11-01 Exercise 3: Fibonacci numbers

0 like 0 dislike
7.9k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列：0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始，其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2)，F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n，輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 7.9k views

93 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 *      *  *** *        *  F0,F1,Fn,n,a;
  *     **  *  *******   ******  *  *

 * *** *** * ** **    *    * *  * **    ** &a);

* **  *** *  * **    *   ** *  * *    
 *******   *  *  ****     
*** *  *** ****  ******** * *   ****   * * ** ***  **
   * ***  **  *  ** ** *** * ***  *    *** *********
 ** ** ** *      ***   ***** **** ** **   * **  **    *
    }


   * **  * **  * *  * *******  * * **   *     **** Fn);

       ** ** *   ***    *** * **** 0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include * *   **    *  ***
int      *
{
int ***  * *   * * 
  ** * *    *   * ** ** ***
if(a==0) printf(0);
else if(a==1) printf(1);
else {
*** *** * *  *** ** *     * ** *   ***
 * * **    ***  ** * ***   *  * ** * *** *     ***  * ** = c0+c1;
*******  **** **   **  * ***   *** * **** *     **   *** *** **   * = c1;
*    * * ***** *** *   *  ***   * *  ** **** ****** * * = cb;
 ***** *  ** **** **** ***      * * 
**     *  * * **   *  * * *** *  * **       *   ***
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  ***** * **** 

int ****** 
{

int * **** * 
 ****  *** ** *  *    * **     

if(a==0) printf(0);
else if(a==1) *   *   
else {
 ***  ** *   * * * * *    ** **** ****     * ***
*     **** * *  * *****  * ** *** ***  *  * ** ** ***** = c0+c1;
**   * *** * * * ** *** *  *  * ***  *  *   **   ***  ** *** = c1;
 **   ***     **** *****  *  *   *   ***  ** **  * *  ***    = cb;
   *  *** *   ***** *   * *** ***
** *  *** * ** ** *  * ** *  *     ***  ** ** *** *


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *** *** * *  

int main(void)
{

int  * *** *  *
   **    ***  ***     ** *  *  ** 

if(i==0) * ** * ***  **** ****
else if(i==1) ** *   **      *  *  
else {
**  ****** * ** ***  * ***   ** *** * ***
*  ***   ****** * **  * *** * * *   *    *  **       *** * = f0+f1;
 **  *   *** * *   *    * ** *  *  *   ***  ** *   ** = f1;
*  ** *****  *  *    ****** * *****  * *    *  *    = fn;
*** *   *** **    **  ** **
*    * *    **  * *  **  * **** *** ** ** ** 
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  **** * ***

int *     
{

int * * * * ***
*    **      ** ** ***  * ** 

if(i==0) printf(0);
else if(i==1) *  *** * *
else {
*    *    **   *  *  *  *   *** * *  *  **  ** 
**  * *** *  ***** *  *** * **** ** **  **   ***  *  = f0+f1;
 *  *  ***    *  * *****     **** **  **  *   ** *****  ** = f1;
 ** ** **** * ** *  *  ** ** ** *   * * *    *      = fn;
************ *** ** * * *** *  *
* * **     ****  ***** *******    **    * *   
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
** * ***** * ** * * * ** *** * ** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
** * ** **** ** ** *** * * * * * *** d;
* * * * ****** * * * *** ** ** ** * * (d=2; d<n; d++)
*** * ** **** **** * * * * ** ** ** * ** *
* **** * * ** * * * * ** * * (n%d==0)
* * * * * ** * * * *** * * * ** **** *** * *** *** *** * ***** * * *

   }
** * *** * * **** * *** * * * * *** * * * ** ** * * * *
* ******* * **** ****** * *** * ** ***** * **
** * * * ** ** ** * **** ** ** * ** *** ** * ***
* * ******** ** ******** ** * * * *** * * * **
* ** *** ** ******* * ***** * ** ** * * * ** * ******* ** ** (e==0)
*** * * * * *** * * ** ** ** ** ** * * * *** ** * *** * * * * ****** * * *
* **** * ** ** *** ** * * * ** * ** *** * * * * ** * * * * *
* ** ** * * ** * ** * ** ** ***** **** * * * **** ** ** *** * * ** *** * * ** ** ** ** * ");
** * ** **** *** * *** * ********* ****** **** * *** ** ****** * * **** *
* * **** ** * ** ** * ** * *** * * **** * * *** ** ** * ** * ** ** ******** ** **** ** ** *****
** *** * ***** * ** * * * * * * ** ** *****

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* *** ** * ** *** *** ** * * * %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
** ** * * **** * * * * **** ******* * * * d;
** ** * * * ** * ****** ** ** ** ** *** (d=2; d<n; d++)
** * * **** ******** * * * * * * ***
*** **** * ** **** ***** **** ** * * * *** (n%d==0)
* * * * **** ** ** *** *** * * * * **** *** *** * * * **

   }
* *** * ** * ***** ** ** * * * * ** ** * *
* * * ******** **** * *** * * ***** *
* *** * * * ** ** * *** *** ****** ** *
** * * * ** * * * * ** * ** * *** * * **
* *** * ****** ** *** *** * * *** * *** ** * * ** *** * * ***** *** ** (e==0)
* * ** **** * ** * * ********* * **** ** * ** * **** * ***** ***** * * *** * **
** ** * * *** ***** *** * * *** ** ** *** * * * * **** **
* * * * * * ******** * * ** * * *** ** * * ** * ** ** * ** * ** **** * * * ** * ** ");
*** * *** ** ************** *** **** * ** * * * ***** * ** * * *** *
*** ***** ***** * * * ***** * * * * *** ****** ** * * ** * *** ***** * * * *** * * ***
* * *** ** *** ** * * ** * * *

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
  *  * ***  ******          *      *  *** *****  * d;
**** ****   ** * ** ** *** *****  *  * ***  ***** (d=2; d<n; d++)
 **   *    *  **** * **     *   *   *  **    ** ****
  **   ***** ** ****    *   *  * **   *   * ********  *   (n%d==0)
 *** *** ****  **  ** *      *  *** ** * ****  *   ***** *  ***** *   *  *** *   *     * 
   }
**     * **   * * **  *  ** ** * *  *** **** **    ** ** *
* *** ** *  *** ***  ***  ****  *******      ****
 *  * ** * * * ** * **   *** * ***           ** ** *  *   **
    ** * **     *  *** ** *** * **  * * *      *  ***   * *  
* ***  ** ***     *  *    * ***** *  ***  *  **    *  ** ***  * *  *  *  **   * ***** * (e==0)
** * *    **  * **  * *     **  ****  **  *   **       ** * **** * **  *** ***    * **   * * * **  *   
 **** **  **  ***  **      ***** ******  *  ***** *   *    **   * **** * ***
** * **   ***** * *  ***** * ******* * * ***  *  ** ****  **  * * * *    **  *****  *** *  **    **** *  ");
*  ***** * * *****    *         * *** ** * * ** *     *      *    * ** **  * *    * **
    ** ********   ****** **   **  **  *****  * **  **  * ****   **   *   ***  * *  * * ***  *  ***   * 
    *** *  * ** ***  **** ***    * ** * **** * * *
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
* *  *  *    *  *   * **    Fn,t1=0,t2=1, n,input;
 ***** ** ** ** *  * *      ** ****   *   **    ***     * 

***** **   *  * *  ** *  * *  *  *   *   n++)
*   *    *   * ** *   * *       
* * **    **  **   *** *   * **  **     * *  * *  = t1 + t2;
* *    * *  *  ***      * * *** * *  *    * * **  **    **
 * *** ** * ***     *    *  *  ***  * * *******  ******  
    }

 ***  * * **   *     * *    * *   *   ** **  

 * **   *  **  **  *  *   *     0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
     ******   * **  ** ****    Fn,t1=0,t2=1, n,input;
****** * *  *  * *  ****** **** *   * ***  ****       *   *

   *    *   *  ***    *** **  **  ***  * ***  * n++)
* ** * * * *** *  **  * ** * *
  *  * ***  **    * * *  **    *    *  **  *** *   *  * * **       = t1 + t2;
***   ****  *** ***  **  * **   *** * * ****   ****** * *
   * *** * **    *  ** **   **  **  *****  **      ** *      *** 
* * *  ***** *   ***   * 

* * * ****** * *  **  * **   * *** *  ",Fn);

 *** *  * ** *  *  ****       ** 0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.127.192
©2016-2025

Related questions

0 like 0 dislike
46 answers
11-30 Exercise 1: Fibonacci numbers (Array)
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 5k views
0 like 0 dislike
99 answers
11-01 Exercise 1: Find out all prime numbers between n and m
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 10k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 4.1k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 6.7k views
2 like 0 dislike
67 answers
11-09 Exercise 2: Reduce the fraction to lowest terms
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 6.4k views
12,783 questions
183,443 answers
172,219 comments
4,824 users