11-01 Exercise 3: Fibonacci numbers

0 like 0 dislike
23.2k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列：0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始，其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2)，F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n，輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 23.2k views

93 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 **        ***  *    * *   F0,F1,Fn,n,a;
  *  *** ** ***   **     * *    * *  *

 *** * *  ** **   **     * **  **      *** &a);

***    **    **  * *   * *** *      ** * *  *    
 * ** * *       **    *  * **  
 **** ***    * * *****  * **** *  * *  *** * * *  ****** **
*   *   **  * **     * ***   ** *   ***  **** ***   **  ***     
  ** **    ****  * **   * ****  ** * ** **  *  ** * ***** * 
    }


  ****  *** *  *     ***  **  ** **** *  * **** Fn);

*** *       *  *  *  ****** ** * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   ** * *   * ***
int   ** 
{
int **  * *    
**  **** ***** ***  ** *
if(a==0) printf(0);
else if(a==1) printf(1);
else {
*  ****    * *** ********* **   ***  *
* *  ***  ** **    ** *     * * *** *     *** *  **       * = c0+c1;
*****     *    * *  *** *** *   ** ***   *   *****  **** = c1;
  **  ***   ** *****    **  *****   ** *** * **   *** * ** = cb;
* * ** * * *  *   *   * *** **
*   *** ****  ***   **    ***  ***   *  *  * *   * *
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   ** ** * ****  

int     
{

int         * *  *
     ** **  *    **   * * 

if(a==0) printf(0);
else if(a==1)  ** ***
else {
 *  * ***   *** ****      *** * *        *  
    ** **  *   * **** **** ******  ** * *  *** * *****  *  = c0+c1;
** **** *     * ** * *    * *  ***   *    *  *    * *      = c1;
  **  * *******   *** * ***   ***** *  * * * * ***   = cb;
 *****        *** ***   ****
 *** ***  *    ** **** **   *  ***  *  * ***** **    


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **      ****  

int main(void)
{

int * * *  *  
**    *  *** ** * * ***  * *

if(i==0)   *  **  ***       * ****
else if(i==1)  *  **         *    * *  **
else {
     * **    *** *   *  ** ******  **** **  * *
**** * *****    **** *  * ***  * *** **** *  **   = f0+f1;
**** *** ** * *    ** *  **  *  *  *   * * * *   * *  = f1;
* *  * **   ***** ***** **** * *  ******** *  ***    ****** * = fn;
** ***   ****   * * *** ***** *
  * ** **   *   ***   *  *** **  * * * ****   * ****
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include     *****      ***

int    *  
{

int * *****   
   ** **  ***   * **     

if(i==0) printf(0);
else if(i==1)   *  * 
else {
** * * ** ***  * **  *  ****  *   ***    ***
 ** ****  ** * *   **  ** * * * ***** ****  *  **     ** **** ** = f0+f1;
**  *********  *** ** *  *    **   * **  * * * * *  * * **  ** = f1;
*****      *     *  * *  * * ** *   *****    **   * = fn;
**** ** **  **   * *  **** ***  ***
* * *   *  * *       ** * *** **** ***  ***** *   
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* ** * *** * ** * ** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
*** * *** ** *** * ** **** ** *** ** d;
* ***** ************ * * * * * * * * * * * **** (d=2; d<n; d++)
*** ***** * ** * *** * ** * * *** *** * ** **** *
* * *** * * ** ** * * * * * * * ** (n%d==0)
* ** ** * ****** * **** ** * ** **** ***** ** ** *** **** ** * *

   }
*** *** * * ** ******* *** ** * * * * ** ** * * *
** * ** ** *** * * ** * ** *
** ** * * * * * * ** * *** * ** ***** * *
***** ******* * * * **** * * * ** * *
*** *** ***** ** * * * *** ** ** * * **** *** *** ** **** * * * (e==0)
* * * * * * ****** * * ** * * *** * *** **** * * * *** * ** * *** *******
*** * * ** **** * ** ** * * * ** * ****** ** * * * * *
*** * ** **** * ** * * * * * * * ***** ****** ** ** ******* *** * ***** * * *** * ********* * * **** * ");
* * * **** * ** * * ***** ** *** * * ** * *** * ** * ** * ** * *
**** ** * *** **** ** * * * * * * *** ** * * * ** * ** ** * * * * ***
* ** **** * *** ***** * ** ******* * * * ****** ***

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* ** *** * ** ** * *** * * **** * ****** ** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* **** * ** ** ***** ** ** *** ** * *** * *** d;
* * * ** * * * * * ** * * * ** * ** ** * * ** (d=2; d<n; d++)
* * ** * * ** *** * * * * * *
* * ** ** * *** ** *** ** * * *** * * ** * ** (n%d==0)
*** ** **** ******* ** ** ** * ** *** * **** **** * * * * * * * * ***** *

   }
******* * * *** *** * ** ** *** ** * * ** *
** *** * **** ** ******* * *** * ***** * *** *
*** *** * ** * ** **** *** * *** * * * * *
* ** *** *** ** *** * ** **** * ** ** **** * ** **
* * * *** * * * * * *** ** * **** ***** **** * * ** * ** * * * ** * ** (e==0)
* * *** ** ** *** **** * ** **** * ** ***** * **** * * ** * * ** ** **** * * *** **** ** * **
** * ** **** *** ** * ** ** **** **** ** *** * ** * **** ** *
*** * * ** **** ** *** * ***** * * * **** **** * *** * * *** * * * ** ** **** *** * * * ** ");
**** * ** ***** *** * * * * ** * * ** * *** ** ** ** ** * * ** * *** * *
*** * *** * **** *** * ** * * * * **** ** *** ** * * * * * * * * * * **
** ** * *** ** ***** ***** ** * * * ** * **

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
  * ******* ** * **    ** * * *    *  *  ***  *** ******  d;
**      * *   *  **   ***        **  *     *  *  * *   (d=2; d<n; d++)
** ***   **** *  *  ** ** **   ** **   *****  *****  *  **
*          *   * * * * *  ***  **   * **** ** *** (n%d==0)
* *    *   **   ** * * * *  **  *****  *** * * *** *     *  *   **   *  * *** ** ****
   }
*** **** *   ** **  *****  * * **   * **** **  *   *  **
 *  * *****        ** *  *  * * ****  *  * ******* *  *
  * *** * ** *****      * ** *   ***  ****     **  *  **  
* *** *  * *  ***  **** ** ***  ***   **   ****  * ** **
 * *  **     * *     *   * **    *  ** ****     * *  * *      **  *  *** ** **     * (e==0)
** *** * *  *  *    ***   *  ** * ** ***     * * *   ** **   *  *  **  ** * ** *** * *** ******  * ***  *  * 
**   * **       ** * **** * * *** *   ******** ** * *       * ***** **   ***  * * **  *
* * * *  *    ***  *** *** * *  *  *   ** * ****** **            * *** *** ******  * * * **      *  ** ** *    **** * ");
  * ** ***  *   *    *  * ** *  ** **      * ****     *****  *      ** **  *  
***  **    **  ** *  * ** *  ** * ** *** *** ******* **    **   *   * * *  *******  *  ** ** *    * **  ***
  * * **   *  ****      *  * ****  * *  **   *** *** * 
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
* *   *   ** * *  *  *** **   Fn,t1=0,t2=1, n,input;
* ** * ** *** *   *******  **  *     ***   *   *  

   **    *** *   * **   ** ****  *   ** *  n++)
   ** *   ********    ** ** 
 * *   *** * **  * *** *  ***** *  ***   *  * **  * * **  = t1 + t2;
*   ****   ** *  **  **  **    *** *  **      * *   * *  * * 
* * ****** *    * ** *** **    ** * ** *    *  * *  *** 
    }

***  *  ** * *   * ** **     ***    *  **  

  **    * * *  *** ****   *  * * 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
*  * ** ******** *  *  *    ** Fn,t1=0,t2=1, n,input;
**   * * ***     *  *** *** *   * * *       **   *    *  *  *

   *  * **** *** *  *    * ****    ******* ****  n++)
  **  * ** *    *  ***** 
 * * ***  * *    *         ******     **** **  *   * *  * = t1 + t2;
*   *  * ***  *****  **   **** **  ***    **   *   **  * * *** 
*  * *** ***  ** ** * **  **** * *** *  ** * *    *      *  *****   **
** * ** **     *   ***  *   ***  *

* **  *  ** *  **  ** **    *   *  **   ** ",Fn);

   * *   *  **      *   ** *  * 0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.95
©2016-2026

Related questions

0 like 0 dislike
46 answers
11-30 Exercise 1: Fibonacci numbers (Array)
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 14.7k views
0 like 0 dislike
99 answers
11-01 Exercise 1: Find out all prime numbers between n and m
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 26.9k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 11.5k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 18.5k views
2 like 0 dislike
67 answers
11-09 Exercise 2: Reduce the fraction to lowest terms
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 18.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users