11-01 Exercise 3: Fibonacci numbers

0 like 0 dislike
14.1k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列：0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始，其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2)，F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n，輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 14.1k views

93 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
  *   ** *  **   ** **        F0,F1,Fn,n,a;
**       *    **  * *   **** *

* *******   *  *  **   ****  *** **  * ****    &a);

 *      *     * *  ** * *****  **  *    *****
   * * *** * * ** ** 
  *** * *  * *****  ** **  * *   *  *  ******* ***   **  *  ** *** 
*  ******   **  * *    ***** **    ** *  ****** **  
 * *  *    ****  *   * ** * *  * *  **  ***   * * ****    *  * *
    }


   *** *** * * *  ****** * *** *  *    **     * Fn);

*  * ***   *       ***     ***    0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   *   *      **
int  ****
{
int *****  *  
*   * *  *****   **    ***  ** 
if(a==0) printf(0);
else if(a==1) printf(1);
else {
****  *   * ** **   *   **    *        * ***  *
**          ** * **  *   *    * ** * *    **  *   ***  *  = c0+c1;
*** **  * *** * *     * *** **   *  ** *  **  *    ** *   = c1;
 * *****  *      ** *  * *  *    * **   * * **  * *   * = cb;
****  *    * ****   * * *    
****  * * **    ** * *       * * *      ** * **
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **  ** * ** *   *** 

int    ** 
{

int  * ***   
  **  ***** * * *    *  **    **

if(a==0) printf(0);
else if(a==1)   **** *
else {
** *** **** *      *  *  **    **** *******  ** 
** *   **  *  ***** *   * *** *    **  * *  *   ** ***    ** = c0+c1;
****      * *  **  * **      ***  * ** ** **    * ****    = c1;
  *   *****  *    *   *****  **   *  ******    *   = cb;
*** **  *   *    *      *
 * *** * * * * ******* *******    **    ***    *


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include     **** **  * 

int main(void)
{

int ** ***  ***  
 *****     * ** * *  ***  *  **

if(i==0)    *    * ** ** **  
else if(i==1)    **** *  * *  * **
else {
  * ***  **  * ** *    ** *  *** *******
* *   *   * **    ***  **   * * *  *** * ***     = f0+f1;
 ** * *****  *   *  ** * **** ***    *  **      * = f1;
   ***** * ** *      *    *  **** ** ****  *  **** ** *  * = fn;
*****  **     * ***  * *  *  
     ** ****    *   * *   ** *  ***    *  ** 
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   **** ** *  *  *

int *    
{

int  *  * ** * 
**  ** * * * *    * **** ** *  * 

if(i==0) printf(0);
else if(i==1)  * ***  
else {
* * *  ** **  ***  **  **** ** *    ***
    *  ** *  **   **************   ****  **  *     ** = f0+f1;
** *****    ***  *   *  ***   ** *****  ******  *    = f1;
*  *** * *   *  **   ***** * * *  * *    ****    * ***  * = fn;
  * * * ** *   *  ** * * ***
      ***    **  ***    **** *  **   *    *   ** **** *
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
***** *** ** * ** *** * *** * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* **** ** * ** * * * * * ** * *** ** * ** d;
** *** * * * ** *** * * * * * * ***** * (d=2; d<n; d++)
* ** * * *** **** * ** *** *** * ** * * * * ***
* ** ** * * * *** * * ** * * **** * (n%d==0)
* * * *** * ** * * * * * ** * ** ** ** ** *** ** * * * **** ***

   }
*** **** * * **** ** * * * ******* * ***
** ***** *** ** * * ** * *** * ** ** * *
** **** * * *** ** * ** *** * ** * * *
* * * * *** * * * * * ** * **
* ** * ** * * ** * ** *** * **** **** * *** ** * * * *** * * * ** * * (e==0)
* * * ***** *** * **** ** * * * * * * * *** * ***** *** ** * ** * * * * *** * *
* * *** ******* ***** * * ** * * * **** * * ******* * ***** * * ** * * **
** * ** *** * * *** * ** * ** * * ** ** **** * * ** * * ** * * * * * **** ***** * *** **** * ");
*** ** * * ****** * *********** ** * ** * ** * *** ** * ** * ** *
** *** * * * *** ** **** *** **** ** **** * * * *** * ** *** * ** ***** * * * *
** ** **** ** *** ** *** * ** * *** ** **

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
***** ** ***** ** ** * * * ********* ** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
** * * ** * * ** ** ** *** * * * ** ** * d;
******** * * *** ** ** ****** ******* ***** * (d=2; d<n; d++)
* *** ** * ** * * ** ** ** * * ** ** **
* *** **** ** *** ** ** *** * ***** * (n%d==0)
**** * ***** * * * *** * * * *** * **** * ** **** * * ** ***** *

   }
** * ** ** ** ** **** * * ** ** ** * **** * * *
** ** * * * * * * ***** * ** ** * *
** **** * *** ** ** * *** * ** * * * * *** * *
* * * * * ** * * * * * **** * ** ** ** *** * **
**** * * *** * **** * ** * **** ** ** * ******** * * * * (e==0)
* **** ** ** *** ** *** *** *** ** ***** * * * * * ***** **** * * ** ** ** ** * * ****
*** ** ******** * * * * ** * ** *** *** * * ** * * * * ****** **
** ** ***** * ** * ****** * * * * * * * * * ** * ** ** * * * * * * * *** ** * * * * * * ");
** ** *** * * *** ***** * ** * ** ***** * *** * *** ** ** * ** * *
* *** * * *** * ** * ** * ** *** **** * * *** * *** ****** * ** * * ** * ** *** * **
** ** ********** * *** **** * * * * **** ** *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
       * ** *   ** *    *    **  * ****  * * *  *     d;
*   *  **   * * ** ** **       *  *** *  ***   ***  **  * (d=2; d<n; d++)
  *  *   **    * ***** * ** * *  ******* * *  ** * 
  **  *        *  *** ** *    ***    **    ****** (n%d==0)
   * * **  *** *** ** * **  **    * ** * * * *    *  ***  * **  *  *    ** ** *** 
   }
 * **** ** **   *    *  ****     **** * * * *  ** *   ** **   *  *
      ***    * ** ****   **** *  ** *  ** *********
 * *  *    **          ****  * * **  **  ** *  **    ***  
***  ******* ** *  **  ** * * * ** *** ***   * ** *** ****  *  *
  **    *  * ****  ** **** ***      *   *** * ** *      **   *    *    *      * *** (e==0)
 *  * *  **  ****** *  * * * *     *   * * **  ***  *   ***  *  * * ***   *  ****** **     *    * ********* **
*** ****   ** ******    *  ***   *****   **   *  *  *** ***** ** ***  * *  *  ** *  * 
    **   **       * *** *   ** * *  * **   *     * **  * **  * **  *****  ** ***   ***   **    **** *** ** *** ** * *    **    ");
   *   *   ***    * **  * * ****   **  * ** *  *  **       ** * * * ** *******   *  
**   *     *  *  * ***  ***  **  * ****** *  ** **    *         * ****   *  ***      **** * ** *    *  
  *  *** *   *   *** **    * * ** ***       **     
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
** ** *  **    *   ***  *  * Fn,t1=0,t2=1, n,input;
*   ***     *   *** * **   ****** *** *  **     *******

 *   ** ***   ******      ***       ***** *  n++)
**   * *  * * **** ******
  *  ** *  *** *****  * * ***   * **   *******  * ** * = t1 + t2;
***** *  *  * *  ** **   **** *   ***** *  * ***    *******
  *****   *  *  *** ** *** ***  ** *   * *  **  **  *  **  * ** **
    }

   ** *     *  * *  ****  * ****    **      ***

****    ** ***  *   **  **  0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
* ** ******    ***  * ***** Fn,t1=0,t2=1, n,input;
 ** **  **  *** ** ** **  **   *     * *****    ** *  

*    **   ** **** *  *****   ** ******* * *   * n++)
** * * **** * *******  *** 
* *    ***  *****  *** ** * *     *   ** *** *    ***** = t1 + t2;
 * ***    *  * ****** * ***       *  **  **** ****** * * * 
* **  *** ***  ** *  *  **** **** *     * *   *   ** *
*  * * *** **** ** *** * *   

  **   *    * *  ******   * *** **    * ",Fn);

* **** *  ** * ****  **      *  *  0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.6.173
©2016-2025

Related questions

0 like 0 dislike
46 answers
11-30 Exercise 1: Fibonacci numbers (Array)
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 8.8k views
0 like 0 dislike
99 answers
11-01 Exercise 1: Find out all prime numbers between n and m
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 17.1k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 7.2k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 11.8k views
2 like 0 dislike
67 answers
11-09 Exercise 2: Reduce the fraction to lowest terms
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 11.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users