11-01 Exercise 3: Fibonacci numbers

0 like 0 dislike
11.1k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列：0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始，其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2)，F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n，輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 11.1k views

93 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
*   ***   *** *  ** *** *    F0,F1,Fn,n,a;
***** *    ** *   **       *** *

    *  *    * * *  * ***       ** **  *  *   **   &a);

 *** * **** ********* * * ** *  * ******     *
* ***** **   *      *   * ****
* * * *** **  **   * ** ** *  * ***  *  **  * * ** ****  * *  
* **   *  *    *      ** * *    **  ** ** * *    **
**  *   *** *******  ** *    * *** *** *** ** ** ** * 
    }


 **** *** ***  **  * * * **   * *** ** ** **         Fn);

   * **    * * ***  ** **  ** * ***** 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *    *  *   * *  
int  * **
{
int *  ** * ** 
  ***** **   ** *  *  * *
if(a==0) printf(0);
else if(a==1) printf(1);
else {
* *      * *  **  *** **  ** *** ***   **** 
 ** *    *     ** *    *   ** *  *** * *  ** *      * *****  = c0+c1;
 *   * * ***  ***   **   * **      *  * *  * ** **   **  * = c1;
 *      **  *   ****** * * ***** ***    * *      *   = cb;
    * * **  * ** **  * ***    * 
 *  *   * **    * ******    * * *   *****    
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ** * *   *** * 

int  *  *  *
{

int ** *** ****
  * * **  ** * ** *    *****

if(a==0) printf(0);
else if(a==1)   *** 
else {
* * *   **    **** *  * *  * * ***  **  *    ** **  *
****  **  * * * * *      **  * ***  *  ***  *** **     = c0+c1;
 * * **   *    * **   * *** ****    ***     ** * * * = c1;
* ***   *   **     ***  * **  *          *       *****   = cb;
  *  *   **** * **  * *
*** ***   *** * **   **  *   *** * * * *** *  *


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *** ****  *   *    

int main(void)
{

int *   **  *  
** ** *** *****  * *  *** * **

if(i==0) * **   ***    **** **
else if(i==1) * * ** *****  *  * * 
else {
 ******* *  ** **    * ** * * **   *     **  **  *  *
* **  ** **  ***  *  **    ** *     * * *  *  ***  = f0+f1;
 * *  *   * ***  ** ***** **** *  ** ** **** ** **  ** = f1;
     *** ** ****   * **  * *** ****  ** * *** * *   *      = fn;
*  *   *  *  *   ** *******    * * *
*   **** **   *** *********   * ** *  **     
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * ***  **** **

int  ***
{

int *  *  * * *
  * **    ** **   *** * ** *

if(i==0) printf(0);
else if(i==1)  **     *
else {
*  *  *   * *  *****   ****     **   **  
*  * *  ** ***   ***   *** *  **   ***  ** **  *** ** *    = f0+f1;
 * ** * * *  * **  ** ** ** **** * *   ***  ** **** ** = f1;
    *  *** *** **  **  *** *** ***** **  ***   *  *** = fn;
 ****  **  * **      ***  * 
  * * ***   ***  * * * *  * *  **   ****    **** 
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* * * * *** ******* * * * * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
*** * ** ** ** * * **** * * ** * * * * * ** * d;
* * * * ** * ** ** * * ** * * *** * (d=2; d<n; d++)
***** ** * **** * * * ******** ** ****** ** ** *
* * * * * * * * ** * **** * * * (n%d==0)
** * **** * * ** * ** * ** **** * ** ** * *** * *** ** **

   }
* * * * * * ** * * ** * * ** * ** ** * *
* * ** ** * ** *** ** ** * *** * ** * ** **
* ** * ********* * ****** * *** *** * ** * **** ** *
*** * *** ***** * ** * * ** * ** * ** *
***** ** * **** ** ***** ** * * ** ** *** ** ** * ******* *** * (e==0)
** ***** * * * ** *** ** ****** ********* * ** ** ** ** *** * * *** * *** * * * **** * ** *** *
*** * ** ** ** * * ** ***** * * ** * * * * *** *** * *
** * * * ** *** * ** ** * ** * *** ** * * *** *** ** ** * * * ** * ** *** * * ");
** *** **** ******* ** * * * **** * * * * * * ** **** * ** * * ****
** *** ** ** * *** * * *** **** ** ** * * * ** *** * * ** ** ** * * * * * ***
* * * * ** * * * **** * **** ** ** *** *** *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* * * * * * ** ** * **** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* ***** *** * * * ** * * ** * * ** ** * d;
* * *** * ** *** * * * * * ** * *** (d=2; d<n; d++)
** ***** ***** **** ** * *** * * ** ***
*** ** *** * *** *** * ** * * ***** *** * (n%d==0)
** ** ***** * ** * * ** * * * ** ** **** * ******** * * * ** * * * *

   }
*** ***** *** **** ** * * * ****** ****** * * *****
** * ** * * ** *** * * *** ** * *
* * * * * * ** * * ** * ********* *
*** * ** * * * * **** ** * *
* ** *** * **** **** *** *** ** *** ** ******* * ** ** * *** ** * * * * (e==0)
* *** ******* * *** ***** ** *** * * * * ** * **** *** **** *** **** * ** ** ** ** * * * * ** * ** **
**** * *** ** * **** * **** * * * * * * * **** *** **** *** *
* *** * * *** * ** * * ** **** ** * **** * ** *** ** * * * * * * * ****** * * ");
** * * ** ** * **** * * * ** ** ** ** ** * * * ** * * * ** ***** **** ***
* ** ** * * * ** * ** ** **** *** * * * * * * ******* ** * ** * ****** *
* * ** ** ** * * ** * ** *** * ** * **

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
 **  * ****     *  ** *   *  *         **  ****     ** d;
  *  **** **      ******* ***  *   * * * *   ***  *****  * (d=2; d<n; d++)
 **    ** **** **  *  **   * * * * ***      *  * ** *  * 
*  * ** * *  *   **  *  **   **** * ** ** *    * **    *  (n%d==0)
******** ** ***  ***  *** ***  *    ***   * ****   *** * *    * * ***    **  
   }
* **      ****   *  * * ****   *  * *  ****    * *** ** **    *   ** 
    *  ****  * ****** ** * *             *  *  * *   * 
  ***  *    * *** * *  *    ** **   **  *** * ***  * **
 *   ****  *****  ******** *  * ** *  **  ******* **  * 
 * *  **** *   * *** *        ****   **  **  ** * **  **   *   *    **  *  *** **  (e==0)
 **        * *  ** * * * * ****    * ***  **** **  *  ** * ***   **  ** * *    *** * * * * *  * 
 * *** *** ***      * **** *   **  *   ***** **  * *** ** *  *  *** ****  * **  * *
  *  ***  *   *   *  *** **    ** * *  ***    * * *** **     *    ***  *  * *    *   * *   ** * ** *** *    ** *  ");
 ** *  *****    *  *** * * *      ****** *     *    * **   ** *** *  **     * **  
**    *   **  *    *  **   ****   **  *** *   ** *  *  **** * ** ** ** *  *** ** *   * *      * ** ** 
* ** ** * * ** ** **  ***  **   * **** ** *** * * * ***      *
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
 * *   ** **  *  **    * ****  Fn,t1=0,t2=1, n,input;
   * *   *    **   *** * * *****   *****    ***  ** **

* * * * *    * *         * ***   * *  ** * ** * * n++)
  ** *  * * ** *** * **  
 **  ****  *** * * *     *  *       *  * ***       *  *  = t1 + t2;
 *   ***** ** * *   *******  ****  * * * **** *          *** 
******** *    ** * *   *  *   *  *  *  ** *  * * ***  *** ** * 
    }

   * * *  *   *  * *   *   *** ***  *    *

   *  *  *** ******  * ** * * *  * * 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
* ***  ******  * * *****       *  Fn,t1=0,t2=1, n,input;
 *   * ***  *** *****    ** ** * *** ** **  **   *   *   

**** *** * *  **** *   ***    *** *  **   n++)
**       * **  **  *    * *
 ** ***     ****** **    *** *  **   * **  **  **  * = t1 + t2;
   * *       **  ** **  * *   *   * * * **  ** ***  *
 ** * * *** * *     * **  ** *** ** ***  ****   * **  * *
* *  *** *   **   * *   *  

**    ** **  ** ** **   *** * * ****  * ",Fn);

 *      ***  * ** *   *  * ***  * *  ** 0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.100.75
©2016-2025

Related questions

0 like 0 dislike
46 answers
11-30 Exercise 1: Fibonacci numbers (Array)
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 7.1k views
0 like 0 dislike
99 answers
11-01 Exercise 1: Find out all prime numbers between n and m
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 13.7k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 5.8k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 9.4k views
2 like 0 dislike
67 answers
11-09 Exercise 2: Reduce the fraction to lowest terms
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 9.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users