0 like 0 dislike
8k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列:0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始,其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2),F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n,輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited

edited by | 8k views

93 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
******* * * ** ** ****** F0,F1,Fn,n,a;
** * * * ** **** ** *** ***

*** ** ** *** **** *** * ** ***** *** ** * * &a);

** * ***** * * * ** * * ** * * *** *
* * ** * ** **
*** * *** ** ** ** ****** ** * ** ** ** ***** ******
**** * * *** * ****** * **** * * *** * ***
* *** ** ** * * * ** **** * *** * ** *** * *
    }


* **** ** **** **** * * ** *** Fn);

** ** ** *** * *** * * * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * * *
int ** **
{
int ** *
* * * ** * *
if(a==0) printf(0);
else if(a==1) printf(1);
else {
* ** *** ** **** * * * * ** *** * **
* ***** * *** ** * * * * ** ** * *** ** = c0+c1;
* * * * *** * ** ** *** ** ** ** = c1;
* *** ******* * ** * ******** * * * * ******* * = cb;
* ** *** *** * *
* * *** * ***** * * * ** * *** *** *
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include * *** * **

int * ***
{

int * * * *
* * **** * * * *** **

if(a==0) printf(0);
else if(a==1) *****
else {
* * * * *** * ***** * * ** *** *
* * *** * * * *** * * ************** *** ** *** = c0+c1;
* * ** * ****** * * * ** * ** ** * ** * * *** = c1;
** ** * * * * ***** * * * * * ***** * ** = cb;
* * ** *
* * ***** ***** * ****** * ** * ** ** * * *


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include * * * *

int main(void)
{

int * * * ***
* * *** *** **** *

if(i==0) ** ** * ** *** *
else if(i==1) * *** * * **** **
else {
* * * * * ** ** * ** *
*** * * ****** * * * ** * * ** ** * = f0+f1;
* * * ** ** ** * ** ** * ** * ** * * ***** = f1;
** * **** **** ** * ***** *** * * ** ** ** * ****** = fn;
* **** * ** ** * ** ** *
*** * **** * * ** ** ** ***** * *** ** ***
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** **** **

int * *
{

int ** * * *
*** ** ** * * ** *** * * *

if(i==0) printf(0);
else if(i==1) * *
else {
**** ** ** ** * **** * * * ** * ***
* * * ** ** * * * ** *** *** = f0+f1;
* **** * * * * * ** * * * ***** * ** = f1;
* * *** * * * * ***** *** ** **** ** *** **** = fn;
** *** ** ** ** ** * *
** * ** * ** * **** * * ** ** *** ** ** ** *****
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
*** * ** * * * ** * * *** * * * *** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* * ** * ** * * ** * ** ** * * **** ** * *** * d;
***** * * * * * ****** *** * * * ** (d=2; d<n; d++)
* ** * *** ** * * * ** *** ** ** ** ***
* * * * ** * * * * * *** ** * * * * * (n%d==0)
* *** * *** *** ** * ** ** * * **** ** * * *** **** *** ** *

   }
* * * * *** ** * * ** * ** ** * *** * ** **
* * ** ** * * * * *** ** *** ** * * * * *
**** *** * *** ** * *** * *** ******
*** * ** * * **** ****** * * * * ** ****
** * ** * * ** ** * * * **** **** ** * ** * * * ** * ** ** * (e==0)
** * *** ** * ** * *** **** * * * ** * * ** * ** *** *** **** ** * * ** * * * * ** *
** *** ** * ** ** * **** *** ** **** * * * * **** ** **
* **** * ** *** ** ** * *** * **** ***** * ******* * * * ******* ***** * ** *** *** * * ** ");
* * ** *** * * ** * * * **** * ** * *** ** ** *** ** * * *
* ** ** **** * ***** * * **** *** ** ** ** * * * * * * * * * * ** * * ** * **
* * ***** * ** ** ** * * * **** *******

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* ** * * * ** * * *** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
** * **** * * *** * **** * **** * * * ** ** * * d;
** ** **** * * * * * * **** **** ** ** * * *** (d=2; d<n; d++)
* * ** * * *** ** * ** *** * * ** * * **
** ** * *** * *** ** ***** **** * * * * * (n%d==0)
***** * ** ** *** * * * * * * ****** ****** * * * ** * ** *** *** ** *

   }
* * ** ** * * * *** * * *** * * **** * ** **
* ** ** * *** * ****** * *** * ** * * *** *
* * * ** * * ** * * ** * * * ** * * *
* ***** * ***** * *** **** * * * *** * * ** **
*** * * *** *** * * ** ** **** * ** * * * ** ** * * * ****** * ** * (e==0)
***** * *** * * ** * * ***** * *** * ** ** * * ** ** * * *** * * * * *** * * * * * ******
* ** **** * * * ** *** * * * ** ** * ** *** * * * * ** *****
* ** *** * ** * **** * *** * * * ********* * * **** ** * ***** * ** ** *** ** *** ** ** * ** ");
* **** * * ** ****** ******* *** *** * * * ** ***** ** *** *
** *** ***** ********** ** *** * * * * * ** * ** *** * **** * *** ***
** *** ** ** * *** * *** * * * ** *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
** **** *** * ****** *** ** ** * * * ** ** *** * d;
* ****** ** ***** ** * * *** ** * * * *** * * * (d=2; d<n; d++)
* * * ** * * ** * * * ** ** *** * ** **** **
** * * * * ** * * ** ** ** ** ** **** * * * (n%d==0)
** ** ** ** ** * * * *** * * ** ** **** *** ** * ** * * * * * ** *
   }
** * * * ** * ******* * *** * * ***** * ** * **
****** * ** * * * * ** * * **** **** * * *
** ** * * ** ** * * ******* ** * **
* * ** * * *** * ****** * **** ** *** **** ** * ***
* ** * * ** *** *** ** * * * *** * ****** * ** * ** * * * * *** *** * (e==0)
**** * ***** ** * *** * * * * ** * * **** * * **** * * ** ** ** * * ** ** ** *
* **** * * * * ** ** *** ** ** **** * * **** ** * * * ** * * ********
**** ** * ** * * * * ** * *** ** * * ** ** ** * *** * ** * * * * **** * * * *** * * ** *** ");
**** ** ** **** ** * **** *** **** ** * ** * **** * * * ** * *
* * * ** * ** * * * ** * * **** * * * *** * *** * * *** * * * *** * * ** * *
** ******** ******** *** * * ** * ***** * *** * *
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* ** *** ** *** * * Fn,t1=0,t2=1, n,input;
* ** * * * * * * * * * ** **** * *

****** **** * *** *** * **** * *** **** * n++)
****** * * ***** *** ** * *
* ** * * * * * ** ***** *** * * * * ** = t1 + t2;
* ** ** ** ** ***** * * ** * * * * ** ** * **** **
* ** * * * * * * *** ** *** * * ** *** * ***
    }

*** ** ** **** * * * **** *********

* * * **** ********* * * 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* ****** **** * * ** * Fn,t1=0,t2=1, n,input;
** * * ** ***** **** * ** ** * ** *** ** * *

** * ** * ** * *** ** * * ** * * n++)
** * * ** * * **
* ** * **** * ** * * * * ** * *** * = t1 + t2;
*** ** **** * *** *** ** * ** * * * **
** **** ** * **** * * * *** *** *** *
*** * **** ** * * * **

**** **** *** * *** **** * **** ",Fn);

* *** **** * * * ** *** 0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.28
©2016-2025

Related questions

0 like 0 dislike
46 answers
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 5k views
0 like 0 dislike
99 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 10k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 4.1k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 6.7k views
2 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 6.4k views
12,783 questions
183,443 answers
172,219 comments
4,824 users