0 like 1 dislike
8.6k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 8.6k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
* *** ** ** *
int main()
{
* ** ** *** ** * *** * ** * *** * * * * ** **
* * * ** *** * * * ** ** %f * * * ******* *
** * *** ****** * = (b*b-4*a*c);
**** ** **** * * = (-b + sqrt(D))/(2*a);
*** ** ** **** * * = (-b - sqrt(D))/(2*a);
* ** * ** ****** * * * * * * * = -b/(2*a);
***** *** * * * * * *** * =sqrt(-D)/(2*a);
* * ** ** * * ** * *** *
* ***** ** * ******
* * * ** * *** * ** * * ** * * *** ** *** ** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and * * ** * *** *
* * * ** * * * * *** * * * **** * **** ** = %.2f\nx2 = %.2f",x1,x2);
** *** ** * **** ****

*** * ** ** * *** ** * if(D==0)
* ** * ****** *** * ***
* ** * * ** * ***** * ** ******* * * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* *** *** * * *** * *** * * * ***** **** ***** * ** * * = x2 = %.2f",x1);
* * ***** * **** **** *
***** ** *** * *** ***** *
** ** * *** ** **** *
* ***** ********* * **** * * ** * ** * * ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * * * * ** * *** *
*** * * * * * * * * * * ** ** * ** * *** *** = ** * * ** ** ** *** **
* * * ** ** * * * ** * ***** ******* * **** * * ** = ** * * *** *** * ***** *
** ** * ** * * * ** ** *
* * * ** * ** * *** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * **

int main()
{
* **** * * ** ** * n, i;

*** * ** ** * * *** ** ** * **** ** &n);

** * * * *** * * * * * * = 1; i <= n; ++i)
** ** *** ** ***
** *** *** * ** ** * *** ** * * ** ****** % i == 0)
** * * *** **** ** ** * ** **** * * * *** ** * ** * * ****** *** * * ** ", i);
***** * * * * * * *

* **** ** * ** ** * 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * * ** * * **
** * ** * * * * ** *

int main()
{
* ** ** ** * * ** * * * *** **** ** *
**** ***** * *** *** ** * ******** ** * * *** ** * * * **** *
* ** *** ** * * **** **** = *** * * *
***** * * * * * ***** **
* * * ** * **** ** *
****** ** ***** ** * *** * *
* * * * * * * * * ** = -b /(2*a);
* * *** ** ****** * * * *** * *
** *** ** * * *** * * * = (-b)/(2*a);
****** * ** * * ** * ***** * ***** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = ** * ** * * *
** ** * ** * ****** *
** *** * * * * * ** * if(D==0)
* * * * * * * * * *
*** *** *** * *** = (-b + * *****
* * * *** ** * = (-b - * * ** *
* ** *** * * * ** *** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * **** ***
* ** * * ** *** * ** * * ****
* * *** * **** ** ***** ** if(D>0)
** * *** **** ** * ***
** ** * * * ****** * = -b/(2*a);
* ** * ********* = (-b + ** * *
** ** *** ***** * * * * = (-b - * *** *
* ** ** *** ** * * ** * * ** * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * * *** *
** * * ***** * *** * ** ** *
**** ** * **** * 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** * **
#include * * * **
int main()
{
** ** *** * ** * * * a,b,c;
*** * * *** * * ** * * * *** *** ** * * * * ** * *** *
** * * * * *****
* ** * ** *** * ** **** ** ** **
* **** ** ** ** * ***
* * *** *** *** ** * * * * * * * * ** * ** * **** * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * * * * *** + ** ** **** * - * * ** *
*** ** * * * ***** *
******** * * * *******
**** ** * * * * * ** if (b*b-4*a*c==0)
** * * *** * ***** * **
* *** ** * *** ** **** ** * ***** ** ** * **** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** * **** * * * + ** ***** *
***** *** * ** * *
*** * * *** **** **
* * **** * * * * * **
*** ** ***** ** ***
** * ** * * ** **** ** ** ** * ** * *** **** **** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * ** * * ** * * ** ****** * *** * * * * *
* * ** ** * * *
* *** * * * * * *** ** * ** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * * * *
#include **** *
int main()
{
*** *** *** * * ** a,b,c;
* ** * * ** * * ** ** ** ***** ** * *** * * * ** * * ******
* * * * * **** * *
*** * * * * ** ** ******** **
** * *** * ** ** ***
* * * * * * *** ****** ******* ** ** *** * * * * * * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ******* *** + * ***** ** - * * * ** ***
* * * * ** ** **
* ** * * ** * **** * ******
*** *** * * * ** * * * * * if (b*b-4*a*c==0)
* * * * *
** * *** * * *** *** *** **** * **** * * * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * ** * ** * + ** ***** * * *
* ** * *** ** * * * **
* * ** ** *** * *** *** **
* * ** * ******* ** * * **
* ** ** * ** ** * *
** **** * * * * ***** * * * * *** ** * * ******* * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= * *** ** ****** ** * * ** * * * * * * ** ** ****
* ** * ****** * *** ***
* *** * *** ****** ** * * * * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
** **** ** * ** *** a,b,c,d,x1,x2;
**** * * ** ** ** ****** * * * ** * **** *** **
* **** **** ** **** * ** **
** * **** * * * * * * * **** *
******** * * ** *** * *** * * * **
* * ** * * * ** ** ** *
* *** *** * *** * **
** ** ** * **** * ** **** * * ** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and ** **** * * * * **
** ** ** ** *** * ** ** * * ** ** * ***** *** * ** = %.2f\n",x1);
** **** * * ** *** * * * * ** *** ** **** * * * = %.2f",x2);
* ** * *** * *** ***
*** **** ***** ** * * * if(d==0)
****** * * * *** **
** ** ** * * ** * ** * *** * * **** * * ** * ******* ** **** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
*** * * *** * *** *** * ** **** ** ** * ** * *** ** * **** = x2 = %.2f",x1);
* * ** ******* **
* ** *** * * * **** ** ** *
* * *** * *** * ** *
** * ** * * ** * * * ** * **** **** * *** * *** ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and *** * * ** * *
* * *** * ** *** ** * * * ** ** *** * * * * * * = * * * *** **** * ** * **
* * *** * * * * * * * ** ** * * * ***** ** * * **** * * = * ** *** * * * ** *
*** * * * ** * **** **
* * * * * **** * *** ****** 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
* * * * * * ** ** **** *** * ******* * * * * *** ** **** * aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
* * ** * ****** * ***** *** * ** ** * - (4*a*c);
** * *** ** * ** ** * * ** * * *** ***** ** * * ****
***** **** *** * * **** * * * * * * ** ** * ** ** * * **** * * **
* * * * * ** *** * * ** * ******* * * ** * * **** * * ***** (-b+spD)/(2*a);
* ** *** **** * * *** * * * ** * ** * *** (-b-spD)/(2*a);
* ** *** ****** * *** * ** * * * * *** ** ** * * * * ** ** ** ** *** (x1==x2){
* ** **** **** ***** **** **** *** *** * * ** * **** * * * *** * * * * *** * * ***** * *** *** *** *** ** ** * * *** * X=%d\n", x1);
*** * ** * * ** * * * *** * * ****** ** ** * * * * * ** *
******* ***** * * * *** * * * ** * *** * * ** * *** * * {
** * * * ** ******* * ** ** ** ** * ** *** **** ** *** * **** * * * ** * **** ** * ** * *** *** * * * * ****** * **** * X=%d或%d\n", x1, x2);
***** * ** *** ** * * ** * * **** ** * * ** * *** **** * * * * **
        }
* * ***** * * * * **** *** if(D==0){
* ** * * *** ******** ** *** * * ** **** ** * * ***** * ******** ** (-b)/(2*a);
* * * * ** * * * ** ***** * ** ** ** * * * *** ** * * *** *** * **
*** *** ******* * * * ** * * * *** * ** * ** * ***** * *** ***** ** ***** *** *** * *** *** ** X=0");
* * * ** * * * *** * ** * ** * * * * ****** **** * ** *
** ** ** *** * * ** **** ** ** * * * * ** * *****
* ***** * * **** ** * ** * ** * **** ** *** * ** * ***** ** ** *** *** * * ** * *** ***** ** * * * ** X=%d\n", x1);
* * * ** ** * *** * ** ** *** ** *** ** ** * ***** ** * * *
        }
*** *** ****** * ** ** * * *** ****** ** * *** * * *
* * * * ** * **** ** *** ** * * *** ** **** * * *** ****** * * * * ** **** * * * * ******
*** ***** *** * *** *** ** * ****
    }
* **** ** * ** ** ** ** **** ** * * * * * * * * ** *
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
* *** *** * * ** * ** a,b,c,D;
* ** **** ** ** * ** x1,x2;
* ** * **** ** ** *** ******* %d * * ** *** * * * * **

**** * * * **** * * * *****
* * * * ** ** ** *** * ** ** * ***
* *** * * *** ***** * *

** * * ***** * ** ** * * A,B,C;
* *** * ** ***** *** * ** * *

* ** * * **** * * * * *** * * *
*** ** ** * * ** * * * * * *** *** * * * of %.2fx^2 + %.2fx + %.2f = 0  are real and * * * * * ***
** ** ** **** ** ** ** ** ***** * * * * * ** * **** = %.2f\n",x1);
* * **** * ** * * * ** ** * **** **** * * * * * ** ** = %.2f",x2);}

* * * * * * ** * ***** if(D==0)
** * ** * ***** * * * * * **** *** * ** * ** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
*** * * ** *** * * **** *** * ** ** * ** ** * ** * ** *** = x2 = %.2f",x1);}

******* ** *** **** if(D<0)
* *** ** * ** ** ** * * ***** ** * **** *** * **** of %.2fx^2 + %.2fx + %.2f = 0  are complex and ** ** *** ** ***
** * * * *** * * * *** * *** * * ** * **** bb,d,dd;
* ***** * * * * * ***** * * * * ** ******* ** **** ** *
* * * ** ** * *** * * *** * **** ** * * *** ****
**** * * ** * * * ** *** *** * ** ** ********* * * ** ** *** ******** = * ** ***** *
**** *** * ** *** * ** ** * ** ** * * * * * *** * = *** * *

* ** * * **** * ** 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* *** * **
int main()
{
* *** * * ******* * * ** *** ** ** * * * *
*** * * ** * *** * ** ** %f ** ** ** ** * *** * ** *
* * **** * * * ** * * = (b*b-4*a*c);
*** *** ** * ***** * * ** *** = (-b + sqrt(D))/(2*a);
* ***** * ** * ******* ** = (-b - sqrt(D))/(2*a);
****** * * **** ** * * * = -b/(2*a);
* * * * * * * *** * **** * *** =sqrt(-D)/(2*a);
* * *** ***** * ** *** * * * **
**** * * *** * * ** * * *
***** ***** ****** * * * * **** * **** * ** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and **** ***** * *
* ** ** * * **** **** **** * ** **** * ** * * * ** *** * = %.2f\nx2 = %.2f",x1,x2);
* * ** * * * *

** ** * *** * ** * ** * if(D==0)
** ** * **** *** * *
* * ******* * ** * *** * ** ** *** * * ** * * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
*** ** * * * ** * * * * * * * * * * * * * * *** *** = x2 = %.2f",x1);
* * * * * * *
** ** *** * * **** ** **
* ***** * * ** ***
*** * * ****** ** ** * *** * ***** * * ** ** ***** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * *** * * * ***
* * * * * ** * ****** * ** * ** ** ********* * ** *** ** * = * ******* * ***
**** * * * * ** ** * ** ** *** * ** * * * **** * = ** ** ** *** * * * **
* * ***** ********
* * ** * ** * ****** * * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
******** * * *
int main()
{
* ** *** * * *** *** *** * **** * ** * *** * ***
* *** ** ** ** ***** ** * %f *** * *** ** * **** * **
* ***** ** ** = (b*b-4*a*c);
** ** ** * * = (-b + sqrt(D))/(2*a);
*** ******** * * * * * = (-b - sqrt(D))/(2*a);
* *** ** *** ** ** = -b/(2*a);
** * * *** ** ****** **** * ** =sqrt(-D)/(2*a);
** * *** * *** * * ** *
* * **** ** * * **** ***
* ** * *** ** * * * ** * * * **** ** ** * ** * *** ***** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** ****** ** * **
*** **** ** * *** * ** *** * * *** * ** ***** * * = %.2f\nx2 = %.2f",x1,x2);
* *** *** * * *** * *** *

**** ** * *** * * *** * ** * if(D==0)
***** * ** ** **** * * ** **
* ** * * ** * * * * * * **** **** * ****** ** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** * ** ** * ** ** * * * ** * ** *** ** * * = x2 = %.2f",x1);
** * ** * *** **
* *** ********* * ***
*** ** * ** *****
* ** * *** ** *** * ** **** * ** **** *** ** *** ** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and *** **** ****
* * *** * *** ****** * ***** ******* ** ** *** * *** * = * * ** ** ** ** ***
** * **** * ** * * **** ** * **** ** * *** * ** ** = **** * ** * * ** *** * ** *
* * * * * * * ** **
* ****** * **** ** ** * * * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.6.166
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users