11-01 Exercise 3: Fibonacci numbers

0 like 0 dislike
20.1k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列：0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始，其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2)，F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n，輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 20.1k views

93 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
****  * **   * * *  * ** **  F0,F1,Fn,n,a;
** **  ****  *  * * ** *    * ****

 *** *     **  ***  ***  * * *  *****  * *** **** &a);

** **   ****    * ** *  ******   ****** *** **  **
* **  ** *  * **  ** ** *  *
*      *   ** ******        *    * ** **  *  * *** * * *
*** *    * *   * *  *   **     **    * ** * * *** **  * 
*  *  *  **    * **      ** *  *** ** * **     
    }


 ** *  *** * *  *  **    *  * **  * *  * Fn);

    *****   * **** *  ****  *  0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    * *  *  *** 
int * * * 
{
int **** ** *** 
 *  * *     *    *   ** ****
if(a==0) printf(0);
else if(a==1) printf(1);
else {
     ******  **** ***  * *  * ****   ** * 
**    ** * ******* *  * ** ** ** *  **  * *** *  *  **      = c0+c1;
  * *   *  ***** * * ***  *  * *  **   *   **  **   = c1;
*** *    *   *   * *  * *    *** **   ** ***** *** * ***   = cb;
* *  *    ** * ***   *  *  * 
  **  ***  *****   **** ****   * **     ***  ****
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include       *** *  *  * 

int     
{

int * * ***   *
*  * * *       * ****  *  * **

if(a==0) printf(0);
else if(a==1)  * 
else {
*  * *   ***  * *** ** *  * * ******* *******  *
***  *  *    *  *  * ****** **     * ** *    ** ***   = c0+c1;
******   ***   * ** **   ** * *******     *      ** * * *  = c1;
 * *   **     * * * *** * **  ** * *   *   *  ** *   **  *  = cb;
 ****     * *** * *   ****  *
**  * ** *** *  *****    * *** **   ******* * 


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * ** *****  * **

int main(void)
{

int   * **  * ***  
 **    *      *  ***        *  

if(i==0)  ** * * ** * **  * ** * 
else if(i==1) * **  **  *   *   * *   
else {
**   * *   * **  ** **    *  * ***   **** *     
*  * * * ***  **** * *   *** ** * *     * *  *****  *** = f0+f1;
  **  **  **  ** **  ** * **     *    **** * *  **  * **  = f1;
    ****** ***   *   *  ** *  * ** ***** **     * ** **   *** = fn;
** *  * *   ** * *  **  * ***
  *   *        * * **  *  *   *    **  * ***
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** * ***  ** 

int * *   *
{

int  ** *  *   
 * **  * *  ** **** ** *

if(i==0) printf(0);
else if(i==1)   * * ** 
else {
** * ***  ***  ***  *    * **    **** *  * 
 ***** **** * *  *** * **** ** ***   ***** **  * ***  *  ** = f0+f1;
 **** *  * ***  **  ** ***  ***** * ** **  * ** * ****  = f1;
**   *       ** * * **** ** *  *  * **      *  * ******     ** = fn;
**    ** * *  **   * **** **
**   *  *  **** *   ** *  ** * *  *** * * * ***  
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* * * ** *** * **** * *** * * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* * *** **** * * ** * * *** * * * * * ** * * * d;
* * **** ** **** * *** * * * * * * **** * ** * *** (d=2; d<n; d++)
* ***** **** ** ** * * * * **** ** **
****** * * * ******* *** **** * ** ** (n%d==0)
*** * * * ** ******** *** * * * ** ** ** **** * * * ** * * * **

   }
*** * *** ** * * * ** * * ** *** ** ** * *
** ** * ** ** * ** ** * * ** *** * * ****
* * * * *** * * ** ** * * ******* * **
** *** ** ** * * * ** **** *** ** ** *
* ** ** * * * * *** * * * **** * ** **** ** * **** *** *** * * * (e==0)
* * * *** ** ** ** * * **** ** * * * ** ** *** *** * * * * * *** * * **** ** * *
** ** * * * **** * * **** * * * * ** ***** * * * ** * *** * *** **
** * ** * * *** ** * * * ** * * ** ** ** * *** * * * * * * * * ** * * * * * * *** * ");
* * * * * * ** *** * * ** * ******* ** * ** * * *** * ** ******** * * *
*** ** ** *** ** ** *** * ** * * * * * * ** ** ** ** ** * * * * ******* ** ** ** ****
* * * * * * * * **** *** **** ** ** ** *** ** ***

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* ** * * * * ** * * * *** * *** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
**** * ******** ********** ** **** ** ****** ** * * ** * d;
**** *** ** * * ** *** * *** * * * * ** ******* (d=2; d<n; d++)
** ** * * * ** ** * **** *** *** ** **
* * *** ** * ****** * ***** * ** **** * *** (n%d==0)
* ** ** * ** ****** * *** * ** *** ***** * * * ** *** ** * **** *

   }
* * * **** * ** ***** * **** ****** * *** ******
** * * *** ***** *** * **** * ** **** *
**** * ** ** * * ** ** * *** ****
* *** ** * **** * ** * ***** ** ** * ***
* ***** * ** ** * * * *** * * ** ** ** ** **** ** * * * (e==0)
* ** * * * ** * * * * ** *** * * *** ** * * ** * * ***** * * * **** ***** *
* * *** ** ** **** * ** ** * ** * ** * ***** * *** *** ** * *
** * *** * * * * * **** **** * ** ** * * * * * * ** *** ** ** ** * *** ** *** ** ");
** ***** * ***** ******* ** * * ******* * * * *** * ****
* * ******* * ** ** ** ** * * ** * ** * * * * * *** ** * **** * **** **** * *
** *** ***** *** * * * ******* ***

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
 ***   **   * **** **** * * * *  * ********   **  **   d;
 ***** *      ****      *     ** *** **  **  **** *   ***         (d=2; d<n; d++)
 *    * **  ****    *   ** * *  ***   *  *   ****  ** 
* **  **  * **  * *   * * * * * ** ***** *** ** ***  (n%d==0)
**    *** *   **** *  *  * **  *   *   *  **  *** **** * ** * *** * ****** * *
   }
 **  ******  * *   *        * **  ** * *****  * * ** * * *  *  
  *   *  ********   ********** ****** * * ** *    ** * **     * 
 *      *    *   **  *** ** * * *   ****** * * * *** * *   
***  **** *  ** * * *  * **    ***     * *** ** *      
  * *** * *  **** ***     **  **  * ***         ***   ******** *    * * *   *    (e==0)
  ** ***   *****      ** *  *** ** **  ******** *   *  * ***  * * * * ** *** *****  * ** *  * * * 
      **  *   *  **  * **        **** ***** ** *  ** * * * **       ***** *****  **   * ** 
  *   *  ****  *   * * *   *    ***   ***  **    *   *** ***** ***** *****   * *   *  ** *   * **     ********  ");
  * *     *   ** * **  * *** *  ***** * *  *       *  * ****** * ** **    **** * ***
 ****        **** * *  **    ** ****  * ****    **  ***** ** * * **  **** *       *******   * **  *  * *  ** * 
* ***** ** **  ***  ****   * *** ***   * **** *****
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
**  *** ** *****  **  ** * ** Fn,t1=0,t2=1, n,input;
* ** ***    * ** **** ** *     **  **   **     *   *    **    

** **    ***     *   ** **  **  * ** ** n++)
 **   *  * * ***    *** *    
**  * ** * *  *    *    *   *  * *  *   * **   * *    *  *** = t1 + t2;
 ****  * **  *   *****   * *    *     *  **    * *  * * *** 
 * *  * *     * **     ***   **  ** * *  * *  *  **    *****   ** *   
    }

* * *  **   * * * * * ***   *    * *  ** *** *  *  *

 * *** *****  *   * ******* 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
* **   * *       ** * ** ***  ** * Fn,t1=0,t2=1, n,input;
************* *    **  * **     ***   ***** ***  **  * *        

    ***   ***    ******  ** *    *  *  * n++)
*    **    **** **  ***  
* ******* * **** ** ***  ** ****  **    ****    * = t1 + t2;
  ***** **       *   *   *       * * **  *** * * *  *  * * 
 ** * ** *** * * ** ***    ****** **** * * ****  * * *
* *   *** **  ***   *    * *  ** 

*** ** *   ** *  * ** *     **** *  ",Fn);

*** ** **  * * *  ** **  ** * **  0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.109
©2016-2026

Related questions

0 like 0 dislike
46 answers
11-30 Exercise 1: Fibonacci numbers (Array)
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 13k views
0 like 0 dislike
99 answers
11-01 Exercise 1: Find out all prime numbers between n and m
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 24.1k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 10k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 16.3k views
2 like 0 dislike
67 answers
11-09 Exercise 2: Reduce the fraction to lowest terms
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 16.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users