11-01 Exercise 3: Fibonacci numbers

0 like 0 dislike
23.2k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列：0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始，其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2)，F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n，輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 23.2k views

93 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
*** ** * *   *   *  **   * *  F0,F1,Fn,n,a;
 * *** *   **** * ** * ****    **  **

 ** ****   * **  *** **     * *   *  *** **     * &a);

* **   * ** *  * *   **    ***   *** *
*   *   **  * * ** *** **   ** 
   **    **   ***  *  * *    **   *      * ***   *  ****  
***  * **** *   ******   ** ** *****  * *** * ** * *
**  *  * * *  * ****        ** * *   *****    *   * * **   *   
    }


*****    * **  * **  * ** *  *******    *   ** *  Fn);

 ********  * *     ***  *   * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  *   ** * ** *
int ** *****
{
int **    * **
******   * *  ***  *  **   *
if(a==0) printf(0);
else if(a==1) printf(1);
else {
* * ** **       * * ** **   * *  *  * *  ***    *  
*   * ** *   *   **  ************ ***  *   * ******* = c0+c1;
      *  **** * *** ***   **   **   ***** *****           = c1;
**  * *  *   *  * *  **    * * * ********** *  * **** *** * *  = cb;
   *  *      * *****     *
 * ****  *** ** *   **  *  * *    *   ***
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *     * * ** * **

int     
{

int  ********  * 
 *** * * * * **  *** * 

if(a==0) printf(0);
else if(a==1)  ** ***
else {
* ***** * * * **  * ** **  ***  *    * *  * *   
* *  * *  ** **  ** **   **  **  *   ***********  * = c0+c1;
**  ** * **** *   ** *    * ** * *** **** **  ** * *  * = c1;
 *  * **    *   *   ****** ******       * ** * ** *    ***** = cb;
 ** * ***     ********  * ***
  ** ** * * *       *    ***  ** *  * * *** *   **


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *** * **   *     * 

int main(void)
{

int **   * *   
**  ***   *  *      *****  

if(i==0)   ** *** *   *  *  * *  * 
else if(i==1)   * * * *  ***     **
else {
 **  ***  *    **** * * **   ** **  ** **
*** * ** *  * *** *   **  * ** **    ***    *** *  * * * = f0+f1;
 *  *  ** * **   *   **   *    *  *      *** ****   **** *  *   = f1;
***  *** * * ***** ******* * **   *   * *    **   * * *** = fn;
**  **   *    **     *    * **  **
** *   **  * * *    *******   * * *   **  ******     * 
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   *   **    

int  ***    
{

int   *** 
**  * * **** *  *  **** *    

if(i==0) printf(0);
else if(i==1) *** **  *
else {
*  * ***   *** **** *** *    *  *  *** * 
  * * * * *  *   * * * *  * ** **  * **   ****   *   = f0+f1;
      **  **   *    **   *** *    ** * * *    **  *** = f1;
 *  **** ***     *   ** **     ***  ****  **** *     ***  * **  = fn;
 *******   **  *** * ******   
 *  ****  *** ***   * * *  **     **** ***** 
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* * *** * ******* * * ** ** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* ***** * * ** * **** * * * ** ** **** * * * ** ** d;
* * *** *** *** **** * *** ** *** *** *** (d=2; d<n; d++)
* * * * ** ** *** * * * ** ***** ** * **** * * *** * ** ***
* * * * * **** * * * ** ***** *** ***** * * (n%d==0)
******* * * ** * * *** *** ** * ** * * ** * * ***** * ** * **

   }
* * ** *** *** **** * *** *** * ** * * * *
* ****** * ** *** * *** ***** ****** ** *
** *** *** ** ** **** * ******* ** ** ***** *
**** * * * ** ** **** * * * ** ** ** ** *
***** ** * **** * * * **** **** ** ** * * *********** *** * (e==0)
** * * * * ***** ** * * *** ** * ** *** ** * **** *** ** * * * **** ** *** * * *
* * ** ** ****** * * * * * ** ***** * ** **** ** * ** ** * * **** *
** * ** ** * ***** *** ****** * * **** ** * ** * ***** * *** ** ** * * * * * * *** **** ** * * *** *** ");
* *** * * * ** ** **** * * ** * *** *** * * * ** *** ** * ** ** ***** *
* *** * **** * * ** *** **** ** * ***** * ** * * * ** **** ** *** * * *** *** ** * ** **
* ****** ** ** **** ** ********* * * * ****

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* ** * ** *** * * ** ***** ** *** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
*** ** ** * *** * *** ** * ***** ** * d;
**** * ***** * * * * ** *** ** * * (d=2; d<n; d++)
**** * ** **** ***** *** ** * ** ***** ****
**** * * * * ** ** ** **** ** * * ** * * * ** (n%d==0)
**** ** ** **** **** ** *** * ****** ** ** * * * ** ** * ** * * ***** * * *

   }
*** *** ** * *** * * * * * * * *** * **
* *** ** **** ** * * **** * * **** ***
**** * * * * * ** * * ******* * ****** **
** **** * *** ***** ** * *** ** * ** *** * ****
* * *** *** ** **** ** **** **** * ** * * * * ** *** ** *** * * * * (e==0)
* ****** *** *** * ** * * * * ** *** ** * *** ** * *** * *** ** ****** * ****** * **
* * * * ******* ******* * * ********* * * * * * **** ** * ***
** *** ** * * ** ** * * * * ** * ** ******* * ** * * ** ** ** * * * ** * ***** ** *** ***** ** ");
**** *** * ** *** * * ** ** * * * ** ** *** ** ** ******
** * ** ** ** * *** * * **** ** * * *** ** **** *** * ** * * ** ** ** ** *
* ** * ** *** ** * *** * * *** ***** *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
 **  * *     ** ***   ***   *  * *  *   * * *****   * *  d;
* * *   *  * *   *  *** * ****** * **** ** (d=2; d<n; d++)
 *    ** ** ** *   **  *     ** *** *    *  *  * **  **  *
**** ***** *    **   *     ** ** *  * ****   ***  * * * *  ** (n%d==0)
**** *     *** ** *   **  * *  **   **  ** ** **** **** **  * *** *   * ***  ** **    *
   }
***  * *          * ** *     *  *  **** *   * *** ******  ** *
 * **  *** ** ***   * ***  **    * **    *   **  **  ** * **
   *** *** *** *     * ****** **  *      ********* ***
**  **  *** * * ** ** * *  *  **   ****  *******  *   * 
   ** *     ***  **    **   *    *   * * * * **** *  *  *****  * *   **  ***    (e==0)
  * ** * *       * *    ** ** *** * *    * **  *** *  **   *** * *  *   *    *   *  **  ***  ***   **          *    *
*  **  *     ******* **** * **  *   *   ***     **      ** * *  *    * *** *  *   *     **
 ** ****  ** ***   * *****      *      ** *   ** *** *   ****  **  ****  **     *   *   **    * * ** *  ***     ** *  **  ");
*   *  *** ***        **  **** **  **  ** *     *     * ** ** *     ***  *  * ****   
  *  *** * *  *        * **** * * ***  *** *** *  *** **  *    ***  *    ** ***    ** *     **  * **
 **  ***   * **  *  ** * *  * *** *    *  *     * *  
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
 *  **** * *    *  *    * * *    Fn,t1=0,t2=1, n,input;
    ** *   * *     ***  *  **** ** *    *   * **  *  

* * ** * **********  * ** *  * *   ***       *  * n++)
  *   *  ****  * *****   
  *    *  **  **   **   ***  ***    *   **   *  **** **  = t1 + t2;
 *  * ******  **      * ** ** *  **  * ** **  **** ***
* ** * ** *  *    * *  ***  * ** *  * *   *   ***  
    }

  *  ** *     *   *** ****** **  *   *   **    *

   * **      ***  **** **  ***** * * 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
* *  *  *** ** ** ***  *  ** Fn,t1=0,t2=1, n,input;
  * * ** **** *** * ** *  ***    * ***     ** * *   *  *  

*    *** * * *  ****   *  **** * * *  **  n++)
** * *** * *** *** *  **  ** * 
  * ** *  * **  ******** ** * ***  *  * * *** ****  * * ** = t1 + t2;
 **   * *** *     ***  *   *****       * ** ** *  *** *** 
 ** ** * *  * ***      *  *** ***  ***** *    * *   ** ** * *  *
* * *   *** * **  * *  * * *

* * ***  ***    *  **   * * * **** ",Fn);

 ***   *  *****  *  **  ****  * 0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.108
©2016-2026

Related questions

0 like 0 dislike
46 answers
11-30 Exercise 1: Fibonacci numbers (Array)
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 14.7k views
0 like 0 dislike
99 answers
11-01 Exercise 1: Find out all prime numbers between n and m
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 26.9k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 11.5k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 18.5k views
2 like 0 dislike
67 answers
11-09 Exercise 2: Reduce the fraction to lowest terms
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 18.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users