0 like 1 dislike
9.5k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 9.5k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
**** * ** * ** ** **
* * ** * * ***

int main() {
* ** * ** *** * * * * *
* ** ** **** *** ** * ** **** * %f * ******* &a, &b, * *
* * ** ** * *** * * * * **
** ***** ** **** *** **** * {
* ** ** ** * ** * * ** ** *** * * * ** *** * * ****** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * * = * ** = ** * ** a, b, c, (-b)/(2*a), **** (-b)/(2*a), * ** ***
* **** * *** * * *
** * *** ***** * if(d==0) {
* ** * * * *** ** * * **** ** **** *** *** * ***
* * ****** ** * * ** *** *** * *** * *** * ***** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * ** ** a, b, c, x1);
** *** * * * *** ** ****
**** * * **** ** ***** * * ****** * {
* ** ** ** * * *** * ** ** * ** * *** *** *
** ** * **** * ********* **** * ******* *
**** ** ** ** *** * *** * ** ** * * * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and * = %.2f\nx2 = * * a, b, c, x1, x2);
* *** ** **** ****** * *
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * *** * ** * *
* ** *** *
#include ** * *** ****

int main()
{
* *** * ****** ***** * * **
* ** ***** **** ** * ** * ** * %f *** ** ** ** * ** * ** *
* * ** * ** * **** * **
** * * * * * ** **** **** * **
** *** * ** * * * * * * ******
* * * * * * * * **** ** * ** *
* * *** ** * **** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** *** ** = %.2f\nx2 = ***** * *** * * *
**** * * ** ** ***** if(D==0)
*** ***** **** * ** * ** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = *** * ****
*** * * ****** * *
** * ** * * * *** * * **** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * ** * * = ** * * * = * ** ** * ** ** * ** * ** ** * ****
* * * ******* ******** ** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** *
* *** * ** *** ** ***
* ** * * * ***

int main()
{
* ****** ** * * ** ** *** ****
** *** ***** ** * * ** * * *** %f ** * ** *** *** *** ** **
* * ***** ** * * *
***** * * ******** **** * *** ** *
* * ** * * ***** * ****
* * * ***** * ** *** *** *
* *** * * ** *** *** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and ** * * *** = %.2f\nx2 = ***** ***
** * * * ** **** ** * ** *
** ** ** *** ********* * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = *** ** * **
* * * * * * * ** *
** **** * * ** ** ** ** **** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * **** = %.2f + **** ** = %.2f - ** ** * * ********* ** * * ** * * ** ** **
* ** * ** *** ** ** * ** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
** * * * * ** * * ** a,b,c,x1,x2,D;
** ** ** * *** * *** * * * * %f *** * *** * ** * **
* * *** * **** * * *** *
* ** ** * ****** *** = (-b + sqrt(D))/(2*a);
* * *** * * ** ***** * = (-b - sqrt(D))/(2*a);
****** * ** * ** * * ** ** * *
** * * * * * * ** * *** * ***** ******* **
* ***** ** ****** * ** ** * **** ** * * ** * ** ** ***** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\n",a,b,c);
***** * * ** ** ** * * * * ** ***** ** ** * * * * * * **** *** * * * * ** = %.2f\n",x1);
*** * ***** ** ** *** * * *** * * *** * * * ** * * *** *** ***** *** * = %.2f",x2);
** *** * * ** *** ** **** * **
* * *** * * ** * ** * if(D==0)
** *** * * * * * *** ***** * * *** * ** * *
* * ** *** *** *** * * ****** * * * * *** * **** * * * ** *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * * ***** * ** * * * * * *** **** ** * * *** ** ** * * * * ** * * = x2 = %.2f",x1);
* **** * * ** * ***** ******** ***** * **
* * * * **** ** * ** *
* * **** *** **** * *** ** * *** * ** ** *
* * *** ** *** ** *** ** * ***** ***** * ** ** ** ** * **** * ** * ** * ****** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\n",a,b,c);
* *** * *** * * * * *** *** ** * ** **** * *** * *** **** **** * ** ** = ** * * * ********* * *
* * ** * ** ** * * * * * * * *** ***** * ***** * * ** * ** ** = ** * * ***** ***
* ****** ***** *** * * * * *** * * ** * ** **
* ** *** **** * * * * * * **** 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
* * *** ****** * * * **** a,b,c,x1,x2,D;
* * *** ** ** * * ** *** * ** * %f ***** ** * * ** ***
* ** * * * **** * *
* * * *** ***** = (-b + sqrt(D))/(2*a);
* * * ** * ** **** **** *** = (-b - sqrt(D))/(2*a);
* * * * ***** * ****** * ***
***** **** ** ** * * ** ** * *** **** *** ** *****
* ** * ** ** ** ** * ** * **** ***** * * * **** ** ** ** ** ** ** * of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
* ******** ** * ** ** * * * ** *** ** * * *** * ** * * * * * *** * * = %.2f\n",x1);
* ** **** * *** ** * * *** ** ** ******* * * ** ** * * * * * * * * = %.2f",x2);
** ** *** ***** * * *** * * ** * * * ** *** *** *
* * ** * * * ***** * * if(D==0)
* * * ** ** ** * ** * * * * ** ****
* * * ** * ** ***** *** * * ** ** *** * ** ** * * *** * *** * * * of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
**** * *** * ** *** *** * * * * * ** * *** ** * * * * * *** ******* **** ** = x2 = %.2f",x1);
*** ** * *** * * ** ** * ** **** **** ****
* ** ******* * ** * * ** *
* * *** ** ** ********* ****** **** ***
*** * *** *** ** ** * * *** * *** ** *** * * *** * *** *** ** * ***** ** * * of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
* * ** * ****** * * ** * ** *** * ** ***** ** * *** * * **** = ** ******* ***** * * * *
** * ** * *** * * * *** *** *** * *** *** * * * ** *** * *** ** ** *** * *** * * = * ** ** * ** ****** **
* * ** ** *** ** ** ** * *** * **
** *** * ** ** * 0;
}
answered by (-258 points)
0 0
prog.c: In function 'main':
prog.c:13:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:19:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:24:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
0 like 0 dislike
Hidden content!
* * ** ***
* * ***** **
int main()
{
** * * ** *** ** ** a,b,c,D = 0,x1 = 0,x2 = 0;
* * * * *** *** * * * ** *** * * *** ** ****

* *** * * * **** ** ** ****** of %.2fx^2 + %.2fx +%.2f = 0 *** *
* * ** * ** * * = (b*b-4*a*c);
** * ***** * ** * * (D < 0)
* ***** * * **** * *
*** ** * ** * * *** * * complex and ** * *** *
****** ***** * * * **** * ******* * = ** * * ** * * ** ***** **
** ** *** * * ** * * * *** ** * = * ** * ** * **
* **** * **** * * * *
* * * * ** ** * (D > 0)
** * * * * * ******* *
* * * ** * ** ** * * * ***** real and * ***** * *
* * ** ** * *** * * * * * * * = * * * **** * *** + sqrt(D))/(2*a));
** * * * * * * *** * * ** = %.2f",(-b - sqrt(D))/(2*a));
**** ** *** * * ***** * *
* * * * ***** * (D == 0)
**** ** ** * ** *** * * ***
***** ***** * * ** ** * *** * real and same\n");
* * ** * ** *** *** * **** ** = x2 = %.2f",(-b + sqrt(D))/(2*a));
* *** ***** *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
your output lack of 1 space at line 8 when print out "Roots of ..."
0 like 0 dislike
Hidden content!
** * * ** ***** **
* * * **** * ** **
int main()
{
**** *** * * * * *** a,b,c,D = 0,x1 = 0,x2 = 0;
* ** * * *** **** ** *** ** * **** * * *** **** * ** ******* * *

* **** * **** * *** * * ** ** * of %.2fx^2 + %.2fx +%.2f = 0 *** ** *
* * ** ** *** ** ** * * = (b*b-4*a*c);
** *** *** * ** * (D < 0)
* * ** * *** ** * *
**** ***** * * * * ** * ** complex and ** * ** * ** *
**** *** * ** ** ** ** * = * ** ** * * ** *** * * ** *
* ** ** ** ** *** **** * = * ** * * ***** *** * * *
** ** * * ****** **
******* * * ** ** * (D > 0)
** * *** * *
* ** * * * * * * * *** * * * real and * ***** *
**** * * ** * * *** ** ***** **** = * *** ** * * + sqrt(D))/(2*a));
* * *** *** ** * * * ** * ** * = %.2f",(-b - sqrt(D))/(2*a));
* ** * ***** *
* * * * ** **** (D == 0)
** ** **** * ** ** * * **
* * ***** * ** *** * * ** * **** real and same\n");
** * * *** * ** ****** = x2 = %.2f",(-b + sqrt(D))/(2*a));
*** ** * * * ** *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * * ** * *
** * ** ** *
int main()
{
* * ****** * ** ** a,b,c,D = 0,x1 = 0,x2 = 0;
* * ** *** ***** *** ** * * * * * *** **** *** * **

* ** ** ** * *** ** ** * * of %.2fx^2 + %.2fx +%.2f = 0 *** ** ****
* * *** * *** * = (b*b-4*a*c);
* *** * * * *** * (D < 0)
* * * ** ****** * **
* ** ***** **** *** * * ** complex and ** *** ** *
*** * * * ** * * *** ** * * = **** * * * * * *
* * * * * ** **** ** ** * ** = **** *** ** * *
* ** ** *** **
* ** * *** ***** * (D > 0)
* * * ** *** ** * ***
*** **** ** ****** * ** ***** ***** real and ** ** * ** **
** * * *** *** * * *** * = * * ** ** * ** + sqrt(D))/(2*a));
* ** *** ** ** ***** *** = %.2f",(-b - sqrt(D))/(2*a));
** ** ** * * **** * *
******** ** ** * ** ** ** * (D == 0)
* * * ** *** ** * * * *
******* * ** *** * * * * ** * * * real and same\r\n");
*** **** **** * ** * *** * * ** * * = x2 = %.2f",(-b + sqrt(D))/(2*a));
** ** ** **** **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** * * * * **
*** *** * * * ***
int main()
{
*** * * * ** ** * ** *** a,b,c,D = 0,x1 = 0,x2 = 0;
* ** * ****** * * * *** * **** ********** * * * * * ***

* ** ** **** ******** *** ** *** * of %.2fx^2 + %.2fx +%.2f = 0 ** * **
***** * ** *** ** ** *** = (b*b-4*a*c);
** * **** ** ** **** (D < 0)
** * * * * **
******* * ** *********** **** * * complex and * *** * *** *
** * ** * * * * ** * * * *** = ** * * *** *** * ** **
** **** **** ** ***** ** **** * = * ** * **** *** ** **** *
** ** **** * * *** **
* * ** * * * ** ** ** * (D > 0)
*** ** * * ** **** **** *
* * * *** *** * **** *** real and * * * * *
*** * ** * **** ******** * = *** * * *** ** + sqrt(D))/(2*a));
* *** *** *** ** * * * * ** * = %.2f",(-b - sqrt(D))/(2*a));
* ** ** * ** *
* ** ** * *** **** * (D == 0)
* * ** **** *
*** *** * ** *** ** ** *** * real and same\r\n");
* * *** * * *** ***** * * * = x2 = %.2f",(-b + sqrt(D))/(2*a));
* * ** **** ** *** * **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** ****** * ***
********* * ***
int main()
{
* * * ** ** * * * ** **** a,b,c,D = 0,x1 = 0,x2 = 0;
* **** * * * ** ** ** *** * * ** * * ** * ***** * *

*** *** * ** ** *** * * ******** of %.2fx^2 + %.2fx +%.2f = 0 are",a,b,c);
** ** * ******* * **** ** = (b*b-4*a*c);
*** **** * ** * * = (-b + sqrt(D))/(2*a);
* ** * * * **** = (-b - sqrt(D))/(2*a);
* * * * * *** * * * **** (D < 0)
*** * ** ** **** **** **
* * *** *** * ** ** * * * * * complex and * * **** ****
* * * *** * * ***** *** ** * * = **** * ** * * ** ** *
* ** **** ** * ** * * * *** ****** = ****** * * ***** * **
*** * **** ** *
** * ***** * ****** (D > 0)
*** ** ** **** *** *** *
* * * *** *** * * * real and * ** ** *****
* * * * * ** * *** **** = * *** ***
* ** * *** * *** *** ** ** = %.2f",x2);
**** * ***** * * * * * *
****** ***** * * * ***** * (D == 0)
* **** * **
* * * *** *** * *** ** ** real and same\r\n");
** ** ****** ** * * *** *** = x2 = %.2f",x1);
*** *** * * * * **** * **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.120
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users