11-01 Exercise 3: Fibonacci numbers

0 like 0 dislike
21.1k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列：0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始，其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2)，F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n，輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 21.1k views

93 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 * ** ***  **  ***  ** *  *** F0,F1,Fn,n,a;
 *   * * **   **      ****  * ** * 

**   ***   **   * *   * *** *** * *** ****** &a);

    **  *     ***   *      *     *  *   *
  **    **   *******   ** ** 
 ** * ***     * ** * *   * **  * ***  *   * *   *  *  ****  *  * 
          ***  ***    ** * **** **   * * * * ** *     *  *    *
 **  *  * ***** **  *     *** ** ** *** ***** * * *  ** *
    }


  * *  *   *** *  *   *     * *     ** ****** Fn);

* *** ****  **  ** ** ****      0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *   * * *   * ** 
int  ***    
{
int **   * ***  
*  **   *   **** *   **  ***
if(a==0) printf(0);
else if(a==1) printf(1);
else {
 *  ** ***** *   ** ** **  * ***  ***  ** * **  *
 **** *  ****  **    * * **    ***  *   *  ** **  *  * * = c0+c1;
 ** ** *** **** *  *  *     *   ****** ** **** ** ** **  * = c1;
 ** *  *      *  **      * **    * **** *     * * * ** = cb;
** *    *  *   *** *****   * * 
  * * **  ** *   * * *   ** ******     * *  ***** * 
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** *    *  *  * 

int *****   *
{

int  * * *** 
**  * * * *  ***  ****    * 

if(a==0) printf(0);
else if(a==1) *  ****  
else {
 *    * * **   ** *** *    ***    ** ****** * **
 ***** ** * ** * **** *    *   **  *    * ** * *** *   = c0+c1;
 ** * *** *    *     ***   **  *   *    * * *    *   ***   **  = c1;
   ** *     *  *  *** * * ** *   * * * ***  **  * *    **  **   = cb;
 **   * *** *  **** ** ** *
**  *    *  ** *** ** * * **    *  *** * ***    ***


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include      *    ***

int main(void)
{

int  ***     ** 
** * ****      *   ***  * **  

if(i==0)   *** * * * * ** ** **   
else if(i==1)  * * * *   *  * **  ***
else {
 **** *   *  * *** ** ** * **   ***  *  *  *   * * 
****   * * ***   *  ** * *****  **  *  *   ****   = f0+f1;
   *    **** **  ******   *       ***  * **  * *   = f1;
*  ** *   * * **  ***  ** *****  *** *  ***  *  *** **  *  = fn;
***   *  *  * * **  **    *
   ** * ***  **** ** *    * ****  *  *   ** ** *  *
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *           

int  * *** 
{

int    *  * *  ***
*** **   *   *  * * ****** *  

if(i==0) printf(0);
else if(i==1)    *
else {
 * ** *** **** *** ** * ** * *    **  * *    * *
*   *  * *** ** * * ***  * **** *  * * ** **    *  **  *  = f0+f1;
*   * *****   ** ***  *  * * *  ***** **  **   ***  *** *  = f1;
***  ***  ***     ***   *         * * ** *    *   *      = fn;
**** ** *     *   **** *  **  *
 ***  * *  ** ***  * *   **   **   *   *  *  **
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* *** *** * ***** ** ****** *** ** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
*** * *** *** ** * ** *** * * *** * * * * d;
* ** ** ** ** ** * * * *** ****** * *** * (d=2; d<n; d++)
**** *** * * ** * ** ****** * ** **
** ***** ** * * ** *** * ** *** ** ** * **** * * * (n%d==0)
** ** * ** * * * * ** * * * * * * * * * * * * ** ** **** *

   }
* * *** * * * * ****** **** *** * ** **** ** **
* * * * * ** * * * * * ** **** * **
** * * ******* **** * ** * * * ** ** **
* * * *** * ****** * ** * **** *** ***** *** *
* * * * * * * **** *** * * ** ** **** ** ***** ** **** *** * (e==0)
**** ****** * * * ** * * * **** * * * *** * * ** * * ** *** ** ***** ***** ********
* ****** * * * * *** * *** ** * ** * *** ***** *** * * **** ******
** * * * * ** * ** *** ** **** * * * ** ****** *** *** * *** ** *** ****** ** * * * ");
** ******** * * *** ** * ** * ** * **** * *** * *** * *** * * ****
* * * * ***** * ** * * ** ******* * * *** ** * ** * * * *** *** ** **** * * * ***
** * ** * *** *** ** *** *** * *** * *** *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
** * * * * ** ** ** ** * *** * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
** ***** ** ** ** * ** * ** *** *** ** *** d;
* * ** * *** * ** * * *** * * * * *** ** *** (d=2; d<n; d++)
* ** * *** **** **** ** * **** * *
*** * ** * *** * * ** * * * * (n%d==0)
* * * * **** *** ** ** ***** * * **** ****** ***** * ** *****

   }
****** ** *** * * * **** * ** * ** ** ** ***** ** *
*** * **** * * * ** * * * *** *** * * ** *
** ** ** * ** * ** *** ** * ****** ** * *
* ** ** * * *** *** **** * * ** *** **
*** *** *** ** * *** *** * * * * * * ** * * **** ** * * * * * (e==0)
** * ** *** * * * ** * *** * * ******* * *** * ** * ****** * * * * * ** ** **
** * * * ** * **** * * ** ** * * * * * * * **** * ** *
* * ** *** * ** * * * * * * * * ** ** * * *** ***** * ** * * **** ** * **** ");
* * ** *** * *** **** * * * ** ** *** * ** ** * * ** *** ** * ** *
***** * **** * * ** * * ** * ** * * * * ** **** ******* ** * **** ** ** * ** * * *
** * * ** * * ** * *** * ** * * * ** **

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
 **    *** ***  **  *  ****    **      * **  *  *   ** d;
 *  * * *** * *  ** ** ****  * ** **    *** *       * * (d=2; d<n; d++)
 * ****    *  * ** **  * *******    * ** *****   *  ****    
 *** ** *   * * ** *  ** **** *  * **     **  * **   *  ** (n%d==0)
* * ***   ***  * ****** *     * * *    *** *  *  *  * * * ****   *** *  * *  *     * * *
   }
      ** * *** * ** ** ** * * * *       *  *    *  * ***** *   
*  *  * ****   * ***  * **    **   **** * * ***** 
 ** *      ****  * ** ** * * ********   *    *  * ** *
* **** *  ** *** ***   *  * **  * **  * ***   * ***   
****  ****  ***** *** *   ***    *   ***** * * *  ***  ** * *** ****      *  (e==0)
**    * *  *   ***   * * * ** ** *    *  *   * * ** *  *      **  **    *** *** **  ** * ** ** *     **    * ***
   * ***** ***** ** *  * ** ** ** ****** * ***** * ** *  **** *    ** *  * *   **
    ** *  *  *** *  *  ***  **   * ******** * * ** ** *******   ***   **  *  ** *  *** *  ****  *        *** * *** *  * ");
 **** *  ***      ** *   * * *  *  *** **  *  *  **   * ** * *   ** * *    *      * 
 * * **  *   * **  *****   * **** *******   *   ** *  ***  **  * **   * * **** *  *  * * *  ** 
* * ******* * *  ** *  *   * *       *** *    * * *      
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
 **** ****   **  * *** ** Fn,t1=0,t2=1, n,input;
**** * ***  * ***  * ** *  *  ***** * ** ** *      *  **   * 

 *  *     **  ** *       **** *** **   *   * n++)
 *** *  **** ** ** *  ** *
 * ** * * **** **  ** ** ***   **      * ****  ** **   = t1 + t2;
   *   ** **    ** *  * **    *  * * *  *** **   * * ******
* ****** * *** * **  ** **  **   *****  **       **     ** 
    }

* ***** * ***    * * *  **  *  *   ** ****  *    *** 

  *** **   * **      **   ** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
**  **    * **   *   ****  * Fn,t1=0,t2=1, n,input;
* * **     **  *    **   * *** *  * *    ***   *****    *  * *

 ***** ***  * ** * * ** **   *      ** *** n++)
***** *  ****     ** ** 
** ** ***  **** *       ** ** **** * **    ***** * ** = t1 + t2;
*** * **   * * * ** **   **   *  *  *       *  * *** **  
    ****** * *  *** *  * ** ******  ** ** **   ** *  ** * **** 
   * *  ******** ** *   *   

  * * *   * *    * * ****  **** *     *  * * * *  ",Fn);

  **  * ***  ***   *** *** * * * 0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.94
©2016-2026

Related questions

0 like 0 dislike
46 answers
11-30 Exercise 1: Fibonacci numbers (Array)
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 13.7k views
0 like 0 dislike
99 answers
11-01 Exercise 1: Find out all prime numbers between n and m
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 24.8k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 10.5k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 17k views
2 like 0 dislike
67 answers
11-09 Exercise 2: Reduce the fraction to lowest terms
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 17.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users