0 like 1 dislike
5.8k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 5.8k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
* * ** * * *
int main()
{
* ** * * *** ** ** * ** ** * ***** * ***** ** **
*** ** ** ** ** * **** * * *** %f * * ** * ** ** *** ** *
* **** * * * ** = (b*b-4*a*c);
*** *** *** * * * = (-b + sqrt(D))/(2*a);
** ** ***** *** = (-b - sqrt(D))/(2*a);
***** *** ** ** * ** * * = -b/(2*a);
* * * * * *** ** * * * * **** =sqrt(-D)/(2*a);
* * ** *** * ** ****** *** * *
* * ***** * * * * *** **
** * * * ** * * * ***** * * * **** * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * *** *** * * * **
** ** ** ** ** *** *** * **** ** * * **** *** = %.2f\nx2 = %.2f",x1,x2);
* ****** **** * **

* ** * * ***** * ** * * ** * if(D==0)
** *** * * ** ***** * *
* *** * ****** ** * * * * ** * * * ***** * * * * ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
*** ****** ** ** *** ** * * ** ** * ** * *** = x2 = %.2f",x1);
* * * ** ** *** *** ** ***
***** * *** * ***** *
* * *** * ** * * *******
* *** * ** * * *** *** * ** **** ** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * **** * * **
* ** * ** ** * * ** * * * * ** **** *** * ** * * = * * * ** * ** **
* ** *** * * * ** ***** ** *** * * ** * * * ** = * *** *** ** * * * ****
* * **** * * ** ** **
* * * * **** ** ** * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** * **

int main()
{
*** ** ** * **** n, i;

** ** * ** * ** ** *** ** ** * ** &n);

* * * * ** * * **** * * = 1; i <= n; ++i)
*** ** * * * * ****** * *
* **** * * * *** **** * * *** * ** * ***** **** % i == 0)
****** ** ** ** ** * * * ** ** * ** **** * * ** *** *** *** *** * ** *** * ", i);
** ** * ** * ** ** * **

** **** * * * * *** * ****** 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** ***** ** *** ** * *
* * ***** ** *** *

int main()
{
**** **** * * ** ** * * ** * * *
****** ** ** ** * * * ** ** ** *** **** * * *** * ** *** ** * * *
* * * *** * *** * ** = ** * *
* ****** * ** * * ***** *** * ** *
*** *** * * ***** ** * *
* *** **** * ** *** **
* * * ** * ** ** ** = -b /(2*a);
* ** ** * * * **** * *** ** *****
* **** * * * * *** = (-b)/(2*a);
*** ** ****** * * **** ** * * * * * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * * ** * ** * ** * ** *
* *** * ** ** * *
*** ** **** * **** * * * if(D==0)
* * ** * * ** * *
* * *** **** ** ** ** = (-b + ** ***
** **** * * ***** * * = (-b - ** **
* * ** ** **** **** ** * *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * ** * ** ***
*** *** * ***** * * *
***** * *** * *** * ** ** ** if(D>0)
** * * * ********
****** * * * **** * * ** *** = -b/(2*a);
*** ** * ** ** ** * * = (-b + * ** *** *
* * * ** ** ** *** ** = (-b - * * ****
** * * * ** ** * *** ** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = **** * * **** *** *
**** *** * ** **
* * **** *** *** * *** 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * * *****
#include * * * *
int main()
{
* ** * * **** * ** a,b,c;
** * **** *** * * * ** * * *** ** ** ** ***** ** ** * *
** ** * * * ** ** ***
* * * * * ** *** ** *** * **** **
* * ** ** * *** *
* * * * *** * ** * * **** ***** * **** * *** * ******** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ** *** ** + ** * ***** * * - * * *** * *
** * *** * * ** ** * *
* ***** * *** * **
* ** **** *** * * if (b*b-4*a*c==0)
* * ** * * ** * * *
*** *** *** * ** * * **** ** *** * * * * * ***** * ** * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * ** + *** ********
** ** ***** * * *** * ** *
*** * ** * **** *
** **** ** *** ****** *
** ** * * ** ***
* * ** * ** **** ** * * * **** **** ** ** * ** **** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = ****** * ** * *** * * ** * ** *** * * *******
* ** * * * ** * * *
* * * * * * * *** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** * * * **
#include * * ** * ***
int main()
{
****** * * * * ** ** * a,b,c;
** * ******** ** *** * ** * * ******* *** ** * * * *
*** ** * * * ** ***** *
* ** * ** **** ** * ****** *
* *** * *** ** ** ***** **
* ** * *** * * * ** * * *** *** * * ** ** * ******** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * *** * * * + *** * ** - * * * *
*** * ** * ** * ** *** ***
* ** * *** *** *****
* * *** * *** * **** ** * * *** ** if (b*b-4*a*c==0)
** * * ** ********
* ***** * ** **** ** * ****** *** *** **** *** *** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * **** * * + ** * * * *
* * * *** * ** ***
*** ** * * *
**** *** * ** * ** ** ** ** **
* * ** * * *** *** *
**** ** ** * * * ** * * * **** ** *** * *** ** ***** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= ** ** * ** * ** *** * ** ** * * * ******* * * ** ** *
***** ** *** ****
* * ***** * * * ** ** * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
**** * ** * ** * **** ****** a,b,c,d,x1,x2;
*** * * ** * ** ** ** **** * ** * * ** **** * ** *
*** ** * ** ****** **
** ** * ** * * * *** * * * * *
* * * * * ** * * ** * ** * *
** *** * * *** ** ** ** **
** * * ****** * * * *
** * * * * * * ** * * * ** * ** * * * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and ***** * * * *
* * ** ** *** ** ** * * ***** ******** * *** * ** ** *** * = %.2f\n",x1);
*** * * ** * * * * * ** * ** ** * * *** ** ** **** = %.2f",x2);
**** * * * * ***
* *** ** ******** * ** * if(d==0)
*** *** ** * * * ** ** *
*** ** ** * * * ** * *** * * * * * ** * ** ** * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ** * **** ******* * * ** * *** * ** * ** * ** * = x2 = %.2f",x1);
* ** *** ** * *** * *
* ***** ** * * *
**** * * ******* **
** *** * * * * * * *** ** ** * * * ** ** ** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and ***** * * *
** * * * ***** * * ****** * **** ** * * ******* * *** ** ** * = * **** * **** ******** *
* ** * * * * * * ** *** *** * *** * * **** * *** * = ** * ** * * *
* * * * ***** * ** **
** ** * ** **** * * 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
** * * *** * ** ** * ***** **** **** * * * aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
* * **** * ** ** *** *** ***** * *** - (4*a*c);
*** * * * *** * * * * ** **** * ** ** *
** ***** ** * ** * ** ** ** * * * ** ** ** * * **** ** * ** *
* ** * ** *** * ****** ** * * * * * * * **** * ** * * ****** (-b+spD)/(2*a);
** * * ** * * ** * * ***** ** * ** * * * ** * * * ** ** (-b-spD)/(2*a);
** ** *** * ** * ******* * ** ** *** * ** ** **** ************ ** (x1==x2){
** * * * * *** ******** * * * ** ** * **** ** * ** * * * ***** * * * ***** * * ** ** * ** *** ** ** * * ** ** X=%d\n", x1);
* * ** * ****** * **** *** ******* * *** * * * * * ** * ***** * *
** * * * ** ***** * ** **** * * ****** * * ** **** ** ***** ** ** {
** ** ** * *** ** ** * * ** ****** * * * ** ** ** ** ** * **** ** * ***** * **** *** * * * * ** ***** *** *** * * X=%d或%d\n", x1, x2);
* * ** * * * ** ** ***** * * ***** * ** * *** * * * ** ** * * **
        }
** * * ** ** ***** * ** **** * * * *** * * * if(D==0){
* ** * * * ** * ** * ** **** * ** * *********** * **** ** *** (-b)/(2*a);
************* *** ** * * * * * ******* *** * * ** ******** * * * *** ** *
**** ** * ** * ** * * *** *** * * * * ******* * ** ** ** ** ** *** * ** ******* * *** ** * X=0");
* * * **** * **** *** ***** *** ** ** *** ***** * *** * **
** * *** * * ****** ** *** ** * * **** ***** * * ** ** ** **
****** * **** ** **** * ** * * ** * *** ** * **** *** * **** ****** * * ** ** *** * * X=%d\n", x1);
* **** **** ** * * ** ** ** ** ** * * ** * *** * *** ** ** ***
        }
* *** * * ****** * * * * ** ** ** *
** ** * ** * *** ** * ** ** * ** * ** ******* ***** *** * ** ** *** * * * **** ** ** ****** ** *
* *** * * * ** * * **** * * * ** * ** *
    }
** **** * *** ** ** *** * * ** *** **** * *** * *
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
** * * ** * * ******** ** * * a,b,c,D;
**** * * ******* ** * * **** x1,x2;
** ** * ** ** ** **** * ** ** %d *** * **** ***** ** *

* * * * * ** ** ** * * * ***
**** **** * *** * * ** * *
** ** * * * * ** * * ***** **** *** **

*** ** * * ** * * ** A,B,C;
** **** * **** * ** *******

* * ** * ** ** ** ** ** ** ***
*** * * * *** * * ** ***** * * ** *** *** * ***** ***** ** * of %.2fx^2 + %.2fx + %.2f = 0  are real and ***** ****** **** **
* * ** * *** **** **** * * * ***** **** * * * *** * = %.2f\n",x1);
***** * *** * ****** * **** * ** ** ** * * * * **** * * = %.2f",x2);}

** ** ** * * * * * if(D==0)
* * * *** * ******* ******* * * * * * ** ** ** **** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
*** * * * **** * * ** * * * ******* * * ***** = x2 = %.2f",x1);}

** ** **** * * * * * * if(D<0)
*** ** * ** * * ** ** * * * ** * * *** *** ** * of %.2fx^2 + %.2fx + %.2f = 0  are complex and *** * * **** **
** ** ** * * ******** * *** * * * * ** * bb,d,dd;
**** * * * * * *** *** ****** * *** * * ***** ** **
* * * ***** *** * * * *** ** * * *** ** *** ** **** * **** * *
* **** *** * **** *** * * * * ** * ** * * *** * * * * **** = * *** * *
* * ** * ** * * **** ** * * ***** *** ** * *** * *** * * * = * *** * * * *

**** ** * * ** **** * 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* *** * * ***
int main()
{
* ** ** * * ** ** * ** ** ***** ******
* ** *** * * * * ***** ** %f * *** * * * * * ***
*** * ** * ** * * = (b*b-4*a*c);
* ** ** ** *** * ***** = (-b + sqrt(D))/(2*a);
* *** ****** ** ** ****** = (-b - sqrt(D))/(2*a);
** * * * ** *** * ** * ** * * * = -b/(2*a);
** **** * *** * * * ** =sqrt(-D)/(2*a);
* * ** *** * ** * * *****
*** * *** ** ** ***
* * **** *** * * * **** ** * * ** ***** ** *** **** of %.2fx^2 + %.2fx + %.2f = 0 are real and * ** * *** ****
** * * **** *** **** * * * * **** *** ** ** * *** ** = %.2f\nx2 = %.2f",x1,x2);
** ***** ** ** ** *

** ** ** * * **** * * ***** * if(D==0)
******* ** * * ** ***
** * * ** * ** *** ****** * ** * ** * ** * ******* * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ** **** * * ** * ** **** ***** *** * * * ** * * ******** = x2 = %.2f",x1);
** *** **** * **** **
* * *** ** * * * * * * * * **
* * * * * * *
** * ** * *** * *** **** ** ** ** ** * *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * *** * ******
* * ** *** * **** ***** *** ** * ** ** * ** = * ** *** **** * ** *** *
**** * * *** *** * ** * *** *** * * ** * * * = * * * * **** ** * ** ***
** * ** ** * * ** *** * *
*** *** ****** ** * **** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
*** *** *
int main()
{
** * *** * *** * *** * ** ** * * * * * *
** ** ** **** * ** ** * *** * * %f * *** * *** ** * *
*** ** ** ** * * * = (b*b-4*a*c);
* ** * * *** ** ** * * = (-b + sqrt(D))/(2*a);
********* * **** **** * = (-b - sqrt(D))/(2*a);
* ** ** * * **** * *** * * = -b/(2*a);
** ** ** * ***** * ** * * **** =sqrt(-D)/(2*a);
* ***** * **** * ** * *** *
** * *** * ** *** ***
* **** * ** * * *** * **** *** ** ** * *** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and * * ** ****** *
*** **** * * ** ****** *** * * ** **** * ** * * * = %.2f\nx2 = %.2f",x1,x2);
******* * ******* ** ** *

* *** * ** * * ** * * if(D==0)
** ** * * ** ** *
* * * * **** *** * ** *** * ****** * **** * * * * * **** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ******** ******* **** ** *** ** * **** * * ** * * ***** = x2 = %.2f",x1);
* **** * *** ** **
*** * ** ******* **
* **** * * ** ** ****
* *** ***** * ** * * * ***** *** * * * ****** * * * ** *** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * * * * * *
**** ** * * * ** ** ** * * ** * **** ** ** ** * * = * * * ******** ** ** * * ***
** *** ** * * * *** * * * ** ** * ** *** **** * = * * **** * **** * ***
* *** ** *** ** ** ** ***
** * * * ***** ***** ** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.166
©2016-2024

No related questions found

12,783 questions
183,443 answers
172,219 comments
4,824 users