0 like 0 dislike
17.9k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列:0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始,其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2),F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n,輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited

edited by | 17.9k views

93 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
* ** *** * * * * * * * F0,F1,Fn,n,a;
**** ** ***** ** * ****** *

* * ** * *** * **** ** * * ** * * &a);

*** * * * * ** * *** *** ** * * * *
* *** ******** *
** * * ** *** ***** * ** * **** ***** ** *** *
* ****** * ** * * * * * * **** *** *** *****
*** * * ** * * * ** *** **** ******* ** *** *
    }


* **** * * * * * **** *** ****** ** ** *** Fn);

* ** ****** ** ** **** ** **** * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * * *
int *
{
int ** * ***
* ** ** * ** **** **
if(a==0) printf(0);
else if(a==1) printf(1);
else {
* ** ** * * *** * * * **
** ** * **** * * * *** ** *** * * ** * ** = c0+c1;
****** **** * **** * ** ** * * * = c1;
* ** * * * * ** *** ***** * * * ** * * ** = cb;
** * *** ** * ** ***
* * * * * * ** *** * * * * * * **
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include * ** * * **

int *
{

int ** ** *
* *** * * * * *

if(a==0) printf(0);
else if(a==1) ***
else {
* *** *** * ***** * * * ******* ** ***
* * * * **** * * ** * ** *** ** * * = c0+c1;
* ** *** * * * * *** * **** * ** * ** * *** = c1;
* * * * * ** * * ** ** ** ******* = cb;
**** ** **** *** * * **
* * ******* * ** ** *** ** * *** ** **


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include * * ** ***

int main(void)
{

int **** **** *
** *** *** **** *

if(i==0) * ** * *** * * *
else if(i==1) * * ** * * *
else {
** ** * * * ** ** ** * * * ** *****
* * * ****** **** * * * * * *** ** * ** * * * * = f0+f1;
* * * ** * * ** * * *** *** ** * * = f1;
* *** ***** * **** ***** ** * * *** *** * ** * = fn;
*** *** *** ** ** ***** *
* ** * *** * ** ** * * *** *** ** **
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include *** * ***

int * * *
{

int * * * *
* * * * *** *** *** **

if(i==0) printf(0);
else if(i==1) *** * *
else {
*** *** *** * * *** * ** * **** *** **
* * *** ** * ******** ************ ******** = f0+f1;
* ** * ****** * ** ** *** * * = f1;
** ********* * * ** * * *** * * ** * * ** = fn;
* * ** ** * * *
* ** * *** *** * * * ** ** * **** ***
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
** *** * * * *** * *** * ** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* * ** ** ** * *** *** ** ** **** ** d;
* * ** **** *** * * * ** * * * * * **** * *** (d=2; d<n; d++)
* ** ***** * ** ** * **** ** * * * ** **
* * * ** ** ** * * ** *** *** * * *** * * ** (n%d==0)
* * *** * **** *** *** ** ** * * * ** ** * * *** ******* *** *** * ***** *

   }
* * * * ** **** * * *** * ** *** ** ** ****
**** * * * * * *** * ****** * ** ** **** * **
* * ****** ** ** *** ** * * * * * *** ** *******
** ******* * ** * *** *** *** * * * ** * *
* *** * * * * *** * **** ** *** ** * **** ** ** * * (e==0)
* * ***** **** * * * ** * * ** *** * ** ** ** *** * * * * * ** * * * ** ** *** *
** ** * ***** * * ** * ******* * * *** * ** * * * **** *** * * * *** *
**** ** * ** ** *** ** ** * * * * * * * * * * * * * ** ***** * ** ** * *** ******* * * * ");
* **** * ** *** ** ** ** *** *** **** ** ** ***** ** ** * **
* * ***** * ** * * * * ** *** * * * ** ** ** ***** * * ** * ** * * * * * *
** ** *** * * * **** * *** *** ** ***** ** * *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
** * * ** * **** * ********* ** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* *** * * * * ** * * * ******** ** * d;
** ** ***** ** * * * ** *** * * * ** *** * ** * * (d=2; d<n; d++)
*** ** * ****** * * ** * * * * ** ** * * * *
* ** * * **** * * * **** ** * * *** ***** (n%d==0)
* **** * ** ** **** ** *** * **** **** * * * **** ** ** * * **** *** *

   }
*** ** * * * * * * ***** ** ** * * * * * *** ***
* ****** ***** * * * * ******* ** * * * * *
* ** * ** ** ** *** * * **** * * **** ****
******* ****** * * ***** * ** *** ** **
*** **** * ** * * *** * **** ** ** * *** *** ** * ** * *** ** * *** ** * (e==0)
**** ** ** ****** * * ** * * * * ******* ** ** * ** ** * * ** ** * ** ***** * * * * *** **
* * *** * ** * ** * * * ** ** * ** *** ***** * ****
* * * **** * * * * *** ** ***** * *** ** ** ** * * *** * *** * * ** * * ** * ** *** * *** * ");
***** * * *** ** * ** * * * ******* *** ** * * * ** *** **
* * ** * ***** ** ** ** * * * ****** *** * ** * * * *** * * ** *** ***
* * *** *** *** *** ** *** ** * **** *** *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
*** * *** ***** * * *** * ** * * d;
** * * ** *** * * * ** ****** * * * ** ***** (d=2; d<n; d++)
** * *** * * *** * **** *** **** ** *
* ** * ** ***** * * * *** ** *** **** ** * *** (n%d==0)
* **** * *** *** ** * *** * * *** * * ** ** * * * * **** * * * ** **
   }
******* ** ** * *** *** * * * ** * *** * * *** *
* ** * * *** * ** * *** ***** ** *
*** * ** * ** **** ** * ***** * * ** * *
* * **** ** * *** *** * * ** * **** ** *
* * ** * * * ** *** * ** * ** * ** * * ** ** * * * *** * * (e==0)
********* * * **** **** * * * ** * ****** * * * * * * *** *** * ** ******** * * *** **
** * ** ** * * ** ****** ***** ** ** ** ** * * *** *** ** **
** * ***** * ******* * ** * ** * * * ** ** **** **** * * * *** ** ** ** ** ** * ");
* * ** ** * * * * *** **** * *** ****** ** ** *** * **** * * * **
****** * ***** ***** * **** * ***** * **** * * * * * * ** * ** *** * * *** *
* * * * *** ** ** * ** * ** * ** *
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
**** ** * ****** * *** ** Fn,t1=0,t2=1, n,input;
* ** ** * * * ****** * * * **** * **** * *

* * ** * * * * ********** * *** *** ******** * n++)
* ** ** ** *** *
****** ** * *** * * ** * *** * * * * *** = t1 + t2;
**** *** *** *** * ** * * * * **
* * * * ** * * * ** * *** ** *** ****
    }

* * *** *** * * **** *** ** * *** * **

* **** * * * * * * ** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* * * *** * * ** **** * Fn,t1=0,t2=1, n,input;
*** * ** ** ** *** * * * * ** ** ** * * * *

* ** * * ******* * * ** ** * n++)
* *** **** *** **** ** * *
***** * *** ** **** * ** ** * ** *** * * = t1 + t2;
* * * ** **** ** ** ** *** ** ** ** ** *
** * ** * ** * * ** * * ***** ** ** * * * ****** ***
** ** * * ** * *** *** **

* * * * * * **** * ** * * * **** ** ",Fn);

** * * ** * * ** 0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.16
©2016-2025

Related questions

0 like 0 dislike
46 answers
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 11.7k views
0 like 0 dislike
99 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 21.4k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 8.9k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 14.8k views
2 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 14.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users