0 thích 1 không thích
15.7k đã xem

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - đã hỏi trong Chapter 5: Selection Statements bởi (5.2k điểm)
ID: 28934 - Xem được từ: 2017-10-26 18:00 - Hiệu lực đến: Không giới hạn

mở lại bởi | 15.7k đã xem
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Trả lời

0 thích 0 k thích
Hidden content!
#include <stdio.h>
* * ** * * * ** **
int main()
{
*** **** ** ***** **** ** *** *** * *** **** *** ***
***** ** * * ** * * ** *** **** ** %f ** * ** **** * * * *
* **** * * * ** = (b*b-4*a*c);
* * * **** * * * * * ** = (-b + sqrt(D))/(2*a);
** * ** * ***** ** * * = (-b - sqrt(D))/(2*a);
** ** * * * *** * ** **** = -b/(2*a);
**** * * ** **** ** =sqrt(-D)/(2*a);
** * * ** ** *** * ** ** *
** * * ** * ** * *** *
* * **** ****** * ** ** ** ** ** * **** * *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and * * **** ** **
* *** ** ** * *** * * * * ** * *** * = %.2f\nx2 = %.2f",x1,x2);
*** * ** *** * *** * * *** ***

** *** * ** * ***** if(D==0)
* * * * *** * * *
******* * * * ***** ** ********* * * *** *** ** * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** * * * **** ** * ** * ** *** * *** ** * * * *** = x2 = %.2f",x1);
* *** * ** * *
**** ** * **** ** **
** * * ** ***** * ** *****
*** * * * * * ** * * ***** * *** * *** * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** *** **
* ** *** ** ** **** * ** * ** *** * ** * * * = ** * ** * ** *** ** **
* * *** * **** ** ***** * *** **** ***** * * = * ** *** * *
*** *** * ** *** *** *
* ****** ** * * **** ** 0;
}
trả lời
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 thích 0 k thích
Hidden content!
#include * * * * *** * *

int main()
{
** ** **** * * ** * n, i;

* * * * *** ** **** ** ** * ** &n);

* ** ** * ** * **** * * = 1; i <= n; ++i)
**** *** ** * ******
**** * *** * * ** * **** * ***** * * ** % i == 0)
*** ** * ** * * ** ** ** * *** *** * **** ** ** * *** * ", i);
* ****** ** ******* ** **

* * ** *** ** ****** ** ** * 0;
}
trả lời bởi (-284 điểm)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 thích 0 k thích
Hidden content!
* * * ** * *
* * * * * ***

int main()
{
** ** * * * ** * * * * **
* * *** * * ** * * **** **** *** **** * ******** **
* * * * *** *** *** * *** = * *
** ** ** * * * * **
*** ****** *** *** ***
** ** * ***** * * * * ** * * ** *
* * * * * ** * ** = -b /(2*a);
** ** ** ** * ** * *** ** * * * * ***
*** ***** ** * ** ** = (-b)/(2*a);
*** * ** ** ** **** * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = **** ** * ** ** *** ** *
* * * ** *** * * **
*** ** * ** ** *** ***** * if(D==0)
* * ** * ** * * ** *
* ** * ***** *** ** ** ** = (-b + ** *
***** *** * *** ** = (-b - ** *** *
*** * * ** * ** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * *** **
* **** ** * * *
***** *** ** **** * if(D>0)
** ****** * ** *
* ***** ** * * * * * * * * = -b/(2*a);
**** ** *** * * *** * = (-b + * **
** ** ** * * * * * ** ** = (-b - * * *
* ** *** ** *** * * * ** * ** * ** **** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ** * * * ** **
* * * *** ***
** * * * * ** * * 0;
}
trả lời bởi (-323 điểm)
đã sửa bởi
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 thích 0 k thích
Hidden content!
#include * **** ***
#include * ** * * **
int main()
{
* *** * *** **** *** a,b,c;
*** * *** *** ** ** * ** * * * * * *** * * **** ****
** * *** ** *
* ** * * ** * * * *** *** * * *
* ** *** * * ** **** **
*** ** ****** ****** *** ** ** * ** **** ** * * * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ** * * ** ** + ** * * **** * * - * *** ******
*** * * * ** * * **
* * * * *** * **
* * * * * ** * * ** if (b*b-4*a*c==0)
*** * * ** * * *********** *
* ** * *** * ** ** ** * * ** * ** * * * * *** ** ****** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * ****** *** + *** * ***
* ** ** *** * *** *
* ***** ** * ** ** * ***
* * * * * ****** * * **
*** ** * * * * *** *
* *** * * * ** * ** ** * * ** ** ** *** ** * * * * * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = ***** ** ** * * * * ******** **** * * * * **
** * *** ** *** ** ***
* * ***** * * ** ** *** * 0;
}
trả lời bởi (-127 điểm)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 thích 0 k thích
Hidden content!
#include ** *** **
#include * * ****
int main()
{
*** * ** *** * ** ** * a,b,c;
* * * ****** ** * * * * * ** * * ** **** **
* *** * * *
** * ** *** *** * ******* **** * ***
** * ** * * ** ** * * *
* * ** ** ** * * * * * * * * * * * *** * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * * * * + *** * *** - ************
* * ** * * ** ** *
**** * * **********
* ** ** * ** ** if (b*b-4*a*c==0)
* ** * ** * **
** * *** ** * ** * * *********** ** ***** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ****** **** ** + *** * * ** * *
* **** * *** *** ** *
* * * ** *** ** ** ****
* * * ** * * **** * *
** * ** *** * * * **
*** * ** * ** ** * * * ** *** ** * ** ** * * * *** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= * * *** * *** * * **** *** *** * * * * ** ***
** **** * * ** ****
*** * ****** * * * ** *** 0;
}
trả lời bởi (-127 điểm)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 thích 0 k thích
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
* ** ** * * * ** *** ** ***** a,b,c,d,x1,x2;
* ** **** * ** * * * * * * **** * * * ** *** **** *
* ****** ** **** ** * * * * *
* * * ** *** ** *** * *** * ***
* * ** * ** *** *** * ** * *
**** * * * *** *** * **** ** *
**** *** * * * *
** * * * * ****** ** ****** * * * ** ** *** ***** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * *** * **
* *** * * ** *** * * * **** ** ** *** ** * ***** ******* = %.2f\n",x1);
*** * ** * * *** * * **** * ** ***** * * * ** * *** * = %.2f",x2);
****** ** ** ***** * *
* * ** ** * *** ** ** ** if(d==0)
* * *** * * * * *
** * * ** * * * * **** ****** * **** * * **** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * ** * ** * * * * ** ** * ** ** ***** = x2 = %.2f",x1);
*** * * ** ***
* *** * *** * * ** *****
** * * * *** *** *
**** ** * * ** * **** ** **** *** **** * **** ******* * *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * **** * * ****
***** ** * *** * *** * **** * ** * ** * ****** ** = *** ** * ** **** *** *
**** * * ** * * * ** ** ** * * * * *** = **** ****** * ** ** *** *
** ******* * ** ** *
**** ** *** * ** ** * * 0;
}
trả lời bởi (-214 điểm)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 thích 0 k thích
Hidden content!
int a, b, c, D, spD, x1, x2;
* *** * ** ** * *** **** * *** * ** * * ** ** * * **** aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
* **** * * * * * * *** * ***** * * *** - (4*a*c);
** *** ***** * ** ****** **** ** ** * **** ***** * *****
** * * * * * *** * ** ** ** ******* * ** * ** * *
* ** * ** **** * * * * ** ** * **** * ** * * * * * ** * * (-b+spD)/(2*a);
*** * **** * * ***** *** * ** * ** * ** * ** ** ** ***** ** ** * (-b-spD)/(2*a);
* * * *** * * ******* **** ** ** **** *** * * ** * **** **** (x1==x2){
*** * ***** *** * *** * **** ******* * * ** * **** * ** ** ** ** * * * *** ** * ***** ****** * * * ** ** ***** * * * *** X=%d\n", x1);
*** ** * ****** *** *** ** * * * * * ** * * * * * **
** * * * ** * ** ** * * * **** * * * * **** * ** ***** *** {
* * * * *** * *** ** * ** * *** ****** * * * * * * ** * *** *** **** * * * *** * **** * *** ** * * * *** * * X=%d或%d\n", x1, x2);
** * **** ** ***** * *** * *** * ***** * * *** * * ** * *
        }
* * * * * *** *** ** ** * ** * * * *** * ** ** * if(D==0){
* * * ** * * * ** *** * ** ** * * ** ** ** ** * ** * (-b)/(2*a);
* ** **** * ** ** * ** * * * *** ** ***** * * ** * ** * ** ** * *
** * * * * ** * ****** * ** **** *** **** * *** * * * ** ** *** * * ** * * * ****** *** *** X=0");
* ** * ** * * * * ** * * *** ** * * ** * ** ** ** * ** *** * *** * *
*** * * * * * **** *** * ** ** **** * *** **** *** ***** * *** ***
* **** ** ****** * *** *** * * * * ** ** * **** * * *** ** * *** * ** *** **** ** *** * * * * X=%d\n", x1);
** * ****** ** * ** ** *** * * * * *** * * ***** * ** **** * *
        }
* ** ** * *** *** * ******** * * ** ** *** *
* * ** * ****** **** * ** * * * * * ** * * * ** ***** **** *** ** ***** ***** * * **** * * * *****
* * * * * ***** * ** ** ** **** * * ** * *
    }
* ** * **** ***** * *** * **** ** * ** * * * ** *
    system("PAUSE");
    return 0;
}
trả lời bởi (-32 điểm)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 thích 0 k thích
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
* ** *** ***** *** **** a,b,c,D;
* ****** * *** * *** x1,x2;
***** *** *** ** ** * * * ******* * ** %d * * * * * **

** ** ******* *** * * *** *
** * ***** * *** * ** * **** ** *
* ****** * ** ***** ** * * * * * ***

* * * * * * ** *** ** *** A,B,C;
** * *** **** * ** * * ** * *

* * ***** * * * *** * **
*** ** *** **** ** ** ** *** * ** * * ** * of %.2fx^2 + %.2fx + %.2f = 0  are real and ***** * ** ** *
** * ** ***** ** * ** * ** * ** ** **** * * ** ** ** = %.2f\n",x1);
* * * * **** ***** * * *** *** * ** *** * * * * *** * **** = %.2f",x2);}

** * **** * *** if(D==0)
***** * ** ** * * * *** * *** ** * **** * * *** * * **** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
** * * ** * * ** *** * * * * ** **** **** ** ****** ***** * = x2 = %.2f",x1);}

**** * ** * ** * * if(D<0)
** * ** *** ** **** * * * * * * ******* ** * *** ** * of %.2fx^2 + %.2fx + %.2f = 0  are complex and **** * * * *
* ** * ** **** * * * ** ** * *** * * * * * bb,d,dd;
* ** * ** * *** * * ** * * ** * * * *** ****** **** **
** * * ****** * * *** * * * * **** *** ****** ** *** **** *
***** *** * * * ** *** ** * * *** **** * **** * * * *** = **** * * * ** *
** * * * ** * * * ** ** ** ***** * * * * * ** = *** ****** * *

*** * *** * **** 0;
}
trả lời bởi (-16 điểm)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 thích 0 k thích
Hidden content!
#include <stdio.h>
*** ** * * *****
int main()
{
** *** ***** **** * * ***** * ** * *
* ** * * * * ** ** *** *** ** %f ****** **** ** * **** *
*** ** * * * * ** = (b*b-4*a*c);
*** * ** * * ** * ** * * * = (-b + sqrt(D))/(2*a);
** * * ** * ** ** *** = (-b - sqrt(D))/(2*a);
** * *** ** * = -b/(2*a);
** * *** ******* ***** * * ** =sqrt(-D)/(2*a);
**** * *** **** * * * *
* *** *** * * * ****** **** *
*** * ** *** * * ** * * * **** * ** ** ** *** * * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and *** * **** *
* * *** * *** ** * ** **** ** * * *** **** * ** ** ** = %.2f\nx2 = %.2f",x1,x2);
* * * ** * ** * * * *

* *** * * ** * * if(D==0)
* * ** **** ** **** ***
* * * * ** ** *** ** * * * ** ** * ******* * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * * *** ** ** * * ** ***** *** * *** * * *** *** = x2 = %.2f",x1);
* ** ** ***** ****** **
*** * ** * * * * ** ** *
*** * * * * * * ** *
** ***** *** ** * ** ** * * *** *** ** ** **** * ** *** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** ** **** ** *** **
* * * ** * * * ** *** *** * * * ** * * * * * = * * * * * ** * *
** ** ** * **** **** ** * *** * * ** *** * * ** = ***** * *** *** ** * * * * * * *
** * * * ** ** * * *
* **** **** * * * ** * 0;
}
trả lời
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 thích 0 k thích
Hidden content!
#include <stdio.h>
** * **** * * ***
int main()
{
* * ** * ****** **** * **** * * *** ** * *
* *** * * * * ** ********* * * * *** %f ** ** * ** * *** **
* ********* ** * * * *** * = (b*b-4*a*c);
* *** * ** * * * * = (-b + sqrt(D))/(2*a);
* *** ** ** **** * *** *** ** = (-b - sqrt(D))/(2*a);
* * ** ** * * * *** * ** = -b/(2*a);
* * * ** ** ** * * * * =sqrt(-D)/(2*a);
** *** ***** * *** *** * * * * ***
** *** *** ** ** ** * * *****
* ** ***** * * * ** ** * * ** ** * * * * *** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and ** * ** *****
** ** *** * ** * ** * **** ** * * * * **** * * * * = %.2f\nx2 = %.2f",x1,x2);
** ** * * * *

* * * ** * * * * **** if(D==0)
* * * ***** ** ***
* * * * * * * * * ***** ** ***** **** ****** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ** * **** * **** ****** ** *** ** * **** = x2 = %.2f",x1);
*** *** ** * ** * * * *** *
** ** * * * * * * **
* * * * * * *** * **
***** ** * * * * **** **** *** ** * * **** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * ** ** ** *
* * ** * *** ** * ***** ** ** * ** * * = ** ** * ** *** ** * * *
* * ** * * * ***** *** * * * * ** *** ** ** * ** = * * * * ** **** * *
***** * * * * *** * * **
***** * ** *** ** ***** * 0;
}
trả lời
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.7.77
©2016-2026

Không tìm thấy câu hỏi liên quan

12,783 câu hỏi
183,442 trả lời
172,219 bình luận
4,824 thành viên