0 like 0 dislike
15.9k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列:0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始,其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2),F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n,輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited

edited by | 15.9k views

93 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
** *** ***** * ** * * F0,F1,Fn,n,a;
* ****** ** ****** **** ** *

* *** * *** * ** ** **** *** * * * ** &a);

*** * **** * ** **** * * **
* ** * ** ** ** * *
** ** * * * * * * ** * ** *** * * ** ** * *
* ****** **** ***** ** * * * * ** * ** *
**** * * *** * ** * **** * * ***** * * **
    }


* * * * ****** * *** * **** * Fn);

** * ***** * ** ** 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * ****
int * * **
{
int * ** ***
*** * ** ** * ****** * * *
if(a==0) printf(0);
else if(a==1) printf(1);
else {
* * * ** * *** * * ***** * ** * ** *
** * * * ***** ** * ***** * * * * = c0+c1;
**** ** ** * * * * * ** ** * * * * * *** *** ** = c1;
** ***** * ** * ** * ** *** *** * * ** * * * * = cb;
* * * * ** ******** * *** * *
* *** ** ** * ** ** * * ** ** ***
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include ** * * ** * *

int * *
{

int * * * * *
* * *** * * * ** *

if(a==0) printf(0);
else if(a==1) *** * *
else {
** * ** ** * * * * ** * ** * * * **
**** * * * * * * * * **** * ** **** ** * = c0+c1;
***** *** ** *** *** ** *** ** * **** = c1;
** ** * *** ** ** * ** *** * ***** * * ** = cb;
** ** ***** ** * ***
* * ** * **** * ** ** * *** * * * * *


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include ** * **** * * **

int main(void)
{

int *** ****
* * *** * * *** *

if(i==0) *** **** * * * **
else if(i==1) ** * ***** * * * * ***
else {
* ** ** ** * ** *** ******* * * *
* * *** ** * ** * ** *** ** ** *** **** ** = f0+f1;
* ** ** ** * ** * * * * ** * * ** ** = f1;
* * * ** *** * *** *** ** * *** ** * = fn;
** * ** * * * * **
** ** * ** * ** ** ******* *
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ****** ****

int *
{

int * * * *
**** ** * **** * ** **

if(i==0) printf(0);
else if(i==1) * **
else {
**** * ** **** * ** ** ** ** *
** ** * * * **** *** * ** ** *** *** ** = f0+f1;
*** ***** ***** * ***** * * * * * *** ** = f1;
*** *** * *** * ** * ** ** ******* ** ** * ** **** * = fn;
* * * ** * * ** ** ***
* ***** * * *** **** * * ** * * * *
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
** * * **** * * ** ** * ** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* ****** * * ** *** * * * * * * * *** * * * d;
** *** * * * ** ***** *** * *** ***** *** (d=2; d<n; d++)
* * * **** * ******* ***** * * * * * * * * **
**** * ** *** * * * ** * * **** **** (n%d==0)
** * * ** * **** * * *** ** * * ******** * **** *

   }
** *** * * ** *** * ** * * ** * * *** * ** ****
* * ** * * * *** ** * * * * * * * * * ** ** ***
** * * **** ** **** *** * * * ** * ** ** ** ***
** * **** *** * * **** * *** * * ***** * ***
* * ***** ** ** ** * *** *** ** ** **** * * **** *** * * (e==0)
* * *** ** * *** * * * ** * ** ** * ***** ** ** ** ** ** * * * * * ** ****** * **** *
***** * ** ** *** ** * ** ** ** ** ** * * * * **** ** * * *
** **** * * * * **** * * * * *** ** ** * * * ** * *** * *** * ** ** * ** * ** * * * *** * ");
* * * * ** **** * * * *** **** * **** * *** * ** ** * ** ** ***
* *** ** ** *** ** *** ** * **** * ** * **** **** ** * * ** * * * *** * *** * ** *
** * **** * **** **** ** *** * * * *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
*** ** * **** * **** * * * ** * *** * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
***** *** * * ** ** ** * * *** * * ** * ** d;
** * ***** * * * * * * * * ** * ** **** (d=2; d<n; d++)
*** * ** ***** * ** * * ** * * ** *******
* * * * ** * * ** * *** * ******* * * ** **** * (n%d==0)
** * * * * * * ** *** *** * * *** ** ** * ** *** *

   }
* ** ** ** ***** **** * * * * * ** ***** *
* ** * * *** ** ** ** *** *** * ***** * *
**** ***** ** ** *** * * * ** * * ** ** * *** ***
*** * * * ** ** ** * * * **** * * *
** *** **** * * *** ** * **** * * * * * * * * * * * (e==0)
* * * ** * ** * *** * **** ** *** * ******** *** * * * ** * ****** * * *** * *** ***
* * **** *** * *** * * * * * *** ** * *** * ** ******* * **** ** *** *
***** ** * ** ** * * * * ** * ** * * * * * * * * * ** ***** ** * ** * ********* **** ** * ** ** **** ");
**** ** * ****** * **** ******* ***** *** *** * * **** **** ** * ** *
* * * ** * *** **** * * ** ** ******** * ** * ** *** * ** ** ** * * ** *** * **** * * ****
*** *** * ** ** *** * * ** * **** ****** ***** ** *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
** *** ** * * * * * * ** * ** ** *** * *** * *** d;
* ******** * * * * * *** ** * * * ** ** *** (d=2; d<n; d++)
* ** ** ***** *** * * * **
****** * *** * **** * ****** ** ** ** * * * (n%d==0)
* * *** * *** **** * * ***** *** * * * * * ** * *** * ** * ** ** *
   }
**** ****** * * *** * *** * *** **** *
* *** * * * * * * * * ** * * *
** * ** *** *** ** ** * ** ** * * * * *
* ** ** * *** *** * ** * * ** * * **
* ** * * ** ** * ** * * ** ** ** ** * ** ***** **** * * (e==0)
* * ** ***** * * *** *** * ** ** * **** * * * * * * ** * * ** * ***** ** * **
* **** * **** ** * * * * ******** ** *** * * * * ***** * ***** *** *** * * **
* * **** **** * * **** **** *** *** *** * *** ** * * ** * * *** * ** * **** * ** * ");
** * ***** * ** **** ** * ** **** ** ****** **** *** *** * * ** *
* ***** * * * * * * ** * * * *** * * ******* * *** ** ** *** *** *** ** * * *
* * **** ****** * * * * *** ** ** * ** *
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* ****** * **** * Fn,t1=0,t2=1, n,input;
* **** ** * ** ****** * ** * ** * *******

* * ** *** * *** * * * ** ** n++)
** * ** *** ** * *
* * ** * * ** ** ***** * * ***** * *** = t1 + t2;
** **** * ** * ** *** * * *** * * * *** ***
** * **** **** * ** * * * ** **** *** * *
    }

** * ** ** **** ** ***** ** * * *

** **** * * * ** * ** ** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
*** * * ** ***** ** Fn,t1=0,t2=1, n,input;
** ** ******** ** * ** * ** * ** * *** **

*** **** * ******** **** * ** *** * * n++)
* **** *** *** * ***
* * * ***** ** **** *** *** ** ** * *** = t1 + t2;
* *** ***** ** * * * *** * *** * ** * * **** *
* ***** *** *** * * * **** ** * * * *** ***
* **** ** **** *** *

* ** * ** ****** *** ***** * * ",Fn);

* * * * **** ** ** ***** 0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.109
©2016-2025

Related questions

0 like 0 dislike
46 answers
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 10.6k views
0 like 0 dislike
99 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 19k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 8k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 13.2k views
2 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 13.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users