0 like 1 dislike
15k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 15k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
* ** ** **** *
** * * ** ** * * *

int main() {
* ** * * *** ** ** ** * * * **
*** * * * ***** ** ** ** %f *** &a, &b, * * * *
** *** *** ** * *** * * *** * ** *
* ******** * ** * * ** ** * ** *** {
** ** ** ** *** * *** ***** ** ** * **** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** * = ** * ** * = * **** ** * a, b, c, (-b)/(2*a), **** ** * * (-b)/(2*a), ** * *
* * ** ** **** *
** ** ***** ** * **** **** *** if(d==0) {
* * ** * * *** *** ** * * *** * ** ***** *** * * *
** * ** *** * * * * ** * *** ** * * * *** ** *** * * **** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = *** * * ** a, b, c, x1);
* ** * ** *** * ** **
* * ** * ** ** * * * ** {
* * *** * **** * * ** * * * ** *** * *** * ** * **** * *
* * ** * * * ** ** ** * * * ***** ** *** * * *
*** ** *** *** * *** * ** * * * ** **** ** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and ** * ** ** = %.2f\nx2 = * * * * a, b, c, x1, x2);
* * * * * ** ** ******
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * * ****
* * ** ** ** * * **
#include * * ** * * *

int main()
{
* * ** *** * *** *** *** *
* **** ** * * * * *** ** %f * * *** **** * * ** **
* * * *** ** ** *
* * * * **** * * * *** * * ***
** ********* ** **** ** ** ** ****
**** * **** * * * *
**** * * * **** * ** * * * ** * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and * **** = %.2f\nx2 = * * ****** * ** **
* **** ** ** * *** * if(D==0)
* ** *** * * * ** *** * ** **** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ****** *
*** * **** * ** ** * ***
*** ** * * * ***** * * * * * ******* of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * * ** = * ** *** = * * *** * *** * * ***** ***** ** *
** * * *** ** **** * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** * ** *
*** *** *** ** *** * **
***** * ** * *

int main()
{
* * ** *** *** **** ****** * *****
**** * ** * * ***** ** * * ** * %f ** * * ** * *** * * *
* *** * * * ** ** ******
* * * ** * ** * **** * * * * *** *
*** *** * * **** ** **** * ** * ** *
* * ***** ** * * * ** * *
* * *** ****** ** ** * **** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * = %.2f\nx2 = ** * * ***
** ** ***** ***** * * *
** * ***** ** *** * * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * *** * * * *** *
* * * * **** * * *
** * * * * * * * * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and *** = %.2f + *** = %.2f - ******** * * *** *** * * * *** * * * ***
** ** ** ****** * * * **** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
* * * ** * ** * ** ** * a,b,c,x1,x2,D;
** * * **** ** *** ** * %f *** * ** * * * * *
** * * * ***** *
***** ** * *** * * ** *** ** = (-b + sqrt(D))/(2*a);
* * * * * * * * * = (-b - sqrt(D))/(2*a);
** * * **** *** ** * *** **
* ** *** * **** ** * ** ** * *** * * *** ** * *
*** ** * *** * ** *** * ** * ***** * *** * ** * * * * ***** * ** * ***** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\n",a,b,c);
** * * * * ** **** * * ** * ** * **** * * ** * *** * * ***** ** * *** * = %.2f\n",x1);
*** * * * ***** ** *** *** * ** * * ** * * * ** ***** * * ************* * * ** = %.2f",x2);
** ** ** **** * * * *** * * * * *
* ***** ** * * * * if(D==0)
* ** *** * ** ** * * * ** *** ** *** *
* **** * * * * * * ** ** * ** * ** * *** **** * * * *** *** * ***** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
****** **** * * *** ** **** **** ** ** ** * * *** *** * ** * * ** ** * *** *** * = x2 = %.2f",x1);
*** ** **** ** * * * * *** ** * ** **
* * * * ** * * * ****
*** **** ** **** * * ****** * * * ** ** *
** *** * ** ** *** **** * * ******* * ** * * * ** *** * **** *** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\n",a,b,c);
* ** ** ** * ** ***** * ** ** **** ** * * *** * * ** **** **** ** * * = * * * ** ** * **
* ** * * * * ***** * ****** * ** * ** ** * * * * ****** * * ** ** * *** = * * * * * **** * * *
* * **** * * * ** **** * ** * ** **** *
* * ** * * ** ** ** 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
** ** * ** ** * ** * *** a,b,c,x1,x2,D;
* * ** * ** * * ***** ** * *** %f * * * * *** **** *** * *
* ** * * ****** *** ********** *
* * *** * *** * * *** = (-b + sqrt(D))/(2*a);
****** * ** ** * * = (-b - sqrt(D))/(2*a);
* * *** ** **** * * **** *
* **** * * * ** * * * * ** ** * ** * * * ***
** ** * ** *** * * * * * * ** * * ** * ******** ** ** ** * * * ** of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
*** ** ** * *** **** * ** * * ** * ***** **** * *** ***** = %.2f\n",x1);
****** *** ** * * * **** ** ** ** * ** * * * ** * * *** * * * ** = %.2f",x2);
* * **** **** ** ** *** ** ****** ******
* **** * * ** * ** ** * if(D==0)
** * * **** * ******** **** ***** * ** *
**** *** ** ** ** ** ** ** * * * *** ** * * ** ***** * * ** * *** ** * * of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
** * ******** * * ** *** **** ** * * **** * ****** * * * *** *** ** * = x2 = %.2f",x1);
* * ** * * * * *** * * ** * * *** ** ***
** * * ** ** *** * *
* * ** ******* *** ** ** * *** ** * * * **** **
** **** * * * * ** ** ** ** * * *** ** * **** * *** *** **** * ******* of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
** * * *** * * * ** **** *** *** * * * **** ***** ** *** ** ** * * ** * * ** ** = * * ** * * *** * ** * * *
** * ** ** *** *** ** *** ** *** * ** * ** ***** *** ******** * * *** * * * = *** * * * * * ***
***** ** * * *** * * * ** * * * *
* ******* * * ** ** * 0;
}
answered by (-258 points)
0 0
prog.c: In function 'main':
prog.c:13:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:19:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:24:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
0 like 0 dislike
Hidden content!
* *** ** *** ** *
* ** **
int main()
{
** *** *** ***** * * * a,b,c,D = 0,x1 = 0,x2 = 0;
* ** ** * *** * ** ******** * ** ** ****** ***** * ** * * *

* * * * **** *** *** ** * **** of %.2fx^2 + %.2fx +%.2f = 0 ** * * *
** *** * * * ** * = (b*b-4*a*c);
*** * * * **** ** *** (D < 0)
* ** *** ** * * * * * *
** *** ** ** **** ** ** * * * ** * complex and * **** ***
* **** * ** * ** * *** * = * * * ***** * ** * * * ****
* ** ***** *** * *** * ** *** * = * ** ** * ***** ********
* ** *** * ** * ** *** ** **
* *** **** ** * * *** (D > 0)
** *** * * ** *
* ******** * * ** * * ** * *** * real and ** * * **** **
* *** ** ** *** * * **** * = ** * ** ** * + sqrt(D))/(2*a));
* ** ** **** ** ** * * **** *** = %.2f",(-b - sqrt(D))/(2*a));
** * ** * * ** * **** * **
* ** * **** * * * **** (D == 0)
* * * ** ** * ***** * **
* *** ** *** * ** * * * **** ** * real and same\n");
* * ** *** ** * * * * * * ** * = x2 = %.2f",(-b + sqrt(D))/(2*a));
**** ** * * ** *** **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
your output lack of 1 space at line 8 when print out "Roots of ..."
0 like 0 dislike
Hidden content!
* * **** *** ***
** *** ******* * * *
int main()
{
* ****** * * ** ****** a,b,c,D = 0,x1 = 0,x2 = 0;
*** * ** * ***** * * ***** * ** ** * * * * * * ***** * * *

* * * * * * ** *** * ** ***** ** of %.2fx^2 + %.2fx +%.2f = 0 ** ** * * * *
*** ** * * ** **** *** = (b*b-4*a*c);
*** ** * * *** * * (D < 0)
** * ** * * ** ** * ***
*** *** * * ** *** * * ** *** * ** * complex and * ** ******
* *** * * * * ** * * * **** *** * = * ** * *** * ** ******* * * **
* ** * ** *** ** * * ** *** * ** * = * * ** *** * ** * *** ***
* * *** * ***
* * **** *** * * *** (D > 0)
* * *** ***** ** ** ** *
* ** **** * * ********* * *** ** * * ** real and * ***** * * ***
*** ** ** ***** ** *** ** **** *** = * ** * * * + sqrt(D))/(2*a));
** ** * * * * *** * * *** **** = %.2f",(-b - sqrt(D))/(2*a));
** * * * * * * *** *
* **** *** * ** ** * * (D == 0)
**** * *** ** *
* *** * ** *** *** * ** * ** real and same\n");
* ** * ** *** * ***** ** ** * * = x2 = %.2f",(-b + sqrt(D))/(2*a));
** * * *** ** *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* *** * * ** *
** *** * ** *
int main()
{
***** * *** ** * * * * a,b,c,D = 0,x1 = 0,x2 = 0;
** ** *** * ** * ** * ** * * ** *** * *** *

* * * ** * **** * * ** ** **** *** of %.2fx^2 + %.2fx +%.2f = 0 * * * * * *** *
* * ** * *** * * = (b*b-4*a*c);
* * * * * ** ** (D < 0)
* * ** * * * * *** * *
*** * ** * * * ** * * complex and *** * ** * **
* * ** * * ** ***** ** ******* = * * * * *** **** *
* ** *** * * * * * * ** * * *** = ** * * * * ** ******* ** *
* **** ** * **** *
** ****** * * * ** ** (D > 0)
**** *** *** * * **** ****
** * * * **** *** ** real and * ******** * *
* ** ** ** *** * * * * ***** *** * = * **** ** ** + sqrt(D))/(2*a));
** * * ** ******* * **** * = %.2f",(-b - sqrt(D))/(2*a));
*** *** ** * ** * *** **
* * **** ** **** * ** ** (D == 0)
* ****** * ** * ** ***
* ** * * * **** * * ** real and same\r\n");
** *** ** ** * ** ****** = x2 = %.2f",(-b + sqrt(D))/(2*a));
* ** *** * * ** * * **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * ***********
* * *** * ** **
int main()
{
** * *** * * * ** * *** a,b,c,D = 0,x1 = 0,x2 = 0;
** * * **** ** * ***** ** * **** * * ** ** ** * ****

** *** ** * * * ****** ** **** of %.2fx^2 + %.2fx +%.2f = 0 ** * ** *
** * ** ** * * ** * * ** = (b*b-4*a*c);
* * *** * * *** ***** (D < 0)
* * * * * * **** ** * ***
* ** * * ***** * * complex and **** *********
**** **** **** * ****** ** * * ** = * ** * *** *** ** * ** * * * **
* *** * ** * * * * * * ** = *** * ******* ****** * *
** * *** * * ** * *
*** * * *** *** ** (D > 0)
* * * * *** * * ***
** **** * * * * * real and *** **** **
*** * * * ** * * * * * * ** = * **** + sqrt(D))/(2*a));
* * * *** ***** ******* * * = %.2f",(-b - sqrt(D))/(2*a));
* * * * * * ** * *
* ** ** **** ***** * ** * (D == 0)
* **** ** * ** **
*** ** ** **** * * * ** *** * **** real and same\r\n");
** ** ***** ** * * * * * = x2 = %.2f",(-b + sqrt(D))/(2*a));
** * * * * * *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* ** * ** * * * *
** ** * ****
int main()
{
** * * **** * * * * ** * a,b,c,D = 0,x1 = 0,x2 = 0;
* * * * * * * **** *** ** *** ** ** * *** ** * * * * *

** ** * * ** **** * * *** * of %.2fx^2 + %.2fx +%.2f = 0 are",a,b,c);
* * ** ***** * = (b*b-4*a*c);
* * * * * ** *** * * = (-b + sqrt(D))/(2*a);
*** * * * * *** * * * = (-b - sqrt(D))/(2*a);
* * ** * ** ** (D < 0)
** * ** *** * ****
* * * *** ** ** * complex and ** * ** **** * *
* *** *** * *** ** * *** * *** = ******* * **** * ** * ***
** ** * * * * * * * *** = * * * *** *** ** **
* * *** ** ** ** * *
** ** * * * * *** (D > 0)
* ** ** * ** *
** ** *** * * ***** ** * ** *** ** * real and *** * ****
* ***** **** ** * * *** ***** * * * = ** * * ** *
* ** * *** ******* *** **** = %.2f",x2);
** * ******** * *** * *
* * * * * * *** * (D == 0)
***** *** * * *
*** *** ** * ** * * *** ** *** real and same\r\n");
*** * *** * ** ** ** * *** * * = x2 = %.2f",x1);
* * * * ** ***** *** *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.50.50
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users