0 like 1 dislike
9.7k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 9.7k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
* **** * * * * *
int main()
{
* ** ** **** ***** * * * * * ** * *** * * ***** * *
**** *** ** **** * * ** ** * * ** * %f ** ** *** **** * ****
**** * *** * = (b*b-4*a*c);
* *** ** ** * ** = (-b + sqrt(D))/(2*a);
* ** ** * ******* **** = (-b - sqrt(D))/(2*a);
* *** ******** * ** * * * * ** = -b/(2*a);
**** * ** * ***** * * ***** =sqrt(-D)/(2*a);
*** * ** * * *** ** **** **
***** * * ** * * *
** **** **** * ** ** * * * * * ** * * *** ***** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and * * * **** *
* * * ** *** * * * * ***** * ** ***** **** * = %.2f\nx2 = %.2f",x1,x2);
*** ** **** *** * **

* *** ** * *** * *** if(D==0)
* ** * ** * * * **
***** *** ** * ** * * ** ***** ** * ** * *** *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** * ** * * * *** ** *** ** ** *** ** **** ** = x2 = %.2f",x1);
* * * *** * **** * *
** * * *** * **** * *
** ****** * * ** **
* * ** * ** * *** * ** ** *** ** ** * *** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * *** ***
** * * *** * * ** * ** ** *** ** * * ***** = * * * * ** * ** ** * ** *
* * **** *** ** ****** * ***** *** * *** ** ** * * * = ** * * * * *** * * * ** * * *
** * * *** ** ** *
*** * **** * * * * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * *********

int main()
{
** ** ** *** * ** n, i;

* ** * ** * * ** *** * *** &n);

** ** ****** * *** *** = 1; i <= n; ++i)
** ** ** *** **** * *** *
* ** ** * *** * * * * ** * * ** * * * % i == 0)
*** **** ** * *** ** * ** ** * * * **** **** *** * *** ** *** ** ** ", i);
* *** ** ** ** ** ** *

** * * ** ** * **** * 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
******* * *
* ** * ** ***** *

int main()
{
* * *** ** *** * * ** * * ** **
*** ** * ** **** ** *** ** ** *** ** **** *** ** *
****** * ** * * ** *** = * * ***
**** * * * * * ** *
* * ** ** * **** * **
* *** * *** * ** ** * * **
*** ***** *** ***** ** ** = -b /(2*a);
* **** *** * * * * ** **** * ** * ** **
** **** *** * * * *** = (-b)/(2*a);
****** ***** ** **** **** *** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * * **** ** ***** ** ** **
* ** * ** ** ** * **
* **** ** * * * * * if(D==0)
*** * * * * ** * *
***** *** * *** * * = (-b + * ***** ****
** ** * * * * * * *** = (-b - * ** *
* ** * ***** ** ** ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = **** *** *
*** *** * * ***
* ****** ** ** *** * * * if(D>0)
** * ** ** * * * *****
** ** * * * * * * ** * * = -b/(2*a);
* * **** * * * * * = (-b + * *** *
* * * ** * ** ** * ** = (-b - ** * * *
** ** * *** * ** * *** * ** * * **** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = *** * ***** *
*** *** ** ** * ***
**** * ** * ** **** ** ** 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** ***** ***
#include * * * * *
int main()
{
* ** * ** ** ** * *** *** * a,b,c;
* * ** * * ** * ** * * * * ** **** *** * *
**** * ** ** * ** *
* * **** * * * **** *********** *
* * ***** * ** * ***
*** * * * *** * * * ** * ****** * * *** ** * * ***** **** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = **** **** * ** ** + * * ** *** * * ** - ** * * * * ***
** * * * * *
* *** ** * ******
*** *** * ** * ** * if (b*b-4*a*c==0)
**** * ****** ** **
** ** ** ** * **** ** ** * * *** * ** ***** ***** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** **** ***** + ** * ** *
****** * * * ** * *
* ** ** * ****
** * **** ** * **** *
*** * ** ** ** * ** ** * **** *
*** * ** * * * * ** * * * * *** ** *** * *** ****** *** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = ** *** ** * **** ***** * * * * * *** ** * * ** **
*** * * * * * *** ** *
* ** * * * * * * * * * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ***** * **
#include * * ** *** *
int main()
{
* ** * * *** *** a,b,c;
*** * ** *** ** *** *** * ** *** * * * * * ***** *
**** * * *** *** *** ***
* * * * ** ** * ** ** *** * **
* * * ******* * ** * * **
* *** ** **** * * * * * * *** ****** * * * ** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ** ** ** * + * ** ** - ** ***
* * ** * ** *
* * ** * ** ***** **
* ** **** *** * ** if (b*b-4*a*c==0)
** * * ** * ** *** *
*** * ** * ** * **** * * ** *** * ** *** ****** * ****** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * ** ** * + ********
* * * * * ** * * *
****** *** *** * * * **
* * * * * * ** * ***
* ** **** ** * *
* **** **** * ****** * ** * * * ** * ** ** *** * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= *** * ** ** * * * * **** ** * ***** * *** ** *
* ** ** ** ** * *** **
* *** * * * *** *** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
* * * ** * ** ***** a,b,c,d,x1,x2;
***** * *** **** ** * * ** *** **** ** ** * * * ** **
** * * ** * *** * **
**** * * *** ** * * **** *** * ***
* * **** * * ** ** * * * ***
** *** * ******** * ** *
* ** *** * *** *
*** * ** *** * ** ****** ****** ** * ***** *** * * *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and * ** *** ** **
* * *** **** * ** *** *** * * * ***** ** * ***** * = %.2f\n",x1);
************* ** * **** * ** ** * ******** * ** * * * = %.2f",x2);
****** **** *** * ** *
* ** ** * * * * * * if(d==0)
*** ** * * *** *** **** ***
* * * * * * *** ** **** ** *** * *** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** * * * ** * *** * * *** * ******** * ** * ** * ** = x2 = %.2f",x1);
** * * * ** ****
* ** *** ** ****** * *
* * * ** ** *****
* ** ** * *** ** ** * * **** ***** **** * * * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and **** * ** * *
** ** ** ** ******** *** * * * ** **** * ** ** ** ** * * = ** **** ** ** * * ** ****
* *** *** * * * * * * ** * ** ** *** **** **** * **** = ** *** * ** ** * *** **
** *** ** * * * *** *
** * **** * * * * ** * ** 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
** * ***** * * * * ** * ** * *** * * ** *** *** aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
** ** ** * *** * * *** * ** ** ** * - (4*a*c);
* *** **** * * * * *** * ** * ** *** * ** * *
*** * ** * ** * * ********* * ** *** * * ** * ** * ********* *
* ** * * * * *** * * **** * * *** * * ***** *** ** ******* * (-b+spD)/(2*a);
* ***** * * *** ** * * **** * *** ** * ****** * ** ** * *** *** *** (-b-spD)/(2*a);
** *** * * * * **** *** * * *** **** ****** * * * * *** * * (x1==x2){
* ** * * ** * * * ** *** ** ** ** *** **** ** * ****** ** * ** ***** * *** **** ** ** * **** *** * * * * * * ** * * ** * X=%d\n", x1);
* * ** * * * * * ***** * ** * * * * * **** ** ** * * *****
** ** ****** ** * * *** ** ** ** * ** * ** * *** ** ** ** {
** * * **** * * *** * * ** * * * ** * * * * * *** ** * * * * * *** *** **** **** * **** * **** * * * * * * X=%d或%d\n", x1, x2);
*** * *** ** * ** * * *** * * **** * * * * *** * ***
        }
**** * ** * * ** **** * * * * * * **** if(D==0){
** ** ** **** * *** *** * * ** ** * ** * * ** * ** ** * *** * *** ** * ** (-b)/(2*a);
* * * * ** * *** * * **** ** ******* * * ** *** ** ****** * * ** * * * *
* ** * ******** ** ** ** ** ** *** * ** *** * ******** * * ** ******** ** ** * * * ** * *** * X=0");
* * ** * ****** **** * * * *** * ******* ** **** *** * ** ***
** * * * ** * * ** ** * * **** *** *** ** * ** * *** ** **
*** *** ****** * ** * ** * ** * *** * ***** *** * ** *** * * ** * * ** * *** * ** **** * X=%d\n", x1);
****** ** *** *** **** * * * **** * *** *** ** * *** **** * *** *
        }
** ********* * ** * * *** * * * *** * *
** **** * * * * * * * **** **** * **** * * ****** * ** *** * * ** ** * * **** ** * * * * * ***
* ****** ****** ** * * * ** * *** * * * ***** *** *
    }
* ** ** * * **** ** **** * *** * ** * * * * ** *
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
* * *** *** **** ** * *** * a,b,c,D;
** * * * *** ** *** * * * * * * * x1,x2;
* * ***** * * *** *** ** ** ** *** %d * *** * * *** **

**** * ** ****** *** *
* *** * * ** **** ** * ****** *** * * *
*** * * * ** ** * * * ** ** ** **** *

* * * * * ******** A,B,C;
* *** ** * * * ** * **

***** ** * * * * *
**** * * ** ***** ** * * ** ** ** * **** ** * ** * of %.2fx^2 + %.2fx + %.2f = 0  are real and **** ** ** * * **
* ** ** * * * ** ** ** * *** ** * * * ** * ** * **** = %.2f\n",x1);
* **** *** * ** ** * * *** ** ** * ** ** ** ** ** * ** = %.2f",x2);}

* * ** * **** **** * if(D==0)
**** * *** * * * ** ** * ** ** ** ** * * ** ** *** * ** * * * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
***** *** ** * ** * ** * * ** *** ****** ** * * *** * *** * ** * = x2 = %.2f",x1);}

** ** *** ** * if(D<0)
*** * * * ***** * * *** ** ** * ** ** * *** * * of %.2fx^2 + %.2fx + %.2f = 0  are complex and * *** * *** **
* ** ********* * * ** * *** ** ***** *** ** * * ** * * bb,d,dd;
** ** ***** *** ** *** * * ** * * ** ***** * *
* * * * * ** * * **** * * *** *** ** * * * * * **
* * *** ****** * *** * * * * *** * * * * ** * * * * ** * * = ** **** * ********
**** ** ** ** * * ** *** ** * * * * * * *** * **** ** = * ** * * * ***

* *** * * **** *** * *** * 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* ** * * ** ** * *
int main()
{
** *** **** * ** *** * ** * * *****
** **** * ** * *** *** ** *** %f ** ** ** * ** **** * *
* ** * *** * *** * = (b*b-4*a*c);
* * * * * * ** ** ** = (-b + sqrt(D))/(2*a);
** * * * * *** = (-b - sqrt(D))/(2*a);
* ****** * * ********* * *** = -b/(2*a);
* * *** ** *** * *** ** * ** ** =sqrt(-D)/(2*a);
* ** *** ** * * *** * ** ** *
** *** * ** **** * * ** *
** ****** ***** * **** ** * * * * * * * * * ** *** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** * ** * ** **
* ** * *** * * * * ** *** ** ** ** ** **** *** * ** = %.2f\nx2 = %.2f",x1,x2);
* * ** * * *

* *** * ** **** ** ** **** ** if(D==0)
*** *** * * * *** *** *
***** *** * * ** *** ** * ****** ** ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ** * ** *** * ****** ** * ** ** **** ***** ** * ** * *** * = x2 = %.2f",x1);
** * ** * ** * ****
* * * * ** * * * *
**** *** *** * * *** * *
* **** ** *** * *** * ** * ** *** ** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * * ** * ***
* * ** ** ******* * * ** * * ** * * * ** ** ** * = * *** ** *** * * ** ****
* ** * * * ** **** * *** * **** * * * * * * = * ** * * ***********
** ** ** *** ** *
* *** ** * ** ** ** ** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* ****** ** * *** *
int main()
{
* **** **** ** *** * ** ** * ** * ***** *** * *
** * *** **** ** ** ** * %f ** ** * **** * * * * * ***
* * * * *** * * * ** * = (b*b-4*a*c);
* ** ** * ****** * = (-b + sqrt(D))/(2*a);
*** ** ** ** ***** * = (-b - sqrt(D))/(2*a);
** * * * ** ****** ** ******* = -b/(2*a);
* * ** * ** ** ** * ** * * =sqrt(-D)/(2*a);
** * ** * ** *
* * * ******* * *
* ** * ** ** ** *** * * * * *** * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and **** *** ***
** * * *** ** * * ** * ***** * *** **** * **** * * * * ** = %.2f\nx2 = %.2f",x1,x2);
** ***** ***** ******

* * *** * * * *** if(D==0)
* * * ** ** * * *
** * ** ** * *** * ** * * * * * * ** * ** * ** * * * * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** * * ** * * * *** * ** *** ** * * ****** * * = x2 = %.2f",x1);
*** ** ** * * * * *** **
* * ** * **** **** *
* ** *** ** * * ** *
** **** * * * * * *** * * * ** * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** * *** **** *
* * * ** ******* ****** * **** * ****** * * ** *** = ** ** ** * ** ** ** * *
*** ** * * *** **** * * ** * * *** * * ** ** * *** * ** = * * ** *** **** * * *
*** ** * * * * * * * *
* ** * * *** *** ** * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.100.164
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users