11-01 Exercise 3: Fibonacci numbers

0 like 0 dislike
6.4k views

In mathematics, the Fibonacci numbers or Fibonacci sequence are the numbers in the following integer sequence: 0,1,1,2,3,5,8,13,21,34,55,89,144

前13的斐波那契數列：0,1,1,2,3,5,8,13,21,34,55,89,144

By definition, the first two numbers in the Fibonacci sequence is 0 and 1, and each subsequent number is the sum of the previous two. In mathematical terms, the sequence Fn of Fibonacci numbers is defined by the relation Fn = Fn-1 + Fn-2 with seed values F0 = 0, F1= 1

斐波那契數由0和1開始，其後的數就由之前的兩個數相加。用數學表示 Fn = (Fn-1) + (Fn-2)，F0 = 0, F1 = 1

Write a program that asks the user to type an integer n, then display Fn on the screen.

寫一個輸入一個整數n，輸出第n個斐波那契數的程式

Example input 1:

5

Example output 1:

5

 

Example input 2:

12

Example output 2:

144

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 6.4k views

93 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 ** *  ***  ***      ** * * F0,F1,Fn,n,a;
 *** *   * *        **    *  ** 

  * *  *****         ** * *  *      * *** &a);

* ** ** *** *       * *   ***  *  *  **  *     *
* * **  ****   ** * *  ***
** ** *****      *  * *  * ***   ** ** ** * * ** *  *** **
*  *****   ***   *  ****  * *** *  ****  * **
 * ***** * ****   ********* ******  * * **    ***  ***** ** 
    }


 ********* **   *****     ** ****   *   * *  ** *** Fn);

*  ***** * ***************  0;
}
answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include *  *   *     * **
int  * * 
{
int *  * *** *
 *  * **  ******** *** * **  ** 
if(a==0) printf(0);
else if(a==1) printf(1);
else {
   * * * *   *    *  **   **** **  ** *   *
*  ** *  *  * * * *** * * ***   ******* * *    *  * * ***   = c0+c1;
* ****  **  ** *** ** ***** * *   *****  *  * *** **   * * ****** = c1;
*    * ***  * ***** **** * * ** * *     * *   **     *  = cb;
    *** *** ***  **  * * * ** **
   ***  ****** **  *  * ** * * ** *  * *  *    ** * **
}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:6:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:7:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:7:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include    * ** * ***** * **

int     *
{

int   * * *      
****   *  * ***  *  **  *   *

if(a==0) printf(0);
else if(a==1) *   * *
else {
*  * ** ** * * ***  ** *     * *  ***  **   
    * *  ** ** **** *** ******   ************ ***  *    = c0+c1;
** ** * *  ***  * * **  * **** * *    **   * = c1;
 *    ** * *   **  * ***  ***  *  ** **    *    ****** * * = cb;
 *    ***   * *  ** *   * *** 
* *** * ***  **  *  *  ** ***      * ***    ** ***


}
return 0 ;
}
answered by (-254 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(a==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(a==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(a==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include **    **     

int main(void)
{

int   ** *  *    **
*    ***  *   **  *** * ** 

if(i==0)   *  ** ** *    
else if(i==1) ** ** *  ***     **  
else {
 **** * ** *    * *  ** ***  ***  ** 
*   **  * * * ** *   ** * *     * * ***   *****   *   * = f0+f1;
 ********** **  **    **  **   * *****  **   ** **  = f1;
*** **  ** * ****** ** ***   *  **  ***** ****   * *******  = fn;
       **  *  ** *  * *    * 
*  *   *** *  *    *  * **  *** *       * *  ***   *
}



return 0;

}
answered by (-107 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include  *   *   *   

int * * * 
{

int * ** * *** 
** ***   **       * ** * *******

if(i==0) printf(0);
else if(i==1)  *  ****
else {
**   **  **    ** ** **  ***   * *    * ***
 **      *    ** ** ***  * **    **  **  **  *  **    = f0+f1;
*       ******  ****  * *  ** *    *      *** *  **** = f1;
** ** *** ***  **  * ***** *  *** **** * **     ***  ******* = fn;
 ***      **   * *** *  **** *
   *  **  ***  *  **  * **  ** *    *        * *  **
}



return 0;

}
answered by (-107 points)
0 0
prog.c: In function 'main':
prog.c:9:10: warning: null argument where non-null required (argument 1) [-Wnonnull]
 if(i==0) printf(0);
          ^~~~~~
prog.c:10:22: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
 else if(i==1) printf(1);
                      ^
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:10:1: warning: format not a string literal and no format arguments [-Wformat-security]
 else if(i==1) printf(1);
 ^~~~
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* * ** * * ** * * ***** *** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* ** * * * * * * * * * ** ** * * * * * * d;
* ** ***** *** ***** *** **** * **** * (d=2; d<n; d++)
**** *** * ** ** * * *** * * ***** * * *** * **
** * **** * ***** ** * * ** * * * *** * * (n%d==0)
* * * * ** *** ** * ** ********* * * ** * * * ** * ** *** *** *

   }
* ** ***** * * **** * ***** * * *** *
** * ******** * **** * *** *
* *** ** * ** ** ** * * * ** ** * ** ** * *
**** *********** * * ** * *** *** ***** * ** *
************** ** * * ** **** *** * * ** * *** * **** (e==0)
* * **** ** * ** ***** **** * * * * ** * * * * ** * * * ****** *** * ** * ** *** **
***** ***** *** ** **** * *** **** *** **** * * * * ** ** ** * ** ***
** *** * * ** * * * * * **** * ** ** ** * *** * ** ** ** ** *** *** ** ** * * * * * * ** ");
* * * * * ** ** ** * * ***** * * * * * * * * ********** *
***** ******* *** * * * ** * * ** * ** ** ** * *** **** ******* *** *
* ** * *** *** * * *** ***** *** * * ** **

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

 int main ()

{

    int a,b,n,e=0;
* * * * * * * * * **** *** ** %d", &a,&b);



    for (n=(a+1); n<b; n++)

    {
* **** * * * * ** *** * *** ** * * ** d;
* ** * ** * * *** ** ** ** * *** ** ** * (d=2; d<n; d++)
*** * ** *** *** * *** * ** * * ****** ***
** * * ****** *** * ** * ***** *** * *** (n%d==0)
** **** ** *** *** *** ** **** * * ** * * ** ***** *** ***

   }
* * * * ** * ****** * ** ** * * ** ** ** * ** ** *****
* ** * ** ** * * ***** *** * * **
** * * * ** ** * **** ** * *** * * * * * * * **
* * * ** * * * *** ** *** * *
**** * * ** * * *** * * * * ** *** ******* ** **** ** (e==0)
******* ** ** ** * ** * ** ** * * ** *** *** ****** * * * ** * * * *** ** * * *
** ** ** ** * * * * * ** * * ** *** **** *** * * * *** * * ****** ** **
*** ******* *** *** *** ** * ** * *** * * * * ** * ** * * ****** **** **** *** * * ** * * ");
** *** ***** *** * ** * * ** * **** ** * * * * * ** **** **
** **** * * * * ** * ** ** ** *** * **** ** *** * * * * * *** ** ***
* *** ** * ** * *** ** ** * * ** * * ** * ** ***

}

return 0 ;

}
answered by (-254 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
main ()
{
    int a,b,n,e=0;
    scanf("%d %d", &a,&b);

    for (n=(a+1); n<b; n++)
    {
*   **     *   ****  *********   * * *  *  **  **  d;
*  ****  *   *    *  **     ******  ** **  ***     **  *  * (d=2; d<n; d++)
 *  ********  *   ***   ******  ******* *  ** *  *     *
***  **** *  * * **  *   ***   *   ******    ** ** ** (n%d==0)
* ****** ***   *    ***  * *      * *   **  *** *  ***  **   *   ***    *   *  ****  *  * ****** *  **
   }
*   **  *    *  ** * **  * * **** *  ** * * * **      * * ** ** *
*  * *   *      *     *   *    * **  *** **  * ** *     ***
* *   *  * *     ****** *  * ****  ** ** * **  *** *
  * * *  *   *****  * *    **** *  *   **** * * *** * *   
 * ****        * *  *  ** *** * **   ***     *    *   **  *******   * ******   ** **** * (e==0)
* **** ** *** ** *  *  **** *** * **  *  *  *** *  * ** *     ***  *  ** ***   **   *    **   ****** **
     ** *  ** **** ******  **   *     * * ***   * ****  **** **    ** * *   
*  *  *  ** * ** ***       ****    *   * ***   *  * ****   ** * **  ***** * ** *  **  *    *  ** *  **  **     *** ");
* * *    *** *    * ** *    * *   ***  *    *  **  *** *  * ** * * *   *  **
 * * * **   ****   * **      **        ** *  ****  *  *   * ***** *  *     ***  * * **  **  * *   ****  *** *
 ** ****   *** ** ** *   ***    *** * *** ** * *  ** *
}
return 0 ;
}
answered by (-254 points)
0 1
prog.c:2:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main ()
 ^~~~
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
  * ******** * *******  *   * *  Fn,t1=0,t2=1, n,input;
*****   ***           ***  ********* * * ***  *******  ****

*** * *****     ** *  ** **   ***** *  * *** n++)
  **       *** **** ** 
* *   * ** **  * *    ***  ** ***  ***** ** ****    **  ***  * *  = t1 + t2;
* *    ***    ******* **  *    **** ** ***  * **    * *  
******   ***** ** **  **    ** **  *  *  *** *** *** **     
    }

* *   *  * ** *    *    ***      * *****  ***  

  *   **** * * * *  *  **    ***    0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
 * ** ** * *   **  ***** * Fn,t1=0,t2=1, n,input;
*** *    *     **  ** ***   * * **   ** * *      ***  

   **     * ******  * ** *   *** ** * **   ** n++)
  **  * **  * * * * * **  ** *
  **  * *****   *   *   ***  * **  * *    **  **  * = t1 + t2;
      *    **   ** **** *  *  *  *** ***  ** *   ***** * **
* **  ***    **** * ***  ** ***  *   * ** * ****** * **    
* * **** *    *  * **  *

     * * * **  **** *  ** * **** *** * ",Fn);

*     *  *     * **  **** *  * ** *  0;
}
answered by (-281 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.178.174
©2016-2024

Related questions

0 like 0 dislike
46 answers
11-30 Exercise 1: Fibonacci numbers (Array)
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 34912 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 3.8k views
0 like 0 dislike
99 answers
11-01 Exercise 1: Find out all prime numbers between n and m
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 7.6k views
0 like 0 dislike
41 answers
12-14 Exercise 3: Fibonacci numbers (Recursive)
[Exercise] Coding (C) - asked Dec 14, 2017 in Chapter 9: Functions by semicolon (5.2k points)
ID: 37370 - Available when: 2017-12-14 18:00 - Due to: Unlimited | 3.2k views
0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 5.2k views
2 like 0 dislike
67 answers
11-09 Exercise 2: Reduce the fraction to lowest terms
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited | 4.9k views
12,783 questions
183,443 answers
172,219 comments
4,824 users