0 like 1 dislike
17.5k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 17.5k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
* ** **
** * * ** * **

int main() {
* * * * * *** * * ** ** * ** **** **
* ** ** * * * ** * * ** **** * * * %f **** &a, &b, *
** * *** ** *** ** ***
* *** * ** * * ***** * * {
* * *** * * *** * ****** * * * * **** *** * * *** **** of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** ** = ** ***** = * * * * ** a, b, c, (-b)/(2*a), *** (-b)/(2*a), *** * *
* * * * *** ** * * *
* * * * *** ** * **** if(d==0) {
** ** ** * *** * *** ** **** ** * * ****** *****
* *** * ** ** * ** * * **** ** * ****** * *** *** *** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = *** * a, b, c, x1);
*** * ** *** * * ***** *
** ** * * ** * *** *** * {
* ** ** * * ** * * * *** * ****** ** *** * ** * * *
** ** * ** ***** ** * * *** ** * *** ** ****** *** *
* * * *** *** * ** * ** * * ** ***** * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and *** = %.2f\nx2 = ** * * a, b, c, x1, x2);
*** * **
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** ** * *
** ** * *** **
#include * * * * * **

int main()
{
*** * * *** * * *** * * ** * * *
** ** * *** * * **** * * ** * %f * ** * ****** ***** *
** * **** * * ** * *** *
* * * * * ****** * * * ***** ** *
****** * ** * *** * * ** * *** * *
* ** ****** * **** * * ** ** *
******* ****** * *** ****** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** ** * = %.2f\nx2 = * * ****
** *** * * *** * if(D==0)
* **** *** **** * *** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * *** ** *
* * * *** * * ** ***
* ** * * * ** ***** * ** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * ** * = * * * = * ** * **** ** ** *** * * *
*** * ** ******** ** * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** * * *
* * * *** ***
* * * *** *** * ** *

int main()
{
* * ** * ****** ** * * * * * *** **
*** * ** * * * *** * * %f ***** ***** ** * *****
** ** ** * * * * ***
** ** ** ** * * * * ** * * ***
* * * * * * * * ***** * *** * ** * *
** * * ** ****** **** *
* *** * * ** * * ****** * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * ***** = %.2f\nx2 = * * * *
*** * *** * ** ******** * *
* * *** * *** * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** **
**** ** ** *** ** ** *
* * ** * * *** * * *** ** ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * * = %.2f + **** = %.2f - * * ***** ** * * *** ** * ** * ** ** * **
** * *** ** ** ** **** * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
*** **** ** *** * * * ** a,b,c,x1,x2,D;
** ** * * *** * *** *** %f * *** *** * * ** ** * ***
* * * ** * *** * * ** **** * *
*** **** ***** ** ** * * * = (-b + sqrt(D))/(2*a);
* * * ** * *** = (-b - sqrt(D))/(2*a);
* * **** * * *** * * * *
* ** * *** ** * ** *** * ***** *** * ***** ***
* ***** * * * * * * ** ** * * *** * ** * ** * * ***** * ** ** **** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\n",a,b,c);
* * * ** * ** * * * **** *** ** * ** * * *** ** ** * ** *** * * * = %.2f\n",x1);
* * ** **** *** ** ** * * * * * * *** *** * ** * **** ** * ** ** ** = %.2f",x2);
* **** ** * ** ** *** *** * * * * ** ** *
* *** ** * ****** ** * ***** * * if(D==0)
* * **** ** * ***** **** * * * * * * ****
****** * ** *** * *** ***** * * *** **** ** ** * *** *** * * ** ****** ** **** **** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
**** * ** *** * * *** * * * ** * * * ******** ***** *** ******* *** * *** * ** = x2 = %.2f",x1);
*** ** *** * ** * *** ** * ** ** ***
** * * * ***** * * **
** ** * ** ** ** * * * * * ***** ** ** ** ** ** ***
* ** * ***** * * * ** * * * * *** ** *** * ** * **** ** ** * ** ***** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\n",a,b,c);
* ** * * * ** ** * * * * * * * ** * * * * ** * * * = * *** * ** ** ** *
* *** * * * ** * * ** * ** * ** * * * *** ** * * ** ** * *** = * ** **** ** * *
*** ** * * ** ** * * ***** *** * *
** ****** * ** * * *** * *** 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
** ** ** **** * *** a,b,c,x1,x2,D;
** ** * * ****** * * * ** * * %f * ** * *** ** * * * **
* * ** * * ****** ** *
* ** * * * * * * ** ** = (-b + sqrt(D))/(2*a);
* * ** * ********* * * * = (-b - sqrt(D))/(2*a);
* * **** * ** *** *********
** * ** * ** *** * * **** ****** * * * * *
*** * ** * * *** ** * ** ** * * ** ** * ** ***** **** * * of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
** * * ** * * * ** * *** * *** ***** * * * * *** * ** ** * ** * = %.2f\n",x1);
****** *** *** * ** * *** ****** *** * ** * ** * * * ** ** *** *** * ** = %.2f",x2);
* * * ** *** ******* * *** * * **
* * ***** ** *** * * * if(D==0)
** * ****** ** * *** * ** **** * **** * * ** * **
* *** ** *** * ****** * ******** * * *** * * * * ** ** * * ** ** * * of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
* ** * ** **** * * * *** * ** ** ** ** * *** * *** * * * ** = x2 = %.2f",x1);
** * * ** *** * * * ** ** ** * * *** *
* ** ** *** ** ** ****** **** *
** * * ** * * **** * *** ****** * * ** ** **
** * ** *** * * * * *** * ** ** * * * *** *** * ** ****** * **** * * * of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
* * * *** * ** ** ** ***** * * **** * * * * * * * ** ** **** ** *** = * * ** * ** ****** * *
***** **** ** *** * * * *** **** * *** *** ** * * *** * ** * ** * = ** ***** * ****
* * *** ** ** * * ** **** * * ** ** * **** *
* * * ** **** * * ** * *** 0;
}
answered by (-258 points)
0 0
prog.c: In function 'main':
prog.c:13:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:19:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:24:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
0 like 0 dislike
Hidden content!
* ***** * *** * ***
* **** **** * ** *
int main()
{
* * * **** *** *** * * a,b,c,D = 0,x1 = 0,x2 = 0;
**** ** * ** *** ** * *** ** ** ** **** *** * ** ****

* * ***** *** * ****** ** * ** * * of %.2fx^2 + %.2fx +%.2f = 0 * *** **** *
** ** ** * ******* * = (b*b-4*a*c);
* * * ******* ** * * (D < 0)
***** * * *** ** * * * *
** *** * ** * * * ** * **** * * complex and * * *** * * *
* * * * ** * * *** *** * * * = * **** ** *** * *
** * ** * * * * * * ** * *** * * = ** ** *** * * **
* ** * ** * * ** ** **
* * *** *** * ** * *** (D > 0)
* ** ** * * **** * * ****
** ***** * ** *** *** * * ***** real and *** * * *****
** * ** * *** * * * * * ** ** = * *** * ** + sqrt(D))/(2*a));
* ** ** * ******* **** * * * ** = %.2f",(-b - sqrt(D))/(2*a));
** * ** ** * * **
* **** * * * * *** **** (D == 0)
** ** * ** *** **** * ** *
**** ** ** * *** ** * ** ** real and same\n");
****** * * *** * ** ** * * ** **** * = x2 = %.2f",(-b + sqrt(D))/(2*a));
* *** * * * * * ***
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
your output lack of 1 space at line 8 when print out "Roots of ..."
0 like 0 dislike
Hidden content!
** * * * *** ** **
* * * * * **
int main()
{
* *** * * * ** * **** * a,b,c,D = 0,x1 = 0,x2 = 0;
* * *** ******* * * * ** *** * ** ** *** * * * ** * ** ** *

** * * ******* *** **** * *** * of %.2fx^2 + %.2fx +%.2f = 0 *** *** ** ****
** * * *** * ** ** = (b*b-4*a*c);
* * ** ** * *** (D < 0)
* * *** ****** ** * * *
* *** ** * * *** * ** * ** * complex and ***** ** ***
*** ** * * * * * ** *** ** = **** *** * * * * * *****
* * * * ** * * * ** ***** = ** * * *** **** ** * * *
** ** * * ** ***
* * * **** ** **** * (D > 0)
*** ***** * ** ** ** ** * *
** * *** * ** *** * *** ** ** *** real and * ********** *
* ** *** *** ** * ** * ** * **** = * *** + sqrt(D))/(2*a));
** * *** * * * * * * * * * = %.2f",(-b - sqrt(D))/(2*a));
*** * ** * ***** ** *
** *** * * * * * * ** ***** (D == 0)
*** * ** * **** ***
** **** * ** * **** * **** ** *** real and same\n");
* ** **** ** *** **** * ** * = x2 = %.2f",(-b + sqrt(D))/(2*a));
* * * * * * ** * * **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * ****** * *** *
* *** *** * ***
int main()
{
*** *** **** * ******* * a,b,c,D = 0,x1 = 0,x2 = 0;
*** * ** * ********* *** * * * * * *** ** * * * *

*** ** * ** * * *** * ** * * ** * of %.2fx^2 + %.2fx +%.2f = 0 * ** * * *
** * **** ** ** * ***** * = (b*b-4*a*c);
** **** * *** ** * (D < 0)
*** ** **** * * *** *
** * * * * ** * *** * complex and ** * * *
** *** * * **** ** ** * * * = * * ***** *** * * * ********
* * * ** **** * ** * * * ** * ** * ** = * * * * ** * ** *
* ** * **** ** **
* * **** * ** * ** * * (D > 0)
** * * ** * * * * * * ***
** * ** ** *** * * *** ** ** real and * ** * * ****
* * ** ** ** *** * * ** ***** * * = ** * *** + sqrt(D))/(2*a));
** ** * *** ***** ** * *** = %.2f",(-b - sqrt(D))/(2*a));
* * *** ** **** *** ****
* * ** * * * * * (D == 0)
***** ** *** *** * *** ** *
*** ** * **** * ** **** real and same\r\n");
* *** * ***** ** ** * * * ** * = x2 = %.2f",(-b + sqrt(D))/(2*a));
** * ** ** * * *** * ***
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
*** *** **
* * *** ** ***
int main()
{
*** **** ** * * * ***** * * a,b,c,D = 0,x1 = 0,x2 = 0;
* ** * * * *** * **** ** ** * *** *** * * * *** * *

* **** * ** **** **** **** ** *** of %.2fx^2 + %.2fx +%.2f = 0 * * ** *
* *** ** * * * * ** = (b*b-4*a*c);
** **** * ******* * * (D < 0)
* * **** * ** *** ****
** ** ** * ** ** ** * ** * *** complex and * ** * **
* ****** * ***** * ** ******* ** * = ** * *** ** * * * * **
**** * ** ** ** * * *** * * ** = * * *** ******** ** ** *
*** ** * * * ****
**** ** * ***** * (D > 0)
* * **** **** * ** **
** * ***** ***** * ** * * real and ******* * ****
* * **** * * * *** ** * = *** **** * * + sqrt(D))/(2*a));
*** * * ** * * * * *** * ** **** = %.2f",(-b - sqrt(D))/(2*a));
* ** * * ***** ****
* * ** *** *** (D == 0)
*** * *** ** **** * **
* * ********** * ** * real and same\r\n");
******* ***** **** * * ** * ** * ** ** = x2 = %.2f",(-b + sqrt(D))/(2*a));
*** * * * * *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
*** * ***** * **
* * * * ****
int main()
{
** **** * * ** ** a,b,c,D = 0,x1 = 0,x2 = 0;
****** **** * * ** *** * ** ** ** * * **** *** **** *

*** **** * * ** * * * ************ * of %.2fx^2 + %.2fx +%.2f = 0 are",a,b,c);
* ** *** *** * = (b*b-4*a*c);
* ** **** * * ** * * = (-b + sqrt(D))/(2*a);
* * * ** *** ** ** *** ** * = (-b - sqrt(D))/(2*a);
** ** * **** * *** (D < 0)
* ** **** * ** ****
* * **** ** *** ** * ** * ** *** * complex and * *** * ** *
* * *** * * ** ** * = * ** * ** * * * *** *
*** **** *** **** ** * * *** ******* = **** * * ** * * ** *
** **** ** ** * ********
** ** ** * *** ** * * (D > 0)
**** **** * ** * ***
** * ******** ** * * * ******* * ** real and * * * **** ** * *
* **** *** ** **** ** ** *** = * * ***** * **
* **** *** * * ***** ** *** ** ** ** = %.2f",x2);
* * * * *
* ** * ** ** * ** *** * * (D == 0)
** ** ** * * ** **** ***
* * * * *** * * * * * * real and same\r\n");
* ***** * ** * ** * * * *** ** * = x2 = %.2f",x1);
** *** * ****
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.109
©2016-2026

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users