0 like 1 dislike
5.2k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 5.2k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
* * ** *** * * * *
int main()
{
** * **** * **** * * * * ** * *** *
* * ** **** *** ** * * %f ** ** **** * * *** **
* * * *** *** * * * * = (b*b-4*a*c);
***** * * * * ** **** * = (-b + sqrt(D))/(2*a);
* ** ** ** ** ********* * = (-b - sqrt(D))/(2*a);
** * * * ** * ***** = -b/(2*a);
* * ** ***** ** *** * * * ** =sqrt(-D)/(2*a);
** ** * * ** ** * * ********
* *** ** ** * * ** * *
*** **** * * **** * ** * ** * * ** * ** * * *** * * ***** of %.2fx^2 + %.2fx + %.2f = 0 are real and * *** * * ** *
** * * * ********** * * ****** * * **** ***** *** * = %.2f\nx2 = %.2f",x1,x2);
** * ** *** * * ** *

* ** * * * * * * ** * if(D==0)
* *** ** ** ******
* ** **** ** * * * ** * **** ** * ** ** * *** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ** * *** ** *** * **** * * ******* ** *** ** * ** = x2 = %.2f",x1);
** * ** ** * ** ***
********* * * * * **
** * * ***** ** *
** * *** * * ** **** ** * **** *** * * * * * * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * ** ** * ** *
**** * * * *** * ** * ** *** ** * ** *** *** * ** * ** ** = * *** ** *** *** **
* *** ******** ** * ** * ** **** ** ** * *** ** = * * * ** * ** *** ** * * *
* **** ** ** * * * ** *
*** ** ** *** * * * ** * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ****

int main()
{
** * ** * **** *** ** *** n, i;

* *** **** * * *** * * * * * * ** **** * &n);

** ** * ** ***** ** * ** = 1; i <= n; ++i)
*** ** * *** * *
* *** * * * *** *** * *** * * * ** % i == 0)
** * ** * **** **** * * * **** * ***** * * * * *** *** * * * * *** * ** * * **** ", i);
* ** ** * * * * **** **

** * ***** * ** ** * 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
**** * ** *
**** ***** ** * *

int main()
{
** *** **** *** **** **** ** **** **
**** ** * ** * * *** ** ***** * **** ***** * * *****
** * ** = * * *
* * * *** ***** * *** *
* **** ******* * * * ** *
** ****** ** ** ** * * * **
* **** * * * * * *** = -b /(2*a);
**** ***** ** *** * * * *** *
* * * * ********* * **** = (-b)/(2*a);
* * * ** *** ** * ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = ** * * **** ***** * *
* ***** ******* * ** ***
*** * *** ** ** * if(D==0)
* **** ** * *****
* * ** * ** *** * ***** ** = (-b + * *
** *** * *** *** * ** * = (-b - * *** ***
* *** * * * * * * * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ******
** **** * * **** * *
* ** ** **** ** *** *** if(D>0)
*** * * ** * **** **** *
* * *** * * * * * * *** = -b/(2*a);
***** * ** * = (-b + * ** * **
* ** * ***** *** = (-b - * *
* **** * * * * ** **** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ** *** * ********
* * * ** ** *** *** * *
* * * * **** ** * ** 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** ** **
#include *** * *
int main()
{
* * ** ** *** * a,b,c;
** ** *** * ** ** ** * * ** ***** *** * *** * ** **** ***** * *
*** * * **** ** ** *
***** * ** * * ** * * **
** *** * * ** *
** * *** *** **** * **** * ** * * *** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ** ** * * + * **** ******* - * * ** * *
*** *** ** ******** ***
* ** * * ** * * *
***** * **** *** * ** ** if (b*b-4*a*c==0)
** ** ** * * * ** * *
*** * **** *** ** * * ** * *** * * *** ** ** ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** **** **** * + * ** ** *
* **** * ***** ***** **
*** * *** * ** ** *
** *** ********** ** * **** ** *
* ** * * ** ** * ** ****
* ** * **** ****** ** * ** * ** * * ** * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * * * *** * ***** * ***** ***** * *** * *** ** * ** **** ***
*** * **** ***
********* * ***** * * *** * *** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * ** ********* *
#include * * * * **
int main()
{
* ** **** * ***** ** * a,b,c;
* ** * **** * * ** * ** * ** * * * *** * *** *
** ******** *** ** ** *
* ** ** * ** *** ** ***** * ***
** * * * ***** * ***
* * * * * ** ** * * * * * *** **** * * ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * ** **** * + * * *** ** * **** - ** **** * * *
* ******* **** ***
***** * * * ** * * **
*** * * ** ** *** if (b*b-4*a*c==0)
* * * * ** * *
** ** * * ** * *** ****** * **** ** * *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * * ** * + * ** *** ** *
** ** ** * *** * **
***** * ** * * *** * * *
* * * * ***** *** * * *
** ** * **** * * ** * ** *
*** * ** ** ** ** ***** * * * *** **** ******* *** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= ** * * * *** *** * *** * * *** ** * * * ** ******** ***
* * * ** * * * ***
********* * * * * * ** * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
**** * ** ** ** * * a,b,c,d,x1,x2;
* * ** ** *** * * * * * * ** ** *** *** ** * **
* *** ** * * **** **** ****
** * ** ** * *** * ** **** * *
** **** **** ** * * * ** * *
* ** * ** * * * ** * *** ** **
* * * **** * *********
** * * * ***** ** * *** ****** * **** ** * * ** * ********* * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * * * * *** *
*** * * ** *** ** * *** * * * ** **** ** * * ** * * ** = %.2f\n",x1);
** * ** * * * ******* ***** *** * * * * *** * * * ** ** = %.2f",x2);
*** * * ** * * * ***
** * ** *** ** * ****** *** if(d==0)
* **** ** ** * * *
***** ** * * ****** ** *** * ** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
*** ** *** *** * * * * ***** * **** **** * * *** * = x2 = %.2f",x1);
* * ** * * * * *
* * * * **** **** * * *
* ** * * ** * ***
** * * * * *** *** ** ** * * *** ** * * * * * * ** **** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and *** * *
* ** ** *** ** * ** **** ** * * ** ** ******* *** = ** * **** ** *** * ** *
* **** * ** * * * * **** * *** ** **** * * ** * = * * * * ** * *** * * *** *
** * * ** * * **
* * ***** * ** * * * 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
* * *** ** **** * ** * * ****** ** * * * * **** * * ** ** aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
* * ***** ** **** * * **** ** *** * ** ** * *** * - (4*a*c);
** ** * * * ** * * * **** *** ** *** ** * * * *** * ***
** ** ** * ** * ** ** * ** * * * ****** *** ** * * ** ** ** ** * ** * *
*** *** ******* ** ***** * * ** ** **** * **** ** * * * ** (-b+spD)/(2*a);
** * ** **** *** * ** ** * *** **** * ** ******** * (-b-spD)/(2*a);
**** *** ***** * *** ** * ***** * ** * * ** * ** ** ** ** * (x1==x2){
*** * * ** * ** *** ** * **** * * * * ** ** * * **** ****** * ** * ** * ** * * * * * * ** * * **** * **** *** * *** * * *** *** ** ** X=%d\n", x1);
* * * * * ** ** ** ** ** * *** ****** ** ** ** * ** ***** ****
* * * * * **** * ** *** * ** ** * **** ** * ** * * ***** **** * * * {
** * * ** ** **** ** * * ** * * ** ** ****** * ****** * ** **** *** * **** ** *** * * * *** * ** **** * * * ** ** ** * * ** X=%d或%d\n", x1, x2);
* ** * * * *** * *** ** **** * * * ** * ** ** * **** * **** ***
        }
**** * * * * * ***** * ***** * **** ****** ***** if(D==0){
* * * * * * ** * ***** * * *** **** * ** * * * ** ** ** * ***** (-b)/(2*a);
* * ***** ******** **** ** * * * * * * **** ** * **** **** ***** * ****
*** ***** * ** ** * *** * * * ** * *** ** * **** * * ** * **** * ******* ** * * * * *** * *** * X=0");
*** * * ****** ** * **** * ** * ** *** * * *** * * ***** * * ***
*** * ** * * * * * **** ** ** ********** * ******
** * * * **** ** * * * *** * **** **** ** *** ** *** ** *** ** ** * * ** * * *** X=%d\n", x1);
*** ** * * *** * ** ** * * * *** ***** ** * * *** ** ** ***** * *** *
        }
*** *** * * * * *** * *** ******** * **
* *** ** *** * * * ** *** ** **** * * *** *** * ******* ***** * * ** ** ** **** **** ** * * * * * **
* * ** * * * ** *** * * ** * ** * * * *** * * *
    }
* * * * ** * * * * ***** *** * *** * * *** *
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
*** * * ** ** ***** * a,b,c,D;
* * *** ***** * * * ** * * x1,x2;
**** * * ** ** * **** * ****** %d ** * ** * ** ** ****

**** * * * ** * ** *** ** *
* * * * * * * ** * * * ** ** ** ** *
* * * * ** **** *** * ** * * **

*** * * * * ** ** * *** A,B,C;
* ******* *** * ** * **** *** ** *

* **** *** ** * * **
** * * ***** * ** * ***** ** ** **** * * **** * * * of %.2fx^2 + %.2fx + %.2f = 0  are real and * * * * * *
* ** * * *** * * * * * ** * *** * * * *** * * *** **** * ***** = %.2f\n",x1);
* * * ** ** ** * ** ** * ** * ** ***** ** *** * = %.2f",x2);}

* ** * * ** ** if(D==0)
** * * * *** * * * *** * *** **** * * * * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
**** ** * ** *** * ** ** ** * * * * * ** * ****** = x2 = %.2f",x1);}

***** * ** ** ** *** * *** if(D<0)
*** * * *** ** * * * * *** ** *** * *** ** * ** of %.2fx^2 + %.2fx + %.2f = 0  are complex and * ** **** ** **
**** ** * * * * *** *** ***** ** ** * ** * * bb,d,dd;
* * ** * * * ****** * * ** *** ** * * ** * *
** * **** *** * * * ****** ** ** ***** ** *** * *
** * * * * ** ** *** ** * *** * * *** * ** * *** *** * **** = ** * *** ****** *
**** ** ** * *** * ** * * * *** *** ** * *** * ** ** * ** **** ***** = ** * * ** *********

**** *** ** ** * * * **** 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
** * * * *** * *
int main()
{
* *** ** * ** ** * * *** ** ** * * *
* * * **** * * * * ***** %f *** * *** * ** * * ** ***
* ***** ** * *** * ** * = (b*b-4*a*c);
* * ** *** ** * ** = (-b + sqrt(D))/(2*a);
** * ** * **** *** * = (-b - sqrt(D))/(2*a);
** ** * * * * *** *** * = -b/(2*a);
**** * * ** ** =sqrt(-D)/(2*a);
* **** ******* * ** ** * ** * *
*** ******** * *** * ** *** **
**** *** * * * * * * * ******* * ** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * ** * ****
******* * * * * * * ** * ** *** * * * ** * * * * * = %.2f\nx2 = %.2f",x1,x2);
* ** *** * * ** * ***** *

* ***** ** * ** * ** if(D==0)
* ** * * ** ** * ***
** * * * ** * ** * * ** * **** * ** * ** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* **** * ** * * * * ** * * * *** * * * = x2 = %.2f",x1);
* * * **** ** * **
* ** * *** * *** ****** *
* ** * * ****** * *
*** *** *** ** ** *** * * *** **** * ** ** * * **** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** ***** ** * **
** * * ** ** *** * *** * ** ***** * * * ** * = * * *** * * *** ** *** ****** *
****** * ** ** * * * * ** * **** * * ** **** ** * = * ** * ** ** ** * * **
* * ** * * ** * *
* * ** * * * *** *** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* * ** *** ***
int main()
{
* **** * * * **** * ** * ** * **** *
** * ** * * ** *** * * **** ** %f *** * ** * ** * *
* * **** * * *** * * * = (b*b-4*a*c);
*** * * * ** * *** ***** * = (-b + sqrt(D))/(2*a);
** * *** ** * * * = (-b - sqrt(D))/(2*a);
** * * * * * ***** ** = -b/(2*a);
** ** * * ** *** *** ** ** =sqrt(-D)/(2*a);
***** *** * *** * *** * * * * * * *
*** * *** ** ** * ** *** *** *
* * * * * * * *** ** ** ** **** *** * ** *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and * * *** *** **
*** * ** *** ** ** ** *** *** * * *** * * *** * *** * *** * = %.2f\nx2 = %.2f",x1,x2);
* * ** * * * ** *

* ** * * *** ***** * if(D==0)
** * * * * ** ** ** **
* ** **** * * *** * *** ***** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ** ** ** * ** * * * ** *** * * *** * * * * *** = x2 = %.2f",x1);
* * ** * * ** *****
** ** * ** * * ** ***** *
** * * * ** ******** ** * ***
********** ** * * * ** ***** * ** ****** * * ***** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** * * * *
**** ** * * ****** *** * *** *** * * * *** * ** ** = ** * ***** * * **
**** * * * ** ** *** ** * * *** * * *** * * * ** ** ** = ** * **** * ** * ** *
**** *** ** **** * *** * *
* ** ** * * * * ** ** * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.6.191
©2016-2024

No related questions found

12,783 questions
183,443 answers
172,219 comments
4,824 users