0 like 1 dislike
13.8k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 13.8k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
* * **** * ** *
int main()
{
**** * * ** ** * ** * *** * * *** * * *** * * *
* ** * ***** * ** ** * * * ** %f * **** * * **** *
* ** * * ***** * ****** = (b*b-4*a*c);
** *** ** **** ** * ** = (-b + sqrt(D))/(2*a);
** * * ** *** * = (-b - sqrt(D))/(2*a);
**** *** ** ** * * * * ***** = -b/(2*a);
** ** * * * ** * * =sqrt(-D)/(2*a);
* *** ** ** ** ** * *****
** ***** *** * ** ** *
** * * * **** * * * * *** ** *** *** * *** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * ***** ** * *
* *** * ** *** ******** * * * * * *** *** ** * * **** = %.2f\nx2 = %.2f",x1,x2);
*** *** *** *** * * * *

* **** ** * * * ** ** * if(D==0)
* * * ****** * * ** *
** *** ** * *** * * * ** * * * ** * **** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * * ****** ****** * **** * ***** ** ******** * **** ** ** * * ** * = x2 = %.2f",x1);
** * *** ** * * **
***** ** * ** * ** *
**** * *** ***** * * * *
******* * ******** *** * *** ***** *** * * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * ****** * *****
*** * *** * ** *** * ** * * * * ** * = * ** ****** * * * * ***** *
*** * * * * ** * ** ** * ** * * *** * ** * * ******* * * = ***** * ** * * * *** **
***** *** * * **** * **
* **** * **** * *** * *** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include *** *** * **

int main()
{
* * * ***** * *** * n, i;

* *** ** * **** * * * *** * * ** &n);

**** * ** * * * * * *** = 1; i <= n; ++i)
* ** **** **** *
*** * * ******** * ** ** *** ** * ** ** * *** % i == 0)
**** * ** ** *** *** * ** * * * **** * * * * ** * * * ** * ******* ", i);
** * * ** ***** * **

* **** * * * *** * ****** ** 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
**** * * * ***
** *** *** * *

int main()
{
* * * * ***** *** *** * *** *** *** * **
******* * * ** * * * ** ** *** * * * ******** * ** * * * ***** *
**** * ** * ********* ** * = ***** *
* * * * ** * ***** *** *
* ** ** * * ** * *
* * * ***** ** * **** ** * ***
* *** * * ** * ***** * = -b /(2*a);
* * ** * * ** *** *** * * * *****
** * *** * * *** *** = (-b)/(2*a);
**** ** * * * ** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = ******* * * ** *
**** ** * * * ****
* *** * ** ** **** * * if(D==0)
** ** * * * * ** ** *** **
* * **** * *** = (-b + ** **
** * * ***** *** * = (-b - * ******
*** *** ***** *** * * * * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** * *
**** ** ** * ** ** ***
* ** ****** *** * * if(D>0)
* * ** * * * *
** ** *** * * * * *** * * * = -b/(2*a);
* **** *** ****** * ** *** = (-b + * * * **
** ** * * ** * ** = (-b - * * ** *
****** * * * ** **** ** *** **** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * **** ***
* * ** * ** * * *
* * ** ** **** ** ** * ** 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** * *
#include * * **
int main()
{
* * ******* ** ** * * * a,b,c;
* * * ** * * *** ** * **** * * *** * * * ** * ** * * ***** *
* * * * * * * ** * *
*** ** ** * * ** ** *** ** * * * ** *
** * ********* ***
* * * * ** ** * * *** ***** * * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ** * * * + * * *** * * - ***** *****
** * *** * * * *****
********* ** **** *****
** * * * * * **** * * if (b*b-4*a*c==0)
**** ***** * *** *** ** **
***** * ** * * * **** ** * * * * * * **** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ****** ***** * + * ** * * *** *
* * ***** *** * * * * **
* **** *** * ** *
** ** *** * ** * **** *
* ****** *** ** *** *
* ** ** * *** * * * * *** *** * * ** ** * * *** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * * * ** *** ******* * ** ** *** * ** * * *** ******
* *** * ** ** * * *** * *
* ** ** ** * * ** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * * * *
#include * * * * **
int main()
{
** ** * ** * ****** ***** *** a,b,c;
*** **** * ** ** * ***** **** *** * ** ** * ** * ** * * **
* *** * ****** *** *
***** * * ** ** * * ** * ** * *
* ** * * ****** * ** *
* ** ** ** * * ** * * * ** * *** *** **** * * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ******* * + ** * *** * * - * * *** ** **
*** ** * ** * *** *
* ** * ** *
* * * *** * *** *** * * * if (b*b-4*a*c==0)
* *** ** ** ****
* * ** ** * *** * ******** * * ***** ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** ** ** * + ** *** *
* * ** * ** ** ** **
* * * * *** * * * * * **
***** *** * * * * * * *
** ** *** * * *** * * *
* * *** ** ** *** ** * *** *** ** ***** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= ** *** ***** ** * * * * * ******** ** **
* * **** * ** * * ***
* ** * * * **** * * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
* ** * * * *** ** * *** a,b,c,d,x1,x2;
* **** * * *** ** * * ******* ** * * * ***** ** *
* * *** ** ** ** ** * * * *
*** ** ** *** * **** * *** *
** *** * ** *** *** ** ** *
** *** * * * * ** ***** *
* * * * ** ** *
****** * *** * ** ** **** * *** *** *** * * *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and *** * **** ** *
* ** * ** ** ** * * *** * * * * * * * * * * = %.2f\n",x1);
** ** * * * *** * * * **** * * *** * ****** ** * = %.2f",x2);
* ** * *
***** ***** * * * ** ** if(d==0)
* * * * *** ** * *
* * * ** * * ** * *** ** *** * * ** *** * ***** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * ** **** *** ** * ** * * * ** * ******** * * **** * * * = x2 = %.2f",x1);
* *** *** ** ***
*** ** * * * * * ********
* * * * ** * *** * * *
***** * ** ** * ** ** ** ** * * * ****** * *** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * *** * * * * ***
** * * ***** ** ** * * ** * ** * * * * * * **** * * * = * ** ** ****** * * * * *
* **** * * *** ** ** ** *** * ** * ** = * ******* *** *** * * **
* * * * * ** *
*** * ********** * *** * * 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
* * * * * * ** ****** * * ** ** *** ** ** *** * * aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
** ** ** ****** * ******* ***** * * ** ** * * *** * ** - (4*a*c);
* * * * * * * * ** * * *** *** * ** * ** * * *
**** * * * *** ** ****** ** * ** * ** * * * * * * * **** * ** **
******* ** ** ** *** * ** * * * * ** *** * ** *** ** ** * * **** **** (-b+spD)/(2*a);
** *** ** * * ** * * **** ** * * ** * * * * ** *** *** * (-b-spD)/(2*a);
* *** *** * * * * * ****** *** * *** *** * **** * **** * ** (x1==x2){
* * * * *** * *** ** ** **** *** ** * **** * * * * * * * * * **** * * * * * * ** ** ******* * * * * ***** * X=%d\n", x1);
** * ** * *** * * *** * * * ** * ** * ** *** ** * *** ** ***
** ***** *** ***** * ** ** * *** * * * * * * ** * * * *** * {
* * ** * * **** ** * ** ** *** ** * ** * * *** *** * * ** ***** ** * ** * * * *** * * *** ** ** * * *** ** * * * *** ** ** X=%d或%d\n", x1, x2);
* ** ** * * ** * ** * *** * *** * ** ** * ** * * * ** * *
        }
** * ** * * ** ** *** * ** ** ** * if(D==0){
** ** * * *** ********* * * * * ** * ** * * * * * *** * * * ** (-b)/(2*a);
* **** * * *** * *** ** ** * * *** * ** * * **** * ******** *** **
* ** *** **** *** *** ** ** * ** * ***** * * * **** * * * ** **** ** ******** * *** X=0");
** * ** ** * * * * ** *** * * *** ***** ** **** ** * ** ** *
* ** * * * * *** *** * ** **** * * * * ** *** ** * * *
** *** * * ** *** ** * ***** * * *** * *** ** * * ** * * * ** * * *** * * ** * X=%d\n", x1);
** ** * * *** * * * * ** * * ** * ** * ** **** * *** ****
        }
** *** * * ** ***** * * ** ** * * * * *** *
* * ** * ** ** * * *** ** ** * *** ******* * * * **** ** ** *** ** ** ** * * ** *** *
* * ***** ***** *** * * * ** ** * **** ***
    }
*** * * * * * * * **** * ** * * ***** ** ** * *
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
***** * * * ** * *** a,b,c,D;
** * * ** * * * * ** * ** x1,x2;
* * **** * ** * * * * * *** * ** * %d * *** * * *** ** * * *

**** *** ** ******* ** * * *
** **** ** * *** ** * *
*** * * ** * **** * * * * * ****

* ** * **** ** * A,B,C;
** * * ** *** * * ** * ** * *

* * * *** * * * ** * ** * ****
* ** * *** * * ** * * * * ** * ** * *** ** * ** * * **** * of %.2fx^2 + %.2fx + %.2f = 0  are real and ** ** ** ****
** ***** * * * ** * *** * * *** * * ** * ** ** = %.2f\n",x1);
* *** ****** ** *** ** * * * * * ** *** * * * * ** * ** * * * = %.2f",x2);}

* ** ** ** * * * * * * * if(D==0)
******** ** ** ******* * * ** ** *** * ** ** * * **** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
* * ** * * ** * ** *** ** * * ** * **** * *** ******* **** **** ** = x2 = %.2f",x1);}

** * ** * * ** *** if(D<0)
* ** * * **** **** * * **** * * ** * *** ** * of %.2fx^2 + %.2fx + %.2f = 0  are complex and ****** ** *** * * *
** ** ** ** * ** * **** ** * **** * * * bb,d,dd;
** **** ** * * * ** ** ** * *** ** * * ** *** * ****
* * ** * ** **** * * * * *** * *** * ** * * ** * *
** * * * *** * *** * ** *** **** ** * * * * *** * * * ** = ** * * * ***
***** * *** * *** **** ** *** * ** * ** * ******* ** * ** *** = *** * *** *

** * ** * ******* * ** 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
***** * * ** * * **
int main()
{
* ***** * * * ** **** *** * ** * * * *
*** * * * ** ******* **** ** * %f ***** *** ** * ** ** * *
* ** * * * * * ***** = (b*b-4*a*c);
* ** *** * ** *** ** = (-b + sqrt(D))/(2*a);
* * * * * ** = (-b - sqrt(D))/(2*a);
* *** **** ** * ** * * * * = -b/(2*a);
* * * ** * * * *** * * * =sqrt(-D)/(2*a);
* * * *** ** * * * **
** ** ******** ** * **
* ** * ** ***** * **** ** **** ** *** ** ** * *** * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and *** * * *** **
** ** ** * ** * * * * * ** * * *** * * **** = %.2f\nx2 = %.2f",x1,x2);
* * * * * * *******

* ** ** * * **** ** if(D==0)
******** ** * * *
** *** ** * ** * ** **** **** * *** * * ** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** * ** *** ** **** ** * ***** * ** * *** = x2 = %.2f",x1);
*** ** *** * **** ***
* *** * * * * *
** * * ***** **** ***
* *** **** * * * * ** * ** **** ** **** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * ** * * *
** * **** * ** **** ***** * ** * * * ** * ** = **** ** * * *****
* *** * *** * ** ** ** * * *********** * * * * = *** * ** * * *** * * * **
* **** * **** *** * *****
** ** ** ***** *** * * ** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
**** * * **
int main()
{
* * *** *** * ** *** * * *** **** * * *** * * * *
* ** ** ** * *** * * * * * ** %f ** * * **** **** *** *** * *
*** *** ** * * * * *** = (b*b-4*a*c);
** * * * * ** * * ** = (-b + sqrt(D))/(2*a);
* * ** ** * ****** * = (-b - sqrt(D))/(2*a);
*** *** ** ** * * * ** = -b/(2*a);
*** ** *** * ** **** ** * * =sqrt(-D)/(2*a);
** * * * * * * ** * ** ***** *
* * * * * * * ** *
* * * **** * ** * * *** *** *** * * **** * * *** * * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and * * ****** ** *
* * * * * * * * ****** * * ** * * * * * * = %.2f\nx2 = %.2f",x1,x2);
* *** ** *** *

** ** ** * *** ** * if(D==0)
* * *********** ***
* * * *** ** ** * ** * ** ***** * ** * * ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * * ***** ** * *** * ** ** **** * * * ** = x2 = %.2f",x1);
** * * * * * ********** *****
* ** * * * * ** * * * *** *
* ** * * * * * ** * *
**** ** ** **** * ** * * ** ** ** ****** * * ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * ** **** ** * *
**** * * *** *** *** **** * ***** *** * * * * ** * *** = *** *** * * * ** ** *
*** * * ** * * * *** ** *** ** ** * * ** = *** *** * * ** *
*** **** ** * * *
** ** *** ******* *** * * * *** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.80.21
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users