0 like 1 dislike
8.6k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 8.6k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
* *** * * * ** *
int main()
{
* ** * ** ** * * * * * * ** * * ** * * **
* **** * * * ** ** * **** * ** %f *** ** *** * **** *****
** ** * ** * * *** * *** ** = (b*b-4*a*c);
* * * ** * ** ** = (-b + sqrt(D))/(2*a);
** * ** ** **** ** ** * = (-b - sqrt(D))/(2*a);
** ** * ** * ** ** ** = -b/(2*a);
* ** * ** ** * * *** * ** =sqrt(-D)/(2*a);
* **** * * * **** ** ** * ****
* * ** * * ** * * * **
**** * * ** * * * * * * * * * ** ** * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** ** * * * *****
* *** * * ****** * **** ** ** **** * **** **** * ******* = %.2f\nx2 = %.2f",x1,x2);
* * * **** * ** * ******* *** *

***** * ** **** *** * ** * if(D==0)
** * **** * ** ** ** *
**** ****** * ***** ** * ** * * * * **** * * ** * *** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* *** ** * ***** * * * *** ** * ** ** * ** * * ** ***** * = x2 = %.2f",x1);
* * * * ** ** *
*** ** * **** * ****** *
** ** * * * * * * ** *
******* * **** * **** ** * *** * ** ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** * *** * *** **
*** ** * * *** *** * ** * * * * * * ** **** = *** * ** ** *** **** *
* * * *** *** *** * ** * * * * ** *** * * ***** * * = * **** * * *** * ** *
* ** * * * ** *
* ** *** * *** * * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * **** ** ** **

int main()
{
** ** ** ****** * *** n, i;

* ** * ***** ** * * **** ** * **** * * * * &n);

*** ** ** *** ** = 1; i <= n; ++i)
* ** * ** *****
* ****** * * * ***** * *** * * ****** * * *** % i == 0)
** ****** * *** * * * *** * * *** * ** * * ****** * * ****** ** * ** *** ** * * ", i);
***** * ***** ** **** **

** * ** **** * * * * * 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** ******* ****
** * * * ****

int main()
{
* *** ** * **** *** ** * * *** * ***
* * ** ******* * **** ** ** * ** * ** * *** ***
** ** ***** ** ** * * * ** = * * *** *
* *** *** * * *** * * * *
*** ** **** * ** * *
***** *** * *** ******** * *** **
** * ** * * * ** = -b /(2*a);
* ***** * * ***** ********* * ***********
* ** ** * * ** ** ** *** = (-b)/(2*a);
** ** * * ***** * * ** * *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = ** ** * * * **
* * * ***** ****** ***
***** ** ** ***** ** ***** if(D==0)
* ** * ** * ** ********
**** * *** ** * * * * *** = (-b + **** * ***
* * ** * *** ** * ** ***** = (-b - *** *
**** * * **** * * **** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** * ***
*** * * * * ** * ** ** * *
* ***** * *** ** *** **** if(D>0)
* * ** ** * ** * * **
* *** * ** ** * ** * ** * * = -b/(2*a);
*** * ** **** * * * = (-b + ** *** * *
* *** *** *** * * ** * * = (-b - **
* ** * * * ****** *** ******* ***** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * ** **** * ** *
**** * *** *** ** * * *
** ** ****** ** * ****** ** *** 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** * * **
#include * * ** ** ** *
int main()
{
** ** ***** ** * * * * a,b,c;
** *** ** ** ** * * ** ** * * ** * * * *** ** * ** *
* * * ** * *********
** **** * ** * * ****** *** *****
** **** *
**** *** * * ** * *** ** ** ** ** *** * ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ** ****** * + *** ** ******** - * ** *** ** **
** *** ** * ** *
****** * * ** ** *** * *
** ***** * * ** ** * * if (b*b-4*a*c==0)
* * ** * * ** ** * * *
****** * * * * ************ ******* * ** *** *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * *** * * + ** * *
* * * * * * * * ****** *
* *** ** **** *** * *** **
* * * *** ***** * * *
*** * ** * ** ** ***
*** * * * * ** ***** * ** ****** *** *** ** * ******** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = **** * ***** ** * ** **** ** * ** * * ** * ***
** * ** ** *** *** ** *
****** * * **** **** * ** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * * *
#include * *** ***
int main()
{
** * ** ** ** * ** ** * a,b,c;
** * ** * ** *** ** * ***** * ** ** * ** *
***** **** * * *
* * * **** * ***** ***** * * ** * **
* *** * *** ** *** *
****** * **** ** *** * ****** ** ** * **** ** ***** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * *** + ** ** * *** - *** *** **
* ********* *** ** * ** *
* ****** *** * * *** * * * *
*** * * *** ** ** * * * if (b*b-4*a*c==0)
* ** ** *** ** * * *
** *** * * ** **** * * * * *** * * * * * * * * * **** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = **** ** ** ** + * * * ** *** *
* * **** * * * **** ****
** * *** * ** ** *
** **** **
* * ** * * *** ** **
** ** ** ***** * * * *** ** * ** *** **** ** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= * ** * * ** * ** * * * **** * * *** * ** ** * ** * *
* ** ** *** **** *
* ** * * *** *** * * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
* ** * ** * * a,b,c,d,x1,x2;
** * ** * **** *** ***** ** ** *** ** ***** * * * *** **** * ***
* * *** * ** * ** *** ** * *** **
* *** ** **** *** ** *** * * *
*** **** * * ** ** * ** * ****
*** * *** * *** * **** ** *
** *** * * * **** **
*** ** * * * ** * **** *** ** *** * ** *** ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and ******* * * ***
* * * * * * *** ** *** * * * ** * * ** ** *** * * = %.2f\n",x1);
*** * * * ** *** * * * * * * * * *** *** ** * ** * = %.2f",x2);
* ** *** ********* * ** **
* ***** * * * * ** * if(d==0)
**** *** ** *** * * * * *
** * * **** ** **** *** * ** **** **** * ** *** * * ** ****** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * ** ** * * * * * * *** ** ** * ** ***** * ***** ** * = x2 = %.2f",x1);
* **** **** * * ***
** ** * * * * ** * * * *
* *** * * *** * * * *
*** ** ** * ** ****** * * * *** * * **** *** ****** of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** * * ** ** ******
* *** * **** ** ** ** * ** ** * * ** * * * * * ** * = *** ** *** * * * * ***
* ** * * * ** ** * * * * * **** **** ** ** * = ** ***** * *** * *
** * **** **** * * ** * **
* * ** * * * * * ** * *** 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
* ** * * * ** * * ** * ** *** * ** * ** *** * * aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
*** ** ** **** * * ** * * * ** * * * ** * *** - (4*a*c);
* * ** ******** * ******* * ** * ** ** * *** * * ** * **
* * ** * *** ** * ** ** *** ** * *** *** ** * * ** ***** * *******
* * * * ** * * ** * ** * *** ** ** ** ** * ** * ** *** ** ** * (-b+spD)/(2*a);
** * * ** * ** ** * * * * * * *** **** * * ** ** *** **** ** (-b-spD)/(2*a);
* ** ** ***** ** *** ** *** * * *** * ** ***** * **** (x1==x2){
* *** *** * ** ***** ****** * ** * * ** * * ** ** * ** ***** ****** * * ***** ** ****** * * ***** ** * * * ***** * ** * ** X=%d\n", x1);
* ******** ** * * *** * * * ** * **** *** * **** ****** *
**** **** ** *** *** * * * ** ** ** * * *** * *** * ** ** * * *** ** * {
*** ** ** * * * * * * * *** *** * ***** ** ** * * ** * * * * **** ** *** * * * ******* * ** * **** X=%d或%d\n", x1, x2);
* * * * * *** * ** *** *** * * *** ** * * **** * *
        }
** * *** * * ** ** ** * *** * * * **** ******** if(D==0){
* ** * * * ** * * * *** * ** * *** ********** ***** *** ***** * * * ** * (-b)/(2*a);
*** ** * * * * * ** ** * * * * * ** * * * * * * * *
* * ** *** ** ** * **** * * * * ** ** * * **** * * *** * * ** ** * * *** * * * ** ** * *** ** X=0");
* ** * *** * * **** * ****** ** ** * * ****** * * * **** *
* ** ** * * ** * **** * ** * * * *** * ** ** **** ** * ***
* * ** ** *** ** * ****** *** *** * ** * * ** ** ** ** * ** ** * * ** *** *** * *** **** * * * *** * X=%d\n", x1);
** * **** **** *** * * * **** * * *** ** * * * * * ** *** ** *
        }
*** ** * **** ** ** **** ** * * *** * ***
** * ** * ** *** ****** * * *** ** * ** ** * **** * * * ** ** * * ******* * ** ****
***** *** ******** *** ******** * *** *****
    }
* ** **** * * * ** * * * **** **** ** ***** * * * **
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
* * *** * ****** * a,b,c,D;
* * ** * *** * * ** ** x1,x2;
* *** ***** * ** * ** *** ** * %d * * ****** * ** * * ***

*** * * * * ** ** * * * *
* *** *** ** * *** * * ** * **
**** * * ********* ** * **** **** * **

** * * *** ***** * * * ** A,B,C;
* *** *** ** * *** * **

* * ** *** * * * ** * * **
* *** * * ** *** * ** ** * ** * * * *** * ***** * of %.2fx^2 + %.2fx + %.2f = 0  are real and ** **** * *
* ** ** ** * ****** ** * * **** ** ****** ******* * * * * = %.2f\n",x1);
* * * * *** ****** * * ***** * ** * ** * ****** *** **** *** **** = %.2f",x2);}

* ** **** * *** ***** ** if(D==0)
** * **** * ** ** ** * * ** ***** ** * * *** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
**** *** ** * * * *** * *** ** * ** * **** * * ** ** ***** = x2 = %.2f",x1);}

* * **** * * ** * if(D<0)
* * * * ** * ** * *** **** ** ** * * ** ** * * of %.2fx^2 + %.2fx + %.2f = 0  are complex and *** ***** ** **
* **** * * * * * ****** * * *** ** * * * * * **** * * bb,d,dd;
* * ** * * * ** *** ****** ** * * ** * *** * ** * ** ***
** ** * * ** * * * **** * * * * ** ** * **** *** * ** *
* ** ** * * ** * ** * * * *** ** ** * * ** ** ** * * ** * = ** ** ***** *** *** *
** ** * ** ***** * * * * *** * * ** *** * ** * * * * ** * * * *** * * = ** * * *** *

* * * **** ** * * * *** * 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* *** * ** *
int main()
{
* * * ** * *** ** * *** * ***** * **** *** **
* ** * * ****** * ***** %f *** ** ** * *********
**** * * ** ** ** * = (b*b-4*a*c);
** ** * ******* * * = (-b + sqrt(D))/(2*a);
* *** *** * ** * * * * * = (-b - sqrt(D))/(2*a);
** * ** * *** ** *** * **** * ** = -b/(2*a);
* * * **** *** ** ****** * ** * =sqrt(-D)/(2*a);
* ** ** **** * * *
**** * * * * ***** ** **** *
** * ** * * *** * * * ** **** * * * * ** * ** ***** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and * **** * * ** ** **
** * * * ** * *** **** **** ***** ** * ** * * *** ** = %.2f\nx2 = %.2f",x1,x2);
* * * * ** ** * ** * **

*** ** * * ** * ****** ** if(D==0)
* * **** * * * * * ***
* ** * * ** *** * ** * * ** ** *** * * ** * * ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** * ** ** * * * * ** * *** ** * ** * * *** ** **** = x2 = %.2f",x1);
**** * * * * * **
* **** * * **** *** * *
* ******* * * * **
***** ** * *** * * * ** *** * ** ** * * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** ** * **
* * * * ** ** ** * *** * * * * * *** * ** * * * * = * **** ** ** ** ** ********
* ** ** ** * ** ***** ** * * * * * ******* **** * ** * = ** * ** * * ** * * ** * *
* * ** ** * * * **
** * * **** *** ********** * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* * **** * **
int main()
{
** ** ** * *** ***** *** *** *** **
* * * * ** ** * ** ** * ** * * %f * * * * * * * ** **
* * ****** ** * ** * = (b*b-4*a*c);
* * * * * ** * ** *** * * * = (-b + sqrt(D))/(2*a);
** **** * * * = (-b - sqrt(D))/(2*a);
* ** * ** * ** * ** = -b/(2*a);
* * *** ** * * * *** * =sqrt(-D)/(2*a);
** ****** ** ** * ** * *******
** *** *** *
* * * * * ** * *** * * ** ** * ** **** of %.2fx^2 + %.2fx + %.2f = 0 are real and * * * *****
** *** * ** ** *** *** ** * * * ** * * * *** * = %.2f\nx2 = %.2f",x1,x2);
* ** * * * * **

***** ** ** ** * * *** if(D==0)
** * * * * * ** *
* *** ** ** **** * *** *** ***** ** **** ** *** * * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
*** ******* ** **** **** **** * * * **** * **** * * ** * = x2 = %.2f",x1);
* ****** * ** ***** * * *
*** *** **** **** * ** * *** *
* ** * * * * * **
** * ** * ** *** * *** ** * ** ** * ***** **** * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and **** * * ** * *
* * * *** ** * ** * *** ** ** * ** *** ** * * * ** * * * = ***** * * * ***** **
****** *** **** *** ** **** *** ** * * ** * ** ** *** * = * * * ***** * * * **
** * * ** ** * * * *** *
* ***** ** ** * ** ** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.1.149
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users