0 like 1 dislike
12.1k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 12.1k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
**** ** *
int main()
{
*** ** ** ** * ** * *** * ** *** *
*** * * * *** * * ** ***** * *** %f * * * ***** * ** ** * *
** * ** ** * ** * = (b*b-4*a*c);
**** **** **** *** * = (-b + sqrt(D))/(2*a);
** ***** * * *** * = (-b - sqrt(D))/(2*a);
*** ** *** **** ** *** = -b/(2*a);
* * * *** *** **** ** * =sqrt(-D)/(2*a);
***** * * * ** *** *****
*** *** *** * * * * ****
* ** ** ** ** ** * * ** ** * * * * *** ** * * *** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and *** ** * *** *
**** * *** * ** * * * ** * * * * * ** ***** * = %.2f\nx2 = %.2f",x1,x2);
* *** *** ** * ** * *** **

* ** *** ** *** * * if(D==0)
*** * ** * ** *
** * * *** ** ** * * * *** * **** ** * ** **** ***** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
*** *** * ** **** * * * * * ** ** ** *** = x2 = %.2f",x1);
* ** * * * * * * **
* * ****** *** * * *
* * ** ****** ** * ***
*** * * * * ** ******* * ***** * ** * **** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and *** ** ** * * **
* ** ** **** * * ** * ** * * ** *** *** ** ** * = ** * ** ** ***** * * *
* **** * * ** * ** *** * * *** * * * * * **** = * ** ** *** * ** ** *
*** ** * **** *
*** * * *** * ** *** * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include *** **

int main()
{
** ** * ** ** * * n, i;

** * ** *** * * ** ** * **** ** ** * &n);

* * * ** * ** *** = 1; i <= n; ++i)
* * ** ** * *** * ***
**** * * * *** * **** ** * **** **** *** * * % i == 0)
******* * *** * * * * ** ** * * ** ****** ** * * * * *** * * ** ***** * * ", i);
*** *** * ** ***

**** *** * * **** * *** * 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* ****** ** **
****** * *** **

int main()
{
* * **** * * * * *** ** ** * * * * * **
*** *** **** * * ** * **** * ** ** ** ** * * * * ** * * *
*** *** *** ** ** * ** = * * ** *
* * *** * ** * *
** * * ** * **
* ***** * * ******** **** * **
* *** * * * ** = -b /(2*a);
** * * *** * ** * *** ** * * ** ** **
*** ***** ** * * ** = (-b)/(2*a);
*** ** * ***** * * ** * ***** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = ** *** ** * ***
* * * * *** * **
*** * * *** ** *** * if(D==0)
** *** * * ** **
** * * ** ****** **** * *** = (-b + * **
**** **** * ** *** ** = (-b - ** *** *
*** * * *** * * * * **** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * ** * **
** * * * * ** * *
** ** * * ** ** * * * if(D>0)
* ***** * ** ** * **
*** * **** * **** * ** ** = -b/(2*a);
* * * * * ******** = (-b + *** ****
* * * * * ** ** ** * = (-b - * * *
* *** * * *** ********** * * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ** ** * * **
* ******** * ** *** *
** ****** * ** ** * 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** * ** * **
#include * ** * *** *
int main()
{
* * *** **** ** * a,b,c;
* **** *** * **** * *** * * * *** * *** ** ******** * ** ***
* ** * ** **** * ** * ***
* * * ** ** * *** ** ** *** *
** *** * * * * * *
** ** * *** *** ******** * *** ** * ** * ** ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ** * ** ** * + ** *** * ** * ** * - * * **
** * * * **** **
* * ** **** * * ***
* * ** *** ** ** * ** ** if (b*b-4*a*c==0)
* * ** * * * * *
* **** * *** * ** * ** ** * *** ** ** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * ** ****** ** + * * * *** **
* *** ***** **** * ** **
* * *** ** **** **
**** * * * * *** * **
** ** * ** *
** * ** ** ** * **** *** * *** ** ** ** *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * *** *** * ** * ***** *** *** *** *
* ** *** ******* **
**** ** *** ** * ***** *** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ****** *
#include * ***** * * * *
int main()
{
* * * * ** ** * ** ** **** a,b,c;
** ** * *** ** *** ** *** ** * * * **** * * * * **
**** *** * * * *** ***
* * * * * * ** ** *** *** ** ** * *
* ** * ******** * *
*** ** ** **** ** * *** ** * * ** * ** ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ** * *** ** * * + * * ** * ** - ** * ** * *
***** * ** * * * *
* ** * * ** *** * **** *
** ** ** ** * * * * if (b*b-4*a*c==0)
** * **** ** ****** * **
* * ***** ** *** ***** * * * ** * *** ** *** * * ** * **** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * * * * + * *** * *
**** ** * ** * ** *
* * * * * * * * *
* ****** * *** **** *
*** * ** * * * ** *
** * * * ***** ********** ** ******** ** * ** *** * *** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= * ** ** **** ** ***** * * ** * * * *** ** **
** * ** * ** ** ** ** ***
* * * *** *** * ***** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
* * *** ******* * * *** *** ** a,b,c,d,x1,x2;
**** * * * ** * ** ** **** * * * ** ** * ** * * *
*** *** ***** ****
** ** * * * * * * ** * * **** *
* * * ** **** ** ***** * * *
*** * **** * * *** *** ** *
********* * ** * * ** *
** * ** * * * * **** * ** * ** * *** *** **** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and **** ** **
* * ** ** *** * * *** * * ** ** * = %.2f\n",x1);
* ** * * *** * ** * * **** *** * *** ** ******** *** = %.2f",x2);
* * * * * * * ** * ***
* *** * **** ** *** * if(d==0)
** *** * * ** * **
* * * * * ** * * ** ** * * ** * * *** * ****** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ** * * ** ******* *** ** * * *** * ** ***** * ** * ***** = x2 = %.2f",x1);
* *** * **** * * ***
* * * ** **** ** * **
** *** * * **** * * *
** * *** ** * * *** * **** ** * * * * * ** ****** of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** * **** *****
**** *** * * ** **** **** * ** * * * * * * = * * ** * * * *** *
** ** **** ***** ** ** ** * ** ** *** ** ** * * ** * ** * = * * * ** ** *** ***
* * ** * ** * ***** * ****
* ** *** ** * * * * * * 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
** ** * *** ** * * ** * **** *** ** **** * ** ** ** * ** ** aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
* ** * ** ** ** * * ** * ** **** **** * - (4*a*c);
******* ***** * * ** ** * **** ** * * ** ** * ****
*** ** * * * * *** *** *** * ** ** * ** * * * ** * * ** ** ** *** * * *
** * * **** *** * *** ***** * ** ** * * ** * ** ** ***** **** ** (-b+spD)/(2*a);
***** ** ** *** *** ** ** * ** *** ******** * * ** * * * *** *** * (-b-spD)/(2*a);
** ** * * ** ** *** ** * ** ** ** ** *** * * *** * * ** * * (x1==x2){
** ** * ** * ** * * * * * ***** **** * * *** * ** * * * *** ** ** ** * * ** ****** **** ** ** * * *** ** * * **** X=%d\n", x1);
* * *** *** *** ** * *** * * * ** ** * * * * ** ** ** ******* *
* * * ** ** * * * * * * ** * ** ** * ** * * ** *** * ** * {
* * * * *** *** * ** ** * * ** * ***** ** * * * * * * * * * * * *** * ****** ** ** * * ***** * * ** * ** * X=%d或%d\n", x1, x2);
** **** * ** ***** ** * ** ** * * * *** * ** * * * ** * **
        }
*** ** **** * **** * ** * ****** ** *** *** * * * if(D==0){
**** * * * ** * *** ** * *** ** ** * ** * * *** (-b)/(2*a);
* * **** * * * * ** * * * ** *** ** * * ****** **
** * * ** * ****** ** ** * * ** *** * * * * * ** **** * *** * * * ** ** * *** * * X=0");
*** * * * * ** * * *** ** * *** * ** *** **** ** *** * * *** * *
* *** ** * *** * * * * * ** * **** * ** * ***** *** ** * * *
* ***** **** * * * **** ********* * ** ** * * ** ***** ** ** * ** * **** *** *** * * X=%d\n", x1);
**** *** * ** * ** ** * ** ** ** * * *** ** **** * * * * * ***
        }
** * * ******* *** * * ** * ** **** * ** * * *
* ***** ** ** * * ** * ** ** * ***** *** * * ** **** * * *** ** * * **** * * * ** ** * *** ** *
* ** ** *** ** * * * **** *** * * ******** **
    }
* * * ********* ****** * ** *** ** * * **** * ******* ** * * * * **
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
* ** *** *** * * ** ****** a,b,c,D;
*** ** *** * * *** ** * * ** x1,x2;
* * * * ** ** **** * ** ******* %d ****** * * ** * * *** *

* * * ** ***** ** * * ** * *
* **** * * *** *** *** * ** **
*** * * ** * * * ** * * * ****

* * * * ** * * * A,B,C;
*** *** *** * * **** * *

** *** ** **** *
* * ** ***** ** ** * * * ** **** * ** * ** *** * * * of %.2fx^2 + %.2fx + %.2f = 0  are real and * * ** * **
** * * *** * ** ** *** * * *** * ****** * ** * *** *** * = %.2f\n",x1);
* ** *** *** * * ** *** * * ** *** * * * **** * * *** **** *** = %.2f",x2);}

* ** * * * ** *** *** ** ** if(D==0)
** * * * ** * ** * *** *** **** * * * *** * ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
* *** ** ***** *** *** * ** ****** **** *** **** **** * = x2 = %.2f",x1);}

**** * * * *** * * * ****** if(D<0)
* * * ** *** ** ** ** * ** ** ** * ** **** ** ** ** of %.2fx^2 + %.2fx + %.2f = 0  are complex and * * * *** ***
**** *** * * **** * * **** * * * * ** * * * * bb,d,dd;
* * * * *** ** ** * ** ** * * **** ****
* *** ** ** * ** ** * ** * * *** ** * * * * * ***
* ** ** * * ******** * * *** * *** ** * *** ** * * *** * = * * * * * ** *
** * * * **** ** * * **** * * * * ** ** * * * *** * = * * * * ** * **

** ** **** * ** ** * *** * 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* * ** *** * **
int main()
{
*** * ** * * ** ** * * * * * * * ** * ***
** * **** * ** * *** ** %f * * *** **** **** ** * * * *
* ***** * * * * * ** *** * = (b*b-4*a*c);
* ** ******** * * * * * = (-b + sqrt(D))/(2*a);
* * * * * * * * * * * = (-b - sqrt(D))/(2*a);
* *** * * *** * **** *** ** = -b/(2*a);
**** *** ** * ** ** *** * * * =sqrt(-D)/(2*a);
* * ** **** * * * **** * * **
** * * ** ***** ****** ** *
** ** * *** ** ******* * ** ** ** * ** *** ****** **** of %.2fx^2 + %.2fx + %.2f = 0 are real and *** * * ** * ***
** ***** * ** * ******* ****** * * ** * *** = %.2f\nx2 = %.2f",x1,x2);
** * * *** * * * *******

* * *** *** * * * ***** if(D==0)
* ** * *** ** * **
* * * ** ** * ** * ** ** * ** *** ** **** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
*** * *** ** ****** * * *** * * ** ** * ** * * = x2 = %.2f",x1);
* *** * * * ** *
* **** * * * ** ** ** *
* ** * * ** * * *
* * * * * * ** * * *** * * ** * * * * * * * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * ****** * **
* *** * ** * * * * * * *** * * *** ** * ** = ** ** **** * *** * ** ***
**** ** * * ** *** * ** * * ** **** * * ** * = *** *** * ** * *** ** *
** * ** ***** *** *** * **
* ** ** * * * * ***** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
****** **** * ** *
int main()
{
***** * * * *** * * * * ** * * ** * * ** *
** **** ** *** ** ** *** *** **** ** ** %f * ** * * *** * * *
** * ** * * *** = (b*b-4*a*c);
* * * ****** * * **** = (-b + sqrt(D))/(2*a);
** * *** ***** *** * ** *** ** = (-b - sqrt(D))/(2*a);
**** *** ** ** *** ** * * = -b/(2*a);
** *** *** **** * * *** ***** * =sqrt(-D)/(2*a);
* * ** * * ** * **
* * ** ** * *** ** *
*** **** ** * * ***** * * ***** * * * ** **** * **** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and * * *** * ** ** *
* * * ** * * * *** * **** ** * * *** * * * ****** = %.2f\nx2 = %.2f",x1,x2);
** *** * * ** * ** *** *

*** * * * *** *** *** *** if(D==0)
* ** ****** * * ***** *
* * *** **** * * ** *** * ** * **** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * * ****** * *** * * *** *** *** ***** *** = x2 = %.2f",x1);
* ** ****** **** *
*** * ** ****** ** * **
* *** * * ******
** ** * ******* *** * * * * ****** ** *** * * * * * * *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * **** *** ** * *
* * ** ** *** **** * * * ***** * * ** *** * = **** * * ** * * ** *
**** * * ** ** * * *** ** ** * * *** * * * *** = * ** *** * ****
*** ** **** ** * *
* * ***** * ******** * * *** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.58
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users