11-01 Exercise 3: Fibonacci numbers

0 like 0 dislike
11.7k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列：0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始，其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2)，F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n，輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 11.7k views

93 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
  **  ** ** *      * *** * * F0,F1,Fn,n,a;
*  **   * ****  *  * ** **  **  * **

 ** ***  *     * ******  *  ***  *   * *        * &a);

  **      *  **  *  * * * *  * * ** * 
  * * *  * **  ****  *   *   * 
 * *   **  *     * **    *   ****  ***** ** *  *  *  * *
******  **  * *  *   * **   *   *******   *   * ** * * 
* * *   *  *      *    * *  *  ** ** *  * * *******   *  *  *** *
    }


   ***  *** ** * ** **** ****    **  *     Fn);

* ****  *  *** *** *********   0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **    ******  
int *  
{
int *    ** *
  * *      ** *****   *  *** *
if(a==0) printf(0);
else if(a==1) printf(1);
else {
* **  *   *** * * **  *** *    **    ***
  ***** **         ** ***** * *     * *   **** **   ** = c0+c1;
  **   *    * *      * *  *   *   **  ** * ** ****  **    = c1;
* ****   **   **   **  *   ****   **  * *****  **** *** * *** = cb;
**    **   * ***** * *  ****
*   *   * * **  ***  ** **** * ***  ** *  ** *** *   *** *  
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  **   * * ***** 

int  *  **
{

int * *    *  
   ** *  * **  ** * *  * 

if(a==0) printf(0);
else if(a==1) *     
else {
 ***   * * ** *  ** ***      **  *    ** ** 
**   * ** *  *** *  * ** *****  ** *  ** *  *   * *  *  *  = c0+c1;
**    *  * *   * *    * * ***  *  **  ****    ** = c1;
 **    ** * *      ***  ****** *  *  ** *   *** ** *** * = cb;
* **  **   *  *** * **    
      **     * *  ** *    * * **  * * *    *    


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ****  * * *  **

int main(void)
{

int  * * ** **
*     * * ** **  ***     *

if(i==0) *  ** *** **** ***
else if(i==1) ** * * *** * ** *    *  
else {
  *** ** ** *   * *   *    ***  * ***   * * ** **
  *  **  *  * **   * ***  ** *** *****  * *   * * * ** = f0+f1;
*   ** *** *** * *** **** **          *    *  * *** * = f1;
**  *    * *****  ***  **  * *  * ** *  **   *    *  = fn;
* **   ** ** ******  *  * ** ** *   **
* ****  *   * **  * **** **   *****   * *    ** * ***
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  **   **  

int *  * ***
{

int ** ***    
 *    **   *  *  *    ***  

if(i==0) printf(0);
else if(i==1) *  ***
else {
****   ** **** *  *   *** * * ****    * **   
** *     *  **   *  *** ***  *  **** * * *  * *  *  *     **  = f0+f1;
*** ** *** *** * *** ***   * *    **     * *    = f1;
      *  ***** *  *          *     * ** ** * *  ** = fn;
 **  ** **** *    *** *  * *   
*** *******  * * * **     **   ***  *   **     
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* ** *** ** *** **** ** * * * * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
*** *** **** * * ** * ** * *** * ** *** d;
* *** * * ** ** *** * ******** * (d=2; d<n; d++)
* ***** * ** * * **** * *** * * *** ** **
***** ** * ** * * ** * **** *** *** (n%d==0)
* ** ** * ** ** * *** ** *** * * * * * * ****** ** * **

   }
* **** ** * * ** * ** *** * ** * * **** *** **
** *** * ** ** ***** ***** * * * * *** *
* *** * *** *** ** * * ***** ** ** ** ***
** ** * * ** * *** * * **** * ** ** * ** * **** * **
** ** * *** * ** **** ** ** * ** * * * ** * ** * ** ** * ** (e==0)
* * ** ****** *** * *** * ** *** * * **** * *** * ***** *** * ** * **** * **
**** * * **** *** ** *** ** * * * ** *** * * * * * ***
* ** *** * ** * **** * * * * ** ** *** * * *** ****** * * * * * **** ** *** * ");
* ** * ** **** * ****** * **** *** * *** * *** * *
***** ***** **** * ** * ** ** ** * * * * ** * * **** *** ** ***** *** * **
* * ** * ** * *** * * *** ** * * * *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
** * *** * * *** * **** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* * ** * * * * * * * * **** ** ***** ** * * d;
*** ** *** * ** * ***** * * * * * * (d=2; d<n; d++)
** * * ** * * * *** **** * ** ** ***
* ****** ** **** * * ** * ** *************** * * (n%d==0)
* *** * * ****** * * **** * **** * *** ** ** * * ** *

   }
** * ** **** ** ** * * * * * ***** * * ** ***
** * * * ** * *** *** ** ** * *** * * * * * * * * ***
* ** **** * ** **** ********** *** ** *** ** * ****
* * ** * ** *** **** * ** ** ** *** * * * ***
*** * * **** **** * * ** ***** ** **** ** ** *** **** *** *** (e==0)
* * ** *** * * * * * ***** *** **** * ** ** ** * * ** * ** ***** ** *** *** * *** ** ** * *
*** *** * ** ***** ** * **** *** ** ** *** * * ** * ** ** **
* * ** **** ** ** * * **** *** ** * * * ** *** * * * ** *** * **** ** * ** ");
****** ** **** ** ** * * ** ** ** ****** * ** ** * ** ** *
* ** * * * ** * **** *** **** * ** * ** * **** ** * * ** * * ** * * *** *
* * * * * *** * ***** * * * *** ***

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
 ** **  ** *  ** ****  *****   *        ** *  **   d;
  ****  * ** ****   ** ** * **   *** * * *  *   *  *  **   ***  (d=2; d<n; d++)
*     *** *** *** ***  ********  *  * * * ***   ** *  
** * **   ******** *     * *     ** *   *  * * ***  (n%d==0)
**  **    * ** *  ** ** ****  *** *  *     **** *    *   ******  *   *** * ** *
   }
  **  * **   ** **  *  ***    **  **   ** ** *   **     *** * *  **
   *     **** ***  *  *   ****** *  *  ***    **   ** ****   
* **** **  *  * * **    **  *       ** **  ** ***  *
* *   **  **  *  *******  ** *** *     **   * *** *  *   ***     
*** * **  * **   ********** **  * *** ** *      ** * * ** *   **** * *** **         (e==0)
 ** * * **  *** ** * * **   ** ** ** **** * *  *   * * ** ***   * * * ****** * *  *   * * **    ***** ***  *
 * ***** ****  *  *** *  ***      ** ** **** * ****** *   *** * ** ** *****   *   *
   ****** * ** *** ****        *  *   * * * * **    *  ***  *  ***    ** * **     * ***   *   * ** **   ** *   ******      *** ");
****  *  ** *  *   **** ***     *     *  *****    *** **** **   * **       ****  * * **
  ** ***  ** * *    ***   ** *  **    * **        * * *  ************  *  **  *    **    **** *    ****** **   * *  
*   ***  **   *  * *** * *  *** *   ** * * *  
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
 ***   *  ******    ***** * Fn,t1=0,t2=1, n,input;
 * * *      ***    *** **** *  *** * *  ***    *   **   ***

** *  ***    * *    * * * ** * ** *  * *  n++)
** * *   ***** ***  *****
 ******* **  *   ** **  *** **  * *  ****  **      = t1 + t2;
 ******** **   ** ***   *****  *  *  ** ** ***   ***  *
  * ***  * *   * *   *        *** ****  * *  *   *  ** * * 
    }

** *****   ***  * **      *   *  * *** ** *     * **

**     *** **    *   *   *   * * 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
   **     *    *   *       *  Fn,t1=0,t2=1, n,input;
  * * * ***  *** * *  *      * * ***** * **  ***   **   ****

 **** **  *  * *    * **  *     *   **** ** *  * n++)
 ** *** ** ***  *   ** ***   *  
 **  *  *  * * *    ****  **  * *  * *  * ** *  * = t1 + t2;
**  ** **  ****  ** * *   **    *******   *****    * **  ** *
***  * *  ** *   ** **** *   *  ******** **  *** *  *   * * 
* ** * * *** * *****  * **

*   *  *  * ***** *       ***** *  *    * ",Fn);

** *   **  ****** *   *   *  **  0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.130.227
©2016-2025

Related questions

0 like 0 dislike
46 answers
11-30 Exercise 1: Fibonacci numbers (Array)
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 7.3k views
0 like 0 dislike
99 answers
11-01 Exercise 1: Find out all prime numbers between n and m
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 14.1k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 6k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 9.7k views
2 like 0 dislike
67 answers
11-09 Exercise 2: Reduce the fraction to lowest terms
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 10k views
12,783 questions
183,442 answers
172,219 comments
4,824 users