0 like 1 dislike
8.6k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 8.6k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
* * ** * *
* * ** * * *

int main() {
**** *** * **** * * **** * * ** *
*** * *** * * * ** * ** * **** %f ** **** * &a, &b, **
****** * *** ** *** * * * ** ** **
** * * * ***** * ** * *** ** * {
** * * * **** * ****** * * ** * * * * ** * ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * ** = *** * ** * = **** ** ** * * a, b, c, (-b)/(2*a), * * (-b)/(2*a), * ***** **
** * * ** **** * *
* ***** ** * *** * * ** * * if(d==0) {
* * * *** * ** * ** ***** * * * * * * ** * * **** ** *
* ** ** *** * * **** ** *** * ***** *** **** *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ***** * a, b, c, x1);
*** * ** * *** ****
* ** ** * ** * ** * *** ** ** {
* * ** ** **** * * * * * ** ******* *** * * ** ** * * * **
* **** * * * *** * ******* * * ** * * ** ** ***** ** *
* ** * ******* ** **** * * ** * ** * ** ** ** *** * ***** of %.2fx^2 + %.2fx + %.2f = 0 are real and * * * * = %.2f\nx2 = * * a, b, c, x1, x2);
** * * ******* * * *
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * * **
**** * * ***
#include ** * ***

int main()
{
***** * ***** ** * ** * **** *
* ** ** * *** *** ** * * **** %f * ** * * **** ** ** **
* * * *** **** * ** * * *
** ** * * **** ***** * * * * ** *
* * * * * * * * * * **
* ** * * ********* * * * *
* **** * * ** * ** * * * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and *** ** = %.2f\nx2 = * * *** ***
** *** * * ** * ******* if(D==0)
* ** ** ** **** * * * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * ** * ***
***** * *** * * * * *
** * * ** *** **** *** * ***** of %.2fx^2 + %.2fx + %.2f = 0 are complex and ****** = * * ** * = * ** ** * ** ** ***** ***** ** * *** * *** *
** * * * ****** * * *** ** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * *******
* * * * ** ** *
*** ** * * *** * * * *

int main()
{
***** *** ***** *** * * * * ***
* * * * ** ** * ** **** *** %f *** ** * * * * * **** **
*** **** * * * * * * *** * * *
* ****** *** * * * ** * *
** * * * * ******** *
* * * * * * ** ***** **
** **** *** * * ** * * * ***** ****** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** **** = %.2f\nx2 = * * * ** * * * **
** * ** *** ** ***** * * * **
* * ** ** * ***** *** * * ** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** **** *
**** * **** ** * **** * * *
*** **** * *** **** ** ***** *** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** ** ** = %.2f + * * * = %.2f - * ** ** * * * **** * * * ** * ** **** * * *
**** ** * ** ***** * * * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
** *** * * ** ** ** ** * a,b,c,x1,x2,D;
**** ** * ** ** **** ** *** * %f * * **** ** * **
***** ** * *** ** * ** * * * **
* * * ** **** *** * = (-b + sqrt(D))/(2*a);
* *** * * * ** ** * ** * = (-b - sqrt(D))/(2*a);
* ** ** ** * **** * *** * ** *
* ** **** * ** * * * **** *** *** * ** ** * *
* **** * **** * ** ****** ** ** * * ** **** ** * ******** * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\n",a,b,c);
** * * * ***** * **** ** * ** * *** ** ** ** ** ** * *** * * * ** * = %.2f\n",x1);
* ** **** * *** * * * ** * * ** ** ** * * ** * **** ** ** * *** * ***** * = %.2f",x2);
* * * ***** * *** * * ** * ***** ** * ** * * *
** ** * * * ** * if(D==0)
* **** ** * ** ** ** ** ** * * *** ** * **** *
* ** ** * ** * ** ** ** ** * * * * * * * * ** **** **** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** * * *** * * * *** ** * ** ** ** * * * * * ***** * * **** * = x2 = %.2f",x1);
******* * * *** *** * * *** * ***** ***
* *** * * ** ** *** ***
** ** * * *** * * * ********* *** * * * ** *
**** * **** * **** * * * *** ** * **** * *** *** *** * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\n",a,b,c);
** * ** **** *** ** **** * ** * *** * ** * ** ***** ** * * * * *** * = * * * * ***** ** *
* ** * ** ** *** * * * ** *** * ** ** ****** * *** * *** * * *** ** = *** ** * * * * ****
* * *** * * * * * * ********** ** ** ** ** ***
* * * * ******** ** * ******* 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
** * ** * * *** * * * a,b,c,x1,x2,D;
* ** * * * * * * * ** %f * ** * * ** *** *********
** * ** ** *** *** *
* ** *** **** * ** * = (-b + sqrt(D))/(2*a);
***** * *** * ** ** * * = (-b - sqrt(D))/(2*a);
** * ** * * * **** * ** * **
* *** ***** * * * ***** * *** * ** * * *
* * ** * ** ** * **** * * ** * * * * * * ** ** ** ***** ***** *** ** * ** ** of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
* * * * ** * * ** *** * * * ** * ** * * * * * * ***** ** *** ** = %.2f\n",x1);
***** ** * ** * * ** **** *** **** ** * * * * ** * ** * **** ** * * ** * * ** * = %.2f",x2);
** *** *** ** ***** * ** * ****** *
* ** **** **** **** * * * ** *** * if(D==0)
*** ** ** * * ** *** * ** *** * * ** **
* **** **** **** * **** *** * ** **** * * ** * * ***** ** ** * * ** *** of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
* ** * ** *** *** * * ** ** ** * * ***** * **** *** * * ** ** ** * * ** *** = x2 = %.2f",x1);
** ** ** * *** ****** *** *** ***
*** * **** * * * **** * **
*** * * ** * ** * ** ** ****** ** ** * * * **
* **** * *** * * * * * * * *** ** * * ** **** *** * ** ** * * of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
** ** * * ** * ** ** * * ** ** * *** ** * ** * ** ***** * *** *** ** = * **** * ** * * *** **
*** * *** ** *** ** ** * *** * ** *** * * * * ** *** * * ** * ** * = * ** ********* * **
* *** ** * ** * ******* * ** * * **
********* ** * ** * * 0;
}
answered by (-258 points)
0 0
prog.c: In function 'main':
prog.c:13:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:19:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:24:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
0 like 0 dislike
Hidden content!
*** ** * ** **
* * **
int main()
{
* **** ** *** * ** *** * ** a,b,c,D = 0,x1 = 0,x2 = 0;
*** *** * * *** **** * ** * * *** ** ***** * * * * ** ***

* ** ** * * ** * **** * ** ***** of %.2fx^2 + %.2fx +%.2f = 0 ** * * **
**** ** * * * ** ** * * = (b*b-4*a*c);
* *** ***** * ** ** (D < 0)
* * ***** ** ****
** *** * * ** ** ** ** ** ** * complex and * * *** **
** * * * ** *** *** ** ** * * **** = * ** *** * ***** * ******* * *
* ** *** * * * * * ***** ** ** * * = * * ** ** *
*** * * * * ** **** * *
* ** * * **** * ** ** ** (D > 0)
**** ** * *** * ** * **
* **** * * * * * *** real and * ** * * * * *
* *** **** * *** ** * * * = ** *** * ** ** + sqrt(D))/(2*a));
**** ** * * *** ** ***** * *** ** = %.2f",(-b - sqrt(D))/(2*a));
* * ***** ** * * * ** *
** * * * ** * * * * (D == 0)
* * * * **** *** **
* *** * * ** ****** ** * ** ***** real and same\n");
* *** * * * *** * ** = x2 = %.2f",(-b + sqrt(D))/(2*a));
* * * ** * **** * ** **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
your output lack of 1 space at line 8 when print out "Roots of ..."
0 like 0 dislike
Hidden content!
* **** ** *
** ** * ** * **** **
int main()
{
** * * * * ** *** *** ******* a,b,c,D = 0,x1 = 0,x2 = 0;
** * ** *** * * * * *** * * * ** * ** ** ** * * **** ***

*** *** * ** * * *** * * ** * * * **** of %.2fx^2 + %.2fx +%.2f = 0 * *** *
* * * ** ** * = (b*b-4*a*c);
** * * ** ** * ****** * (D < 0)
* * *** *** *** *** ** * *
*** *** * *** * * * * complex and *** * ** ****
*** * * **** * * * **** * = * * *** * ** * *** *** ** * *
** * * * ** * ** **** * = * * *** *** *
* * *** * ** ******
* **** ********* * * (D > 0)
** * ** * * * *** ***
***** ** * **** ** * ** ** ** real and * ***** *
* **** * * * ** *** ** * * = ** * ****** + sqrt(D))/(2*a));
** * * ** ** ** * * *** *** * = %.2f",(-b - sqrt(D))/(2*a));
** * ******* * ** *
* * * * * *** * (D == 0)
*** ***** *** *
** *** ** *** *** *** * ** ** * real and same\n");
** ** * ** ***** * * ** ** *** * = x2 = %.2f",(-b + sqrt(D))/(2*a));
* ** ***** * * **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
******* * **
* * * **** ***
int main()
{
* **** * * ** * ** * * a,b,c,D = 0,x1 = 0,x2 = 0;
** * * ** ** **** * * * * * * **** ** ** * **

* *** * ** ** ** * * ** **** ** of %.2fx^2 + %.2fx +%.2f = 0 * * * * **
* * *** * ** ** ** = (b*b-4*a*c);
** ** *** ** * * * * ** (D < 0)
** ******* ********
* *** * * ** * * * ** * *** complex and * * * **
**** ** *** *** * ********* ******** = ** * * ** * ***
* *** ****** * * * ** ** * *** * * = * * * ** ** *** *** **
* ** * * *** * ** **
**** *** ** ** * * *** (D > 0)
* * * *** *** ** * **
* ***** * * *** * *** ****** real and * *** ******
*** ******** ** *** * ** ** * * ** = *** *** * + sqrt(D))/(2*a));
* * * ***** ** * * ** **** * ** = %.2f",(-b - sqrt(D))/(2*a));
*** ****** * **** ** *
* ** ** * * ** *** * * * * * (D == 0)
** ***** ** **** *****
** * * ** ** * ** ** * ** * **** * real and same\r\n");
** * ** *** *** * **** ****** *** ** = x2 = %.2f",(-b + sqrt(D))/(2*a));
* * *** *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* ****** ** ** *
* ** * * * * **
int main()
{
*** * * ***** ******* ** a,b,c,D = 0,x1 = 0,x2 = 0;
* * *** ** * * ** * * ** *** *** ** * ***** ** *** **** **

** * * *** * ** ** * **** ** *** of %.2fx^2 + %.2fx +%.2f = 0 * * *** *
** ** ** *** * * * = (b*b-4*a*c);
** * * * ** ** * ** (D < 0)
** ** ** ** ****** * * *
**** * * * **** * * ***** complex and * * * *
** ** * * * * * * ** ** * *** = * * *** ** ** * * ** * * *
** *** * * * ***** * * * * ** = * ** ** * *** * * *
* * * * * ** * *
* * * * * ** ** ** ** ** (D > 0)
* ** * ** * ** * ** * *
* * *** * * ** * ** * ******** real and * * ** * ** *
*** * * * ******** ** ***** = ** ** * + sqrt(D))/(2*a));
* * ** * * ** *** * * ** = %.2f",(-b - sqrt(D))/(2*a));
** * * ***** *** **** * *
** * * * ** * ** * * (D == 0)
* ** ******* ** * * * *****
*** ** ** ** * * * * ** ** * * **** real and same\r\n");
******* * ** * *** ** *** *** * * = x2 = %.2f",(-b + sqrt(D))/(2*a));
* * **** * * * *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
****** * *
* **** * * *
int main()
{
*** *** * ** ** a,b,c,D = 0,x1 = 0,x2 = 0;
* * **** ** * * ** * * * *** * * * ** * **** * ** ** * * *

*** * * *** * * **** * *** of %.2fx^2 + %.2fx +%.2f = 0 are",a,b,c);
* * * * *** * * = (b*b-4*a*c);
*** * * ** *** * **** * * = (-b + sqrt(D))/(2*a);
**** * *** * * * ** = (-b - sqrt(D))/(2*a);
*** **** * ** * * * (D < 0)
**** *** **** ******** *
**** * * * * * * * ** * * *** ** complex and ** *** * *
** * * * **** * **** ** * = * * * * * * * ** * ** ***** *
**** ****** **** ** ***** * * = ** ** * ** ** ******* *
*** * ** * *
***** * ** ** * ** ** * (D > 0)
* * * * ***** *** **
* ** ** * *** * * **** real and * ** * ** **
*** *** ** ** * * ** ** *** ** * * = * * * ** **
***** **** *** * ** ***** ** = %.2f",x2);
**** **** *** * * ****
** ***** **** ** * (D == 0)
*** *** * * * * ** *
*** * ***** * ** * ** * * * * * real and same\r\n");
** * * * * * **** * * ** * ** = x2 = %.2f",x1);
**** ** ******* ***
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.255.97
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users