0 like 0 dislike
2.9k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列:0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始,其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2),F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n,輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited

edited by | 2.9k views

93 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
** ** *** * * * ********* F0,F1,Fn,n,a;
******* * *** ** ** * * **

** * ** ** *** ** * ** ** ** ** * * * *** &a);

***** * ** * ***** * * ** * **** ***
* * *** * ** * **** *
*********** ** * ** ** **** * *** ** * ** * * *
* * * * * * * * * * ** ***** ** *** * ** *****
* * *** * **** * * ** * * * ***** ** *
    }


**** *** **** ** ***** ** **** * Fn);

* ** * **** * * ** ** ** * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include **** * * *** **
int ** *
{
int ** **** * *
***** **** **** **** **
if(a==0) printf(0);
else if(a==1) printf(1);
else {
* *** * * * * * * * * * ** ***
* *** ** * **** ** * * * * * * * ** *** = c0+c1;
* ** ** * * * * * ** *** * ** * * = c1;
* * * * ****** **** ** ** * ** ** * * * ** **** = cb;
***** * ** ** * ** * *
* * * * * ****** ** * * **** * * *****
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include * ** * * *

int * *
{

int ** *
** * ** *** * * **

if(a==0) printf(0);
else if(a==1) * ** *
else {
** * ** ** * * ** ** ** * * ***** * * *
** * *** ** * * * *** ** *** * * * **** ** = c0+c1;
* * **** *** *** *** ** ** ** * ** ** = c1;
* *** ** * ** * ** ** * * ** * = cb;
* * **** ** **** *
* ** * ***** * ** ** ** * * **** * ** * *


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include *** * * *** * *

int main(void)
{

int * *** *** **
***** * ***** *

if(i==0) * * ** *** * *
else if(i==1) * *** * * ** * ** **
else {
** ***** ** ** ***** * *** *
** ** * ** * * *** ** ** * * ****** **** ** = f0+f1;
*** **** * * ****** * * *** *** * = f1;
** *** *** ** * * **** * * * ** ** ** ** * = fn;
** * **** * ***** ** ** *
** * * * *** **** *** ******* * *** ** *
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** *

int ** *
{

int ** ****
* * ** * *** ** **** * *

if(i==0) printf(0);
else if(i==1) ** * ***
else {
** * ** *** **** * * * * * *
*** * * * *** * * ******** * ** * * ** = f0+f1;
** * * *** * ** ** ** * *** * * **** = f1;
** ** ** * ** * *** ******* * ** ******* = fn;
*** ** * * ***** ** * *
* ******* ** * * ** ** ** * ** * * *
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* ***** * ** *** * * ** * ** * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
** * *** * **** * * **** * ** * * d;
* *** * * * * * *** * * ** *** ** ** * (d=2; d<n; d++)
* * ** *** ** ** ** ** ** *** * ****** **
**** ** ****** * *** * *** *** **** *** * (n%d==0)
* * * * * * * * * *** **** ** ** ** ** ** ****** ***** ****

   }
***** * **** * ** * **** ** ** * *** * ** * * ** *
**** *** ***** ** *** ***** ** *** ** * **
*** * * *** *** ** ***** * ****** ** *
* ** ***** *** ** * *** ** * **** ** ** *
***** ***** * * ***** *** ** ** * ***** **** * ***** * * * * ** * * *** * (e==0)
* * * * * * * ** * *** * ******** * ** ****** ** * ** ** * ** ***** * ** *** * * * **
*** * ** **** ** *** *** ** ** **** ** * ** * ** ** * ** * ** ** *
*** * * * ** * ***** ** * ******* * * ***** * *** * * *** * * *** ** * ** *** * * * * * ");
* *** * * **** *** *** ** **** * * ***** * **** * * *** ** *** *** **
** ** ** ****** ** * *** ** * * *** * * * * *** * ** ** **** ** *** ** ****
** **** ******** ***** *** * ** *** ** **

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* ** * *** **** * ** *** ** * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* * ** * *** ** * **** *** ** * *** * * ** **** d;
**** * *** *** *** ***** ** *** *** * ****** (d=2; d<n; d++)
**** ** ** * * * * * ** * * *** **
* ****** ***** *** ********** * ** **** ** * * * (n%d==0)
* * ***** * ** * ***** * ** *** * *** * **** * ** *** * *** ** *

   }
* ** ** ** * **** * * ** * ** *** * * * *** *
* * * ** * * ****** *** ** ***** *** * * ** *
***** ***** ** * *** *** * ********* * ** *** * * * *
** ** * *** * ** * *** * ** **** * *
* ** **** ** * ***** **** * *** ** *** * * ***** *** *** *** ***** ***** (e==0)
** ** * ** * ** *** ** ** **** * * * * *** *** *** * ** * ********* *** * * ** *
*** * ***** * ****** *** * ** ** * * * * ******* * * * * *** ***
* ** ** **** *** * *** * ** ***** * ** * ** ** **** *** * * ** * ** * * * **** ");
* * ** **** ***** ** * ** *** ** * * * ** * * *** *** * * *** ***
*** ** * ** * ** * * *** * ** ** ** * *** * **** ***** * * * ** * ** * *
**** ** * ** ** ****** * **** **

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
* **** * * * ** ** *** *** d;
* * * * ** *** **** * * * ** * * * (d=2; d<n; d++)
** * * ** * ** ** ** * * * * **** *
* ** * ***** * ** ** *** * *** **** * (n%d==0)
* ** ** * * *** * * ** *** ******* ** * * **** * * *** * ** * * ** *
   }
* * ***** *** * * ** *** ** * ** * ** ** *****
* *** *** ** * * ***** * * * * ** * * *
* * * * * * ** * ** * * ** ***** **** **
*** * *** * * * * ** ** * * ** * *** ** * * *
**** ** * * *** * ******* * **** * * * * ******* * **** **** ** (e==0)
* * *** * **** * * ** ** * * ** * * * **** ** *** * *** ** * * ** * * * *
* **** * * *** * ** ** * ** * *** ** ** * *** ** * * ***
** ** * ** ** * *** * * *** ***** *** * ** * * * * * *** ** **** **** * * ** ** ** * ** ");
* * ** * *** * ** *** ***** ** **** * ****** ****** * * * ***
* *** ** ****** **** * ***** ******** ** ** * * * *** ** * * ****** ** *** ** * * *
*** ** * ** *** *** *** * ** * * ** ** **
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* * ** ** * **** * Fn,t1=0,t2=1, n,input;
* * * ** ** ** * * ** ** *** ** ** * * ***** ** **

* ** *** * ** ***** * ** ** n++)
* * **** ***** * *
* *** *** * ** * ** * * * *** * * * = t1 + t2;
* * * * ** * * * **** * **** * * ** * **** ****
*** **** *** * * ** ** * ** *** ****** **
    }

* ** ** * ** * * ** * **** * *** ****** * *

* * *** ** * **** **** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* ***** *** ** * * *** Fn,t1=0,t2=1, n,input;
** * * ** * * **** * *** * * * * **** *

**** ** * * ** ** * * ***** n++)
******* *** ** * * ** * ***
*** *** * * ** *** * * ** ** ** ** **** ** * = t1 + t2;
* * ** * ** * * * * ******* ** * ** *****
** *** **** * ** ** **** ** * * * **** *
**** ** * *** *** * ** *

** *** ** ** * * * ** * *** * * ",Fn);

* ** ** * * * ***** **** ** 0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.100.50
©2016-2024

Related questions

0 like 0 dislike
46 answers
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 1.9k views
0 like 0 dislike
99 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 3.4k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 1.4k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 2.4k views
2 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 2.3k views
12,783 questions
183,443 answers
172,219 comments
4,824 users