11-01 Exercise 3: Fibonacci numbers

0 like 0 dislike
2.9k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列：0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始，其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2)，F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n，輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 2.9k views

93 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
* **********   ** * * *   *** *  F0,F1,Fn,n,a;
 * * **    * *     *  * **  

*  ***  ** * ****  **  *** * ** *   *     *   *   * &a);

** *** *  *   * *     **  **    *  ** * *
*** *    ** *  ** *  ***
 **    *****   *** *  **     ** *** *   ***    ** **   *** ** **
**  * ** ** * * * **** ** ***   * * *    *** *** ** 
* * * * ** **** * ** ***  *  * *     ****   * ***   ** * 
    }


***  * ** **** *  *   * ****** * *  *    ** *   * Fn);

   * *   ***** ** * **  ** ** ** 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** **** *  *** 
int   *   
{
int  *       
**  *  ******** * *** * *  *  * 
if(a==0) printf(0);
else if(a==1) printf(1);
else {
 ** *   *       * * ** **  ******    * *    **** **
*******  * **  * *    **  * ** **   ** * *     *   = c0+c1;
   *  * * **** * *  **    *  * *** **** *  ***  * ** * ** = c1;
* ***** *  *** *      *** *  ***  *** * ****  **   * *   ** *    = cb;
  **  *  *      ** * *    *
** **   ***  **** **  ****** *  *  **** **   *   *  *
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * *  *  ***** * 

int   **   
{

int * **** *  *  
* * ****   ** * *****    **

if(a==0) printf(0);
else if(a==1)  *   * **
else {
 * ***  **   **** ***  * **  **  ***    *  
 **  ** * * *      **        **  **   * *  ***** * * **  ** *  **   = c0+c1;
*   * * *   *** *  ****  ** *** *  ****   * ** **    = c1;
******     * *   *  *** * *  * *    *  **  *    **    ** = cb;
    ** *  *** * ** ** **    
   * *     * ***  ********  ****   * ****** ****** 


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *   *** * ***

int main(void)
{

int   ** ****    
*  ** ****** ** * * *  ** * 

if(i==0) *  *  * * *  *  * **
else if(i==1) *    *     *** *  ** 
else {
 ****   ** **** *  *****   ** *** *   **  ***
 ** *  **** ******    *  *   *   * * **   *  **  *     = f0+f1;
**  *  **  *  ** * *  * ***   **   * * *** *  * * **  **  = f1;
 ** **   *****   * **   * ** *  * * ********    *   = fn;
* ** *** ***   * *  *     ***  
* ******   ******* *   *  * *   *    * **    ** * * ** *
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ***   *  **** ***  *

int  ***  
{

int  ***   *  *
*****      **     ****  * 

if(i==0) printf(0);
else if(i==1) ***  * 
else {
 *******  * ******** **** ** ** *   **   *   
 **  **  ** ** *    ***   ** *    ** **** *** *** *  ** ***** = f0+f1;
 *   **   * * *  * * *  ****    *** **  **   * **  **  *   = f1;
    **   ** * ** ** **  **  **    * * * **   * **  *****  ** = fn;
     **  * *** *  *   *  **
  * *  *  *     *   ***  *   **** **      ** *  
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* ** * * ** *** * * *** * **** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* ** * * * **** * * ** * * ** * d;
** ** ** * ***** ** ** * **** * ** ** * (d=2; d<n; d++)
* ** * ** * ***** * ** ** * ***
* * * * ** ***** * ****** * * ** (n%d==0)
*** *** * *** * * * ***** ** * * ** ** ** * * * * * * ***** *

   }
* ** **** ** ***** * ** *** **** * ***** * * * * * * ******
* ** * ** *** * *** **** ******** * ** *
* ** * * * * ** ** * * ** * **** * **
******* ** * ** ** **** * ** ** * ********
* *** * * *** ** *** ***** * * ** ** **** * * * * (e==0)
** ** *** * ** * ** *** ** ******* * ******* **** * * ** * * * ** **** ******* * ** * ** **
* * * * *** * *** ** * * * * ***** * * * ** *** ** ** ******
*** *** * ** * *** ** ** ** ** * ****** * * * ** * ** ***** * * ** **** * ***** ** ** ** ");
* ****** * * ** * * * * * ***** ****** ** ***** ** ***** ** * * ***
*** **** * ** *** * * ** * ** * * * ** ** ** * * * * * ******** ** ** * * * *
* ** *** ** *** * * *** ** *** * ** ****

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
*** *** ** **** ** ** * * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
**** * ** * * *** * * ** * * *** ** * * * * d;
* * * *** *** * * * * * ****** *** ** * (d=2; d<n; d++)
** ** * * * *** ** ** * *** * **** * * * **
*** *** * * * ** *** * * ***** *** * * * ** ** (n%d==0)
***** * ** *** * * *** * * * * * * *** * * ** * * ****** * ***

   }
***** * ** * * * **** ** * * * **** * * *
* * * *** *** ** * * * * * ** ** * * **
* * * * ** **** ** * *** ** * * *** * * ** *** ** *
** **** ** ****** **** ** ** ** * ***
* ** * ***** * * ** * * ** * ** **** * * ** *** * * * * * * (e==0)
** *** ** **** ** * * ** ** * * * * *** *** ** *** *** ** ***** ** ********* *
* **** * * *** * * *** *** * * ** * * ** * ** *** *** ****** *** ** *****
** ** ** *** **** ** *** * * **** ** * * ***** ** * * *** ******** * * **** * * ** * ");
* * * * **** * ** ** * *** ******** * * * ** * * ** ****** ** * * **
*** ***** * * * **** ** ** ** * *** * * *** **** * ** * * * * **** * * ****** * * **
**** ** *** * ********* * ** **** *** ** ***

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
 * ***** * ** **  *  * *  *   *** *   *       **   ** d;
  *   ****** * * **     * ***** *   ** **  **** **** *  ** (d=2; d<n; d++)
  **   ** ***   **** * ****  **** ***** *  * ***** **
  ***** * ***  *    ** *** * * ** **      ** * * * * *   **   (n%d==0)
 **  ** ***  *    *  *** * ** * ** * *   *  *  *   *  *     *****  *     *   *  *    *
   }
* * ****    * * * *** *  **       *****   *** **   **     *
   *   ***  ** **    ** *****  * ** * *   **   * * * **
 *  * *     *** ** *  ** **  *    **  *    * * *** 
  **  *** * * * *** *   * ** ** * *     ** * ******* *  *   *
* *** *    ****    * * *** *    * *** **** **     *** * ******* *    ** *    ***  (e==0)
  *    **** *    ** ***** * ** **  *  * * *** *  *   * *****    * * * ** *         * ***      * * * *   * 
 **  * *  * *****   **  ****  * * *  *  *** ** *      * *  ** **   *  **** **   ****  * 
***  ***  * *** **   ***    **  ***** ** * *   *  **    * * ***  *   ** *** *  *        *    **  *    *   ** ** *** *  * *  **** ");
* ***** ***  * **    **     * ***  * * **   **      *   * * *****   * **** *** *
 **    *  * * * *  * * * **** **  ** *  *     **** ** * * ***** * *  ******  ** *** * ****    *
* *****   **** ***  **  ** * *  ** * **   * **** **
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
***  *  ***   **   ** *  ***** Fn,t1=0,t2=1, n,input;
 *     ***   ***   **  **    **  *****   **     **     * 

    * *  **   *** ******* * *  * ** ** * n++)
* ** *** * *  *  **  *  **
***  **      **  *  *  * *     *         *  *      *  * *  * = t1 + t2;
** *** * **  **  * *   * *    *   ***    **   * *   *  ** *     
****   ***  ** **  *     * **   *******   * * *** *   
    }

******** *****  **   * * ** ** *****   * * 

* * **  *  * *     * **** **   ** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
   * ***   ***   *  *   ***  Fn,t1=0,t2=1, n,input;
   *  ****  ** ** * ** *  *    * * **  *     *   ** ***

 *   *  *****     *   **    ** * **   * * * n++)
**** *    **     *****   *  
*   ** *  * *      ***  ** ** * ** * ******   *    * = t1 + t2;
**** *    ****** * ** *  **  * *** *****  *  * ***** *      **
*      ****  *   *      *  *  ***   **** *    *** * **   *   
**  * *** **  ******** ** **

*   *  **    *** *** *** ** *  **  *    ",Fn);

***** ** * * *  **** *   *  0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.176
©2016-2024

Related questions

0 like 0 dislike
46 answers
11-30 Exercise 1: Fibonacci numbers (Array)
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 1.9k views
0 like 0 dislike
99 answers
11-01 Exercise 1: Find out all prime numbers between n and m
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 3.4k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 1.4k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 2.4k views
2 like 0 dislike
67 answers
11-09 Exercise 2: Reduce the fraction to lowest terms
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 2.3k views
12,783 questions
183,443 answers
172,219 comments
4,824 users