11-01 Exercise 3: Fibonacci numbers

0 like 0 dislike
9.2k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列：0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始，其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2)，F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n，輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 9.2k views

93 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
   ****     ***  *** * * * * F0,F1,Fn,n,a;
*  ** ****    * ****  ** ** ***   

 ** * * * * **** ** **  ** *****  * **         &a);

***** *** *  ***** * **    *   ** *    ***
* ****  *  *   ***  *  ***   *
** ***    ** * *   *** * *    **  **  **     ** *   
*  *   *   **** * * * ** ** *** ** * ** * *        *  * *
 *      **  * *** **  ** *** *** ****  ***   **** *  **
    }


  **   *****   *** * * * *      * ****  *****  Fn);

 ******        * *  *    * *  ***   ** 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** *    ******
int  **  *
{
int      *****  *
** *  ** *** *    *  ** *** 
if(a==0) printf(0);
else if(a==1) printf(1);
else {
  * * ** * * *   ** * * ***  *** ** ** *     * *  
*** *   * ** ****  * **** **      ***   ***  * ** ***  *  = c0+c1;
 *  * * ***            *** *  **** *  * *   *   ** ****     = c1;
* ** * * *  *  *** * *  ***** *    ****  * ****    * *  = cb;
**  *  ***  ** * ***** * *  
*  *** * ** *  **       ** * ** ** **  ** **   
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include     **   * ******* 

int    **  
{

int    *     * *
** *  ***** * *  *  * * **   * *

if(a==0) printf(0);
else if(a==1) ** ** 
else {
  ****  * *  * *  ******  ** **** ***  ***
* * *  **    ** *   *  **     *** ***   *** *** *** ** *  = c0+c1;
           * * *  * *  ** ***   **   * **** ****   *  *      = c1;
   *   ***  * ** * **    * **     ** *  *    **** = cb;
 *   **  ***  *    ** * ** * 
* * *   * * * **  **     *  *** *  * * * ** * * *    


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *  *  ** * *

int main(void)
{

int * * *  ** * 
* * **  ***** * * ** * 

if(i==0) ** ***  ** * * * ** 
else if(i==1) ***   * * *   ** ** *
else {
 *   *  * * **       * ***   ****   *** * **
* *     * * ** *   *  * **      * **  * * *   **    *  = f0+f1;
 **** * ** **** ***   ** * **  *** * ******* *****  ** *    = f1;
*  * ** ** ** *    * *   * ** **    * *  *** *   ****** = fn;
 **   **   ***  ** **** * ** *  
   * ** ** **  **  ** * *   ***  ** * * ***  * 
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **** * ****** *

int  * *  * 
{

int ** *  * ** 
** *** ** *   * *  ** * ** ** 

if(i==0) printf(0);
else if(i==1) **** *  
else {
 *** * ** *     ****     *** ***   * 
** ** *  ****  **** * **  ** ***  * *** ***   **  **** * *******   = f0+f1;
***  ** ***  *    *** * * *   *** **  *  **** *  ** *   = f1;
     * *  ****    ***  *  *  ** *  *****   * *     *     = fn;
*** * ***   *   **    **    *
   ***     **** ***  * * **** * ** *** **     *
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
** * ** * ** ** * **** * * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
****** ** * *** ** *** * * * * * ** * ** * ** * d;
* ********* * * ******* * * *** * ** (d=2; d<n; d++)
** * ** *** ****** * ** * ** *** ***
* *** ******* ** * *** * ** ** * * * *** *** (n%d==0)
*** * ** *** * ***** *** *** * ** *** * * * * * ***** ** ******* * *

   }
* * * ** ***** ****** * * *** * ****** ***** *** ** *
*** * ** * ** *** * ** *** * *** ** * * **
* * ** * * * *** ** * ** * * * * * **
** *** * ** * ** *** ** * ** * * * * ** * ** * ***
** *** * * ***** * * ** **** ** * **** ** *** ** * * ** (e==0)
** * ****** * * *** *** ** * ***** ** ** ** * * ***** * * ** * * ***** * * * ***** * *
*** * * **** *** *** * ** ** * * * * ***** ** *
* *** * * * * * * * ****** *** **** * * * **** ** * * * *** ** * *** * * ** ** *** ** ** * ** ** *** ** ");
**** * * ** * * * * ** * ** * * ** * * ***** *** * ****
** * * * * * * * ** ** *** **** * * * *** ** * * ************ **** *
* ** ** ***** * * ** **** *** * * *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
** * * * * *** ** ** ******* %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* *** * * *** * * ** * * * ** * *** * * *** d;
* * ** **** ** * * * ** * * * ** ** *** ** (d=2; d<n; d++)
*** ***** ** * * ** **** * * * * * * **
* * * *** * ** *** *** * *** ** ** ** * ** (n%d==0)
* * * ** **** ** *** * * * * * **** *** * *** * * ***** * *** * ***

   }
* *** ** * ** * ** * * * * * * * * * * * * ** *
* ** ****** ***** * * ** ** *** ** * * *
** * ****** * *** ** *** * ** * ** ** ** * *
**** * * *** * * * * *** * ** ** ** ****** * **
** * * ***** ** * * * * * * * * ** ***** ** * ** **** *** *** * (e==0)
* ** * * ** ** ***** * * **** * * * * * **** * ** ******** **** *** * ** *** **** **
** ** ** *** * ** * **** ** * * * ** ** ** ** *** ** *** *
** * ***** * **** **** ** ****** ** ** ** ** *** **** ** * * * *** ****** * *** ** ** ** ** * ");
* * **** * * ** *** ******* ** **** * ** *** * * **** ***
* * ***** **** * * *** * ** * **** *** *** * * ** ** * * * ** ******* *
** *** * * * ** * * *** ** **** * *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
**** ** **  *        * *   * * *  ****      ** ** ***  *  d;
  *  **   ** *   *   ** *  *   ** * *     * *  * ***  *  *  (d=2; d<n; d++)
*  ***   *   ** *  *    *  ****  ** *****   * *   **  ** 
* ****  ** *** *** *** *  *****  * ***** ** ** ** *   (n%d==0)
** ***   *  *** *** ** **      ***  *  *****   **   ****    *   **  * **  * *******  
   }
 * * *** *** *** **  *        ** *  ** * *     ***  **  ** * * **
 * ** **  * *   ***  ** * * * **  ** * * ****** *  * *    *
  ** * ** *  * *******  **  ****** * * * *  *** *   * 
******   ** *    ***  *    *  **  *   *** *  **  **  *  *  *
  * * *       *  *  * **  **       *  **** * **  *  *  * ****** **  ****  *  * *** * *  (e==0)
* * * * *  *        ** *  ****** **** *  * * *******  * ***   ** * ** *** *     **  *** * * * *** *********  *   ****
** ***  *  * *      * **  * * *** * * *  *   * ***  * ***     * ***    ** *
 **    * * ** ** * *   ****  *** ****     * ** ***** *  *   * **** ****    **** ***    *** *   **  *  ** *  **    ");
  *  * **      * ****         * * *   **    **  *    **  **  **    **     *  *   **  * **
     **   *** **  ***   **  * ***     * * **   * ** **    *   *    * *      * *** * ** ***  ** **  *  *
****  ****  *  * *   **   **  ****   * * **  ** ***  *  
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
  *   * ** * **   * ** *  *** ** Fn,t1=0,t2=1, n,input;
** * * **  ***   * *  *** *    **   ***     **** ***   ****  **

*** ** *  ** **   *  * **   ** *  *** * * n++)
     * *    * *  **  * 
    ****** ** ****** * *****  *** * * * *  **  **** = t1 + t2;
*  **** *   **   * ***** ** *   * ** * **  *  **         *  **
*    * **** *     *****  *     **  **   * *******  *  *
    }

*  *  * * *  **  *      **    *  ** * *   * * *

*    *  * *  ***** **    * *  0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
* ** *** * *  *   ***    Fn,t1=0,t2=1, n,input;
*  ***   *  *  *** * ***   * **** *  * **   **    * * * ****

** ********   ***** * ** **  * ***** * **   n++)
 * **  *** ***   **  *   * 
 ** ** *  * *   *  *  ***     **  **    *   * *     *  = t1 + t2;
*  * * * *     *    *   ** *  *  *  **  **  *   ***   * *  * *  ** 
  **         *   ***  ******   ***  ** *  *  ** * * ***
*  *     *   *** *   * * 

*   * * *     * *** * *  * **  **  ** * * ",Fn);

**  ****  * ** * * * ** *  **  0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.115
©2016-2025

Related questions

0 like 0 dislike
46 answers
11-30 Exercise 1: Fibonacci numbers (Array)
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 5.8k views
0 like 0 dislike
99 answers
11-01 Exercise 1: Find out all prime numbers between n and m
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 11.5k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 4.8k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 7.8k views
2 like 0 dislike
67 answers
11-09 Exercise 2: Reduce the fraction to lowest terms
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 7.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users