0 like 0 dislike
7.9k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列:0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始,其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2),F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n,輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited

edited by | 7.9k views

93 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
** * * * * * ** ** * F0,F1,Fn,n,a;
** * ** ** * * ******* * **

** ** * ** ** * * * * * *** * * ** &a);

* * * ** *** ** * * * *
* ** * *** ******* *
* * * * * **** ** * ** * **** * ** * * * **
*** * *** * ** ** **** ** * * * * ** * * **
* **** * ** ** * *** ** ***** * * *** ****
    }


* *** *** ***** * *** * **** * **** Fn);

** **** * *** ** * ** 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** * *** * ****
int *** *
{
int * ** ** *
* * * *** * * ** *
if(a==0) printf(0);
else if(a==1) printf(1);
else {
*** * *** * * * ** * ** ***
** * * *** * **** ** * ** * * ** **** *** * = c0+c1;
* ****** * *** ** ** * ** ** * * * ** **** = c1;
** * ** * *** *** * *** ** * * * *** * * ***** = cb;
***** * * ***** * ***
* * * * ****** * **** * ** * * ** * * *** **
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include * *** * * *

int ** * **
{

int ** ** *
* ******* ** ** * * * *

if(a==0) printf(0);
else if(a==1) ** *
else {
*** *** ** ** * ***** * * * ***** *
** * ** * * *** * **** ** ** * ** * = c0+c1;
*** **** ****** * * *** *** * * ** *** ** = c1;
* * ***** *** *** ** * ** * * * * * * * * * * *** = cb;
* * * * **** ** *
** ***** * * ** ** * *** *** * * ***** * * **


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include * * * * ** * *

int main(void)
{

int ** * * *
* ** **** * ** * * ******

if(i==0) *** ** * ****
else if(i==1) * * * * * **
else {
*** * * *** ** * ** * * * *
** * * * * ** * *** * ** ***** ** * * ** ** ** * = f0+f1;
* * ** * * * * * * *** * * ** * **** * = f1;
* * * ****** ** ** *** * * * * **** = fn;
** * **** ** *
****** ****** * * ** ** * * ** * ** * *
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include *** * ****

int * ***
{

int * *** **
* * ** ** * **** * **

if(i==0) printf(0);
else if(i==1) * ** * **
else {
* *** ** * * * ** ** ********
** * *** * ** * * ** ******* *** ****** *** = f0+f1;
*********** * * * * *** * ** ** * * ** *** = f1;
* ** * ** ** * * * * * * * ***** * *** * * = fn;
** ** **** ** ***
** **** * ** * ** * * * ***** *** * *
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
*** ** * * * * * * * * *** * *** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
******** * *** *** *** ** * *** * * * * * * * *** d;
* * * *** * * * * *** ********* *** *** * (d=2; d<n; d++)
* * ** *** * * * ** ** * * **** ** * ***
* * * ** * * * ** * **** * * * ** * (n%d==0)
****** * *** * *** * **** * * ** * * * * * * ** *

   }
** * * * * * ** * ** *** **** ** * *** *** * * *
* ******** * * ** ** * **** * * *
**** ** ** ** * *********** * ****** ***** **
**** ** * * ******* ** * *** * *
* **** * ** ** **** ** * *** * * * *** ***** * *** * *** ** (e==0)
* * *** * * * *** **** *** * * * * ** * ** * * * ** * * * *** * * *** * * *
******** * * ** ** * * ** **** ** **** * ** * ** ** * * ** **
* * * *** * * **** *** ** * * * *** **** ******* **** ***** ** *** * * * * * * ****** * * ");
* ** * ** * * * **** * * * * * * ** * * ** ** * *** * **
**** ** * *** * ** * ** *** * * ****** *** ** * * ** * ** * * **** *** * * ** * * * *
*** ** * *** * ** * ** ********* ** * *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
**** * ** ** *** ** * * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
** ** ** ** * * *** ** ******** * ** ** * d;
* * * * * ** ** * * ** *** ****** * * * ** ** (d=2; d<n; d++)
** *** **** *** *** * ** ** ** *** * *
** ** *** ** * ** ** * * * ** **** **** ** (n%d==0)
** * *** * * ** * **** *** ** * * *** **** * ** * * ** * *

   }
* * ** * * * * * ** **** * * ** **** **
** ********* * * * ****** * * * * *
**** *** * **** ** * * * * ***** **** ** *** * * * *
**** **** ****** * * * * ** * **** * * ** * ***
* *** * * ** *** * ** * * ** *** * **** * * * * (e==0)
** **** * ** *** ***** * *** ** * * ** * *** * * *** ** * * * *** * * *
* ** ***** * **** * ** ** ** ******* * * ** *** ** ** * ****** *
** ** ** ** ***** ** * ***** * * * ** * ** *** * * * * ** ** *** * *** * ** * * * * ");
* **** * * *** ** * *** * ** * *** * * * * * * ** * ** ** **
* * * *** * ***** * ** ** *** * * **** *** ** ** * ** * **** ** * ** ***** * ***
**** * ** * * * ** *** ** * **** *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
** ** *** * * * *** * ** * * ** *** ** *** d;
** *** * ***** *** ** *** * * * * **** **** ***** * (d=2; d<n; d++)
* **** ** **** * * * ** * * *** * ** * **
* *** ** ***** * * ** **** ** * ** (n%d==0)
** ** ** * ***** ** * *** * *** ***** * * ** * *** * * * ** ****** *
   }
* *** ** ** ** * * ** *** **** *
*** ** ** ** * * *** * ** ** ** **
* ** ** *** **** * * ** *** ** *** *******
* * * ****** * * * * * * * * *** * ** ***
** *** * * * * *** * ** ********* *** ** * ** * ** * * * * * (e==0)
* *** ** * * * *** ***** *** * ** * * * * *** * * * * * ** * * ** ** * **** * **
* * * * ** * **** * * *** * ** *** ** ** * * *** ****** ** *** *
**** * ** * * **** * * * * * * * * * * *** * * ** **** * * ******* * * * * * *** * ** ** ");
***** * ** ** ** * ** * * ** *** *** ** * *** ****** *** **
** **** * *** ** * *** **** ******* * * * **** * **** ** * ** * ** * ** * **
* * ** *** ** ** * ***** * * ** *** **
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* ****** * ** ** **** Fn,t1=0,t2=1, n,input;
* **** ** **** * * * * ** * * ** *

** * ** ** *** **** *** * ** ** * n++)
* ** **** *** * * ** *
* *** ** ** ****** * *** ** ** ** * ** ** = t1 + t2;
****** ** ** ***** * ** *** ** * *** *** **
** ** * *** ** * * ** * ** *** * *
    }

** * ***** * * ***** * * * **** ** *

** * *** * *** ** *** * 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* * * * * ** * ** ** ** Fn,t1=0,t2=1, n,input;
******* ** * ** * * ****** * * * ****

***** *** * ** ** *** ** * * *** n++)
* ** ** ***** ** *** ***
** *** *** * * * ** ***** * * * * * ** **** = t1 + t2;
*** ** * * ** *** ********* * ** ** * * ** * *
** * * * ****** ** * * ** *** ** * * **** * ** * *
*** ** * ** * ****** ***

* *** * * ***** *** * *** * * * * ",Fn);

*** * * * ** * ** * 0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.222
©2016-2025

Related questions

0 like 0 dislike
46 answers
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 5k views
0 like 0 dislike
99 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 10k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 4.1k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 6.7k views
2 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 6.4k views
12,783 questions
183,443 answers
172,219 comments
4,824 users