0 like 0 dislike
11.2k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列:0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始,其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2),F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n,輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited

edited by | 11.2k views

93 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>

int main()
{
*** *** * ** ** * ** ** ** F0,F1,Fn,n,a;
** ** *** ** *** ** ****

***** * * * ** * **** ****** ** *** &a);

* * ** ***** **** ** * * * *** * *
* ** * **** *** *
** * ** ** * * ** ****** ** * ** *** * ** ** * *
** * * * * **** ** ***** ***** *** ** **
* ** ***** * * *** ** ** * * * **** *** **** * **
    }


** *** ** * * *** * * * * *** ** * *** Fn);

* ** ** * **** ** * ** ** 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ****** **
int * ***
{
int ****** ** **
* * * * ** ** *
if(a==0) printf(0);
else if(a==1) printf(1);
else {
*** *** **** * ** ***** * ** *
** * ******** **** * * * ** *** ** * * * * = c0+c1;
* * ** ** ** * * * ** * * * * ** ** * = c1;
*** * ** ** ** * * * * * * * * **** * * = cb;
** ****** * *** ** * * *
******** *** ** * * * **** ****** * **
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include * ***** ** *** **

int
{

int * * ** * **
***** * ** * * ** * * *

if(a==0) printf(0);
else if(a==1) * * *
else {
* * ** *** *** ** * * * ***** * *** *
** ****** **** * * ** * ** * * ** ** = c0+c1;
** ** ** * * * * * ** * ******* = c1;
* ***** *** * ** * * **** *** ** * ** ** = cb;
* * * * * * ** * *** *
** ** * * * * * ***** * * ** * *


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include ****** * **

int main(void)
{

int * **
* ** * ** * *

if(i==0) ** * * * *
else if(i==1) **** * * **** *
else {
* ** ** ** *** * * ** ** * ***
* * *** **** * * * * * ** * = f0+f1;
* **** ** * * ** * ** **** ** ** * * * ** * = f1;
* * * * ** ** * * ** * * * * ** ***** * ** = fn;
*** * *** ** ** *
*** * * * ** **** ** ** ** * ** ***
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * *** ** *

int *** *
{

int * * * *
** ** * * ** * ** *** **

if(i==0) printf(0);
else if(i==1) * **
else {
** * ** * * ** * ** * **
*** ** *** ******** * ** * * *** **** = f0+f1;
** * * ***** * * ** *** * ** ** **** *** **** = f1;
**** *** ** * * * ** ** **** * * ******** * = fn;
** ***** ** ** * * * * *
* * ** *** * *** ** *** * * * ***
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* * **** * *** ** * *** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
** ** * *** *** *** *** ** * ******* * * * d;
****** ** * ***** *** ********* ** * **** ** ** (d=2; d<n; d++)
** * ** *** ** ***** * * ** ** ** ** ******** * ** * **
**** ** ***** *** *** ** * * *** * * ** ** **** *** (n%d==0)
* * ** ***** * ** *** * * * ******** * * * ** ** * * ** * *** *

   }
* * * *** ** ** * *** *** * ** *** * *
* * * ** * * ** * * * * *** ** *** *** ***
* ** ********** *** ** ** ** ** * * ** ** *
* ** * ***** ** * ** *** ** ** * ** * *
*** * * * * * **** *** * ** ** * * * *** ** * * * * *** ** ** * * * (e==0)
*** * *** * * *** ** ** ***** ***** *** ** * ********** ** * **** *** ** *
*** * *** **** * ***** ** ** *** * *** * *** * * *** * ** *
* *** * * *** ** * ***** * ** ** *** * * ** * ** *** *** ** * * *** * ** ** **** * * * ***** * * ");
** * * *** * *** ****** * **** * * ***** ** * * ****** * *** *****
* * * * *** ***** *** ** * ** * * * * ** * *** * * * * *** ** * ** * * * **
* * * ** *** * * **** * * * ** * **

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* * **** ** *** *** **** * * *** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* * ** * ** *** ** * *** * * *** d;
* ** * * * ** * * * **** ** ** * * ** (d=2; d<n; d++)
*** * ** ** ******* ** ** * ***** * * ****
*** * **** * * ** * ** * * * * * * (n%d==0)
*** *** ** ****** *** *** * * * ** * ***** **** * ** * ** ** ****

   }
** ** ** * * * * * * * ** * * *** * ** **
* * * * *** *** *** *** * * *
** * ** ** ** * * **** ** ** ** * * * * ***** *
* * *** ** ** ** *** * *** * * **** ****
** * * *** ** * * * ** * *** ******** * **** ** * * * ** (e==0)
*** ** *** * * ***** * * * * ** * *** * * ** ** * * * * ** * * *** * * ******* * *
* * * ** **** * * * * ** *** * ** * ****** * ** *** * ***
** ** **** *** * * * * * * * ** * * ** ** * * * * * * *** ** * ** * *** ** * *** ");
*** ** ** ** * * * * * ** * ** * ** **** *** *** ** ***** **
** * ** ** * ***** ** *** ** * * * **** * * * ** ** ** * * ******** *** * ** **
* * * ** * ****** ** * * ** ** * ****** * * *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
*** * ** ****** * ** * *** ** ** * * ** **** d;
* *** ***** * **** * *** *** ** * * ** * * ** (d=2; d<n; d++)
* * ** * * *** * * * ** * ** *
** * **** ** * **** ** * * *** ** ******** (n%d==0)
* * * * *** * * ** ** *** * ** *** ****** ** * ** * **
   }
* * * ** ** ** * *** * *** *** * * *** * ** ** *
* * * * ** * ** *** ** ** * * * *** ** ****
** ** * *** * ** ** ** *** * * *
** ***** *** * * * **** * * * * *
* * **** ** ** ** ****** *** * ** * ** * ** *** * * ** * (e==0)
******* * * * * ** * * *** * *** * * ***** * * *** *** ** * * * *** *** * * ** * ******* * ** *
* ** * **** * ** **** * * * ** * * ** * * **** * * * *** * ** ***
** * *** **** *** * * * * * ** * * ******* ** * * ** * **** **** * * ***** * *** ***** ***** ");
* ****** * * * * * *** * * ** * **** * * *** * * *** *** ***** **
** ** ** * ** * ** ** * * ** *** * **** * * ***** ** * *** * * ** **
** ** * *** * **** * **** *** ** ** * **
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* * * *** *** **** ** Fn,t1=0,t2=1, n,input;
** * * ** * ** ** ** * ** ** * * * * * * **

* * * *** * * * **** * * ** **** n++)
**** * * * *** *** *
* *** ** * ** * **** * *** * * *** * * *** * = t1 + t2;
* * * * * * * ***** *** ** ** * *** * * *** ** *
** * ** ** * ** ** * * ** ** * ** **** * **** **
    }

* * * * ** * **** * * ** * *** **** * *** * ***

* *** ** ** * * * ** * * ** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
*** ** ** ******* * *** Fn,t1=0,t2=1, n,input;
* * * *** *** * ***** ** ** **** * * * * **

** *** ** *** ** * * **** * **** n++)
* * ** * ***** * *
* *** ** ** * ** * ** * **** * ***** * ** = t1 + t2;
*** * * * *** ** **** ** * ** ** ***** * * *
* *** * *** *** * ** ** * * ** ** *** *** * * **
** ** * ***** * **

* * * * * * ** ***** * * **** ",Fn);

* * *** *** *** ** 0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.127.120
©2016-2025

Related questions

0 like 0 dislike
46 answers
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 7.1k views
0 like 0 dislike
99 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 13.7k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited
| 5.8k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 9.4k views
2 like 0 dislike
67 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 9.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users