11-01 Exercise 3: Fibonacci numbers

0 like 0 dislike
8k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列：0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始，其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2)，F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n，輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 8k views

93 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
    * *  ******* ** ***  *  * *    * F0,F1,Fn,n,a;
 ****     ** * * *    *  ***** * *

*  *  ****   **   ***  *  *****   * * **  ** *** &a);

* *    ** ***  *   *** *     ***  * **
***** * *     *   ***  *  ****  
*** *** **   *  ** * * *** * *****  ***  **** * *  *  
  * * ***   *  *       * *** ****   ***        ** **   * ****
** **  ** ** *    ** *  ***  ** **    **  *  *  *****    **
    }


      ** * **   *****            **   *  * Fn);

 ****  ***    **  * ***         ** * 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   **  *  * **  
int  ***  *  
{
int ***  * * * 
 * * ** ** **  ** * ******* ***  
if(a==0) printf(0);
else if(a==1) printf(1);
else {
* * **** ** *     **** ******* * **   ****** 
  *  *  * * *  **** ***     * ***  *   * * * * * * = c0+c1;
* **  *   ***   ***  ***  ***   *       ***   *  ****  **  = c1;
* *** **  **   ******* *   *  ** ***  *** ***  *** * **  = cb;
*   **  * * *   *  **      ** 
 * *** * **  *** *   ****  ****   ***  **     *  *  * * **
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ***  * ** ****  

int * *** 
{

int ** *  ***** 
   * **** * **  * *** ***

if(a==0) printf(0);
else if(a==1) * **
else {
* ******   ******  ** ****** ** **  *    *
 *   ** **  *  ** **  ***  *    *  * ** **  * * ***** = c0+c1;
**   *  *   * *  * * *      *   *      * ***  ** **** ** **  = c1;
*** ***  **  ** **** * ******* *** ** **  ** *********     = cb;
 * *   ********   **    **
* ***** *   * *     * *********  ****   *** *  *  ****


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ***** ***   **

int main(void)
{

int ***   *    *  
* **** ******     ****    *** 

if(i==0)   *** * ***   *  * *  ****
else if(i==1) ***   *** *  *   *   **   
else {
    *  ** * **  ** * **     *     ***    ** *  **
 ***    ** *   ****  * *    *** ***   *  ** ****** *** = f0+f1;
 ** * *   *****  * **   ***  **   **  *   ** * ****  = f1;
 ** *** ***  *  ***  ****** * * **** **   **  *   * ***  * *  = fn;
*****  ****** *  **  * *  
  * ** *  * **  * ***  *** *  * *******    **  * ***   * 
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include   *  * ** *  

int  **    
{

int     *    ******
***  *****     *  ***   * 

if(i==0) printf(0);
else if(i==1)  *  * 
else {
   *** ***  * *  **** * *****  *****  *  *  ***  
**** *         ***** ** ***** * **    *    ****        * ** = f0+f1;
*    * **     *** ** * ** *  * * **  * * ** *  * **** *   = f1;
*  *  * * * ** * *  *    ** ** *** *  **  *    ** *** = fn;
 * * *** **  * * *  * 
     ****   **********  *    *****  ****   * 
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
** * *** * * * *** *** ** * * ** * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* * ** * * ****** ** * ***** * *** * * ** * d;
*** ** * * ** * * * * ** * **** *** ** *** * (d=2; d<n; d++)
**** ** **** * ** * ****** * * * * ***
*** ** * * * ** * ***** * ** * * ** ** (n%d==0)
** ** * *** * ** * * *** * * ** *** * *** * * * **** * ** * * *

   }
** * * * * *** * * *** ** * * ** * *** ** *
* * * * * ***** ** ** ***** * * * * ** * *
** * **** * ***** * * ** **** **** * * * * *** *
**** **** * *** * ***** * ** ** ** * **** * **
**** * ****** * * * ** * *** * * ** **** * *** ** * * ** *** (e==0)
* * * * ** * ** * ** * **** * ****** * * * * *** * * * * * ** ***** ** * *
***** ** ** ****** * * * ****** * ** *** *** * ***** * * * **** * **
** ** * * ****** * * * ** ***** ** ** *** * **** **** ** ******** ** * **** ** ** ** * *** ");
* ***** * * * * ************** ** ** * * ** * * ** *
*** * ****** * * * * ** * ****** * * ** ** **** *** *** *** * * * ** * * ** **
** ** * ** * * * ** ** ***** ******* ***** * *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* * * ** * * ** ** ** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
** *** ** *** ** ** * * ******** * * ** * d;
** * ** ** *** * * *** * **** *** * *** ** (d=2; d<n; d++)
*** ** * ** * * ** * * * ** ** * ** * *
* *** * ** * * **** *** * ** *** * * ** (n%d==0)
* * * * ** * * * * * ** * * * ** **** ** ******* ** ** ** *

   }
* * * ******* *** * ** * ** * * * * ** *
* * *** *** * ***** * ** * ******* ** * *
* **** * * ** * ****** ****** ** ** * *
** ***** * *** *** ** **** * * * * * *
* *** ** * **** ** *** *** *** * * * * *** * **** ** * * (e==0)
** ** * ** **** * *** **** * *** ** ** * *** ** *** * * * ****** **** * * ** *
** **** * * * * *** ** ** * * *** * * * * **** * * * * * *** *
**** ** ** **** **** ** ****** ** * ** ** ** * ** * *** ** * * * ***** ***** **** * * *** ");
* * *** * * * ** * ** **** ** ***** * *** **** ** ** **** * **
* * * *** *** * **** ***** * * * * *** * * ** *** ***** ** ***
* * * * * * ***** *** *** * ** ** *** **

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
*   *****  *  *   *    *   **    ** * *  *   ****     d;
  ** *  *   * **** **    *    * *  * *  *  * ***  ** **  **  (d=2; d<n; d++)
  *    *    * * ***** * *   *  **  *** * * ** *      *    
***          ***   ***** ** * *  ***  *** ***** *** (n%d==0)
*  *  **    * **   *   ***      **** *    *         *** *    *** ***  * *****  ** ** ***** **
   }
**   **  **  *  **   *    * * **** * **   ** * * * **** ** *  **
  *  * ***  * *** *** *** **  * * *   *** ***    * **
***  **  ***   *   * *    ** * *  * ***  **  ***** **** * * *  **  **
 * * * **** ****   *    ****  * *   *******  *    * 
* *   **  ** * *  **** **   * * *  * ** *  *  *  *    ***      *** * ** * * ****  (e==0)
**  *   **  ** *  **    ** * *  **  * * *   *   * ** * ** * ***** ** *****  **  *    *  ***  ** *  **** *   ******  * **  *
* ***  *   *** ********* ***    *    **  * *  * * *** **    *      * ** *** * * 
** ***** * *** *** ** ** * *    ***  *** **  **** *   *  ****** ****   ****  ****  *  * *  *      * * *******  *  ***  *   * ***** ");
        *   ** **   * * **  **   **   **  ******    **    *  *   **    **  **  **   ***
 ** *    *** * * ** **   *  *   * **  ** *  * *   * ** ** *  ** ** ** ***** *****     ** ** *** *  *   
**  **** *****  *** * ** * *      * **  * * *  *** **
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
  ** *** **  ** *****   ***    * Fn,t1=0,t2=1, n,input;
* *    *  ***  *  * *       **** **  *  * *  * 

   * ** **  * *   ** * *        * * ***  n++)
 **** *  ** **    **  ** 
  ***   * *  **   *   *  *  *  * *     *   * * ******  * = t1 + t2;
  * * *** *  *   * *** *  *    *** *  *  *  ***** **  *
 * * ****** * * *  **  **** * ***  * **********  * *  *  ** 
    }

* * *******    **** *  *  ** *   *  * **  * ** 

* *****       ***** *  **  **  *** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
** *   *  *  ***       **  ** Fn,t1=0,t2=1, n,input;
  ** * **** * ****   *   *****  *********** **   *  *** 

******   * *******    ** * *  *  ****      * * n++)
 *   ***    ** ** ** ***
 ***   *    **** *********  *     *  * *   ** *  *** * **  ****  = t1 + t2;
 *       ** * ******* ******* ****   *   ** *   * ***       *
*       *  ** *  ** ***** *** * *   *  ***   *  ** ***
 ** * **  *  ** **       **  **

   *  *** *  *       ** * * *     ** ** ** *  ",Fn);

 ** *     *   * ***  **  *** 0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.12
©2016-2025

Related questions

0 like 0 dislike
46 answers
11-30 Exercise 1: Fibonacci numbers (Array)
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 5k views
0 like 0 dislike
99 answers
11-01 Exercise 1: Find out all prime numbers between n and m
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 10k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 4.1k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 6.7k views
2 like 0 dislike
67 answers
11-09 Exercise 2: Reduce the fraction to lowest terms
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 6.4k views
12,783 questions
183,443 answers
172,219 comments
4,824 users