11-01 Exercise 3: Fibonacci numbers

0 like 0 dislike
2.9k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列：0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始，其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2)，F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n，輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 2.9k views

93 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
* * ** *     *  *     *  *** F0,F1,Fn,n,a;
 ** *  *  * *    **  ** *  ** *   

***** *   ***   *  * *  *     ** * *  *  *  &a);

 **    * * *    ** *******  **** ** * ** *
***  *** *  *  *** ** * **  ** 
 * ** * * **   *** ****  *  ***     * ***  **   
 ** **  *   *** * **    * *   *  * **  *** * *  **  **   *
***  *** ** *   ******* *** ****  **  **** ** *  * *  *  
    }


   *   * *  *** * *  ***   * * *    *  *  *  Fn);

 ******    *****    * *  **** **  * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** **    *** **  *
int *** *  
{
int ** * **  **
**  *****  * * * * *** **** * 
if(a==0) printf(0);
else if(a==1) printf(1);
else {
**   **  ** **  **   ** *  *     ** *** ** 
  *    * **** *******    *  ** ***  ***  * **   ** **  *   = c0+c1;
*    ** ** *   **    ***     *  *  *   * *** *  *   ***    = c1;
 *   **    *    * *** ***  ** ** *  * * ** **  * * = cb;
* *** *        *****   *  ****  
*** ** * ** *   * * *   *** * *        *** * 
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include               

int *  **
{

int * *       
   *  **   *  *  * **       ***

if(a==0) printf(0);
else if(a==1)  *  ** 
else {
* * *     *     ** **** ***    * *  **   ***  ** *
*    **  *    *   ***  ** * * *  *   * *  *****   ** * *   * = c0+c1;
*   *   *  *  *           **    *  ** **   ** *     * ***  = c1;
*   *   *   * ****  *  **     *** *   *** *** * * ** *  ***  = cb;
***   ** * ******  ** ** *
   **    **   *     ** *   *    ** *    * * ****   * *


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * * **  *     **

int main(void)
{

int   ***    
 *******  * ** * * ** *  ***

if(i==0) **  ** **      * *
else if(i==1) *   *  **  **  ** * * ** 
else {
  *   **   ****** ******   * *  ** **  ****    
    * *** ** **  ** **  *   **     * **    ** *** * = f0+f1;
    *  * * **   *   * **  *  * * * *      *  *   * ******* = f1;
** *  ***     * *  * *  ** ** ******* ***    *********    = fn;
* *    ** * *   *     * **
*** ***   ***   * *   * * *     ** * ** ** ** 
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * ** *   ** * * 

int *  
{

int * *  *  * *
*** **** **     *  ** ** 

if(i==0) printf(0);
else if(i==1) **  * 
else {
 * ***  ***** * * ** *  * *    ***  ***** *
 *  *   ****  * ***   * ***    **   *** * *  * **    * **** = f0+f1;
        *   *    * *** *  ** ** *  **          ****** * *  ** *  = f1;
  *   *          *** *  **  * * * ***  *    * ** *      * = fn;
***  *   **  * **  *    
*** * ** ** *   **** *    **   ** **      *   ***** 
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* * * * **** * * ** **** * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
** * ** ** ** * * * ** ****** ** *** * *** * * d;
* *** * ** ** * *** * ** * ** ***** *** ***** * (d=2; d<n; d++)
* **** * *** * *** ** **** * * * * * * * * *
* * ** **** * ******* * * ** * *** * ** (n%d==0)
* * * ** * * * **** * * * * * *** * ** * *** * * * ** * * **

   }
* **** ** * ** * ******* ** * * ** * *** * * *
* ** **** * **** ** * * ** * ***** ** ** *** * * * *
***** ** ** ***** ***** * ** ******* *** *
* * * ** * *** * ** ** ** ** * **** *** * *
* * ** * ** * ** * * * * * **** ** * * * ** *** * ** *** * * (e==0)
*** ** **** ** *** * ** ** * * ** ** ** * * ** ** * * * ** * *** ** * *** *
** ** * * *** * * * * * * * * * ******** ** * * ** * *
* * * * ** ** ** ** *** *** **** * * *** ** ** * **** **** *** * ** ** ** *** * *** * ** ** * * * * ");
*********** *** * * * * ** ** ***** ***** *** * ** *** * * * * *
** *** ** * **** *** *** ** ****** ** *** ******* *** *** * * * * * ** ** ** ****** ***** ****
***** ******* ** * *** * ** * * *** **** *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
** *** ***** * ** * * * ** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* * * * ** *** * * * *** ** ** * ** * d;
** * * ** * ** * *** *** ** ** * ** * *** * ** (d=2; d<n; d++)
* * * * *** * * * ** * * ***** ** * *
* * * ** * ** * * ** * *** ** *** ** ***** (n%d==0)
* **** * **** * * * ** ** ** * **** ** * **** *** *** * ** ** *

   }
** * * ** ** ** ** * **** * *** ** ***
* ** * ** * * * * ** ** *** * ** ** * * **
** * * * * ** * * ** ** * * * * ** *
** * ** * ** * * ******** **** ** * * * * *
* * * * ** * * * * ****** ** * *** * ****** * **** * * (e==0)
* * * *** * ***** **** ** * * ** * * * * ******* * ** * ** * ** ***** ** * ***
**** *** ** * ** * * * *** ** * ** ** ** ***** * * **** * ** * * ** *
* *** * *** * *** ** * ** * * * * ** * *** *** **** ** * ** ** ** * * * *** ** * * ** ");
** * *** ** * ** * * ** * ** ** * * * *** * ** * * * ** * * *
* * * * * *** *** ****** **** ***** ** *** *** ** ** * *** ** ** *** * * * * * * * *
* ** *** ******** *** ***** ***** ** * * **

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
* *   * * *   * *  ** * **   *****     ** * ******   d;
 ***    * ***   ****   * *   * *** * *** * ***** *** (d=2; d<n; d++)
*  *  ** **  *** ** ** * ***  *     *  * * * ** * * * 
  **** *       **** **   **** *   *  ****************  * (n%d==0)
  *       *     *  *  *   * *    * *   ***  * ***   *  *   *  ***** ***     **
   }
*  ****** **  ****  * ***   * * * *** * *** **** ***   ** * *  
   * *  ****     **  *  *******   ***     *     
**  *     *    * *  ********** *** *    *  * * * ** ***
* **   *  * *  * **  ***   *      * *   * *   ** ***
  **  ** * ****** * **   *    * * **   *       **  *** *     * *  *  *  *   (e==0)
   *   *  **  *    ** * *** * * ** * * * *  ** **  ** **     **  ****  ***   ***** * ** ** *   *  **  ****
 **** ***  * *     **      ***    ** *** ** *** *     * **  **  * **  **** **   ****   *** 
  ***  *   * *** *****  **   * *  ***  * *  ** * *** *  *   ** **     *  * **   *     * *  **** ** ***  *      ***** ");
**  ** **     *****      **    * * * **      *  * ****  *  *  * *  *** ******  * ** ***
*  * *****   * **  *** * **    *  *  ** * ***  **      ** **   **   **  ***  **   *   ****   ** *  *      *
****  * **  ****   ** *  ** * **   * *     * *  *  ** 
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
   ******   *    *  **          Fn,t1=0,t2=1, n,input;
* ** * ** **** * * **      *    ****** *********** ***

**   ********** **   * * ******** ***  n++)
**  *       * * *  * *   
*  **   *  ** *   * * *   ***  *   *** *  * *  *  = t1 + t2;
** **** * ** ********** ** * *    ** **  *** ***** **   
*** * * **   * * **   * **             ***  *****   ** **** *
    }

*********   *  *** *  *   *  *   *  *** * **  **

 *  * ***** * *  *  * * *   *** *  0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
 *** ** **  * **  *    Fn,t1=0,t2=1, n,input;
 ** * *** **  * ***** * **   * * ****   *  ** *   ** ***  *

***  * * *  * ** ***  *      * ** *    n++)
  *  ** * **  *    * **  ***  
   **   * ** *  *  **  ** **   ***  **  *  **   * *** = t1 + t2;
*    **     **** *   ***  *   * **  *    *   *  ** *** *
   *   ** ** * *****     **  * **   *** ******  * * *   *    *  *    *
*     * **  *   * *    *** *    *

  *  *  *** *** *     *    **    * *  ** * * ",Fn);

 *  **  * * **** * *   ***  ** * 0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.117
©2016-2024

Related questions

0 like 0 dislike
46 answers
11-30 Exercise 1: Fibonacci numbers (Array)
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 1.9k views
0 like 0 dislike
99 answers
11-01 Exercise 1: Find out all prime numbers between n and m
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 3.4k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 1.4k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 2.4k views
2 like 0 dislike
67 answers
11-09 Exercise 2: Reduce the fraction to lowest terms
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 2.3k views
12,783 questions
183,443 answers
172,219 comments
4,824 users