0 like 1 dislike
6.6k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 6.6k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
* * ** ** * *
* * **** * * * *

int main() {
* * * **** ** ***** * * * * *
* ******** * * *** * * **** %f * * *** * * &a, &b, **
** * *** ** * ** ** * * * *** *
* ** **** * ** * * {
*** ** * ******* **** * ******* * * * ** * ** * * **** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ***** = **** * = * * ***** a, b, c, (-b)/(2*a), * *** (-b)/(2*a), **** * *
** ***** *** ** *
* * * ***** *** ** * ** *** if(d==0) {
* ** ** * * ***** ** * *** * * *** * * * ****
* * * *** * ** ** * * *** * * **** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = *** a, b, c, x1);
* * * *** *** ** ** *
* * ******** * * ** * * * * {
* ** ** * *** *** * ** *** *** *** *** * * * *
*** * ******** * * ** **** * * ** ***** * * ** * * *** * * *
**** **** ** * ** * *** *** *** *** * *** ***** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** * ** = %.2f\nx2 = * * * * a, b, c, x1, x2);
** * * * ** * * ***
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * * * *
** **** * * ***
#include ** * **** **

int main()
{
*** ** * **** *** * * * **** * *
* * *** ** * ***** * *** * %f * * ** ** * * * ** * *
*** ********* ** * *** *
**** * * * **** * ** ** * * *** *** *
*** *** ** * * * * ** ****** ******
*** * **** * * * ***** ***
**** ** ** ******* **** * * ***** * *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and * = %.2f\nx2 = * * * * ** *
* *** **** * * * if(D==0)
* **** ** **** * ****** * **** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = **** * * *
* * * *** ***
** ** * ** *** **** * ** * * ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * * * * = * * * = **** * * ** * *** * *** ***** ** * **** *
**** * *** * * * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** *** ** **
* * * * *** * *
* ** * * * *****

int main()
{
* * * ********* ** * **
******* ** ** ** ** * ** ** ** %f ** ***** ***** * ***** *
** ** * ******* * * *** ** * *
** * *** * ** * * * *
* * **** * *** ***** ****** * ** *
** * ** *** * * * **** *** ***
*** *** *** * *** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and **** ** = %.2f\nx2 = ** * ** ****
***** **** ***** ** * ** * ***
* ** * ** ***** * **** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * *** * ***
*********** * * * * ** **
** * ** * ******** * ******** * ******* of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * *** = %.2f + * = %.2f - * * * * * * * * * ** ****** ** * *
* * * * ** * * *** ** ** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
** ** *** *** * ** ** ** * a,b,c,x1,x2,D;
** *** * ** **** * ** * ** %f *** ****** ** * ** **
* * **** * * * * * *
* * ******* ** *** * * * * ** = (-b + sqrt(D))/(2*a);
* * ** ** *** ** * = (-b - sqrt(D))/(2*a);
* ** **** * * *** ** * ***
**** * *** * ** * ** ** ** ** ** ** ** *** *
****** *** ******* * **** * ** ** * ** * * ** *** **** * * ** ** * * * * *** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\n",a,b,c);
** * * ******** ** * * *** ** * *** * * * ** * * ** ** * * ** **** ** ** * **** * * * = %.2f\n",x1);
**** * * ** ** ** *** ** * * ** *** * * * ** **** ******* ***** * ** = %.2f",x2);
** * * * ***** * * ** *** ** **** ** * *
** * * *** ** * ** *** if(D==0)
* **** * * * * ****** ** * * ** * ** **
* * * ** ********** *** ** ** *** *** * ** * ***** **** * * ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * ** * *** *** ** * ****** ** ****** **** * ** *** * ** * * * ***** = x2 = %.2f",x1);
* * *** *** **** * ** * * * * *** * * ***
** * * ******** * **
* * * * * ** * **** ** * **** ** * *** ***
* **** ** * * * ** *** ** ** * ** * * * ** ** *** * **** **** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\n",a,b,c);
* * ***** ** *** * * *** *** ** * * * * ** ** * ** *** = * * **** * ** *** ** *** *
* * * * * *** * ** * *** * ** * * ******* ** ** *** * * ** **** *** * *** = * * ** * ***
******* * * ** *** * ** ** * *** * ** * ***
* * ** * ** *** ** ** 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
** * ** **** * ** * * * * * a,b,c,x1,x2,D;
* ************* * ** * * * ** *** %f ** ** * ** * *****
**** *** * ** * * **** * *** *
* *** * ** *** ** ** = (-b + sqrt(D))/(2*a);
** *** * * ** * *** = (-b - sqrt(D))/(2*a);
** * * * ***** ** ** *** *
*** * * ********** ** * ** *** * ** *
* * ** * ******** * * * * * * ** *** *********** *** * * * * ***** *** * **** of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
* * ** * * * **** *** * * ** ** ** * ***** ** ******** ** *** * = %.2f\n",x1);
** * **** * * * * *** *** *** * * * * ** * * * ** *** * * ** * ***** = %.2f",x2);
* * ** ** ** * * ** ** * * *** ** * * *
** **** *** *** ***** * if(D==0)
* ** * * * *** ****** * * ****** ** ***** ** *
* * * * ******** * * **** *** * * ** *** **** ** * *** * * * * of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
****** *** * * * * *** ***** * ** ** * *** ******* ********* **** *** = x2 = %.2f",x1);
* ** ** *** * * * * * * * ** * * * * *
* * ** * **** ** * **
** * ** * ** ** * * * * * ** *** ** ** *
* *** *** ** * * ** ** * * * *** * **** *** ** ** ** * * * * * * * ** of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
* * * **** *** *** **** * ** ******* ** ** ***** ** *** *** ** * **** = * * *** **** **** ***
** ****** * * * *** ********** * * * * ** * ** * **** *** * * * ** * = ****** ** * ** **** *
* * * * ** * *** ***** * * ** ** ** ** ****
******* ** * ** * * ** ** 0;
}
answered by (-258 points)
0 0
prog.c: In function 'main':
prog.c:13:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:19:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:24:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
0 like 0 dislike
Hidden content!
*** ** * ** **** * *
** ****** ** * **
int main()
{
* **** * ** * ** ** * * a,b,c,D = 0,x1 = 0,x2 = 0;
****** ****** * * * * * **** ** ****** ** * * ** * * ***** **** * **

*** ** ** * * * * * * * of %.2fx^2 + %.2fx +%.2f = 0 * ** ****** *
** *** * ** * * ** * = (b*b-4*a*c);
* ** * * *** * * * * * ** (D < 0)
* ** * ***** ** * * * *
* * ** ******* ** *** * complex and * * *** *****
* ** * * * * ** ** * *** * ** = ****** * * * * * *** ***
** * *** * ** ******* = *** * * * ** * ** *
** * * * **** * *** *
** * ** *** * * * * (D > 0)
* * **** ***** ** ******
** * ******* ** **** ***** ** ** ** real and * * ** * * **
*** ** *** ** * * * * * ****** *** = ***** * + sqrt(D))/(2*a));
* *** ** ** ** * ** * *** = %.2f",(-b - sqrt(D))/(2*a));
* ** **** * * *
* **** * * * * * * *** * * (D == 0)
***** *** * * * * * *
******* * ** *** * **** * real and same\n");
** *** * **** * * * * * ** = x2 = %.2f",(-b + sqrt(D))/(2*a));
***** * **** * * **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
your output lack of 1 space at line 8 when print out "Roots of ..."
0 like 0 dislike
Hidden content!
** *** ** * * *
* ** *
int main()
{
* *** ** * * **** * * * a,b,c,D = 0,x1 = 0,x2 = 0;
* * * ** ** *** * ** * * *** *** **** ** * * **

* * * * * * ** * ** ** ** of %.2fx^2 + %.2fx +%.2f = 0 ** ** *
* *** *** * *** * ** = (b*b-4*a*c);
* ** ** * * * * ** ** * (D < 0)
* ** * ** * ** * * *** *
* ** ******** * ** ** ** * ** ** * complex and * * *** *
** ** ** * * * ** ** = ***** *** * *** ** *
**** ** ** **** * * * * * ** = * * * ** * *
* ** ** **** ** * *****
* *** * * * * *** * *** *** (D > 0)
** * *** ** * ** * ** *
* ******* *** * * * ** ** * **** real and *** * **
* * * *** ***** * * ** * *** = ** * ** *** + sqrt(D))/(2*a));
** ** ** ** * ** **** ** ** * ** = %.2f",(-b - sqrt(D))/(2*a));
***** **** * * * * * **
* * * ** ***** **** (D == 0)
** **** * *** * * *
* * * * * * *** * *** * * real and same\n");
* **** ** * ** * ****** ** ** = x2 = %.2f",(-b + sqrt(D))/(2*a));
* * * *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
*** ** * *** *
* * * * ****** ****
int main()
{
**** ***** * ***** * * a,b,c,D = 0,x1 = 0,x2 = 0;
* **** * ** ******* * * ** ** * ** *** * * ** * *** *** *

* * * * *** * * **** ** * * * of %.2fx^2 + %.2fx +%.2f = 0 ***** **
* * * * * ** * * * = (b*b-4*a*c);
* ** *** * ** ** * * (D < 0)
* * * * *** **** * * **
* ** * *** ** *** * *** * * complex and ******* * * *
* ** *** * * **** *** ** ** * * ** = ******** *** * ****** *
* * * * * ** *** ** ** * * * * * = * ** * *** ** ** ***
* *** * * * ** **
** ** * ** ** ***** (D > 0)
**** ** ** * ** *
*** * ** * * * * ** real and * *** ** ** *
**** ** *** ** ** ** ** ** = * ** * * + sqrt(D))/(2*a));
* * *** * *** *** ** * * * ** ** = %.2f",(-b - sqrt(D))/(2*a));
** ** * * * *
* * * * ** ** ** * **** (D == 0)
** * *** * * * * * ** ** *
* * * *** ** ** ** * * * * * real and same\r\n");
** *** * ******* ** ** ** * ** * = x2 = %.2f",(-b + sqrt(D))/(2*a));
* * **** * * *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * * * * **** *
* * * * * * **
int main()
{
* ** * ** * **** * ** *** a,b,c,D = 0,x1 = 0,x2 = 0;
* * * * * * * **** * *** ** * ** ** * * * * ** ** **** ** *

***** * ** * * ** * *** * * of %.2fx^2 + %.2fx +%.2f = 0 * * * ** *
**** *** * * = (b*b-4*a*c);
* * ***** * * * * *** (D < 0)
* ** ** * ** ***
** ***** * * * *** * * * * complex and * *** *
* * * * * * * ***** ** * ** * = * * * *** ** ** ** * * * *
***** *** ******* *** ** *** ** * * = * * * ** * * * * ****
**** ****** * * *
* * *** * *** ** * ** (D > 0)
**** ** * ** * * *
* * * ** ** *** * * *** *** * real and *** ** **
*** * ** * * * * **** = ** * * ****** ** + sqrt(D))/(2*a));
* * * * ** ** ** ** *** * = %.2f",(-b - sqrt(D))/(2*a));
** **** * *
* * ****** * ** * * ****** (D == 0)
* *** *** * * *** ** *
* ** * * * * * ****** *** * * real and same\r\n");
** ** ** ***** * ** ** *** = x2 = %.2f",(-b + sqrt(D))/(2*a));
** * *** ** ** *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** *** * ** *
** * ** ** *** ** *
int main()
{
* ** * ** * * *** * *** a,b,c,D = 0,x1 = 0,x2 = 0;
* * ** * * * * * * ** * * * * * * * * * ****** *

* * **** ** *** ** * * * ** ** * of %.2fx^2 + %.2fx +%.2f = 0 are",a,b,c);
** ** ** ** ** ***** = (b*b-4*a*c);
* * * ***** *** * ** *** = (-b + sqrt(D))/(2*a);
* ** ** ** * * **** * = (-b - sqrt(D))/(2*a);
* * ** * * ** * * (D < 0)
* * * ** ** **** **
** * ** * ****** * ** **** * complex and * * * * * * * * *
* ********* * * * * *** * ** * *** = * *** * * * * * ** * **
** * *** **** ******* * ** ** = ** ** ** * * * * * *
* ****** * * ** ** *
*** * ** ***** * * * (D > 0)
* ** ** *** *
******* * *** * * ** ** * real and * *
** *** ** * ** * ** * = ** *** * * *
*** * * * * **** **** ** *** ** * = %.2f",x2);
** * * ** ** * * *
** *** * *** ** * (D == 0)
** ** * **** ** * * * *
** * *** * **** *** *** **** * * real and same\r\n");
*** ** * * * * ** ** * *** ** ** = x2 = %.2f",x1);
** **** ** ** *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.130.185
©2016-2025

No related questions found

12,783 questions
183,443 answers
172,219 comments
4,824 users