0 like 1 dislike
7.6k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 7.6k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
* ** ** * * *****
int main()
{
* ** **** * ** * ** ** * * ******* ** ** * ** *
* ** * * * * * * **** * * * %f * ** * * ** **** * **** ***
* * ** ****** * *** * = (b*b-4*a*c);
**** * * ** * * ** * * = (-b + sqrt(D))/(2*a);
** ** * * ** * *** = (-b - sqrt(D))/(2*a);
* * * * * **** ***** * = -b/(2*a);
* * *** * * * ** **** * =sqrt(-D)/(2*a);
* ** *** *** * * * ** **** ** *
*** ** ** * ** **
* *** * ** ** * ***** ** ***** ** *** *** * * * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and * **** * *
******* * *** * ** *** * * * ***** ** *** * * * ** *** * = %.2f\nx2 = %.2f",x1,x2);
*** * * ** * * ** * * *

* * *** * ***** ** * ** ** if(D==0)
* *** **** * ******* **
* *** ** ** ** ****** *** ** * ** ***** ** **** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ** * * * * * * * * * **** **** * * ** * ** ** * ** = x2 = %.2f",x1);
* * ** * *** *** * *** ***
* ** ** * ***** *
* ** *** *** * **
* * ** ******* ****** * ** * *** * ***** ** ** * * *** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * *** *** *** ***
* *** * * *** ***** * * ** * *** **** * *** *** ** * = ** ** * **** ** * **
* ** * ** * *** * * ** **** * ** ** * * ****** * = * ** ** **** ** ** * ** * *
* *** * * * * * * **
* *** ** ** * * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * * * * *

int main()
{
*** * * * * ****** n, i;

** * * **** ***** ** * *** * * * *** &n);

**** ** * * ** ****** = 1; i <= n; ++i)
** * **** * * ****
** ********* * ** ** ** * * * ***** *** % i == 0)
* * * ***** **** * * *** * ** * ** * ** * * * * ** ****** * * *** ", i);
** ** * ******* *

** * * *** ** * * ** 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * ** ** * ** *
*** ** ** * * *

int main()
{
** ** *** * * ** ** * ** *
** * ** * **** * * * * ** * * ** * * * * ** *** * *** ***
* ** * * ******* * = * ** ** *
**** * * ** * * ** *** **
** * * * ** ** * * *
** * ***** * ** * ** ***** *
* * **** ** * ********* = -b /(2*a);
** * * * * ********* **** *** ***
** ******* ** * = (-b)/(2*a);
* * * * ** * * * * * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * *** * * * *** * * **
* * *** * * *** * ***** * *
* ***** ** * ** ** if(D==0)
**** *** *** * * * * ** *
* ** * * * ** * ** *** = (-b + * *
* ** ** ** ** = (-b - * * *
**** ***** *** ** * ** * ** *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = *** ** *** * *
* ** ** ** ** * * ** **
* * *** *** ** * if(D>0)
* ** * *** * * * **
************ * ****** ** *** * * = -b/(2*a);
* ** * ** * ** ** *** * * ** * = (-b + * ** *
*** *** *** * **** ** = (-b - **** *
* ** ****** ** ** * ** ** **** * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ********** * *
** * * * *** * *
** * * ** ** * * * 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include *** * *******
#include ******* * *
int main()
{
* *** * *** * ** * * * * a,b,c;
** * * ******** * * * ***** * * *** ****** ** * * ***
* ** ** * * ** ** **
** ** * ** ** ** ******* * *
** ** *** * * **
**** * ** ***** * * * * *** * * *** ** *** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ** ** * * * * + * * ****** ** - ** ** * *** **
** ** * * * ** * * *
* * ** * *** * ****** ****
* ** ** * * **** ** ** *** * * if (b*b-4*a*c==0)
* * ** **** ** *** *
* * ** * * ** * * ** ** * ** ** * * ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * ** * + * * ****
**** * * * *** ****
** * * ** ********
* **** *** ** *** ****
**** **** * * * ** * ***
** *** * ** * * * ** ******** * ** **** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = ** ***** ** * * * * *** * * ** **** *** * * ****
************** * * ** *
** *** * ** * ** * * * ** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** ** * ** *
#include * * ***
int main()
{
* ***** * * * * * * a,b,c;
* *** ** * ***** * ** ** * * ** ** * *
** ** ** *
* * ** * **** ******** * * * ** *
* *** * * * * * *** * *
***** *** * *** ****** ** ** ** ******* * * * * * ***** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = *** ***** * + ** * * * * - * *** * ****
* * ***** * * *
* * *** ** * * *
** * ** ** * * * if (b*b-4*a*c==0)
* ** **** ** * * ***** **
** ***** *** ***** ** ** * ** * ** * * * * ***** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * * * * * + *** * *
* ** * **** * *
**** * ** * * ** * **
*** * ** ** * * **** ** *
* * ** ** ****** ** **
* *** * * * ** * * ** **** * * ** *** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= **** *** * * * * *** ** * * ** * * * * * * *** *
* ** * ** * ** ** **
*** * * **** * *** * * *** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
*** ** * * * * ** *** ** a,b,c,d,x1,x2;
** * *** * * ** ** * * * * * *** **** * ** ****** * ** **
**** * * ** * * * * * * * *** *
* ** ** *** ** * * * ***** * * **
***** * * ****** * * **** ** *
** ****** * * ** **** *
*** ** * ** ** * *
* ** * ** * * * ** * ** *** ** ** * ** * ** ** ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and **** ** ** * * *
* * ** * * * * ** * ** *** ** **** * * * * = %.2f\n",x1);
* * ** * ** *********** * *** * * * * * ** ** * = %.2f",x2);
** * ** * * * *** ** *
*** *** * *** * * if(d==0)
***** ** ** ** ** **
* *** * *** * * ** **** * *** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * * * * *** * ***** ** ** ***** * * * * * **** * *** = x2 = %.2f",x1);
*** * **** * ***** *
* * ***** * * ** ** ***
* ** * * * * * *****
******** ** * * ****** * * * ** ** ** *** * ** **** of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** ** ** ** * *
* * *** * * * * **** ** ** * * * **** **** * ** = ***** * * * * * ** *
* **** * **** * * ***** ** * * ****** * ** *** ** ** = ** **** * ** *** * *
* * **** ** * * ** * *
* **** * **** * *** * * * 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
*** ** * * * * * ** **** * ** * * ** ** ** *** ** *** ** * * * aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
* * ** * ** *** * * ** *** * ** **** * ** - (4*a*c);
** * ** ** * *** * *** **** * * * * ** **** * ***** * * **
* ** * * * ** * * ** **** * * **** * *** * *** * * * ** * **** ** * *
* **** ** **** * * * * *** * * ** *** * ** ** * * * (-b+spD)/(2*a);
* ** *** * * * ** * * ** *** * *** * * ** ** * ** ** * * ** (-b-spD)/(2*a);
* * ****** * ********* ** * * * * *** * *** ** * *** ***** * * (x1==x2){
*** ** * * ** * ** ** ** ** ** ** * *** ** * * ** * ** * **** * * ** *** ** *** *** *** * ** * * *** * * X=%d\n", x1);
* * ** * ** ** ** ** * * * * * ** * * *** ** * ** ** *** ***
** * ******* *** * *** *** * **** * * * * *** * ****** ** * * {
** ** ** *** ** ** * * * ** * ** ******* * * * ** ** *** * * ** * * **** * ** * * * * ** * * * * ** * X=%d或%d\n", x1, x2);
*** * ****** * *** ** ** * *** * ** * * * ** ******** **** *
        }
* * *** * * *** *** * ** ** * * * * ** ** * if(D==0){
* *** ** * ** ** * ** ******* **** * * * * *** * * * ** * ** * * * ** (-b)/(2*a);
**** ** * *** ** * * ** ** * * * *** ** * *** * ** * ***** * *
* * * * *** ****** **** * **** *** **** * ** ** * * * * **** * ****** ** ** ****** * * ****** * ** *** X=0");
* * * ** ********* *** ** **** ** ***** *** *** * * ** *
** * **** *** ***** * ** ** * ** * ** * ** * ** *** * * *** * ** *
*** * * * ** * ** ** * * * ** * **** * ******* * *** ** **** *** ** * ** * ** * * **** * **** * *** **** * X=%d\n", x1);
*** * ** * * * * ** **** * * * ** ********** ** ** * ******* * * *
        }
* ** *** * *** ** * ** ** * * ** ** ***
**** * * *** * * * ***** *** * **** * ** ** * ** ******* ** ** * * * **** ** ** ** ** * ** ***
** **** ** *** ***** ** * * ** ** * *** *
    }
* * ****** * * ** *** *** **** * * ** *** * *******
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
*** ** ** * * * * a,b,c,D;
* * *** *** ***** * * * x1,x2;
****** ****** *** * ** * * ** * %d **** * * ** *** * * *

* *** * * *** *** * *** * * * *
* * * * * **** * * ** *** * ***
** ****** * * ** ** *** ** *

* * ** * * ****** ***** ** * A,B,C;
* * * * * *** **** * *

** * ****** *** * * * *****
**** * ** * ******** * *** * ** * * ** * ** *** * of %.2fx^2 + %.2fx + %.2f = 0  are real and * *** * ** * **
** * ***** ** * ** * ** ***** ****** * *** * * * *** * **** * * = %.2f\n",x1);
****** * ** ** **** * * * ******* ** ****** ** ** **** * ** ** * = %.2f",x2);}

*** * * **** * *** ** ** if(D==0)
* * * * *** ** *** * * ** * * ** ********* ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
*** * ****** * *** ******** ** * * *** ** * * * ** * ** * *** = x2 = %.2f",x1);}

* * * * ** ** * if(D<0)
** * *** * * * * * ** * * * * * ** * *** ** **** of %.2fx^2 + %.2fx + %.2f = 0  are complex and ** * **** ***
* * ** * *** ** ** * *** * * * ** * ***** * * * ** bb,d,dd;
*** *** * * **** * * * **** * * * * *** *** * ** *
** *** ** *** ** ** *** * * ** ** * ** ******* * ** ****
* ***** * *** ** *** *** * * * * ** ** * * * * * * = * ** *** **** ***
** * * ***** **** * ** * ** *** * * *** * * * ** * ******* ** **** = * **** ** ****

***** * *** *** * **** 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
*** * *** ** ****
int main()
{
* * *** * * * * ** ** * *** * *** * *** *
* **** * * * ******* * * %f ** * * **** *** * * ** ** * *
**** **** * * * * * = (b*b-4*a*c);
* * * *** * * ** * ** * = (-b + sqrt(D))/(2*a);
**** *** ** * ** *** ****** = (-b - sqrt(D))/(2*a);
** * ** * * * *** *** = -b/(2*a);
** ** * ***** * ** * * * * * * * =sqrt(-D)/(2*a);
* *** ********** * * * ** * *
***** ***** ** ** *
* * * * ** ******* ** * * ***** ** ** **** *** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and *** * ** ** **
** ** * ** * ** *** ** *** ** * ** = %.2f\nx2 = %.2f",x1,x2);
** ******** * **** *

** * * * ** * ** *** ** if(D==0)
**** * * * *** * *
*** * ** ** ** * * * * ****** **** * **** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** ** *** * * * **** * ** * * *** ** * * * * * * * **** = x2 = %.2f",x1);
**** ** *** *** ** *
* ** **** *** *** * * ****
* ** * * * * * ** *
**** ** * ** * ** ** *** * * * ** *** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * ** *** ** * ****
***** ** * ** * ** *** * *** *** *** ** ** = ** ***** ** * **
* * **** ** **** * ****** ** * ****** * * ** * * ** ** * = ** ** * ** *** * * ** ** *
* * ** * **** * *
* *** *** * * * **** * *** ** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* * ** * *
int main()
{
*** *** ** **** ******** *** * ** *** ** *
* * *** * ** * ** ** * * %f ** ** * * **** *** ** ** *
***** * * * * ***** ** = (b*b-4*a*c);
* * ** ******* * * = (-b + sqrt(D))/(2*a);
*** * * ** * * *** = (-b - sqrt(D))/(2*a);
**** * **** * * * * ** *** = -b/(2*a);
******** ** ** *** ** * * =sqrt(-D)/(2*a);
* ***** ** * * * * ** ** ** * *
** * *** **** ** * * *
* ** * *** ** ** * ** ******* ** *** *** ***** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** ** ** *** **
*** * ** * * ***** * *** * *** ** ** * ** *** * * ** * = %.2f\nx2 = %.2f",x1,x2);
* * * * ** ** ** * ***

* **** * ** *** *** if(D==0)
** *** * * * * * * *** **
** *** ** * * * ** **** ******* *** ** * ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* *** * *** * *** ** *** ***** * **** ** * ****** ***** = x2 = %.2f",x1);
* * * *** * * * * **
* * ** * **** * *** ** *
* * *** * ** * * ** ** ** *
*** * *** ** **** * ** * ** * * ******** * * ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and *** * * * **
** ****** * *** ** ** * ** * ** * *** * *** * ***** = * * * *** * *
* * * ** * ****** * * * * * ** * *** ** **** = ** **** ****** *** ** *
** * * * *** ** * ** *
* ** * *** **** * * * * **** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.107
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users