0 like 1 dislike
19.7k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 19.7k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
** ******* * * * ***
int main()
{
* * * * *** * ** * * * ** * *** * ** *
* *** * * * ** *** * *** ** %f ** * ** * * * *** * *
*** *** *** *** * ** = (b*b-4*a*c);
* * * * * * * ** ** = (-b + sqrt(D))/(2*a);
* ** *** * ** * ** ** = (-b - sqrt(D))/(2*a);
* * * ** * ****** ** * * = -b/(2*a);
** *** * ** ** *** * * =sqrt(-D)/(2*a);
* * ** ***** ** *** * * **
* * * *** ** **** **
** ** *** *** * * *** ** ** * * ** * * * * *** *** ***** * of %.2fx^2 + %.2fx + %.2f = 0 are real and * * * * **
* *** ** ** ***** ** ******* * * * ** ** ** ** ** = %.2f\nx2 = %.2f",x1,x2);
* ** ** *** * * * *

**** ** * ** ** ** * * * * if(D==0)
* ** * * * *** **
* ** ** * **** *** ** *** ** **** ** * ** * * * * ******** ******* * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
*** ****** *** * *** **** * * * **** * ** ** * * ***** * *** = x2 = %.2f",x1);
* **** ** * *** * * ** * * *
* **** * * ** * *
** * ** * * **** ** **
** ** * ******* *** ** * * * * ***** *** ** ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and *** *** ** *
* * * **** *** * * ** * * * * * ***** ** ** **** ****** = *** ** **** ****** *
** *** **** * * * ** ** **** * * **** ** * * * = *** ** ** **** * *** **
**** * *** * **** ** * ** *
** * * * * ** * ** * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include *** *** * *

int main()
{
* * ** * *** * ** n, i;

* ** ** * *** * * ** * ** * &n);

* * ** ***** * * = 1; i <= n; ++i)
* * ** * ********
*** * * * ** *** **** * *** * * ** * * % i == 0)
* ** * *** * * * * * * * *** ** *** * * * ** ** * *** * ** * **** ** ** ", i);
* ** * * ** *** * ****

**** **** * ** * * * * 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * ********* **
** * * * ****

int main()
{
********** ********* * ** * ** * ***
* ** *** * * ** *** ** ** * ** * * *** * *** * *
**** **** * *** **** *** = ** **
* **** * * * *** **** *
** **** * * ****
* ** ** ** ** **** *** ** *** ***
** ** *** ** ******* ** = -b /(2*a);
* ** * ** * ** ** * *** ** * ** * *** *
* * **** ** ** * * * ** = (-b)/(2*a);
* ** ** *** ** *** *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * *** ** * ***** ***
* * ** ****** * ** * *
****** * * **** *** * if(D==0)
** * * * * *
****** *** *** = (-b + ** *****
* * * * ****** * ** ** = (-b - * * * **
* **** * * ** **** ** * * **** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** ** ***
* * *** **** ** * ***
* ** ** * *** * * if(D>0)
** ***** * ** **** * * **
* * **** *** * * * = -b/(2*a);
*** *** ** * * ** ** ** ***** = (-b + ****
** * * ** * * * = (-b - ** **
* * * ******* ***** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = *** * *********
** * * * ** *** *** *
* *** * * * *** *** ** 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** ** *****
#include ** * *
int main()
{
** * * * ****** *** ** * a,b,c;
*** * * * * *** *** ***** * *** ********* ** * * * * *
* ** * ** * **** *** *****
* * ** ***** * ******** **** * *****
* * * * ** ** **
* **** * ** * * * * * **** *** ****** *** *** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ** * * ** * + **** *** * - * ** ** * * ****
* ****** * ** * **
** *** **** * ** * ********
* * * ****** * * *** * * if (b*b-4*a*c==0)
* *** ** * *** *
*** ** *** **** * ***** * *** *** *** * * * *** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ****** * ** + * ** * * ** *
* * * * * * * * * *
* * * ** * *** *
* * * * ** * ** * *
* * * * ***
***** ** *** **** * * * **** ******* * * * ** * * *** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = *** ***** ** * **** ** * ** * ** * * ** *
* * ******** ** *** ***** *
* **** * *** * ***** *** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** ****** *** *
#include ** * * ****
int main()
{
* * ** * * * * ***** * a,b,c;
* * * ** * ** **** * * ** ** *** ** * ** **** *
* ** * * **
** ** ***** ***** ***** * * *
** *** * * * **** *
*** ** * ** * **** * * ** ** * ** ** **** * ** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * * * * * + *** **** * * - * * ** ***
** * * * *** ** **** *
** * *** ** * *** ****
** * ** *** * * * ** ** *** if (b*b-4*a*c==0)
** **** **** * *******
**** *** ** * * * * ** ***** * * *** ** * ** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** ** ***** ** + ** ** * * *
* * *** **** * *** **
** * * * ** * * * ** *
* *** *** *** * *** *
* * * * *** *** * * *
*** * ** * * ** *** ** * * * ** * * * *** **** * ***** *** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= * * * * **** *** * * * * * * * ** * ** * * ****
** * ** * * * ** * * *
*** * * * ****** *** * ** ** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
*** * * ** ** * * **** a,b,c,d,x1,x2;
** * *** * * * ** **** * * ** * ********* *** * ** ***
* * * *** ******* **** ** * ***
* * ** *** * *** * * ** * *
* ** * *** *** *** * * ** * * * ******
****** * *** *** ******** ** **
** * * * * * * * * * *
*** * * * * ** **** *** * * * ** * ** ** * ** * **** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * * *** * *
****** ** * ****** * ******** ***** ***** * *** * * = %.2f\n",x1);
* * ******** * *** * * * * * * * * * * * ** ** * ** * ***** * = %.2f",x2);
* * *** * * *** * ****
** ** ****** * ** ** * * if(d==0)
* * * ** * * ** * *
** * ** * ** * ****** *** ************* ** * ** * *** *** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
**** * * * **** ** ** * **** * * * *** **** * ** ***** * ** * = x2 = %.2f",x1);
******* * * *** *
*** * ** * * *****
* * **** * * ** * * ** *
* ***** * * *** * *** *** * *** * *** *** *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * ****** ** * * *
** * * * ** *** * ** * * * * ** ** ***** * ** *** = * * *** * ***
* ** * * * * *** * *** * ** ** ** ** * * * * **** ** = ** * *** * * ** **
** * * * *** *
****** * ***** * * * * 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
* * **** ** ** * ** ** ***** ***** * ** * ***** aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
***** * * * * ** **** ** * * ** * **** ** ** - (4*a*c);
* **** * * * * *** * ** ** * * *** ***** * * * **
* * ** ** **** * *** ** * * ** **** ** * ** ****** * ** ***** * * * *
*** ****** ** ***** *** * * ** * * * ** ** *** **** * ** (-b+spD)/(2*a);
** * ** ***** * **** * * *** * * ** ** * * * *** ** (-b-spD)/(2*a);
* ***** *** **** **** *** * ** * * *** ***** *** *** * * (x1==x2){
** * ***** * * * * ** *** * *** * * * * ** *** ******* * *** * * * **** * **** * * * ** ** *** * * *** ***** *** ** * ** X=%d\n", x1);
* ** * * * ** *** * * *** * * ** *** ** *** *** ** * **
******* * * * * ** ****** *** *** * ***** * ***** ** * ** * ** * ****** * {
** ** * ** ** * * * * * ** * *** * ** ** ** * ** * ** ** ** **** ** ** * ********* * * *** ** ** * ****** * * * X=%d或%d\n", x1, x2);
** * *** ** ** * * * * * * **** * ** * * * ** * * * ** * ** ** *
        }
* * ** * * * * ** ******* * * ** * ** * * * if(D==0){
* ***** ** * * * * *** *** ***** * * ***** * ** *** * ** * * * * (-b)/(2*a);
* ** * ** * ** *** * ** ** * ** * * *** * * *** *
*** * ** * * * *** * * ** * * * * ** * ** ******** * ** ***** * *** ** ** * ** * X=0");
** ***** * * * ***** * ** **** *** *** ***** *** ** * ** * **
* **** * ** * * ** * ** * * ** **** * ** *** * * ** * ** ** *** *** **
*** ** ** * * ** * * * * *** * * * * ** ***** ******** **** * ** * **** ** ** * ** * ** ** ** * X=%d\n", x1);
** * *** * * * *** ** ********* ** * * ** ** ** ** ** **** *****
        }
* * * * * *** ** *** * * *** ** ****
*** *** * * *** * * *** ** * **** * * ** * ** ** * *** *** **** * * ***** **** ** ** ** *** **** * * **
**** * *** * *** * * * * ***** ** * ****
    }
** * * *** * **** * * ** *** *** * * * ** * ****
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
** *** *** * *** * ** a,b,c,D;
*** * * * * *** x1,x2;
*** * ** * * ** * * *** * * * * * %d *** ** * *** **** *

*** ** ** ** ** * * ** * ** *
******* ****** *** ***** * * * * ** **
*** * ******** * * ** * * ** * * * *

** ** * * * * * * * A,B,C;
** * *** ** * * *** * ** * * ***

* * * * * * ** * ** * * * ****
** **** * ** *** * * * * ** * *** * ** of %.2fx^2 + %.2fx + %.2f = 0  are real and ** * * * * **
** * *** * ** ** ** * ** **** ** ** ** ***** * * = %.2f\n",x1);
** ** ** ** * *** ** * *** * ** ** * * * * * * * * = %.2f",x2);}

* * * ** ** *** *** ** if(D==0)
* *********** * ** *** * ** ** * * * * *** ** ** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
** * * ** * *** **** * ** **** *** ** ***** ** *** * * * ** = x2 = %.2f",x1);}

* * * ****** **** * ** ** if(D<0)
** ** ** ** * ***** **** *** * ** ** ** * *** * ** ** of %.2fx^2 + %.2fx + %.2f = 0  are complex and * **** ** * *
*** *** **** ****** ********* * * * ***** ** **** * * ** * bb,d,dd;
* ** *** * * * * * ** ** * * * * ***** * ** *
* **** * ***** **** * * * **** **** * * **** ** * ****
** **** *** ** * * * * * * * ******* *** * ** **** * = *** * ***
* *** * ****** *** ***** * ** *** ** *** ** ** *** ** * ** = * **** ** ** *

*** ******* * * ** * ** ** 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* * *** * * * *** **
int main()
{
* * ** ** ** *** * * * * **** * * ** * ***
* **** * * * ******** ** ** * *** %f ** * ** *** * * * ** * *
* *** * * * ***** * = (b*b-4*a*c);
* * *** * * *** *** = (-b + sqrt(D))/(2*a);
*** * *** ** ***** *** * = (-b - sqrt(D))/(2*a);
** *** * * ** ** = -b/(2*a);
* ******** *** *** * * * =sqrt(-D)/(2*a);
* ** *** ** * * * * * ***
* ** ** * * * **** **
* ** * **** ** ** **** ** * * * *** ** ** * *** * * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and * *** * ** **
**** * *** * * **** ** ** * * * * **** = %.2f\nx2 = %.2f",x1,x2);
* ** * * *** * ** * * * *

*** * ** ** ** **** *** if(D==0)
* *** * * ** * * * * *
** ****** * **** *** * ** *** * ****** *** ** *** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* *** * * ** * * * * * * *** ** *** **** * ** = x2 = %.2f",x1);
* * *** ******* *****
*** *** ** *** *** * * *
* * *** * ****
** *** * * * ** **** * * *** ** * * *** * * * *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * ** **
* ** * * ** * * **** ******** ** ** * * **** *** = * ** * ** * * * * ***** *
* * * * ** * *** * ** * * ** * ** * ** *** * * ** * = ** ***** * * * * ** *
* *** *** * * * **
*** * *** * *** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* * **** ***
int main()
{
* * ******* * * ** ** * *** ** * ** *
**** ** * ** ****** ** ******** * *** %f **** * ******* *** ***** *
*** * ** ** * * *** * = (b*b-4*a*c);
* * * **** * * * * = (-b + sqrt(D))/(2*a);
*** * * ** * * * **** ** = (-b - sqrt(D))/(2*a);
** *** * * ******** ** = -b/(2*a);
* **** *** ***** * * ** *** * * =sqrt(-D)/(2*a);
*** * * * * ****** **** * ****
* * * ** * ** ****** ** * * *
*** **** * *** *** * * ** ** * * * **** * of %.2fx^2 + %.2fx + %.2f = 0 are real and ******* ** *** **
* ** ****** * *** ** * * ** **** ** * * ** ** ** * * = %.2f\nx2 = %.2f",x1,x2);
* * ****** * * *

* * * * ** ** * ** ** ** if(D==0)
** ** ***** * **
* * * * * * * * *** * * * * **** *** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ** *** * ** * *** *** * * * *********** *** = x2 = %.2f",x1);
***** * * ** * * * * * **
******* ** ** ***** ** ** *****
* ***** *** * ** ***
*** * * *** * * *** * ** **** * * * *** * * *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * * ***** *
* *** * ** * * * * **** ** * * * * * * * * = ** * ****** * ** ******
** * ** * * * * ** ** ** ** * * ** ** * ** = * ** **** **** * ** *
* ***** *** ** ** *
* * *** ** ** * ** ** **** ** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.108
©2016-2026

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users