0 like 1 dislike
19k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 19k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
** * * ** ** * * * *
int main()
{
** ** * ** ** ***** ** *** * ** ** **** ******
** *** **** **** *** * ** ***** * %f * ** * * * * * * * ***** *
* **** * * *** ** = (b*b-4*a*c);
***** * * *** *** ** = (-b + sqrt(D))/(2*a);
** ** * * * * * * ***** = (-b - sqrt(D))/(2*a);
*** **** * ****** ** * * * * = -b/(2*a);
***** * * * * ** ** *** *** * * * =sqrt(-D)/(2*a);
** * ****** ** * ****** ** * *
**** * * * * ****** **
* ** ** * * * **** *** * ** ** * *** * ** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and ** * **** ** * *
* * * ** *** * *** * ***** * * **** * * * *** ** **** = %.2f\nx2 = %.2f",x1,x2);
** **** *** * * * * **

** ** * * ******* * *** ** ** if(D==0)
***** * ** ** ** * *
* *** ** * ***** **** * * ** ***** * * ***** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ******* ****** *** ** * * * ** ** ***** * * **** = x2 = %.2f",x1);
***** ** * *** * *** *
* * * ** * ** ** **
** ** * * *** ** ** *
** * * *** **** * ** * ** * * * ** ******* ** * * * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** * * * ** *
*** ** * *** * * ** ** ** *** ** * * * * ** = * * *** * * *
*** * *** *** * *** * ** * *** * ***** * **** * * **** = ******** ** * * **** **
*** * * ** * * ****** *
*** ** * ****** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * *** ***** *

int main()
{
***** ***** ********* * * n, i;

* * * ** * * ***** * * ******* &n);

** * ** ** *** * ** * * * = 1; i <= n; ++i)
** ** * *** * *
* * ** ** * ** * ** * * ** ** * *** * % i == 0)
* * * *** * *** * ***** * ***** * ** ****** * ** *** * *** * ** * * * ", i);
* * * ***** * * ** **

*** * * * * *** ** ** * ** ** 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* *** * ** **
*** *** * * *

int main()
{
* ** * * *** ** * *** * ** *** ****
* * * ******** * ** *** * * * * ** ******* *** * * *
* * *** ** ** **** ** = * *
*** * *** ** * * ** ** * *** * ***
* * * * ** *** ** ****
**** *** * * * * * * * * ** * *
**** * ** * * * * ** = -b /(2*a);
* *** ** * **** * * * * * **
* * * ** ** **** * ***** = (-b)/(2*a);
* * ** *** * * ********** ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = *** ** * * * * * **
* * ** * * ** ** *
* *** * ** * ** **** if(D==0)
*** * * *** **** *
* ***** * ** ** * * * = (-b + *** *
*** ** ** * ********* * * = (-b - *
** * * * ** *** *** ** * ** *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * *
* * * * ***** * * * * * *
** ** * *** ** **** ** if(D>0)
* * * *** * **** *****
* * *** ** ** * *** * * = -b/(2*a);
* * * ** * ** ** * * = (-b + * * ****
* * ** * ** * ** ** * = (-b - * ** ** *
*** * * * ** ** ** ** ***** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * *** * * **
** * ***** * ***** *
* ** *** * ** * *** *** 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** * ******
#include * * *** * **
int main()
{
* * * ** *** * a,b,c;
* *** * * * * * **** * ** * * * * ** ** * *** ***
**** * * * * *
* ***** *** * * * * * *
****** *** * **** * ** *
* *** * * *** ****** ** * * * * ** ** * * ** *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = **** ** **** * + ** * ** * * - * **** * * ***
* ** * ** * * * * * **
**** *** * ** * ***
* * * * ** * ******** if (b*b-4*a*c==0)
* *** * **** *
***** * * * ** **** * ** * * **** * ** ****** * * *** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * *** * * + ** ** ** ** *
** * * ** **** * ** **
** *** **** * **** **** *** **
**** * * **** * ***
***** ** * * ** ** * *
* * ** * ** * * *** *** ***** ** *** **** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = *** * * * *** ** * * *** ******** **** * ****** * *
***** * * ** **** ** *
** ** * ** * ********* ** **** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include *** * ***** * ***
#include * * * * * *
int main()
{
* ** ***** * ** * a,b,c;
**** * ** ** * * * * *** * * *** * * * ** * *** * *
** * * * * * * * *
*** **** ** * *** * * ****
****** * **** * ******
** * *** *** * * * *** * * * * ** * * * * ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = *** * * + * * * * * * - ** ** * * *
**** ** * * * *** * ** * *
*** *** ** *** **** * *
**** ** *** * * *** * if (b*b-4*a*c==0)
* * * * * ** ** ****
* * **** ** ******** ** **** * * ** * ** * ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * * * * + ** * * *
** * ** * *** ** * **
* * * * *** ** ****** *
* * * *** * * * ** *
***** * * *** * ** * *** * * *
* ********* ** * * * * * * ** ** * **** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= * * * * * ** ** * ** * * **** * * * *** ****
**** ** ** * * ** * * *
* * ****** * * * * * * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
* ** * ****** ** * * a,b,c,d,x1,x2;
* * * ** ** ***** * * ** ** ** * ***** * * * *** ** * **
* ** * * * **** ** ** ** ** * *
***** * * * ** *** **** **
* **** * * * ** * * * *** **
* ** * * ** * *** * ** ****
* **** * ** ** * ** ** **
* * *** *** *** * ** * * ** * ** * ** ** ** ***** of %.2fx^2 + %.2fx + %.2f = 0 are real and * * * * * * ****
***** * *** * *** * ** ** ** * *** * * * * = %.2f\n",x1);
***** * * * ** *** * ** ** **** ** ** * * ** * * = %.2f",x2);
* ** * *** *****
***** * **** ****** if(d==0)
* * ** ** *
* ** * *** ** * ** ** *** *** **** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
*** ** * *** * * * ******* ** * ** * * * ** **** *** *** = x2 = %.2f",x1);
* * ** * ******
* *** * *** ** ****** *
* *** * * * * *** *
*** **** * * *** * * ** * * * * * **** ** ** * ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * * *
** ** * *** * * *** ** * * ** ** * *** * * * * * ******** * = * **** * * * * * **** * *** *
***** * * * * *** ***** * *** * * ***** * ** **** = * * * * ** * * *** ****
**** ** * * * ** ** **
* *** **** **** * * ** 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
** * * * * * * ** * * ** *** **** * **** **** *** * ** * aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
** * *** ******* * * * ***** * **** ** * * * ** - (4*a*c);
* ******* * *** ** ** ** ** * ** * * ** ****** * * * * ***
* * * ** * * *** * * ** * **** ****** ** ***** * * * **** ***** **
**** **** * ** * * ** * ** * * *** * *** * *** *** * * * * (-b+spD)/(2*a);
* * * * ***** ** * * ** *** * * * * *** ** ** ** * * (-b-spD)/(2*a);
* * * * * ** * ** **** **** * ** ** ** ** *** * ** * ** ** (x1==x2){
* ** * * *** * * ** * * * * * * *** * * *** * * * *** * * * ***** * * **** ** ** * * *** * * * ****** *** * ** * * ** X=%d\n", x1);
* **** * ******** * * ** * * * ** *** ** * ** ** * ** ** * * *** *
** *** * * * * * ** ***** ** ** * * * **** * * ** ** {
* ** * ** * ** ** * * * * * *** ** ** *** * * ** * ** * * * * ** ***** ********* ** * ***** * * **** ** *** * * X=%d或%d\n", x1, x2);
* * * ** * ***** * * * * *** ** * ** * **** ** * ******
        }
******* *** * *** ** * ** ***** ** * ** *** ** * ** if(D==0){
* * * ***** * * * * *** **** * ** * * ** * * *** * * * * (-b)/(2*a);
* ****** * * * ** *** * **** * * * * ** ** * * ** ** * ** **** *** *
** ** *** * ** ********* * ** * *** *** * **** ***** * ** **** ** * * **** ** ****** ** *** ** * * X=0");
* * * * ** ** * ** ***** ** ************ * * * * ** ***** *** * *
** * ** * ** * * * * * * ** * ** **** * * * * ****** ** * * ** **
** ** * * * ** ** ** * * ** * **** ** * ** *** * **** * ****** ** ***** * ****** * * * * * ** * ** * * * ** **** *** X=%d\n", x1);
********* ** **** * * *** **** ***** * *** * * *** * *
        }
*** * * *** ** **** * *** **** **
*** * * *** * * ** * ** **** * * ** * * * ** * * *** ** * *** *** ** ** * * **** ***** ** ** **
** * * * * * * ** * ** * **
    }
** ** * ** * * **** *** * * ** * ** * * * *****
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
* * * * * ** ** ***** a,b,c,D;
* * ** ** ** * ** * **** x1,x2;
* * *** *** * * * * * * * ** * %d ** * ** * * **

* * **** ******* * * * *
** ** * ** * ** ***** ** * * **
* *** ** ** ** * **** * ** * *

** * ** * ** * * *** * A,B,C;
* * ** ** * * ** * * * **

*** ** * * * ** ***** ****** ** *
** * **** ** * *** * * * * ***** **** * ** ** of %.2fx^2 + %.2fx + %.2f = 0  are real and * * * ** *
** ** ** * * * * * * * ** * * ***** ** ** = %.2f\n",x1);
* ** * * **** * ** * **** *** ***** ** ** ** *** ** = %.2f",x2);}

*** *** * * ****** * ** ** * if(D==0)
* ** ******* * * ** * * *** **** *** ** * ** * ** ******* of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
** ** * * * * ** * * *** ****** * ****** ** ** * * ** * = x2 = %.2f",x1);}

****** * ** * *** * * * if(D<0)
* *** * * ** * ***** *** * * * *** * ** * ** * *** of %.2fx^2 + %.2fx + %.2f = 0  are complex and ***** * ***
** ** * * * * * * ** * ** * * * ** bb,d,dd;
* * *** * *** * ** * * ** * * ** ** *
* ** ** ** ****** * ** * *** * * * *** * * * * * * *** ***
* * *** *** * ***** * * *** *********** * ** * ** * = * *** * * *
* * * * * ** *** * * * * ** *** ** * *** * ** * * ** *** = ** * ** *

***** *** *** * * ** **** 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* **** * **
int main()
{
**** ******* * **** ** * *** * * * * *
**** *** * *** *** ** **** * %f * * ** * *********** * **
* ** ** * **** * * = (b*b-4*a*c);
***** *** * **** *** * * * = (-b + sqrt(D))/(2*a);
** ** ** ***** ** ** = (-b - sqrt(D))/(2*a);
* * ** * ****** *** * *** *** = -b/(2*a);
**** * ** * *** * ** *** * *** =sqrt(-D)/(2*a);
* ** ** * *** * *** * ** * * ***
* ***** * ** *** * **
** **** * *** ** * * *** * * * * ** ** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** ***** * ***
** ** * *** * * * *** * * ** *** **** * ** * * * ** = %.2f\nx2 = %.2f",x1,x2);
*** * * ** ** * **** *

* * *** * **** if(D==0)
* * *********** * **** **
* * ** *** ** * * ** ***** * *** ******** **** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ** ** *** * * * ** *** **** ***** ***** **** ** = x2 = %.2f",x1);
* **** * * * ** ** * *
** ** ** ****** ** * *
* * ** * ******* ** ****
*** **** * * ***** ******** *** *** *** * * * ***** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and *** *
** ** * ** * * * ** * * *** * ** ** *** * * * * = * * * * ** * * ******* *
** * * ** * ** **** * ** * ** ** * * * ** * ** * = ***** **** * * * ** * ***
* ** * * * * *
* * **** * ** * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* ** * * **
int main()
{
*** *** * **** * *** * * **** ***** * *** *
**** ** * ****** ** ** ***** * * * %f ** * * * * ** * * * ********
** * * * * * ** * * = (b*b-4*a*c);
* *** * ** * = (-b + sqrt(D))/(2*a);
* * * ** * ** * * * * = (-b - sqrt(D))/(2*a);
* * * * ** * * *** * = -b/(2*a);
* **** * ** *** * * *** * * * =sqrt(-D)/(2*a);
*** ** *** * ** ** * **
*** ** **** * **** * **
*** * *** * * * * ****** * * * * * * * * * * * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** ** *
* * * * ** *** * * * * *** ** *** ****** * ** *** = %.2f\nx2 = %.2f",x1,x2);
*** * **** **** * *

** * * * *** ** * if(D==0)
* * ** * * *
** * * **** * * * * ** *** * * ***** ** * * *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
*** ** **** * * * * * * ***** *** ** *** * ** * ** * *** ** = x2 = %.2f",x1);
** ** ** * * * **
** * * ** * * ****
** ** * ** ** * * *** * *
* ** * * ** * * **** * *** ** ** ***** *** * ** *** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * **** *** ***
* ** ** ** *** * * * ***** * ****** ** * *** * * * = ** *** *** * * * ***
* * * * * * * ** ** *** ** * * * *** ** ** ** * ***** = ** *** * * * * * ** ** *
* * ** * * **
*** * *** * *** * ** * *** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.109
©2016-2026

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users