11-01 Exercise 3: Fibonacci numbers

0 like 0 dislike
6.6k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列：0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始，其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2)，F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n，輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 6.6k views

93 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 ** * * *** * *  ** ******   * F0,F1,Fn,n,a;
*** ** ***  *  *   **  **   * 

 **  * *  *****    ** *  *** * * *  * *   &a);

**   * * *     *****        * **   ******* * 
 ******* * ******  *     ***
 * * *   **** * **  *****    *    **     *** ****  * ** ***   *   * *  
    *  *   *    *   **  * **** *  **   *  ** ****    * ** * 
*  * **  *  **** ***  * *     **  * * **** * ** **  * *
    }


  **      ***** *       *   *  *** *  ** ** *** ****** *** Fn);

* ***    *****      * ** * * *  0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *** * ** *
int   *** **
{
int  *  **** * *
**    ************    * *    
if(a==0) printf(0);
else if(a==1) printf(1);
else {
****     * *  ** *     *  * ** **    ** *
 *   *** * * *** **   *  * * **   * *    ***** *       * = c0+c1;
*  ** *** ** ** * *  ***  *     * ****  * ******* * *   = c1;
   ****** * * *  **   ** ** *  *  *  **** *  ** * ** **   = cb;
* * ****   *****  **  ** *  
* * *    ** **** * *   *    ***  ** ** * **  *****   *
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **  **   ******

int *   ** *
{

int    **   *   
**  *  * *  *****   **** *    *

if(a==0) printf(0);
else if(a==1)  **    *
else {
  *** ***** **   *   ***   *  *** *  *  **     **
  ***  ***  *  *         ** **   *** ** ***  * * *  ** *  * * * * = c0+c1;
 * *  ****** ********  ** *  **  * *    * *   **  * ** **  = c1;
** ****  * **** ** ** **** **    * **  **  *   * = cb;
**   *****     * * *  ******* *
* * * ** **  **** * ****  **  **   * *****  * *  *


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * * *  * *   *    *

int main(void)
{

int ***  ** *** *
 ****  *** *   *******  * *  

if(i==0) * *  *** * * *  * **
else if(i==1)     * *  **     *  *  * *
else {
***** * * * ***  *****  **  *****   * * **  
 ** * **** ** ***  ****** * ***  * * * * ** **   * * *  = f0+f1;
  * *    ** * *** ****    ** *  *  ** * *   ****** * **  = f1;
   *  ****   ** *  **  ** *  * ***   * *** ** **** = fn;
   ******* ******* *  ****     
** *   * *** * *   * *  *     **** * **      ***   
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   * **  * * ** 

int * * 
{

int  *  ***   *
 *    *       ** * * ** **  *

if(i==0) printf(0);
else if(i==1) *** **
else {
**  **    ** ***** * **  ** *   ** *   
 * * *** * * *** * *  *     ***  **** **** *******   ** *** = f0+f1;
  ****   ** *  ***   **   ***** *    * * ****   ** * ***** * = f1;
   **  **     *  **** *   * ***  *   ***** ***    *** **  *   = fn;
* *  *  *    *  *** *  * ** 
 *   **   *  *    *******  * ***  *  *** *   ***  **
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* **** * * *** *** * ***** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
** * ** ** * * ** *** ** ** * ** ** * * ** ** ** * d;
***** ** ** ********** **** ** * * ***** * * ***** * (d=2; d<n; d++)
*** * * * ** ** ** ** *
* ** * * * * **** ** ** ** * ** **** * ** * (n%d==0)
** * * * * ** ** * * ** *** **** * ** * ****** * ** ***** *

   }
** * * ** ** ** * *** ** * * *** * * *** * * * **
*** ** * * * *** * *** ** *** * ** * ** *
* ** **** ** * **** ** * ** * * * * * * ***
* *** ** ** ** * * ** **** ** * ** **
***** ** * * * **** * ** ****** * * * * **** * * * ** * (e==0)
* ** * **** *** ****** * * ** ** * *** **** * * ****** ** ** *** * * * ***** * ***
* **** * * *** * * ***** * * ** ***** *** ** * * *****
* * ** * * ** * * ** * * ** ** **** ***** * * * *** * *** ** **** ** * * **** * * *** *** ** ** ** * ");
** * * * ** ****** ** ** *** * * *** * * ** *** * ** ** *
* *** * * ** * ** ***** ** ** * ** * * ** * *** ** *** ** *** * ** * *****
**** * ***** * ** * ** * ** *** ** * * **

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
** * ***** **** **** ** * * *** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* * * ************ ** ** **** * * *** * ** ** d;
*** * ****** ** * ** * * * ** * * ** ** **** ** (d=2; d<n; d++)
** * * * * ** * **** * ** **** **** ** * * **
* **** * * * *** *** ** * *** ** ** * *** ** (n%d==0)
*** *** * * * ** * * ****** * *** ** ** * ** ** * * * ** * **

   }
* ** *** * * ** *** * * * ** ** * * ** * * ** **** * *
*** * * * **** **** * **** ***
*** *** *** * ** * *** * * ** * * ** **** ** * *
*** * ********* ** ** ** * ** ****
* * *** * ** * * ** * *** * * **** ** ** ** **** ** (e==0)
* ** ** * * ** ** ** ** ***** ** * ** ******* ***** * *** ******* * *** ***
** **** * * * * ** **** ***** * * *** *** ****** ** ** ** ****
* ** * * * ** * * ***** * * ** ** * ** ** ** * ****** * * ** * *** * ** * * ** * * ** * * ");
** ** * ** ** ** *** * ** * *** ** *** *** * ** * ** ** * * **
*** * ***** * ****** ** * ** ** *** * * * * *** ** ** * * **** * ** * * ***
* ***** ** * ** ******* *** ** * * * ** *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
*  ** *****  * *  ****  *** * * **   * *    ***  *  *   d;
   * **   **** *  * ** * * * * *      *  *** ** ** (d=2; d<n; d++)
 **** **     ***    * *  *  *     ***   **  ***** * 
*   *     *  * * * * *** * *******    **** *** *   **  (n%d==0)
  ***  *   **  **** *  *   * **   ***     **    * ** ** *   * * * *** *  ***  *** * **
   }
  *** ****    *** * * ** *     **  ***** *** ****  *   *** * ** ****
**     *  ***  * *** *   ** * ** * *  *     *  ****  **
     * *  *   **   *   * ***   **   **  ** ** **  **  *
*  ***          ***  *** ***   **    * *** ***** *    * *
**   ***     * *   *** **    ***  ***      *  *  *    ** * * **  * **    **    *   * ** (e==0)
* ** * ** *** * ** ***     *   **** ** **** ** * * *** *       ****  ** ** * ***  *   * * *  *      ** *   *** *  
 * * ********     *** *     *   ** * ****     * *** **      * ** * * ** *  ** *  *  **  
  ** ***  **  ****  *** ** *  *** * **   **  *  * *   **    *  *  **    ****  ** *  **    *   ***     *  ** * **   * ");
***  *     *  *  ****  *    * ** * *** *   **   * ** *      *  ***   **     **  *  ** 
 * *** *   ** **    * *  * **  ***  ****   ** ** *   **    *  *  ****** ** * ****   *  *   **** ****  ***  *****
 *  ****** **  * **  ** ****  ******   * ** * 
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
    ****  * ***       * ****** Fn,t1=0,t2=1, n,input;
*****  *   ***   *** **     * ** ** * * *   **** *   * * * ** ****

  **  ***  ***  *    * *      **            n++)
    * * * * *  ***    *  
* *   * *    ******* * *  *   *** * *   ***** *** **   * * = t1 + t2;
* ** *  *   * *   *** *    ***********  * * * *  **   *   
      *** *  *   ******* ** * ** *     ***  **       ** *** *** 
    }

 *  ***    * ** **   **   *   ** *    * * *    *   

** * **** * * * *  * ***** **  * * 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
* **** * **  ****  **  **     Fn,t1=0,t2=1, n,input;
 *     **** **      **  *  **    *** * *     *** **  *  

  ** *** *  *    *  **** *** *****   * **  n++)
** ****   *        **   *
*** ******* ** **      * *  *  *  * **  * **    *     * *    * = t1 + t2;
*   ** *** **  *  *        ****  *** * *     **  ** ****
  ** *    *   *   ** * *    * *** * ****  * **  **  * *  
* *  *** ** *  * *   * * *

  **  *     *   ****    ***   *  **       * ",Fn);

 *  *** *   ***** **   ** *****  0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.130.92
©2016-2024

Related questions

0 like 0 dislike
46 answers
11-30 Exercise 1: Fibonacci numbers (Array)
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 3.8k views
0 like 0 dislike
99 answers
11-01 Exercise 1: Find out all prime numbers between n and m
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 7.8k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 3.2k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 5.3k views
2 like 0 dislike
67 answers
11-09 Exercise 2: Reduce the fraction to lowest terms
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 5.1k views
12,783 questions
183,443 answers
172,219 comments
4,824 users