11-01 Exercise 3: Fibonacci numbers

0 like 0 dislike
18k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列：0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始，其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2)，F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n，輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 18k views

93 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
*** ***  ****   *** * *  ** ** F0,F1,Fn,n,a;
*****  **  * ** *** **  **

 ** **  ** ******  ***** *  *****  **   * * *  * &a);

* *      *  * *** *   ********  **  *** **** *
  *  **    ***  * * * *  * 
** *  *   * ***   **  * ** **    ** *** * ***   * *   *
 *  *  ***      * ** **  ** ***   ***  *  ** ** * 
   *      *   ****  **      **  **   **   *    *    * *** ****
    }


**   ***** * * *****  *  ** ****  ** * **  *  *     Fn);

* * ** *   * *  * ****   *   0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ** *    * *  
int    *  
{
int  ****  *   
*  ** * **   ** *    ***  * *
if(a==0) printf(0);
else if(a==1) printf(1);
else {
*** ** *  *** *    *       * *  ** *  * *   
 *     ***    *   ** ******* * ** * **     ** *** *  **  = c0+c1;
**** * **  *** *   *  *  **   ***** ****   ***** ***** = c1;
* ***    * **  *    **   ** *  *** ***   *******        = cb;
   ** *   **  * * **  ******** **
** **** *   **** *    ****   * **** * *  **** *** ***   
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** ***  *   *     

int * *** * *
{

int    * **** 
**** *    *     *    ****** *

if(a==0) printf(0);
else if(a==1) *    * 
else {
 *    *** *** * ** * ***  ** * ***    ****  **
*** ** ** *    **   ** ** *    ** *   ** ** *      * *  = c0+c1;
**   ***  *  * * ** ***  *   **  ** *  * ******  * **** ** * = c1;
***  *  *      *** *** **    ** ** ***  ** * *  * = cb;
* *  * *  * * * **** ****** **  
  * *  *     ****      *     ***    ** **  *  **    


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * *** *  ***   

int main(void)
{

int   ** **     
 ** * *  * *   **    * *********  

if(i==0) * * *** *     * ** *  *
else if(i==1)  *  ******* ******* 
else {
* *  **  ** * ** ********** ** **  *    ****
** **    * *  *      ***  ****  *  * ** **    * *  *  = f0+f1;
   * ***   *  *   *  ***     ***  ***** ******  *** **   ** = f1;
 ** * ** ** *    * *      ***   *** *** ******   **     * *  *   = fn;
   *********  ** * * *    * **  
  * * * * ** **     *  * *      *  * * *** ***  **
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  * ****** * **   

int ***  *
{

int ***  **   
     *  *  ** *    * ****  **

if(i==0) printf(0);
else if(i==1) *    * *
else {
  *   * ** **     ****** * **** * ***  *
*  *  * * *    *   *  * * ** *   *   **  ** **  ****    = f0+f1;
 ******  * *     **  ** * * ***    * *****   *     * = f1;
* *  ** ** * *  * * *  **    * ***  ***   **   * ** = fn;
*  ** *  **** *  *   *
 * *    **** *** *****   ** *** *      **  *  ** ** 
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* * ** * * ***** **** * * * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* * ** * *** *** ** *** *** *** ** ** *** d;
* ** **** ** * ***** * * ** * ** * ******* ** * (d=2; d<n; d++)
* ** *** * ********* ** *** ** * * * ** * **
** * * * * *** * * *** * *** ****** * *** (n%d==0)
*** ** * ** * * ** ** * * ****** * * **** * * *

   }
** * * * * **** * * * ** ***** ** ** ** ** *** *** *
****** *** ** ** * *** *** ** * * *****
** *** * ** * **** * * * * * * * ** *** ***
** ** * ** * *** * * * * ** * ** ** *
*** * * ** ******** * ** * **** * * ** * *** * * ** * * (e==0)
* * * * * ** * *** * * *** * ** * * * ** ** * *** **** ***** **** *** * * * *** **
* ** * ***** ***** ** * ** * *** **** ** ****** ** * ***** ** *****
* *** * ** ** ****** *** ** * * * ** * *** * ** ** ** ** *** **** ** * *** ** ** ** ");
** * * ** ** ** ** * **** * * ***** ** *** ** * * * ** *
* * * * * **** ****** * * * * **** * * * * * * * ** **** ** ** * **
***** * * * ****** ** * * ** **** *** **

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* * ** * * *** * ** * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* **** ** ***** *** * ****** *** * * * ** ** * d;
** ** ** *** ** * *** *** *** ***** **** * (d=2; d<n; d++)
* * * * *** * *** *** *** * ** ** *****
**** ** *** * ** * * **** ** * ** * *** (n%d==0)
* ** *** *** * ** * ** * * ****** * ** ** * ** * **** ** * * *

   }
* ** ** ** * * * * ** * ***** *** *** ** * * * **
*** ** * * ** ** * **** ** ** ** ** ** * ** *** *
*** * * *** *** ** * ************ *** * * ***
* **** * **** * * * * ** * * * * * **** *
** * ** * ** **** * *** *** * * * ** * * *** ** * *** * (e==0)
* * * ** * ** * *** ******** ** ** * ** ** ***** * * * ** * *** * ** * *** *** *
**** * *** ** ** * ** ** * ** **** * * * *** * *** * *
**** * *** ***** *** *** ******** ** * * ** ***** **** * * *** **** ****** **** * * * *** * * * * ");
* * * ** * ** * ** ** * **** * * * *** * *** *** ** * *
**** ***** * * * ** * **** * ********** * * *** * * * * * ** * ** **** * ** * *** * * *
** * ***** * ** * * *** * ** * * *** * ** *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
      * * * ** *   * ****  **** *** * ***     *     **** d;
*** **     ****   *    * * ****        *    *** *   (d=2; d<n; d++)
* * ****   *  *  ******  *   * *** *** **** ** ***   ** *
 * *     **  *   **  **** *     ** * * **  ****     **   * (n%d==0)
    ** *  **   ** * *    * ****** * ***       * *** *** * **** *    **** * *
   }
* ** ***  ****  *****    *  **  *  **   ***     * * **   *  ***
* *   *     * *  *   **** * *   *** **  *   * ***** * 
** ** ** * **     **  * * ****  ** * *** * *** *     ***
*   ***  ** * ** **  *  **** * * ** **  **  ******
* * * * **   **** *  **  *   * * * *****     *  **   * *     * ** *   ** ***   (e==0)
 *    *  **   * ****   **    *** ***  *  ** **    *    * * **  *  **  *  *   * ** **** **  **   *  ****   ***
***  * **    *  **  * *  * ***  **  ***  * *** *   *   *** * *** ******  ** ***  ***** 
  *   *  ****** **      **** * ***  *       *  *  ** **  *    ***** *  **     * ** * *  **  **  ** *  *   *** *  ** * *   * ");
*     ****  **  *      ****  **** ** **  *    * ** **     ** **** * ** * * *** * *  ** **
  *** *  *      *  **      ***     ** * *   * ***  *    * **    **   ***  *** ********    **** ***   * 
**** **  * ***** *   ***** *  * **  *** *           *   **
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
  ****   ***    * *    *** **  Fn,t1=0,t2=1, n,input;
** * *    ** ** **  * *  **** * **   *** * **  * ** *    *  ** 

* *   ***** ** *** **  **   **    * *** ** ** **   n++)
***  * * ** **   *    **  *
*** *       ****  ***** * *  *  ***   *  * **** *** * = t1 + t2;
  ****** ***   *** * * **  *** *** * *****   ** * 
  **  ** ****  **  * ***    *** *   ** ******  ****  * 
    }

  *  **  *   * * *** ** *     * * *  **   ** 

* ** * *******    ** ***    * *  0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
**   *   ** *  *    * *  * * ** * Fn,t1=0,t2=1, n,input;
 *   ** *  * *****   * * ***** *  * *    *   **   * **

 *****      ** * **  *    * ****** *    *    n++)
 *  *     **  **  *   *    * * 
*  ****** *** *  *  *  **** * ** * *    *  **  * = t1 + t2;
**      * *** *   ***   *   *       *     * * * **
* *  *** *** *   *    **   ** **** *     *** * *****
*** * *  ** **   *  * * *  

** ** * *  *     *****   *  ****   *******  ",Fn);

** **  **   ** * *    **     0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.190
©2016-2025

Related questions

0 like 0 dislike
46 answers
11-30 Exercise 1: Fibonacci numbers (Array)
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 11.8k views
0 like 0 dislike
99 answers
11-01 Exercise 1: Find out all prime numbers between n and m
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 21.5k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 8.9k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 14.9k views
2 like 0 dislike
67 answers
11-09 Exercise 2: Reduce the fraction to lowest terms
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 14.7k views
12,783 questions
183,442 answers
172,219 comments
4,824 users