0 like 1 dislike
11.6k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 11.6k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
********** **** * * ***
int main()
{
**** ** ** * *** * ***** ** * * * * ** * **
*** * * * ** **** * ******* * %f ** ** ****** *** ** * **
* ***** * * *** ******* = (b*b-4*a*c);
* ** * * * *** * * **** ** = (-b + sqrt(D))/(2*a);
** ** * ** *** * ** ** = (-b - sqrt(D))/(2*a);
* ***** **** *** ** ** *** = -b/(2*a);
* * * * * *** ** **** ** ** =sqrt(-D)/(2*a);
** * ** * ** * * ** *
**** **** ** * *******
*** * *** * ***** * ** * **** *** * * * * *** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and *** * ** ** ***
** ** *** ****** ** ** * *** * ** * * * * * * * ** *** * = %.2f\nx2 = %.2f",x1,x2);
** * * * **** **

* * * * * * * * * * if(D==0)
* ** ** *** ** *** *
** * * **** *** * ** * ** ***** * ** *** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * ** **** * **** ****** * * * * * ******* ****** = x2 = %.2f",x1);
**** * **
* ** ** * **** * *
******* * ** * ****** ** *
**** **** * *** * * ** *** *** * * *** * *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * * * *
* * * * ** **** * * ** *** *** * ** ** * * ** ** = * * ** * *** ** * ***
*** ** *** * ***** * *** * * *** **** ** ** * ** ***** * = *** *** * ** * * *** *** *
* *** *** *** * ** **
*** *** * *** ** *** * **** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * * ** *

int main()
{
* * * * *** *** * n, i;

* * ** * **** ** ** * ** * * **** * ** * &n);

* * * * ***** **** *** * = 1; i <= n; ++i)
* *** ** * * **
*** **** **** ***** * * ** * * ****** % i == 0)
* * * ** ****** **** ** ***** ***** ** **** ** ***** * ** * *** * ", i);
* *** ** * ** * ** *

****** * * *** * * ** ** 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* ****** ** * * *
** * *** ****

int main()
{
* * * ** * * * * * * * * * * ** ******
* * * ** *** ********* * ** **** * * *** ** * * ***
** * ** ** *** ** * = **** *** *
* * * **** * ** * * * * * ** *
* * *** * **** ******
******* *** **** ******** * * ** **
*** * *** * * *** * ** = -b /(2*a);
** ** * ** * * * * * * ** ** *** *****
**** ** * * * = (-b)/(2*a);
** ** * ** *** * * ** ** ***** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = ** **** ** **** * * ***
* * **** * ** * **** *
** ** * * ***** * *** if(D==0)
* ** **** * **
* * * **** *** * * * **** = (-b + * *****
** ** * ** * * * * = (-b - * **
* *** * *** ** *** ** * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = *** * * *** * ***
* *** * * **** * **
** * *** * * *** * * if(D>0)
** ** * * ** *** *
* * ** ** ***** * **** *** = -b/(2*a);
* ** ** * *** * * ** ** = (-b + * * **
* * ** * ** * * * ** = (-b - ***** *
* **** * * ** ** * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * * ***** * * *
*** * ** ** **** * **
** ** * *** * *** *** ** 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * * ***** *
#include * * * ***
int main()
{
**** * * ***** ** *** * a,b,c;
* ** * * *** * **** * * * **** * * *** ** ** * *
******* * ** * * * *
*** ** * * ** **** ** **
*** ****** **** *** ****
* * ** * * ***** **** * * * ******* *** * ** **** * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * * * * ** + ** *** ** ** - ***** ** * ****
*** * * * * * * *
** *** * * * ****** *
** ** * * * * *** ****** *** ** if (b*b-4*a*c==0)
** * ** * *** * * * ***
* * *** ** * * ** * * ** ** * * *** ***** ** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** * * * + * * *** *
* *** **** ******
** * * * ****** ** * *
* *** * * * * * *
* ** **** *** * *** *
* * * * * ** * ***** * * **** * * *** * ** * ** * ** * ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * *** * ** ** * * *** * ** ** * * * * ** * * * ** * *
*** ** * *** ** *** ***
* * ** * * * **** * * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ******* ***
#include * ** *** * * *
int main()
{
* * *** * ** ** * * * ***** a,b,c;
* ** *** * ** ** *** *** ***** * * * **** * * * *** * **** *
*** ** ** ** ***** * * **
* * * * * **** * * ** * **** * ** *
* ** *** ** * * **
* * **** ** * * **** ** ** ***** ** ** ***** ** * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * ** **** * * * + *** * ** *** *** - ** * ** ** * * *
**** **** *** * * *** * *
** * * ** ** ***
* ** ** ** * ** * ** *** if (b*b-4*a*c==0)
* *** * ***** * * *
* ** ** ** * * ***** ** * * ****** ** ** * ** * *** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * * * ** + ** * ** **** *
*** * * * ** ** * *
* ** *** * * **** ** *
* * ******* ** ***
*** ** * ** ** * * **
* * *** * * **** * ** ** ** * * * * * * * ** * ****** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= * * **** * **** * ***** ** * * * * ** * * ***
* ** **** * * * * *
** * ** ****** *** ** * ** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
* ** * ** * ** ** **** a,b,c,d,x1,x2;
*** ** *** * ** ***** ****** ** ** * * * ****** ** * **
**** ** ** ** * * ********* * **
* *** * *** ** ******** * * **** **
* * * ** * ** ** *** * * * *** ***
*** * * * ** ** *
* *** **** *** ** * * *
* * ****** * ** * * * *** * * * ******* * * * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** ** * ** * * *
* *** *** * *** * * *** * ** ** * ** **** * ** = %.2f\n",x1);
* *** * * * ** ** ***** ***** * ** * * * ***** = %.2f",x2);
* * * ***** * **
* * * *** ** *** **** if(d==0)
****** * * ****** *
* ** * *** ****** *** ** *** *** * ** **** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** * * *** * ** ***** ** * * ** * *** *** ** * ** *** * * = x2 = %.2f",x1);
* * * ** ***** * * *
*** * ** ** ** *** ** *
**** * * **** *
* ** **** ** ** * * * * * * ** ******* * ** *** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and **** * * *****
** * * ** * * * * * * * ** **** * * * *** = * *** ******** *** * ***** *
* ***** * ** ** * ** ** * * * * * **** ** **** * *** * = * * ** **** ****** * *
** ** *** ** * * *
****** * ** * * *** * 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
** ** ******* ** * ** *** ** *** **** ** * ** *** * * ** aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
* * * ** ** * * * ** ** * * * * **** - (4*a*c);
* ** ** * * * * ***** * ******* *** * *** * * ** * *
* * * * * * ** * ** *** ******* * * * *** * ** * ** ** * **
*** ** *** * ** * ** ** *** * * ** ** ** ** * *** *** * * *** * *** (-b+spD)/(2*a);
* ** ** ******* ***** ** ** * * * ** ******* ** ** * ****** * (-b-spD)/(2*a);
* * * * * ** * * * * ** * * * **** * *** *** ** ****** ** * (x1==x2){
** * * *** * *** *** ** ** *** ** ** * * **** ** *** * * * *** * ** ** *** * ** * * ** * *** * * ** *** * * * X=%d\n", x1);
* * * * ** * ** * * * * ** ** ** ** * * * ****** * * * * **
* ** * * ** * * ** * * **** * ******* * * * * **** ***** *** {
* * ** * * *** * *** * * ** **** ** *** *** * * ** ****** * * * * ** ** * * * * * ******* ** ** *** * * *** X=%d或%d\n", x1, x2);
* * *** * ** ** *** **** * * ** * **** **** ***
        }
** ** ** **** * **** ** **** ** *** * * if(D==0){
* ** * * * **** *** ***** ** ** * *** *** * ** * ** ** ** ** (-b)/(2*a);
*** * * * * ** * ** * * * * * ** ** ** **** ** **** * ** ****
*** * ** ** * ******* *** * * * **** * * **** ****** * * *** ** ** * * * *** ** * X=0");
** * *** ** * * ******** ******** * ** ** * ** * *** *** * ** ** **
* ** * *** ** ** * * **** * ** * * * ** * * ** * * ***** ** * * *
* * * ** * * * * *** * * * * ** **** **** * * * * ***** *** * * * *** ** * ** **** **** *** * X=%d\n", x1);
* ***** * * * * *** *** * *** ** * * ** *** ****
        }
* * ** * * * * ** **** * * **** * **
******** ** ** ** * **** * ** ***** *** * ** * ** **** **** * ** * * *** ***** ** * * ** *
* **** *** * * ** * * ** * *** ***** *
    }
* * **** * * ** **** *** * * * ** * * *
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
* *** * ** * * * * a,b,c,D;
* ** *** * *** ** ***** * ** x1,x2;
** * ** * ** * * **** **** * * * * %d ** * **** * * *** *** *

*** * ** * * * ** **
** ** * ** **** ***** *** *
** * * *** * ** * * * *

** ** * *** * **** * * A,B,C;
**** * *** *** * ** * ** *

** * * ***** ** * * * * *
*** * * **** **** * * *** ** ** ******** ** ** ** ***** of %.2fx^2 + %.2fx + %.2f = 0  are real and *** * *** * *
* ** ** * * ** ** ** ** ** *** * * ****** ***** **** * = %.2f\n",x1);
* * *** * ** * *** ** ** ** * * * * * *** ** *** ** * = %.2f",x2);}

* * *** *** * ** **** * * if(D==0)
* *** *** ** * * ** * ** ** *** *** * * ** *** * * *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
** ****** ** *** * * * * * * * ** ** * ** **** * * ** = x2 = %.2f",x1);}

* ** *** * ** * * * ** if(D<0)
* ** * * * * * ** **** * * * ** ** * * ** ** ** * * * ** *** * of %.2fx^2 + %.2fx + %.2f = 0  are complex and * *** * * *** *
** * * * ***** **** *** * ** **** * **** * bb,d,dd;
* * ****** *** * *** * ** * *** ** * ** ** *** * * * *
* * *** * *** ** ** * ** ****** * * * * * ** ***** * * ****
** * ** * * ** * * **** ** *** *** ** *** ** * * * *** * = * * * ***** * *
** *** ** * * ** ****** **** ** *** ** * * * ** * *** = * ** * * ****

** **** * ** *** * 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* * *** **
int main()
{
*** **** * ** ** * * * ** *** * * *** **
** ** * *** ***** * * * ** %f *** **** *** **** * ** *
***** * * * * = (b*b-4*a*c);
*** * ** * * * * ** = (-b + sqrt(D))/(2*a);
* * **** * * *** *** * * = (-b - sqrt(D))/(2*a);
* ** ** ** * * * * *********** = -b/(2*a);
* *** ** * ** ** ***** ** *** * =sqrt(-D)/(2*a);
* *** * ** * **** ** **
* **** ** ***** ** ** *
* * * ** *** ** *** * ** * *** * * * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and ** ** *
*** ** * * **** *** * *** ** ** * * * * ** * ** *** = %.2f\nx2 = %.2f",x1,x2);
* * * * * **

** *** ** ** ** *** ** * ** if(D==0)
* * ** **** * * *
**** * ** * * *** * * * * * * ** ***** *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** * **** ***** *** * * **** *** * * * * ***** * ** * = x2 = %.2f",x1);
* * *** ** *** * *****
*** *** * *** * ** * **
** * ***** * *
***** * * *** ** * * ** ** *** ** * ** * * *** ** ******* of %.2fx^2 + %.2fx + %.2f = 0 are complex and ***** * *
* *** ** ** *** *** ** ** ***** * ** * * * ***** * * = * ** ** ****** *
* * * ***** * *** * * ** * * * * ** * * * = * * ***** * * * ***** ***
** * * * * * * * *
* * ****** * * **** * * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* * **** *** * *
int main()
{
**** ** * * * *** * ** ** ***** *** ** ** * *
* ******* * * * ** ***** * * %f **** *** **** ***** ** ***
* * ** * ** * * ***** * * * = (b*b-4*a*c);
* ******* * * * ** * ** * = (-b + sqrt(D))/(2*a);
* * * * * *** * ** = (-b - sqrt(D))/(2*a);
* *** * * ** ** *** * = -b/(2*a);
****** *** * ** ** * * =sqrt(-D)/(2*a);
*** **** * **** * ** **** *
*** * ** ** * * * * * **
**** * ** ****** *** * ** * *** ** * * * ** **** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * ** **** *** * * * *
* ** * **** * ** * **** * * * ** ** = %.2f\nx2 = %.2f",x1,x2);
* ** * * * * * ** **

** ** ** ** * * ** **** if(D==0)
* *** ***** * *** ** *
** * * ** * *** *** * * **** ** * ** *** ** * * * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** * ** * *** ** * * * * *** *** * * * ***** * = x2 = %.2f",x1);
** * ** * * *** * *
* ** * * * * * *** ** *
***** * ** *** * ** *
** * **** * ******** **** ****** * **** **** * ** ** *** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** ***** **** *
* * *** * * ** *** ****** ***** **** * * ** *** * ** = * ** **** *********
* * * * * * * ***** * *** *** ** *** * * = *** ***** *** * * **
** ** ** * *
** * * ******** * * * * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.203.112
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users