11-01 Exercise 3: Fibonacci numbers

0 like 0 dislike
7.9k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列：0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始，其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2)，F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n，輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 7.9k views

93 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
* * ****  ****** **  *** * ****  F0,F1,Fn,n,a;
   **  * * *** **  **  * * ***  **** *

*  ***    *  * **     * ** **  ****** ** **  ** * &a);

**  * *** *     *  ** **   * *      *     **
 * *  ***** *****   * **   *
    * ***** ***  *** * *** **   *  *    *  * ****** *  *
     **  ***   *  *** ***** * ***  *  * *  *        *****  *  *
**** *  ** *  **** ** ** *  * *  ***  * * *  **   ***  * * **** * *
    }


    * * ** * ***    ******* *      *** *  ** *** * Fn);

*  *   **  *** *   *  *** **  *** 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   *  * *   **** 
int  *   *
{
int  ** * **  
**   ***  *         **
if(a==0) printf(0);
else if(a==1) printf(1);
else {
* * *  *** ***  ** ***  ****   ** *** ** * * ***
 * ** *  * * ** ** *** *   **  *    *  ** *  ****  * **  *  = c0+c1;
  ****** * ** * **    *   ** **** **** ** **   *  ******     = c1;
 **   *      ****  *** ***   *****  ***   * **    *   ** = cb;
**  **  *  *  **** **** * 
 * **** *  * ***   *  *          * *** * * ** * ***** *
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **  ** *** * ** **

int  *  ***
{

int    ****  
*  * ****   * *****  ***

if(a==0) printf(0);
else if(a==1)  *    
else {
 ** **   *    * ** * **** **** *  **
    *** **   * *** *** ****  *    **   ** ** ** *   = c0+c1;
***** * *    * * **  * ** *  * * ***   ***   * **** ** * * * = c1;
 **** *  *  * * *** * *  *** ** ***   *  *   * ** * = cb;
  *      *  ****  *  *  ** ***  *
* *  *  ** * ** * *  **        ** ****** * * * 


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ***  *     

int main(void)
{

int   * * *        
**  ** **    * * **    * *

if(i==0) * **** *****      
else if(i==1)  ** * *      *   *  * *
else {
* * *  **  * ** ** *    **** * ** ** ***   * **
  **  *    *  * * * *  * *  **   *  *   *  **   ***  = f0+f1;
  *  * *    * *  * ***   *** *   ***  ** **  *  ** **  = f1;
 ******  * * **     **    *   * *   * *  * * **    ** * = fn;
*** *  * ******  *  *     * * 
    * ** **** ** *   *** *  *    *  ** **  ** **** ** ***
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *     *  ***  

int ***   *
{

int    *  * *** **
 * **  ** *   **** **** 

if(i==0) printf(0);
else if(i==1) **  ** **
else {
**** ** **** *  **   **   *  ** *  ***** ** ***
*  *** *** *     **  *  **  *   **  ** ***  **** * ** = f0+f1;
     * *** *  *** * * * * * * *    * ** * *  *  **     **   *   = f1;
    ***   **  * * *** **  * ****   ** * * * * ** **  * ***  ****  = fn;
 *     *** * *  * * ***** ***
*****   ***    * *    * ****    *  *** *  **** 
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
*** * ** ***** * ** * ** * ***** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
** **** ** * *** ** * ** * ** * ** * * ** ** d;
* * * * ** * ** * * * * * *** ** * * ** (d=2; d<n; d++)
** * ****** * * * * *** * **** * ***
* * * * *** **** * * * * *** * * ** (n%d==0)
* * * * * * *** * ** ** ** ** * ** **** ** ** ** * *** ***** ** *

   }
** * ***** * ** ** ********** *** * * * ** * ** ** * ***
* * **** * ** * **** ****** *** * ** *
** * ** ** ** *** ** ** * *** * * *
* *** ** **** * ** ** * ***** * * ****
* * ** * * * * ** * ***** *** * * * *** * * ** ** * * (e==0)
* ** *** * * **** * * **** ***** * * * *** ** ***** * ** * * * ** * * ****** * * ** **
* * * **** ** **** * ** ** * ** * ** * ** * * ***** **** * * * *****
*** ** * * * * * *** ** * * ** * * *** * * *** *** * * ** ** * * ** ** * **** ** *** **** ");
* * ******* * ** **** ** ** * * *** ** * **** ****** * **** *** * * **** *
* * * ** **** ** ** * ** *** **** ** * ***** * * ** ** * ** *** * * ** ** * **
*** * * * ** * * * **** * * ** * *** *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* ** ** * ** *** * * ***** *** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
** **** *** ******** *** *** * *** * ** * **** **** * d;
*** * * ** * * * * * **** ** *** * *** * (d=2; d<n; d++)
** ** * ** * *** *** ** * *** ** ****
* * *** **** * ** *** ** ** ** * * * ** (n%d==0)
**** *** * * * * ** * *** **** * ** * * * **** *

   }
* *** *** **** * * **** ** ** * * ******
* * * *** *** * * *** * **** * *** * * * **
* * * * ** * * * * ** ** ** ***** **
* **** * * *** * ** *** * * ** * *** *** ** **
* * * * ** **** * ** ** ** * * * * *** * * ** **** **** * (e==0)
* * * ** **** * * * * * *** * * ** * ** *** ***** * ** * ** **** * **
* ** * * ** ** * *** ***** * * ** **** ***** **** ** * **
* ** * * *** * * ** * **** *** ***** *** ** ** ** ***** ***** ** * ** * * * * * * * *** **** ");
** * * ** * ** * ** * ** * ** * * **** ** *** * * * * *** *
* ** **** * * * ** ** ** * * * * * * * ** * ** ** ***** **** ***** ** * *
** ** *** * ** * * * **** * ** * * ** **

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
* *  **     *** * *   *     **   **  **   ** **** * **  *   d;
   * *  **** *  *******    **    *******    ** *   * *  (d=2; d<n; d++)
*     ***  *****  **  *  *   * ***  *  **  **  * * *  **** *  **
    **    **   *   * * **          ** *   *  *     **** (n%d==0)
**** ****  *    * **** **** **** * ** ** *  *  ***   *  *   ** ** *    **** *** *  ** 
   }
  * **** *  *** ***    ** ** * * *    *  * **** ** ** **   ****  **  * *
***   ** *  * *        ***** **  *** *****  ** ** * *  
*   * * ***** ***  ***  *  ***** *  ** *** *  **    ***   * * 
*  *** *  *     ** **    * * *     * ** ****  *   *  * **
     *******   **  *  * * **  ******** * * *    ** *  *  *  *  **** **  **  *  *   (e==0)
  **  * * *** **  * ** ***  ** *   *****    ** *   *       *    ** ** ** * ** * *  * * * *  * ****    *  *  *   **  * *  
  * * ** *   * *        ** *  ***  * *      **   **   ***  **       *     * 
*  **** *   * ** ****  * *    *  * ** *  **  ** ***  ** ****     ** *  **  *  ** ** **** *** *  **  ****   *     *  ");
*  * *  ** *** * ** ***** * *  **    ** **  **  ** ***  * * **  ***    **  **
 ***   *  * ** ***  * * * *  **        **  ** *     * ** *** *    *    *  **** ** *** **  * * 
**  *  ***  ** *  **       ********* ***  **** *
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
***** **  * ****** **  *  * *   ** Fn,t1=0,t2=1, n,input;
* *  ***  ***** *  *** ***** * *  *   *     **  ******       * *

  *  * *      **  *** *   * ** * *** **  ***** n++)
 **  ** *  *** **    ** *
*  * ****  ***** * ***  *  ****   * **  * **  ****   *  = t1 + t2;
 *   ** **  **  **** ****     ** ** * * * * *** *  ** *   * 
  *  * *  *** ** ** ** *  * * ****** *   *   * * *  *     *****
    }

*** ***** ******* ***  **  * *   ** *** *   **   * *** 

 ***** *** ** * * ** ****  **** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
**  ***   * * ** *      ** * Fn,t1=0,t2=1, n,input;
 *     ** *    **  * ** ** **  * *  *    **    ** * * *

 * ** ** * ** ******      * **     * *  ***    * n++)
**   **  *  **    ***
*  * * **  *  ** ** ** *        ** *** ****      * *** ** * * = t1 + t2;
* *    ** ****  *  ****** **   * ******* *      ** ******  
 **  **     *    *  **   ***    **  *  ***   *   *  *****   *
  * * * ****** **    *  * *

  * ***  ***  * ***  ***** ***** *** * ",Fn);

*  ***    **  **** *   *****   0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.184
©2016-2025

Related questions

0 like 0 dislike
46 answers
11-30 Exercise 1: Fibonacci numbers (Array)
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 5k views
0 like 0 dislike
99 answers
11-01 Exercise 1: Find out all prime numbers between n and m
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 10k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 4.1k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 6.6k views
2 like 0 dislike
67 answers
11-09 Exercise 2: Reduce the fraction to lowest terms
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 6.4k views
12,783 questions
183,443 answers
172,219 comments
4,824 users