0 like 1 dislike
17.5k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 17.5k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
* * **** **
int main()
{
********* **** *** * ***** ** * ** * ** * *
* * * * ****** **** * ** * %f * * * * *** ** ** ** **
* * ***** ******** *** = (b*b-4*a*c);
*** * * * * * *** * ** = (-b + sqrt(D))/(2*a);
* ****** * ** * ** = (-b - sqrt(D))/(2*a);
* *** ** * *** * * * * * ** = -b/(2*a);
* ** *** *** ** ******* =sqrt(-D)/(2*a);
** *** * ** * * ** *** * *
** * * * ** **** *
* * * * * * **** *** *** * * ** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and * * * ** ****
********* ** * * **** * ***** * * ** *** * *** * * * **** ** = %.2f\nx2 = %.2f",x1,x2);
******** ** ** ************

* ** * * * * * * if(D==0)
** **** ** * * * ******
* ** * ** * ** * ** * * * * ** ** ** ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** ********** * * **** ********* ** * *** * **** * * **** ** = x2 = %.2f",x1);
* * * * * ** * *** *
** * * * * **** * * * **
***** * * * ** ** *****
** **** **** ** ***** ** *** * ** ****** ** * * ** *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and *** * *****
* ** * * *** * *** ** * * * ** ****** * * * * * ** = ** * ** ** * *** **
*** ** * ** * * * * * ** * ******** **** ***** * *** * **** = * *** ** *** ** ** * *****
** ** * * * **** **** **
** **** ****** * * **** *** * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** ** * * *

int main()
{
* ** * ***** *** * ** * n, i;

*** **** *** * * *** * ***** *** ** * &n);

*** * * * * **** *** ** * = 1; i <= n; ++i)
*** * ******* ** **
** * ** * * * ** *** ** *** * * * ** * % i == 0)
***** ** * * * ** ** * ** * * ***** * *** ** * * * * * ** *** * * ** ** * ", i);
*** * * * * *

* ***** **** ***** ** * * 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** *** *** ** * ** *
**** ***** *

int main()
{
* *** ** * * * ** * * *** ** *****
** * ** * * *** *** ** * ** * *** * * *** *******
* * *** ** * ** ****** * = * ** ** *
* ** ** **** * * * *** *
** * ** * * * *
*** ** * **** * * ** ******* * ***
** **** * * ** * * ******* = -b /(2*a);
** ** ** * ** * * ** * *** *
******** * * * * * ** * = (-b)/(2*a);
***** ** ****** ** ***** * ** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * ** * * * * **** *
* * ** ** **** **** * * *
**** ** * *** * * * if(D==0)
* ** * * * ** ** *
* * * * * * = (-b + * * * *
*** ** * ****** * * ****** = (-b - * **
* **** * * ** * *** ** ***** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * *** * *** *
***** * * ** * **
* * ** * * **** * * * * if(D>0)
* ** *** **** * ***
** ** ** ** ** *** * * = -b/(2*a);
** **** ******* * * * = (-b + ** * **
****** **** *** ** * ** = (-b - * ***
* ** ** *** * * * ** *** ****** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = *** * * * * *
* * ** **** * *** *
** * * * * * * **** * 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * ** * ***
#include *** **
int main()
{
* ** *** * ** * * ** * a,b,c;
* * * ** ***** * * *** * * *** ** * * ** * ****
*** *** * **** ***** * **
* * * * ** * * ** * * * *
* * ***** ** **** **
** * ** ** * * **** **** ***** **** *** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * **** *** + * ** ******* - * **** ** *
** ***** ** * *** *
*** * * ** ** *** * *
***** **** * * ** * * ** * if (b*b-4*a*c==0)
******* ** * ** * ** *
*** * * ** *** * ** * *** * * *** ** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** ** * ** ** + * ** *
* *** * * ** * *
** * ***** ****** **
** *** ** **** * * *
* *** ****** *
*** **** * *** * * * * * ** ***** * * ******* * * ** ** *** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * * ** ** * * ** *** * * * * ******** * ** ** * *
** *** * * * ** *** ** *
* ** *** ** ******** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * *
#include * ** * *
int main()
{
***** *** * **** *** a,b,c;
***** * * * * * ***** ** ** * ** ** * ** ** ** * *
** *** ***** * * *
* * * * ** *** * *** * * ** **
* * * * ** * * *
* ** * * * * * ** * * ** ** ** ** **** * * **** **** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ** ******** + ******* ** ** - ** * ***
** **** ** * ** * * *
* * * *** ** ** ** *
***** * * ** *** ** ** * * if (b*b-4*a*c==0)
* * * * * * * ** * **
**** *** * * ** * *** **** *** ***** * * * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = *** * *** + * ** *
*** * * ***** * *** * **
* * ** * *** *
* ** ** * *** ** ** **
****** * ******** * *
*** ** *** * * * * ** * ** * * *** * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= *** * * * * * * * * ***** *** * * ** * * * ** * *** ***
** ** * * * * *
* ** * * * **** * ** **** ** * ** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
** ** * * **** ** **** a,b,c,d,x1,x2;
* * ** *** * ** ** ** * ***** * **** * * * * ** *** *
** *** * * ******* *** * ****
* * ** * ** * **** * * * *
* *** * * ***** ** ** * ** *** ** ****
* *** *** ** * * * ** * **
* ******* * * * *
* * * ** * ** ***** * * ** * *** ** * ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and * **** * **
* ** * * ** ** * * *** * *** * ** * *** ** * * * = %.2f\n",x1);
* * * ** *** ** ** * **** * *** * ** * * **** ** = %.2f",x2);
** * * * * * * *** *
* * * *** * * ***** * ** * if(d==0)
* * * * * **** ** *
* ** ***** * ** *** ** ** ** * **** * * * * * * * * ** **** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** * ***** * *** * ** * *** * ** * * * * ** ** * ** * = x2 = %.2f",x1);
**** *** ** **
* ** ** ** * ** *** * ** * *
* ** *** * ** * * *
* * * * * * * *** **** * * ***** * *** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * *** * *
** * * * * * ***** ***** ***** * *** * * = ** * **** * ******* ** *
*** * *** ** * * * **** ** *** * * * * *** *** = ** **** ** * * * * * ***
** * ** * *** ** * *
** * ***** ****** ***** * ** 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
** * **** ** ** ** * ****** *** ******* ** * ** ****** * * ** aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
*** ***** ** * * ** * * * ** * ****** *** - (4*a*c);
** * *** * ********* * * * *** * * *** *** ** *** ** *
* ** * * * ** *** ** * ** * * * * * * * ** ** *** * ** *** ** * *
*** ** ** * ** ** * * * * ***** * * ** * ** * *** * ** (-b+spD)/(2*a);
***** * * **** *** * *** * ** *** * * * * * ** ** * * *** (-b-spD)/(2*a);
******** * ** * * * * * *** * *** *** * * ** * ** * * * ** *** (x1==x2){
* **** ***** * *** ** ** * * ** ** * * *** * ** ** * * * ***** * ** * ** * ****** *** * ** * * *** * ** *** ** * *** *** X=%d\n", x1);
* ** ** * ** ***** * ** ** * * * ** **** ** **** * *** * ** * * *
*** **** ** *** *** ** ** *** * **** *** *** * * * * ** ** *** {
* * *** * * ** *** ***** * * ** *** ** * * ** ** *** * * ** * *** ** * ** ** * ** *** **** * **** *** ** *** **** * * X=%d或%d\n", x1, x2);
* * *** *** * ***** * *** * ** * * ** * * * ***** * **** **** * *
        }
* ** ** **** * * * * * ** *** * ******* * * * if(D==0){
* * * ** ** * **** * * ********* *** * * * ***** * ** (-b)/(2*a);
* ** * ****** * ** ** ** * * * *** **** * * ** * ** * ** ** **
* * **** * ** *** * ********** ** * ** *** * ***** ** ** * * * * * * * ** ** ** ** * X=0");
* * ** * **** * ** **** * * ***** **** * * * * * * * * *** ***** * ***
* ** **** ** *** * ** ** * * * ****** * * * ***** *** * ** ** ** *
**** * ** * * * * ** *** ** * **** ***** *** * ***** ** *** * * * * * *** * ** * * ** ** *** *** * X=%d\n", x1);
* *** ** ** *** ** *** ** ** * * ****** * * *** ** ** * *
        }
* ** * * * *** **** ***** **** * * * *
** **** * ******* ** ** * * ** * * *** *** ***** * *** * ** * **** **** * * ** * *** * * ** **** * ** **** * ****
** * * **** * * **** ** ** *** * * *
    }
** * ********* * * * ** * * ** *** *
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
**** ** ** * *** * ** * a,b,c,D;
* ** * * ***** ******* * * x1,x2;
** ** * *** ** **** ** * * %d * * * ** * * * * ** * ** *

* * ** * * *** ** ** ** **
* * ** * ** * ** ** * *** *** * * *** *
* * * * * * * * * ** * ** **

*** *** *** * ** **** ** A,B,C;
* * *** ** * * *** ** * * *

** * *** **** * * ** * **
**** ** ** * *** ** ** ** * ** * * ** *** ** *** **** * of %.2fx^2 + %.2fx + %.2f = 0  are real and * ** * ** ** *
* **** ** * * * * * ** * * *** ** * * * ****** ** ***** = %.2f\n",x1);
*** ** **** ** ** ** * * ***** ****** ** * * * * ******* = %.2f",x2);}

* * * *** ** * ** if(D==0)
* * *** * * ** ** ** * * * ** * * *** ** * * *** * ***** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
* * * ** ** *** * * * *** ** ** ** ** * * ** ** * **** ** = x2 = %.2f",x1);}

* *** ** ** *** * * * if(D<0)
* * *** * *** ** * *** ** * *** *** * * ** * * * * of %.2fx^2 + %.2fx + %.2f = 0  are complex and ** * * **** *
* **** ** **** ** ** * * * * * ** * * * **** **** * bb,d,dd;
******* **** ** ***** * ** ****** ** * *** *
* * * **** **** * ** * * ** **** * * ***** * *****
* ** ***** * ** * ** ** * * * **** ** * *** * ** = * * *** * * **
* * ** **** * * ** * ** * * * * * * ***** *** ** ** * = *** ** * ** **

* * * * * * ************ * 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
**** **** *
int main()
{
** * ******* *** ** ***** **** ** * * *
*** * ***** ** **** *** * **** %f *** * **** * ** * *
* ***** *** * * * * = (b*b-4*a*c);
* ******** * * **** * **** = (-b + sqrt(D))/(2*a);
* * * * * **** = (-b - sqrt(D))/(2*a);
** ****** *** ** ** ** ******* = -b/(2*a);
* * *** **** * * *** * *** ** *** =sqrt(-D)/(2*a);
* ** * **** * * ** * *** ***
*** ** **** * ****** **
* * * *** ***** * *** * ** ** ** * ******* * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and * **** ****** *
* * * * * ** * * **** * * * * * ** ** * = %.2f\nx2 = %.2f",x1,x2);
* * **** * * * *

**** * ** ** * ** if(D==0)
* * *** * * **** * **
** * * * *** ** * * * * * ** * * * *** * *** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
*** * ** *** *** * ** ** * ** **** * * ** *** * * * = x2 = %.2f",x1);
******* *** * * * * ****
*** ***** ** **** * *****
** ** ** * **** **
** * *** * * ** ** * * ** * * *** ****** ***** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * * * *
* ** * * *** *** * * ** ** * ** ******** *** = ** * * * * * ** ** ***
* ****** ***** * *** ** * ** * ** ** ****** * ** = *** * ** * * *
* *** **** * ** * ** **
* ** * * * ***** ***** * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* ** ** * * * **
int main()
{
** * ** *** * * ** * **** * * * ** ** * *
**** * ******* * * * * ** * * * %f ***** ******** ** * ** * *
*** *** ** * * * * * * = (b*b-4*a*c);
* ** *********** ** ****** = (-b + sqrt(D))/(2*a);
*** * **** * ******* **** ** * = (-b - sqrt(D))/(2*a);
** ** * * **** * * * * ** *** ***** = -b/(2*a);
** * ** **** * * * * *** *** =sqrt(-D)/(2*a);
*** * * * **** * **** *
* *** * ** *** ****
** * ** *** ** **** ****** **** * *** ** ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and * * * ** **
* *** * ** * * * * * ***** * *** ** **** ** *** * * ** = %.2f\nx2 = %.2f",x1,x2);
*** * *** ** ** ** *

**** * *** * * * if(D==0)
* * *** * * * ***** * * *
**** * * * ** * *** ** ** * *** * *** * *** ** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * * * * * **** * ** ** ** ** * * ****** * *** ** ** = x2 = %.2f",x1);
* **** ** * * * ** * *
* * * * ** * *** **
* * * ** ** *****
* * * ** ** ***** * ****** * * * * * * * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * **** ******
* * * * **** **** * * * ** **** * *** * * * * * *** = **** ** * * * *** **** * *
** * **** **** ** ** *** **** **** *** * **** = * ** * * * * ** * * * *
*** * * ** * ****
* *** ***** * *** ***** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.109
©2016-2026

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users