11-01 Exercise 3: Fibonacci numbers

0 like 0 dislike
11.8k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列：0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始，其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2)，F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n，輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 11.8k views

93 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 * * *   ** ***   *      * ***  F0,F1,Fn,n,a;
 * *  ***   **** *  **  *  *

*** ** * *    * *  *** *   ***  * * ***   * * **   &a);

*  *  *** * ***      *****   **  ***   * * *
**   ** ***    **  *  * **
  **  * **     ** ** * *** ** *  * ** ** *  *  * *  * *
** ******* *** *** **  **  * *      *    *   *    **** *  * 
 *   *   *  * ** ***    ******* * *   * * * * ** * ** ****
    }


 *** ****  *  * ****     *  *  * * ** *  ***  *    Fn);

 * **  ***   * **    * ** ** ** ** 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  ** * * * *
int * * ***
{
int  **  **  *
  ****  ****           ***   *
if(a==0) printf(0);
else if(a==1) printf(1);
else {
******   * * * ****  ** ***  ** ***  *** *** 
* *  ***  ** * ** ***  *** **  ** *  * **  * * ** * = c0+c1;
  **** *   *   * * *  ** * ** ** *   * *  * *  **   = c1;
*     ** ****  * *   *    * *  *****   *  ***    * * = cb;
 *   ** * *  ***   *  * ***
** ** ** ** *     * ****     **** * **** ******  *
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    * ***  

int *   * 
{

int *   *   ** 
  ** *   * ** *          *   *

if(a==0) printf(0);
else if(a==1) ** **
else {
 * ***    **   ****** ** *  *  *** * **  
  * * * *****  *   ** * ** *  *** *  *  * *  **** = c0+c1;
** *      ***   * ** **  *    ** **   ** **  ****  = c1;
 * * ****  **  *       ** *  **    **  ***  **  *      = cb;
 *** *******  *** * *** ** ***
* ****  * *  *   ** ***  *   *****  ** *** *  * 


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **  ***  ** * *

int main(void)
{

int  * ****  
*  **  ****  * *  **     

if(i==0)   ** **         *** *  
else if(i==1)   **  *  ** **  ** 
else {
   * **** * *      ** **** *  *  *  * *
*** ***  *** * * *  *    ***  *****  ** ** * ***** **** *    = f0+f1;
   *    *  * *  ** **    **** *   *     *    **   * * = f1;
*   *******  ** **  *  * **** * **  *** *   **  **  * = fn;
   *** *** * * ***  *  **  * *
*  ***    * **  * **  ****  *  * ***  *****   * 
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include     *    *   **

int ***     
{

int   *  * **  
 *  ********  * ***  * *

if(i==0) printf(0);
else if(i==1)  *  **  
else {
*     *********** *   ***  * *******      * *  **  
    ****  *** ***  **      *  *   **  * *  **  ***** = f0+f1;
*** **   *    *  *     ** * *  *** *  *  *  ** *** * * * **  ** = f1;
*** * **   *   *****  ** * *   ** *** *    *  * ***   *** = fn;
   *  * ** ** * * *   *******
   ** * ***   ****    ** ** ** **  * *  * * ***
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
** ***** * * ** * * *** * * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
***** * ** * *** * * ** * ******** * * * d;
* * * * *** ** * * ** * * * * ** ** (d=2; d<n; d++)
* ** * * * * * * *** * ** *** ** ***** * **
* ***** * ** ***** * * * * ** * * * ** *** (n%d==0)
* * *** ******* * ** * * * ** * ** ***** * ** *** * ** ***

   }
***** * ** **** ** *** ** ** * *** * ** * ******* *
* ** * * **************** * **** ****** * *
* ** *** * ** * * * ** * * ** * ** ** *
** * * ** * * * ** * * * * * * *** ** *** ** *
* * * **** * * * ** * ***** ** ** * * *** * * * ** ** * **** ** (e==0)
* ***** * * * *** **** ** ** ** ** ** *** * * * ** * *** *** * * **** **** ** *
* *** * ******* * * * ** * * * ** * *** *** * ** ** **** *** ** ** * *
** ****** **** *** * * * **** *** * * ****** *** ** * * **** *** ** ** * *** * ** *** * **** ** ****** ");
* **** **** ** * ** * ** ** **** ***** ***** ** * *
*** ** *** * *** * * ** * * * * * *** ** **** ***** **** * * *
*** * * * ** ** * *** * * * * * ** *** *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
****** ***** *** ***** * ** ** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
*** ** * * *** ****** *** *** **** * ** * ***** d;
* **** ** * * * * * * * * ***** ** * * * ** * * (d=2; d<n; d++)
* *** * * ** ** * * ** ** ****** *
****** * * ** *** * ** * *** **** * (n%d==0)
** *** * * * ** * **** * * * *** * ** ** **** * *** * * ** *

   }
** ** ** * * * * ** **** ** ** * * *****
**** **** ******* ** * * * ** * * * *****
* * * * * **** * ***** * ** *** * * * * *
* *** * ** ** ***** * * * ** * * *
** ****** * * * *** ***** * * *** * ** *** ** *** **** * * * (e==0)
** * ** **** ** **** * * ** * *** ** * * ** **** * * * ** * *** * * ** ** **
** ** * ** ** ** ** ** ** ****** * ***** * **** ** * * * ******
* *** ** * * *** ** *** ** ** * * * * * ***** * ** * ** * * * ** ** * *** ");
********* ** *** ****** * ***** *** * * ****** * * **** ** ** * ***
* ** * * * * * **** * * ** * * **** ******** * ** **** **** **** * * * * *****
* * ** * * * * * * * ** * *** *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
  *   *         **  **** **   ********  * *  *  ***** *      d;
  **    * *  * *   * *  ***** ** **** *   *** ***** ******* (d=2; d<n; d++)
 * * *  *****    * * *  ***** ***** ***** **  **** **** 
 *  *  **  * *     * * **   ** ** ** ** ** * ** *****  **  * *  (n%d==0)
***** *  *** ***  ** **** *   ** *   ** * ** ** *********   *  * * **  *  ****    
   }
**  * ** * * **    * ****  * *  **     *** **   * *   **  ** 
 * *  *****  *****  *  *   ****   *    *******   *      
 * *     * ** ** *** * **** *****    **    ** ** ***** 
    ****** ******* *  * ****** ******      ** ** *** *****
 *  ** ** *  *   **   ** **     ********* *  *  ***   *  *   ** *  **   * (e==0)
*  * * *  ***  * * * *****  * *     *******  * * * ***** ***************** ****  * *  *   ** **** *    ***   * *
*** ******    *    * ****  ***  *  ***   *   *     * * ** ********* *  *  **** * ** **  *
 * * **    ******  ***  ***  *   *   *     * ****       * * *** * *  ** * * *****  *      * **   *     *  **** * *  * **   ");
  *  ** **       ** *  * ****** **  * *   ** ***********  *    *** *     *   ** *  *  
   *  **   * *  **   *  *   * * *  *  **  ** **   **   **  ** ******** ** * *** **  ******      **  
*    **   **    *      * *     ** ***   * ** * * *  *  
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
  * *   **  * ** *  * ** ** Fn,t1=0,t2=1, n,input;
** *** * ***** ***** **       * ** * *** * *****    

* *   **   * *** *** *** *   **** *     * **    n++)
***  *   **   **      ***  *** 
  * *  ****** *  ** *   *  *       *    **  *  ** *  **** = t1 + t2;
   * * ** **    *  ** * *** *  ***** * * * ***** * **  
* **   ***** ** * ** ******** **** **      * *  ***  **** 
    }

**   * * ******   ** ** **** *  **  *  ****** ******

* ***      *** ** *  *  ***  *** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
    ***** *  * **  **  ***   * Fn,t1=0,t2=1, n,input;
 *  **** ** ***  * **  * *  ***      * *           ******* 

*  ***** * **** **   ** ** ***     * ******  *** n++)
 * *  *  * * **   * * **  * **** * **
** *  **    *** **    *** *  **   ****      * *** *  * *  = t1 + t2;
  **  ** * **  **    **  *          ***  ****  *  * *  ** *
  ** * * * **  *  ****  * *******  ** * * *     *** *   **   *
 **  *    * ****  *  *  **** 

*  *** * ** * **** ***** * *  * *    *  ",Fn);

 * ** ***   * ******* *  * 0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.100.101
©2016-2025

Related questions

0 like 0 dislike
46 answers
11-30 Exercise 1: Fibonacci numbers (Array)
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 7.3k views
0 like 0 dislike
99 answers
11-01 Exercise 1: Find out all prime numbers between n and m
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 14.3k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 6k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 9.7k views
2 like 0 dislike
67 answers
11-09 Exercise 2: Reduce the fraction to lowest terms
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 10k views
12,783 questions
183,442 answers
172,219 comments
4,824 users