11-01 Exercise 3: Fibonacci numbers

0 like 0 dislike
11.2k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列：0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始，其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2)，F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n，輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 11.2k views

93 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 *    *  ********** ***** *      **  F0,F1,Fn,n,a;
 ****  * ******   ********    ***  * 

*  ** ***   ****   *  **** *    *** **   **** ** &a);

* * **     **   *   *  *  * *****   *  *  *
  *   *** *      * *    **
*  *** ******    ***** *   * * * **  * *** * * ***   * ** 
    *  *    ** ** *  * * * ** **** *** **   **  **    * * 
    *  *****   *** * ****  **  * ***  *  ** **   ** *  **
    }


    ** *   **  **   *** ***  ****  *    **  Fn);

 *    * ** *   *******  *** *   0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    * **** *** * 
int *** *  
{
int    *  *    *
  * * * **   ** ** **   *   * 
if(a==0) printf(0);
else if(a==1) printf(1);
else {
  ****   *** *** ***    *** *  ***   **
****** * *     **   **  * *      **   ****  * * ** * *     = c0+c1;
  **  *********** ***   **** **   ** *   * *   ***  ********** = c1;
** * *****   * **   **  **** *  * * *  ******* = cb;
 ** *    * * ** **** * 
* *      *   * ****  ** *   * **    ****  *
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  **  *  ***** * 

int ****
{

int   *****  
*  **    ***  ** * * * * *

if(a==0) printf(0);
else if(a==1)  **** 
else {
** *       *   *  *  **  *  * **  *** * **  ** ** *
 ** **  * **  ***    ***** ** *  ***  * **   ** * = c0+c1;
          *     *   * **  *   ***    *  **   ** *** * = c1;
*  ** ***  *  ** ****  **      ******  *  * ** ** = cb;
    * **  **  * **   * ** * 
 ****  ******  **      **  ** * *    * * *     


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   *  *    **  *

int main(void)
{

int *** *** * *** *
  ** ** ***     **   *****       * 

if(i==0) * *   * ** * ** * 
else if(i==1) *  * *  ***  * ***
else {
*  * **    *** ***  * *   ** ****  ****
* *   * ***  ******** * ** *  * **** * **** *         ** = f0+f1;
    *  * *** * *** *   *  ** **  *  ***   **   ** ** * = f1;
* *  * *  ******* **  **  *  *  * *  *** *   **** ** = fn;
*    ***** **  * * ***    * *
     *  * *** * ** * * *  * *** ** *   *    *
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *** *   ** * * 

int   *  **
{

int     *  *
*** *  * *   *  * ** *  

if(i==0) printf(0);
else if(i==1) **** 
else {
 *    * *  * ***** **     **** *  * *    
*   * * ** *  *****  *** ***      **  ****  ****    = f0+f1;
** **   ***      * **  ***   ** ** **  * * ******   = f1;
*    * *   ***  ** *** *** *     **      *  * *** = fn;
 * ****   * ******    ** 
 **     *** *** *  *  *** ****   *   **  *  ** ***
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* * * * ** ** * * * ** ** * * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* *** * * * * * * **** *** *** * * * * * ** *** * ** d;
**** ******* ** ** ** ******* ** * ***** *** (d=2; d<n; d++)
* * * ** * * ******* *** * **** * * ** **
* *** * *** * ** * *** * * * ** (n%d==0)
***** ** * ** * * * * ** *** ** ** ***** ** * * * **** **

   }
* *** * ** * ** ** * * ** * * * * * *** *
* *** * * *** * * * * ** * * * ***
** * ** ***** * ********* * ** * * * * **
* * ** * * * * ** ***** **** * ** * * * * * * **
* * * ** * * * * * * * * * ** *** ** * ** * ** ** * ** ** **** (e==0)
*** ******** * *** * ** ** *** * * **** ** ** ** ** ** ** * ** * * * * * *** **
* * * **** ** ** *** * ** ** ** ** ** * * * ** * *** ** * * * *
**** * * ** ** ** *** * ** ** * * ** ** * * ** * ** ***** ** * ******* ** * * * ** ");
* *** * * * ** ** ** ** ** ** ** * ** * * ***** ** ** * * * ** *** **
* * ***** * *** ***** * ******* *** ***** * ***** * * **** * ** * *** *** * ***
* ***** * ** ** * * * * * * * * * * *** **

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
** * * * * *** * *** **** * * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
*** ** * ** * * * * * **** *** ***** * * ** * * *** d;
** * ** ** * *** *** ** ***** ** * * * * (d=2; d<n; d++)
* * * *** *** * * **** * * ** ** * *
**** * ** *** * ** * * * ** * ** * * ** *** *** **** (n%d==0)
* ** ** ** * ** ** ** ***** ** * ** * * * ** * ** **

   }
* * ******** **** ** *** * ** ** * * ***** *** *
*** * ** ** * ***** ** ** ****** ** ** ** ***
** ** * * ***** * * * *** ******** * * *
* **** * * ** * * * * ** * ** *** **
** ** *** *** ** *** * ** * * * **** * * ****** * * * * (e==0)
* ***** * * **** * * ** *** ** **** ** **** ******* * ** ** * * * **** ** * * ** *** ** *
* * * * **** * * ** * * * * ** * *** ** * * ** * *********
* * *** ******* * ** ** **** ** *** * ** * * * *** ** * *** ** * ***** ** **** * * ** * ");
* *** * * * * ** **** * ****** * * * * * ** ***** *
*** * * * * ** * *** ** * ** * * * *** * * ** ** * **** *** *
** ** ** *** ** ** * * * *** ****** **

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
***  * ***** * * ** ** ***  *** *    ***   * **  ***  **   d;
   * *** *  * ***** *  ****    ** * *  * * *     ** *   (d=2; d<n; d++)
**** * **   ****   **    *** ***  ** *  ** *** *      * *
*  *** * ** * *  *** * ***** **  * **    *  *** ***** **  (n%d==0)
  *** * *  *    ** *  * **** * ******** **    * * *** * *    *  * *    
   }
*  ** ** * ***  ** *  * * ***  *** *     *  ** **** ****
**   *   * *    * *   * *  * *** *   **** ** **   *
 *   * **** ***   ****  ***    *** *** *    **  **   *    
**  **    *  * * ** ** *** * *   ******     * * *** *
   ** *  ***    ** *   ***   * *  ** * * * *   **   *  **    *  ***   * *  *    **** *  (e==0)
 * * **   *      * *** ** ** *  *  *   * * ****     *  *  * ** *   *** * ** *  * ** ****** ** * ****
 **  **** ***** **** *** ***    **  **    **  ** *  **  *   ** ***** **   *    ***    
**  *  *   **** *  * ** **   *    ** **** ** *    * *  ** *     ***    ** *  *** ********   * ** * ******      * ");
 * ******   *  **   * *  **** ***     ********* ** * ***       **  * **      * ** * *   
****   *** *  *  *****  * ******  ***    ** *     * *   **    *    * * *** *** * *** * *    * * **  
** ** ** *  *** *    ***  * *   ****** * *  *  ***   ***
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
  **   **** *  *   ** *    *  * *  Fn,t1=0,t2=1, n,input;
*    *  ****** *  ** **  ***  ***   *  ** **** ***   

  * * * ** ***   **  *  ***  ********* *     n++)
*  * **    **   **   *       ** 
 ** **  *   ******  *** ***    *    *** ** *   ****     = t1 + t2;
 *** **     * *  *  ** *****   * **   * ***** * *     *  
* *  * **** *** * **     ****  *  **  ** *       *  *****
    }

   **     *  *** *  * *  * **** ********  **  ** 

****    * ***** *  *   *   **  * 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
*        * *   *  * ***    * **   Fn,t1=0,t2=1, n,input;
  **     * * ***  * ******* * ** **    **     ** * *   

***   *  * *    **  * * * ** * * *  * ** n++)
  * * ******  *   *  ****
**  * * *****  ***  ***  * * ***  *  *       *****  *** = t1 + t2;
   **** ** ****    **** * **  *     ** * ***  *  *  * ** ***
 ****** * **    ** *  ***  ***** * ** *    **   * * *   
   * ** ****  ****** * *

 * ***  **   *   ****   *** *  * ****  ***  ",Fn);

* *  *** **   * **  * *   * ***  0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.190
©2016-2025

Related questions

0 like 0 dislike
46 answers
11-30 Exercise 1: Fibonacci numbers (Array)
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 7.1k views
0 like 0 dislike
99 answers
11-01 Exercise 1: Find out all prime numbers between n and m
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 13.7k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 5.8k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 9.4k views
2 like 0 dislike
67 answers
11-09 Exercise 2: Reduce the fraction to lowest terms
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 9.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users