0 like 0 dislike
17.6k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列:0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始,其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2),F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n,輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited

edited by | 17.6k views

93 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
******** * * ** *** * F0,F1,Fn,n,a;
* * ** * ** *** ** * *

* **** * ** ** ** **** ***** * **** ** &a);

** *** * ** * * * **** *** ** * * **
*** * * ** * ** *** ******
* ** ***** * * * * ** ** *** * **** *** * * * *
* *** * * * * *** *** ** * ***** * * **** ** *
** *** ** * * * ** * * * *** ** * * * * *** ***
    }


* ** * * * * **** * * * * * ** * * * ** * Fn);

* * *** * ** * * * * ** 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** * ** * *
int **
{
int *****
* ** * ** * * * *** *
if(a==0) printf(0);
else if(a==1) printf(1);
else {
*** * ** * * *** * * **** ** ***
** ** * *** *** ** *** *** **** * ** * ** = c0+c1;
* * * * * ** **** * ******* ** ** ** * * ** * * * * = c1;
* * * *** ******* ** * * ** ** * * * ** = cb;
****** * *** * * * *
** ** * * *** * ****** ** * ** ****** **
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include * ***********

int ** * **
{

int *** * *
*** * ** * ** * ** *

if(a==0) printf(0);
else if(a==1) ** *
else {
** *** ** ** * * * * **** * ** ** ** *
* * ** ** * ** ** * *** * * * * ** * * **** * = c0+c1;
** * *** ** * *** * * * *** *** * ** ** * = c1;
* * **** *** ** *** * * * * ** ** * ** * = cb;
* **** * ** **** * ***
* ***** ** *** ** ** **** ** * * *


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include * * * ** *

int main(void)
{

int * ** *
* * * ***** ** * *

if(i==0) * * * * ****
else if(i==1) * ** * * *
else {
* *** * *** *** ** * * * ** *** *
* * * ** *** *** * * * * * ** * * * * ** = f0+f1;
** * * * * ** * * ** ** * * ** ** = f1;
* **** ** * **** * ** ** ** = fn;
** * **** * * **
*** * * *** * ** * * *
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** * * ***

int * * *
{

int **** * *
* * ** ** * * ** *

if(i==0) printf(0);
else if(i==1) *
else {
* * *** ** * *** ** * *******
** ** **** * * * * ** * * *** * **** * ** * * = f0+f1;
* **** *** * * * ** ******* ** * * = f1;
* * * *** * * * * * *** * * * **** * = fn;
*** * ** * *** ** **
*** * * *** * ** *** * *** ** *** **
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* ** * * * * * * * ** ** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
** ** **** **** ****** *** * *** *** * **** *** * d;
** *** * *** * ** * * ** * * * ***** * *** (d=2; d<n; d++)
** **** * *** ** ** ** **** ** * * *** *
* ** ** ****** ** * ******* * * ** * *** (n%d==0)
* **** * *** *** * * ** *** *** * * * **** * ** * * **** *** ** ***

   }
** * *********** * **** ***** *** ** * ** * * * * *
** ** ** ** ** *** ** * ** * ** * * ** ** * **
****** *** * ** * * * ** ** * ** **** * * **** **
** * * * ** ** * ** * * ** *
*** ***** * * * * ** ** ** *** * **** *** * ** ** * ** * * **** (e==0)
* *** ******** * * **** * * * * **** ** * *** * * * ** * * ** ** ** * *** **** * *
**** * * * ** ** * *** * ** **** ** **** ** * * * * * *
* * * *** * * * * * **** **** **** * * ** * * ** *** ** * * * *** * * * **** * * ");
** * ***** **** * * * * *** * ** * *** *** * **** * * *** ** * *
* ** * * ** **** ** * *** * ** ** ** * ****** **** * * * ** ******** ** *** * ** *
** * * ** * * * * ** * ****** *** *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* * ** * ** **** * * *** *** * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* **** ** * * *** * * * * * * *** d;
* ** ** * * ** * ** * *** ** ** *** **** * * (d=2; d<n; d++)
**** * ** ** * ** * * ** ** ** * * *** * *
** **** * ******** * *** * ****** * * * ** (n%d==0)
**** * * ** ***** ** * * ** * ** ** * * **** ** ** ** **** ** * *****

   }
* ** *** ***** * ** * ** * * *** ** * ****
** * ** *** * * ***** * * *** * ** ****
* * * * * *** * *** * ** ** * * *
**** * * ** * ***** **** * ** * * ** * * *
*** *** ** * * **** * ** * * * * * * * * * * * * * *** * ** **** (e==0)
*** ** * **** * * ** ** ****** * *** * * * ****** *** * * ** * * ** * ** *** * **
*** **** * * * * * * *** * * * * * * ** * *** *** ** *** *** * *
** * * * * * * **** * **** * ** * *** * * ***** ** * * **** ********* ** ******* * * ");
** *** ************ *** ** * * * ** * ** * ** * * * ** ** * * **** **
** *** * **** ** *** * *** ** ** * *** **** ** * *** ** *** ** ** **** * ** * **
* * * ** ** * *** ** ** * **

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
** * * * ** * *** ** * * * * ** * ** d;
* * *** *** * * * ** * * ** * ** *** * (d=2; d<n; d++)
* * * * * * **** *** ** * * ** * ****
***** ** * ** **** * ** * **** *** **** * * * ** (n%d==0)
*** *** * *** * * ** ** * *** * * * * * * ** * * ** * * ** **** *
   }
* ** * * * * * ** * * * **** ** * * * * *** *
* *** ** * ** * * * ** *** * *****
** * * * ** * * * * *** * ***** * * *
** ** *** * * * *** ************ **** **
*** * * * ***** ** * * ** ** * ** *** ***** ** * ** ** *** ** * ** **** (e==0)
** * *** ** * ** **** * * ** * *** * * ** ***** ** * ** * * ***** *** *** * * * **** ***
* * * *** **** ** * ***** * ** **** * ****** *** * * *** ** * * *
***** * * * * * * ** ** *** * ** *** * * * * *** *** * ** * * * * **** *** ** ** * * **** ** ");
***** * ** * * * *** ****** ** ** * * ********* ** ***** * * * * ***** **
**** *** **** ***** ** * ***** * ** ** ** ***** * *** * * ** **** ** ** **** * ** ** **** *
* * * **** *** *** *** ** * **** ** ** *
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* ***** **** ** **** ** Fn,t1=0,t2=1, n,input;
* ***** * * *** **** * * * * * * **

*** **** ** ** ****** ** ** * ** * n++)
** * ** * *** * *
**** ** **** ** * * * * *** *** *** * * = t1 + t2;
* * * ** *** ** ** * * ** * ** **
*** * * * * ** **** * * **** ** * * * ** **
    }

* * * * * *** * * ** ** *** *** *** *

* ** ** *** * **** ** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* * * * *** ** * ** Fn,t1=0,t2=1, n,input;
* ** * * * ** ** * **** * * ** * *** *** *

** ** *** * ***** ** **** *** * n++)
* ** * ***** *** *
*** * ** * *** **** * * **** ****** *** * * = t1 + t2;
*** * ** ** **** ***** * * ** * * *** * ** *
* *** ** *** *** ** * ** * *** * * *
* * * * ***** *** *** *

* ** * * * * **** *** * * * ***** ",Fn);

*** * ** * *** ***** * ** ** 0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.100.103
©2016-2025

Related questions

0 like 0 dislike
46 answers
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 11.5k views
0 like 0 dislike
99 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 21k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 8.8k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 14.5k views
2 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 14.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users