0 like 1 dislike
19.7k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 19.7k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
*** ** * ** **
* * * ** * * * ****

int main() {
* ** ******* *** **** * ** * ****
* * * * ** * * * * *** %f ** * ***** &a, &b, ** *
** * ** * * ** * ** *** *** ** ***
* * * * ** * * ** * ** * * **** ** {
***** ** ** **** * * * ** * **** * ****** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * * = * * * ** = ** ****** a, b, c, (-b)/(2*a), * * * ** (-b)/(2*a), ** ****
* * ***** * ***** ** **
*** * * *** * * ** ** if(d==0) {
* ** * ** ** ****** ** ** * * * * **** ****** **
* ** *** ** ** * * * * * *** ** ** * ** ** **** * **** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** * ** a, b, c, x1);
**** *** * * * ** * * ***
* * *** **** *** * * * * * **** * {
** *** *** **** ***** ****** *** ** * * *** *** * * * * ** * ** ***
* * * * * ********* ** * **** ** * * * ** * * * * ** * *
* * * ** *** * * *** ** ** *** ** * ** * * ** * * **** of %.2fx^2 + %.2fx + %.2f = 0 are real and * *** * = %.2f\nx2 = *** ** a, b, c, x1, x2);
** * ** *** * *
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * * ** *
* * * * **** *
#include * *** **

int main()
{
* * * ** * * ** *
** * ** ** ** * ** * *** ** %f **** * ***** *
* * *** *** * * **** **
** * * *** * * * * *
** ** *** ** *** * * ****
** * **** * * *** *** *
* *** *** * *** ** * ** * ** ** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and * * * * = %.2f\nx2 = * ** **** *** ****
* * ***** * * *** *** * ** if(D==0)
***** ** * * ** * ******* * ** * *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * ** ***
*** * * * * * * *
******** * ** ** * * * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** = * * * = **** * ** ** *** ** ** ** *** * * ** **
** * ** *** * * ** ** * * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** * ** ***
* * * ** *** *
* **** * * * * **

int main()
{
** * ** * ** **** * ** ** **** * * **
* ** ** ** *** ** * ** *** %f ** * * ** * * ** ** * * * **
* ***** * *** ** **** * * *
** * ** * * * ** * ** ***
* ***** *** * ** *****
* * * ******* ** * ** ** * **
*** ** *** **** * ****** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * * = %.2f\nx2 = * **** * * * * *
** ***** * ** **** * *** * ** ** *** *
** * * * *** ** ** *** *** * ** ***** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = **** ** ***
*** ** * ** * ** *** *
* ** *** ** *** * **** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and *** ** = %.2f + * * = %.2f - * ** ** ** * * * * *** *** * * **
* ** **** * * * ** *** * *** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
* *** * ** * * * * * * a,b,c,x1,x2,D;
* * * **** *** ***** * ** ** * %f **** **** *** ** ** *
* ** * * * **** ** * *** * * *
*** * * * **** ** = (-b + sqrt(D))/(2*a);
* * * * * * **** = (-b - sqrt(D))/(2*a);
**** ** * * *** **** ** ** *
* * * * ** * * *** * * * ** ** * ** **
** * ***** *** * * * ** * ** **** ***** ***** ******** ** * * * * *** * ** * * **** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\n",a,b,c);
* * * ** * ***** ** * *** **** ** *** * ** * * * ****** ** *** ** * *** = %.2f\n",x1);
* ** ****** * * * * * ****** ****** * *** *** * * ****** * *** * * ***** ** = %.2f",x2);
*** ** **** *** * * * ** * ** ***** * * *
* * * * *** ** * if(D==0)
* *** * *** ** **** ** * ** *********** *
** ** * ** * ** * ** * ** * * **** * ** ** * ** ** *** * * * * * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** * * * * * *** ** ***** * * * * ***** * *** * *** ** * * * * *** *** = x2 = %.2f",x1);
* *** * * * * ** * * ** ** ** ** *** * **
** ** **** * ** ** ***
**** *** * *** *** ***** * ** * ****
* * ** * * ** *** ** *** ** ** * * *** **** * *** *** ** * *** ** ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\n",a,b,c);
* ** ***** ** * *** * * *** * * * **** * ** * * ** *** * ** ***** = ** **** ** **** *
** ***** ** * *** * * *** * * ***** *** * * ** ** * ***** * * *** ***** * * = ** ** ** * **** * ***
* **** *** * ** * ** * * * ** ** ** * ** ** ** ***
* ** ** ** ** ** * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
* * *** ** ** ** * ** ***** a,b,c,x1,x2,D;
*** **** ** **** * * * *** * * * * %f * * * ** * *** * *
* * * **** ** ** *** * * * *
* ** * * ** **** * ** * = (-b + sqrt(D))/(2*a);
** ** * * * * **** **** ** = (-b - sqrt(D))/(2*a);
* ** ** ** * *** * ** * ** ****
** *** ****** ** * *** * *** * * ****
** ** ** ** ** *** * ** ** * ******** * **** ** * * * * * ** * ** ** * *** * *** of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
* * * * ** **** ** *** ** * * ** * * * **** * *** *** ** * ***** = %.2f\n",x1);
*** * * * *** * ********** * * * **** **** ** * ** ** ***** *** * * *** = %.2f",x2);
* * * * *** * * * * * * * ** * *
* ** ****** * ** ** * * if(D==0)
* *** * ***** *** * * * * * * ****
**** ** ****** *** ** ** * ***** ******* ** ******* * ** * *** **** ** * ** of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
**** ********* * * ** ** ** ** *** * * ** *** * * **** *** = x2 = %.2f",x1);
* * * **** ** * * *** * ** * * **** * *****
*** **** * **** **** *
** *** * ** ***** * * *** *** ** *** *** * ***
** *** ** ****** *** * ** ** *** *** ******** * * * * * **** * ** * ** * * *** of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
* *** ** * ** ** ** * ** *** ****** *** * * * * ** *** *** ** * * * * = * * ** *** ** * ** *
** * * ** * **** * * *** * *** ** ** * * * *** ***** ** = * * * ** ****** * ***
*** * * ** * * *** ** * *** * ** **
* ** ** *** * ** ** 0;
}
answered by (-258 points)
0 0
prog.c: In function 'main':
prog.c:13:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:19:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:24:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
0 like 0 dislike
Hidden content!
* * * * ******
* * ** * ** * **
int main()
{
* * * * ******** * * ** a,b,c,D = 0,x1 = 0,x2 = 0;
** ** ***** *** * * * *** * *** * *** * *** *** *** * * *

** ** ** **** * ** **** * * of %.2fx^2 + %.2fx +%.2f = 0 * * ** * ******
* **** * ** ** * ** = (b*b-4*a*c);
* * * * * *** ***** * (D < 0)
*** *** * ** * ***** * **
* ** * * * *** ** * * * * ** complex and **** * *****
* ** * * **** * * ***** * = * * * * * ** **
* * *** * * * *** ******* * * ***** * ** = * ** * ** *** * *
** * ** *** *** ** * **
* * *** *** *** * * ** (D > 0)
** * *** * *** * * ******
** * ****** *** * * * * real and * ** ** *
** ** ** * * * **** * * * * = * **** + sqrt(D))/(2*a));
** * * *** *** ***** **** ** *** * * = %.2f",(-b - sqrt(D))/(2*a));
* * * * * ** ** ******* **
****** ** * ***** (D == 0)
* * ** ** * * * **** *
* ** **** * * * * ** *** ** * real and same\n");
* ****** * ****** * *** * = x2 = %.2f",(-b + sqrt(D))/(2*a));
** * * * ** * * **** **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
your output lack of 1 space at line 8 when print out "Roots of ..."
0 like 0 dislike
Hidden content!
** * ** ** ** *
** *** * *** * **
int main()
{
* * * ****** ** * * a,b,c,D = 0,x1 = 0,x2 = 0;
** **** ******** * * * * * * * * *** * * * * ** * ** **

* ** * ** ** * **** *** ** **** * * of %.2fx^2 + %.2fx +%.2f = 0 * **** *** * **
* ** ** * ** * *** = (b*b-4*a*c);
****** * *** ** * * ** (D < 0)
* * **** *** * ***
*** * ** ** ** ** * **** * * * * ** * complex and *** * ** ***
*** *** * **** * **** * * * ** = ** ** * **** * *** * * * ** *
* * ** * *** * ** **** * = ** ***** * * * *** * *
**** * *** ** ** * * *
** * ***** ******* (D > 0)
* *** * *** ** *
* ** ** * ** * * * * * * ** real and ** * * *
** * ** ** * ** * *** ** * = *** ** ** * + sqrt(D))/(2*a));
*** * *** * * * ** * * *** * * * * = %.2f",(-b - sqrt(D))/(2*a));
******* **** * **** ****
**** *** *** * * (D == 0)
** * ** ** * * ** * *
* ** * * * ** * * * * * **** real and same\n");
* ** * ** ** * * ** * ** ** * = x2 = %.2f",(-b + sqrt(D))/(2*a));
** *** *** **** * ** *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * * ** ** **
* **** * * **
int main()
{
*** **** ** * ** * * * * a,b,c,D = 0,x1 = 0,x2 = 0;
* * * **** * * ** **** **** ** ****** * *** * ** * *

* ***** * * *** *** *** * * * * of %.2fx^2 + %.2fx +%.2f = 0 * ** * *
* * * * * * * ** ** * = (b*b-4*a*c);
* **** *** * * * (D < 0)
* ** ** * * *******
*** *** * ** ** **** *** complex and ** ** *****
*** ***** ** ** * ** ***** * = * ** ** * * * * * * *
* * ** * ** * * * ** ** * ******* = * * ** * ** * * * * ** **
** ** * ** *** ***
* * ****** *** *** * (D > 0)
* *** * ** * ** **** ***** *
** ** * * ** * **** * * * * * ** ** real and * *** ** ** * *
** ** ** ****** ** ** ** * * = ** ** ** + sqrt(D))/(2*a));
* ** * *** * ** * * **** * * = %.2f",(-b - sqrt(D))/(2*a));
**** ** ** * * ** ** ** **
* ** * *** ** * ** (D == 0)
* * * * *** * * *
** * * * * *** * *** * ** * ** real and same\r\n");
* * **** * ****** *** = x2 = %.2f",(-b + sqrt(D))/(2*a));
*** * * ** * *** *** ***
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
*** **** ** * ***
* *** ***** * * **
int main()
{
* ** * * * * *** * **** * *** a,b,c,D = 0,x1 = 0,x2 = 0;
* *** * *** ***** * * ** * *** ** *** ** *** * *** * * * **

** *** * * ** * * * *** * ** *** of %.2fx^2 + %.2fx +%.2f = 0 ** * **
* * ***** *** ****** * ** = (b*b-4*a*c);
* ** * * * * ** ****** * * (D < 0)
* * * * * * * * * *
*** * * *** **** ** **** * * * * complex and * * *****
** ***** ** * ** *** *** ** * * = ***** **** * * **** ** ** ****
**** * ****** * * ** ** ** = *** * **** ** * * *****
** * * * * * * * * *
* * * * * * **** *** (D > 0)
* * ** * * * * **
* ** * * ** * *** ** * ***** ** real and * *** * * **
***** * ***** ** **** ** * * = ** ***** * * + sqrt(D))/(2*a));
**** * **** ** ********* * * * = %.2f",(-b - sqrt(D))/(2*a));
* *** * *** * * * * *
** * * *** * ** * (D == 0)
** * * * *** *
* * * * ***** * ** **** real and same\r\n");
***** * * ** ** ** * ** *** = x2 = %.2f",(-b + sqrt(D))/(2*a));
***** * ** *** **** ** ** *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** * ** ** ****
* ** *******
int main()
{
* ** * ** **** *** ** * a,b,c,D = 0,x1 = 0,x2 = 0;
* * * *** * * * * * * * * * * * ******* * **** * *

**** ** * * *** * *** ** *** *** * ** * of %.2fx^2 + %.2fx +%.2f = 0 are",a,b,c);
** *** * * * ** *** = (b*b-4*a*c);
** ** *** * * * * ** = (-b + sqrt(D))/(2*a);
** * * ** * * ** * * * * = (-b - sqrt(D))/(2*a);
* * * * * * * **** ** (D < 0)
*** **** * *** *
* * ** *** * ** * ** ** ** complex and ** * * *** **
* * * * * ** ** ** ** * ** * = **** * ** *** *** *** ** *** **
* * ** * * * ** * * *** * = * * ** * * * ***** *
* ** *** * * * *** * ****
*** * ** ** *** ** * (D > 0)
* ** * * *** ** * * **
* * ** ** * * **** ** ** *** real and ** * * * **
** * ** ** * *** ** * * * * = ****** ** **
* *** ** * **** * * * * = %.2f",x2);
* **** ** *** * *
* ** *** ** ** *** ** (D == 0)
**** * * * *** ** * *
* * * *** * ** ** **** * real and same\r\n");
*** ** * **** * * ** * * *** = x2 = %.2f",x1);
** ** * ****** *** *****
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.108
©2016-2026

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users