11-01 Exercise 3: Fibonacci numbers

0 like 0 dislike
14.1k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列：0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始，其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2)，F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n，輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 14.1k views

93 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 *  **  ** ***  ***  * F0,F1,Fn,n,a;
*  *** ** * **     * **  * * ***  * *

 ** *   ***   *  ***   * *****    ******    **  &a);

*    **   *     *   ***** *   *  * ** ***  ** 
    * ** *  ** * *   * * 
***   ******  ** ** *  * ** *  **** ****  * ******* * **  * * *   
 **      ** *  **** **  ***** *  **** * * ***   *  *  *   **
* **** **  * *  * **  **** ** *     * **    *    *** **   *** *
    }


   *   *   *  ***   **   *  * **   *   *    **** * * Fn);

** *  ** *   * * ***    ** * **   0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **  *   **  *
int  *  **  
{
int  *    ***  
*     *  *    ** * *    * ** 
if(a==0) printf(0);
else if(a==1) printf(1);
else {
 *  * ********  *  **** ***  **  **** ***
*   *   *  **** *   ******* *    * *  **   ****   **  **  = c0+c1;
*  * **** * ** *  *  *** **** *  *  *   **** *** *   = c1;
* *   ****** ** ***  * ** *  * **   ** *   *** * *  ** ** = cb;
** * * *** * * *  * ** *   **
**   **      ***      ** *** * * **  *  *
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ******* **

int * ***  
{

int     *   * *
  * * **    * * **    **  

if(a==0) printf(0);
else if(a==1)  ***    * 
else {
 *  * *  * * * *  **    * * ** * *       *  *
* *     ** * * ***  **  * *  **** * **  **  ***    *     = c0+c1;
    **   ***    **    ** ******   ** *  ** *  *  **      = c1;
**    *      * ****  **** **  *******  * *        **    * = cb;
*****  **  *  *  ** *  *  ***
    *  *   ***** *  *  * * *   ****** **** 


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ***  * **** * **

int main(void)
{

int ****  *****
*  *  * *    *  ** ** ** *    ***

if(i==0) *  **  *   * *   **   * 
else if(i==1)  ** ** ** *  ***  * *  
else {
**  * *  *  * ** * * *    *** **  **   *  
 **    *  * ** ***  **  *           ** ***  ** *****  **   = f0+f1;
****  *** **   ***** *  *  **   ****  * *  ***  *  * = f1;
*** * *  ** *   ******* * ** ** **  **    *   * ****** = fn;
 * *     ** **  ********  * 
** *  *  *   ** ** * * *   ** *   ** * **  * * **    **
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include ** * * ** *  

int  *** *
{

int  ****    **
 *   *    ** ***** * *** 

if(i==0) printf(0);
else if(i==1)     ** *
else {
***   *  **  **  *****    *   ******  *   
  * *  * ****      * * *  * * *****          **    * **  = f0+f1;
  *   *  *****   ** **** ***** *  *****    ***   ****        = f1;
**   *       * *** **  **  * *     *  **** ** *  ** * *   = fn;
 ** * ***  * *  ** * *** **  
*  ***** *  ***     *  ** **  *** *  ** *    * 
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* *** * * * **** ******** * * * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* *** * * * * * ** ** *** * * * * ** * * d;
***** * ** * ** ** *** * ** * * * *** * *** ** (d=2; d<n; d++)
* * ** ** ** ***** ** * * *** ** ** * ******
* **** * ** * ** * **** * ** * ** * * (n%d==0)
* ** ** * * * ** * * * * ** **** ***** * ** **** * ** **** * * ** *

   }
** * ** ***** *** * * ******* ** ** ** ** * ***** * *
* * * * ** **** * * * * * * ** * ** ** ** *
* * * * *** * * * * * ** * * * * **
** ********* * ** * * * ******** * **** **
** * * * **** *** * ** * * *** * ** ***** *** ** * ** * * * * (e==0)
** * * *** ** * ** ****** *** * **** *** * * * *** * * * * ****** * ** *
* * ***** * ** *** *** ** ** ** * * * ** * * ** ** ** * * * * ** ** *
* ***** * ***** ** *** ** * * **** * **** * * ** ** ** *** * * * ** ** *** * **** * ** **** ***** ");
* * * *** ***** * * ** * **** *** ****** * * * ** * *** * *** *** * **
* * ***** *** ** ** **** * ** ** * * * ** * ** * *** * ** * * * * ** * *** **
* ** * * ** ** **** * ** ** *** * * ** *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* *** ** * ** * * ***** ** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
** *** ** ***** ***** * * * ** ** * ** * * * **** * * ** d;
** ** * * * * * * * * *** *** ** * * (d=2; d<n; d++)
* ** *** **** *** **** * ** * ** * *
* ** ** *** ** ** ** ** * * ** ** * ** ** *** (n%d==0)
************** * ** * **** * **** *** * * * ***** *** * *

   }
* * *** * * *** * ***** * * ** * * **
*** * * * * ** * **** ** **** ** * * * ***
**** * *** * ** ** ** *** ** ** * * ** * ** * ** ****
* * ***** ** * * *** * ** ** * *** **
* * ****** ******** *** * * * *** * * ** * * * ** * ** (e==0)
* * ****** * ** ********* * **** *** * * ** * *** ******* * * * ** ** ** * * ** * * *
** * * * ** * * *** * * * ** * * * * ** * * * *** * * *
* * ****** **** ** ** *** ** ** * * * * ** * * * *** ** * **** * * **** * ** ** *** ** ** * * ");
* * * *** * ** * * * *** ** *** * * * ** ** * * *** * *********
* * * * ** * ** **** *** *** * ** ******* * *** * *** * ** * * * * * ***
**** ** ** * * ** * *** *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
* ***  ** ***   * *   *****  * *  ****  **     ***   * **   d;
 ***   **  **** ** * * * **   ***  ** *  *  * ** * ** (d=2; d<n; d++)
 ***      ***  *   **** ** *  *  ** ***  * **** **
   * * *** ***   *          ** ****  ****   ****   *    ** * (n%d==0)
** *******  ***** **  ***    * ******* ** * ***  *** ** ** **  * *  *  *   **** * ***  *
   }
*   *   **        *** * *** * ** * **   ****   ****   ***  
  ** ***  **** *   ** **** *  ********* * ** *** * *
 **    *  *    * * *** *** *   *     ** *  * * * **  ** * **
 * *  * *****    *  * ** **  *** *  ***  **** *  ***
* ** *** ** *     ****  *** *  ******   *   *** * ******** *** **  ***** *  *   *  *   (e==0)
**** ** *     ****  ******  *** ** ****  * *  ** ** ** *    ****   **  * * *****     * *  ** *   *
 ** **** ***  ** *  ***  **** ***** *** * ** *  * *   **** **  * * * ** *  *   **
 *  *    * **    ***        *** *   *  *  * ***** * *  * ******** *** ** **    *  * *    *   *** **    *  ***   *  ** *** *   ");
     **** **** ** *   *  **    * **** *  * * ** ** *  ****  *  ***  ********   **   
 * ****** *   *     * **** **  ** ***  *  * *   ***  * *** ***  * *** *      *     ****   *    * * *
*** ** * * *** ** * ****       *****   * *   *  ***
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
   *** ** ** ** **   *   * Fn,t1=0,t2=1, n,input;
   * * * ** * * *** **    ***        ** *** **  **  *  ** 

 * ** *** ** *****     ** **   **  *  **     n++)
***  * **  ***   *  **** *     *
 ***** **  * **       ** **  *  *   *** *  **  ****  *   * * = t1 + t2;
 **** * *  * *** * * **   ****  ***  *** *  ***  *   ***
 *  * *   ****   *****   ** **  * ***** * * ** *   * *  *
    }

*   ** *    * ** * ***  *  * *******  *** *** ****

**** ***      *  * * *** *     *  0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
****  ** *  **    **  ** ** Fn,t1=0,t2=1, n,input;
** **   ***  **   * ***  ** **  * ** * ***   * * *    **** *

**  *** * *  * ****** * ***  *  ** **     *    *  * n++)
*** * **** ***  *  * * *  * 
 *   ***     *   * ** * *  ***** *** *  * * **   * * ** = t1 + t2;
** *    * ** * * ***  *   **        * **  * *     *** * 
 ** * **  **   **  **   **** * *   * *** ****   ***  * **  
    *    *** ****   * ***  *

*  * ** * * ** ** *** **   * ******  ",Fn);

*           * *    *  *  *** 0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.6.173
©2016-2025

Related questions

0 like 0 dislike
46 answers
11-30 Exercise 1: Fibonacci numbers (Array)
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 8.8k views
0 like 0 dislike
99 answers
11-01 Exercise 1: Find out all prime numbers between n and m
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 17.1k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 7.2k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 11.8k views
2 like 0 dislike
67 answers
11-09 Exercise 2: Reduce the fraction to lowest terms
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 11.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users