * ** * + * * ** **** * * - * * *****
** * ** * *** * **
*** * * ***** ****** * **
**** ** * ** * * ** * *** if (b*b-4*a*c==0)
* * ** * ** * ** * ***
* * ** ** **** ** * * * *** **** * ** ** * *** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * **** * + * * * ** * * **
* * ** ************ * ***
**** * ** ** * * * * *
*** ** ** * ** * ** *
* * * ** ** ** *
* * *** *** ** ** *** * * *** * * ** **** ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * * * **** ** * ** * ** * ** * * *****
* ** ******
*** * * * * * ***** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * * *
#include * * * *** *
int main()
{
*** * ** *** * * * * * ** a,b,c;
** * * * * ** * * ** * * *** *** ***** **** *** **
** * * ** * * * *
*** * * ** * * ** * **** *** *
* *** * ** * ***** * *
*** * ** * *** ******* * * **** * * * * ****** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * * * **** + **** * - * * ** * *** *
* * * * *** **** ****
*** * ** * * *
*** * * * ***** ** * if (b*b-4*a*c==0)
*** * * * * * ** * **
* ** ** *** * * * **** *** ** * **** ***** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** ** **** ** + ** * * ** * *
** ** * * * *
* ** ****** ** ** *
**** ** * *** ** *** ** *
** ********* *** ***
*** * ** ** ** * * *** * * ** ** * * * * ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= *** ** ******** *** ** * * * * ** ** *
**** * * ** * *
** **** * ** * * * * * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
* *** * *** * * ** * * a,b,c,d,x1,x2;
**** * *** **** * * * * **** * * * * * *** * * * *****
**** * * * * * * *** * *** * ** *
**** * * * * ** ** * * ** * * ** * *
* * *** ** ** ** * * * * *
** **** ** * ** * ** * *
* **** ** ** * * *
* ** *** * * *** * * * * * ** * **** * * * ***** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * ** *** *** **** *
***** * ** ** ***** ** *** *** ** **** * * * *** * * * **** = %.2f\n",x1);
* ** * * * * * * * * *** ** * * *** *** * * *** * = %.2f",x2);
** * * *** *********
*** ** ** * ** ** * if(d==0)
** ** *** ** *
* ******* ******* *** * *** *** * * ** ** * *** ** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** * *** * ** *** * * * * * ** * ** ** * * **** * = x2 = %.2f",x1);
* ******** * *** *
** * ** **** * ****** *
* * * ** * ** *** * *
* ** * *** *** * * * ** * ** * * ****** *** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and **** *** * **
*** * ** * ** **** *** * *** ** * ** * ** * * * * * = ********* * ** **** ** *
* **** * * * ** ** ****** * *** * *** * * *** ** = ** * * * ****** **** ** ***
***** **** *** ******* * *
*** ** * * *** ** * *** 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
** * * ** ** * ***** * ** **** *** * * ***** * ** aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
* *** * *** * ** * ** * * **** * * * *** * * - (4*a*c);
**** *** ***** * * ** ** * ** *** ** * * ** * * **
* ** ** *** * * * *** * * * *** ** ** ******** ** **** * * *** * *
**** * * * * * *** * ** ** * ** * ******* ****** * * * * * ******** (-b+spD)/(2*a);
**** ** **** ***** ***** ** **** * * * ** ** * * * * **** ** ** (-b-spD)/(2*a);
** * * ******* * *** * **** * * **** * *** * * * ****** (x1==x2){
* ** **** * * * ** *** *** ** ** * * * ** * * * *** ** * * ** *** * ** * **** ******** ** ** * * * *** ***** * *** * * *** * ** *** X=%d\n", x1);
*** ****** * * ** ****** * **** * * ** * ** ***** * ** ****
*** * * ** * ** * ** * * *** * * **** ** ** * * * *** {
* **** ** ***** *** ******* * * ** ***** * * * * ** * * * ** *** ** ** * *** * * * *** * * *** * ** **** X=%d或%d\n", x1, x2);
**** * * * *** ** *** ** ** * * * * * * * * ****
        }
* * *** * *** *** * ** * *** * ** if(D==0){
* * *** * *** * **** * ***** * * * * * *** * ** * *** * ** * * * (-b)/(2*a);
* *** * * ** ** * ** * *** ** * * ***** ** * ** * * ***** * ***** * ** * *
** * * * **** ** * *** * * *** * ** * * **** * ** * * *** ** * ** ** **** * * ***** ** * ** * * ** X=0");
****** * * * * **** * * * * * *** * ** ** ** ****** * * * * * * * *
*** ** *** * * ** ** ** * *** ***** ** ** ** ** ** * *** * *****
* * * ** ** * * ** ** * *** *** **** **** ** *** * * ** ** ** ****** ** ** ******* * * X=%d\n", x1);
* * * * * * * *** ** ** * ******* * ** ** * * * **** ****** * * ** ** * * *
        }
******* * * * *** ******* *** * * ** * * * * *
** ** ** * **** *** ***** * * ** ** ** ***** * * **** ** *** ** ******* * * * * ** ** ** * * *
** * * * * ******* ** * ** *
    }
*** * * ** * ** * * * * ******** * * *** * *** ****** *
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
* * ***** ** *** ** ** a,b,c,D;
***** ***** ** * * * *** ** * * x1,x2;
* * *** ** ** **** **** * ** * %d ** * ** *** * ** ****

* **** ** ** ** ** *** * * *
*** * * ***** * * *** * *** * *
* * * **** * *** * *

** * * ** ** A,B,C;
* *** * ** * *** **

** ** * ** **** *
** ** * * **** *** * * * * * *** *** * * * ***** ** * * * * of %.2fx^2 + %.2fx + %.2f = 0  are real and * * * ** ** *
** * * * ** ***** * **** * * * ** * * * * * * * * * = %.2f\n",x1);
** ** *** ** * ** * * **** * ** *** ** * ** * * ***** = %.2f",x2);}

* ** * * * ** * ** ** *** if(D==0)
*** * * ** *** * *** * **** * ** * **** * *** *** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
* * ** * ********* ** ** *** ** * *** ** * ** * *** *** * ** * = x2 = %.2f",x1);}

**** * * **** ** if(D<0)
*** ** ** * * * ** * ** * ** * *** * ** ** ** of %.2fx^2 + %.2fx + %.2f = 0  are complex and * ******** * * *
****** **** * * *** ** * *** *** * ** *** ***** *** bb,d,dd;
* * ** * ** *** *** * *** * * * ** ** ** ** **
** *** ** **** **** * *** * * ** ***** * * ***** *** * * ** * *
** ** * *** *** ** **** * *** * *** * **** = * ** * ** ****
* ***** * *** * *** * ** **** * * * ** ** * * ** = * ***** ** ** *

* ** * * ** * * ** 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* * * *** * **
int main()
{
* *** ***** **** ***** * ******** * * ** * ***
** * * * ** * * * * * ******* %f *** ** * *** * ** * **
* * ** ***** *** * = (b*b-4*a*c);
*** * * ** * = (-b + sqrt(D))/(2*a);
* * * ** ** ** * ** = (-b - sqrt(D))/(2*a);
* * * * * *** **** * * * = -b/(2*a);
* ***** *** ** * ** *** ** *** *** =sqrt(-D)/(2*a);
** ** * ** ** ** *
* * * * * ** * *** *** *
*** * **** ** *** * ***** ** *** **** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * ***** ** * *
****** **** ***** ** * * ** ** ********* ** * *** = %.2f\nx2 = %.2f",x1,x2);
* * * ** ** *** * **

* * ****** ** * ** ** * if(D==0)
* * ** * * **
* * * * * ** * * * * * * * * * * *** * ** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * * ** ** *** ** ** * ** ** * * * * *** **** * = x2 = %.2f",x1);
* ** * * * ** * *
** ** ** *** *** ***** *
** * *** * **** *
* * *** * ** *** *** ** * * * * * * ** *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and *** * * * * *** *
** * * *** * * ** ** * * ********* ** ** ** ** * = * *** * * *** * ** *
* ** * * * ** * ** * * ** *** * * ** * ** ** * * = ** ** ** * * * * ** * *
*** * * **** **** * * *
** * * ** *** * * *** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* * ** ****** *
int main()
{
** ** * * * ** * *** ** ** **** * *
* *** *** * * ***** ** *** ** * *** %f * * * ** ***** * ** * ** * * *
* ** * ******* *** * ** * = (b*b-4*a*c);
* ** *** * ******* * * = (-b + sqrt(D))/(2*a);
** ****** ** * = (-b - sqrt(D))/(2*a);
* ** * * ******* * *** * * = -b/(2*a);
** ***** * * * * * *** =sqrt(-D)/(2*a);
* **** ** *** ** * **** *** ***** *
* ** **** * *** ** * **
* * * ** ** ** ** * *** ** **** ***** * * * * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and ** * * * * *
**** **** * * ** * ** *** ** * * * * * * * ** *** = %.2f\nx2 = %.2f",x1,x2);
* *** ** * * ** ** * * **

* * * ** * ******* ** ** if(D==0)
** * * * ** ******
** * *** ** * *** ** ** **** * *** ** ** * * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
**** * * * *** ** * *** * * ** * * ***** *** * * = x2 = %.2f",x1);
* * * ***** ***** **** *** *
** * * * * * *
* * ******** * * * *
** * ** ** * * * ** * * ****** * * * *** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** ** * *
* * ** * * * ** * **** * * * ** ** ***** * ** = ** * * ** **** ** *** *
** * * * ** * ********** **** ** * *** ** = * * * ***** ***** *** * * **
* * * * * **** * *
**** ** ** * ** **** * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.165
©2016-2026

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users