0 like 1 dislike
9.5k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 9.5k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
* * ** * * ** *******
** ** ** *

int main() {
*** * ** ** *** * * ** ** * ** ****
**** * *** ***** * *** ** ** * %f * * ** &a, &b, * * * *
** ** * * ** ** * ** *** * **
* ******* * *** * * * * *** ** {
** * * ** * * * * *** * * ** *** ** * *** * * * *** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** * = ** ** = * *** ** *** *** a, b, c, (-b)/(2*a), ****** * ** (-b)/(2*a), ** **** **
*** ** * * *** ******
* * ** ****** ***** ** if(d==0) {
* * *** * ** ** ** * **** ** *** * * ** * *******
**** ** ** *** ******* ** **** ***** ***** * ** ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * ** * * a, b, c, x1);
* * ** ** * * * ***
** ***** * * **** * * * * {
**** * ** ** *** * *** ***** * ** ***** * ** * * *
*** * **** **** ** * ** * * * * ** * ** * * *** * ** * **
* *** ***** * * * * * * ** * * * * * *** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and * **** = %.2f\nx2 = * * *** a, b, c, x1, x2);
* ** * * * * ** ** **
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** **** ** * **
* * * ** * *
#include * * ***

int main()
{
* * ** **** ******* * * * ** **
* ** * * * * * * * ***** %f * ** * ** * * * **
* *** * * **** ** ****
****** * ****** * * * *
*** * * ** ** *** ***** * ** *
** * * *** ** * * * * ** ***
* *** * * *** *** * * *** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and ** ** = %.2f\nx2 = * * * **** *
* *** * * * * * if(D==0)
**** * *** * ******* **** *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** *** *
** * ***** **** *** *
* * ***** * * ** ** * *** *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * * = ** ** = * ** ** * **** ***** * * * * * * * ** *
** * ** *** ** **** * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** *** *
* * * ******** * *
**** * *** * ** ***

int main()
{
** * * * * *** * * ** **** ** ****** **
*** * * ** * ** * * *** ** * * * ** %f *** * **** ****** * **** *
* * * * ****** ****
** * *** ** * * *** * ** *** ** *
* * * ** * * ** * * * * *
* ** * * * ** *** ** * * *
**** ** * * **** * * * * * **** * ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** * ** = %.2f\nx2 = * *** ** ** *
* * * *** * * ** * * ** *
* * * * * ****** * ****** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * *** * *
* * * ***** * *********** *
* ** **** ** * ** * * * ** **** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** * * = %.2f + * ** = %.2f - * ** * * ** *** * * * * *** * **** *
* * ** **** * *** *** ** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
** ** * * ** * * a,b,c,x1,x2,D;
** ***** * ** ** * ** * ** ** %f * * ** * * * * * ** *
* * ***** * * * *
* * ** * * * * ** ** ***** = (-b + sqrt(D))/(2*a);
* ** ** * * ** ** * * = (-b - sqrt(D))/(2*a);
**** * * *** * * ****
** ** *** * **** * * ** *** * * *** ** *
* *** ** * * ****** ******** ** **** ****** *** ***** ***** **** ** ** * ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\n",a,b,c);
** ** ** ** ** * ** * * ** ****** ** * * ** * ******* * * ** ** * * *** = %.2f\n",x1);
**** *** * * ** * * * * * *** ** * *** * *** * * *** * * * *** = %.2f",x2);
**** ***** * * * *** * ** * * ** ***** *
** * **** **** * ** * *** if(D==0)
******* * *** *** * *** * ********* * **
** * * * ** ** *** ** ** * * *** * * *** ** * ** ** * * * * ** * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * **** ******* * ** * ** **** ******** * ** *** *** * * * * * * = x2 = %.2f",x1);
** ** ** * * ** *** **** *** * * * *** * *
** ** * ***** * * * **
* ** ** * * * *** **** * * * * * ** * *
***** * * *** * * * ********* ** ** * ****** *** *** * * * ****** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\n",a,b,c);
** * ** **** * * **** * * **** *** * *** * **** * *** *** * * * * *** ** * ** = * * ** * * * *** * ****
* ** ***** * **** *** * ** * * *** * * * * *** * **** ** * * ** * * = * * ** ** * * ** *** *
** ** *** ** ***** ****** * **** * * ** ** ***
* ** *** ** *** * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
* *** ** ** **** ** a,b,c,x1,x2,D;
***** * * ** * * ** * ** * %f * * * **** * * * * *** **
*** * ** * *** ** *** ***
* * * *** * * ** *** = (-b + sqrt(D))/(2*a);
*** ** * ** * * *** = (-b - sqrt(D))/(2*a);
** ** * ** ****** **
* ******* * * * ** ***** * * * * **
**** **** * * * ** * ** ******* * * * ** * * * ** * * ** * ** ***** *** * * of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
* ** *** * * *** **** *** * *** ** * ** *** * **** ** *** ** * = %.2f\n",x1);
* ** ** * * ** *** * * ** * * *** * * * ** * ** ** * *** * * * * * *** = %.2f",x2);
* * * * * ** ** ** * *** ** ** ** ** ** * **
* * * * * ** * **** ** * if(D==0)
** *** * * * *** ** * * * * * ** * *
* *** ***** * * **** * * * ** **** ** *** * * ** *** ** of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
* * * *** ****** ** **** * ** *** ** * *** * *** ** ** * *** ** ** *** **** ** * * = x2 = %.2f",x1);
** * * * * *** **** *** * * ********** **** *
** * ** ** ****** ***** **
*** ********* * * ** ** * * * ** **
* ** * *** * * * * * * ** * * ***** ** ****** * *** ** ** *** * ***** ** of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
***** **** ** ** ** * * *** * * **** * * * * * * ** * *** * * ** * *** * = ***** ** * * * ** *** * *
*** * *** * ** **** * ** * ** * * * ****** ** * * = * * ** **** *** *** ****
****** ** * * ******** ** ** * * ** * * * **
* * ** ***** ** * * * * * 0;
}
answered by (-258 points)
0 0
prog.c: In function 'main':
prog.c:13:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:19:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:24:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
0 like 0 dislike
Hidden content!
* * * * * ** *
** ** ** * *
int main()
{
* ** ** **** ** *** * * ** a,b,c,D = 0,x1 = 0,x2 = 0;
*** * * * ** ** ** *** ** *** **** * * * ** *** * * ******

* * ** * * *** * ** * ** * *** *** * of %.2fx^2 + %.2fx +%.2f = 0 ** * *
* ** ** ****** ** ** = (b*b-4*a*c);
* ** * ** * * * * * ** * (D < 0)
** ******* ** ***
* * *** *** ** * * * ** complex and * * * *
* * * * *** * * * * * * ** = ******* * * * * * ** * *
* * ** *** ** **** ***** ** ** = ** * *** * **** * *** ***
* * ** ***** * ** **
**** *** ** **** **** (D > 0)
** *** **** * ****
* * * * ** ***** * * * * real and **** * ** **
** *** * ** ** * * * * * * * * = ** * * * ** + sqrt(D))/(2*a));
* *** * * * * * * * * **** * *** * * = %.2f",(-b - sqrt(D))/(2*a));
* ****** * * * * * ***
* * *** ** * * * * ** (D == 0)
*** * * * * ***
* * * * ** * * * * * **** ** *** real and same\n");
***** * * **** * *** * ** = x2 = %.2f",(-b + sqrt(D))/(2*a));
* * ** * ** * ****** * *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
your output lack of 1 space at line 8 when print out "Roots of ..."
0 like 0 dislike
Hidden content!
********** **** *** ***
** ** ** ****** * ***
int main()
{
*** * *** *** * * ** ** a,b,c,D = 0,x1 = 0,x2 = 0;
* * * ** ** ** ** * ** * ****** * ** * *** * **** *

** * * *** * ****** * * * ** *** * * of %.2fx^2 + %.2fx +%.2f = 0 * * ***** * *
** * *** * ** * ***** ** = (b*b-4*a*c);
**** * * ** * * * ** (D < 0)
* *** * * *** * *** * *
* * ** *** ** **** *** *** complex and * ** *
* ** ***** ** * * * ** **** = *** * *** **** * * * * ***
** * **** ** *** * * * = * ******* * * * ** ** * *
*** *** ******** * * * ** * *
* * * * * * * *** * * (D > 0)
** **** * * ** *
* * * * * *** * ** ** * ** real and * ** * * ** *****
** * *** *** **** *** ** ** ** = * * *** * ** + sqrt(D))/(2*a));
* **** *** ** * *** ** * * ** = %.2f",(-b - sqrt(D))/(2*a));
**** ** * * *** **
* * * * * * * ** * (D == 0)
* * *** * * * *
** * * * *** *** ** * ** *** real and same\n");
*** **** * ** * * ** * ** = x2 = %.2f",(-b + sqrt(D))/(2*a));
** *** * * *** * ** **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * * *** * ** * *
*** ** * * ***** *
int main()
{
* * * ** ** ** ** a,b,c,D = 0,x1 = 0,x2 = 0;
** * * *** ** *** *** ** * ** * * * ** * ** * * *

* * * * ** **** ** ** ** ******* * * ** of %.2fx^2 + %.2fx +%.2f = 0 * * **
** * * * ** **** * = (b*b-4*a*c);
* *** ****** * * * * * (D < 0)
*** ** *** * **** *****
* *** ** * * * ** ** ** ** * complex and * * *** ** *
** **** ** **** * * *** * * ** = ** * ** *** * ** *** * ** *
** **** * ** * * * * * * = ** * ** * * * ** *
* *** * * * **** * *
* * **** * * * * (D > 0)
** ** ** * ** *** * **
*** ** * * * *** * * * ** * * * real and *** * ** ** * * *
** ** ****** * * ** * ***** * * = ** *** + sqrt(D))/(2*a));
*** * * * * * *** **** ** * = %.2f",(-b - sqrt(D))/(2*a));
** * ** **** * *****
* * ** * * * *** (D == 0)
* *** ****** **** **
* ** ****** ** **** * ** * **** real and same\r\n");
** * *** * * * * ** * * ** = x2 = %.2f",(-b + sqrt(D))/(2*a));
* * * ** * ***
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * * * *** *
* * * *** *****
int main()
{
* * **** * *** ** * ** a,b,c,D = 0,x1 = 0,x2 = 0;
*** * *** * * * **** * * * ** * ** * * *** ** ** *** **

** ** * * ** * * * * *** ***** *** * of %.2fx^2 + %.2fx +%.2f = 0 * * ** * *
* ***** * ** * * = (b*b-4*a*c);
* * * *** * * *** (D < 0)
* **** * * ** * *
**** * *** ********* * ** ** ** complex and * * * * *
* * *** ** **** * * * * * = * **** ** * * *** **** *
** * * *** *** * *** * * * * = * ** ** * * ***** *
* * * ** *** * ** ***
* ** * * * ** (D > 0)
*** ** * * *** **
* *** ** * ** * ** * ** * real and *** * ** **
** * ** * * * ** ** * = * ***** * ** + sqrt(D))/(2*a));
* ** * * ** * *** ** ** ** = %.2f",(-b - sqrt(D))/(2*a));
* *** * *** * * *
**** *** ** * * (D == 0)
** **** ** * * *****
* * * **** ******* ** * *** real and same\r\n");
* * **** ***** * *** * * ** * ** = x2 = %.2f",(-b + sqrt(D))/(2*a));
*** *** ** ** ** * *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
*** * * *** * *
* * *** *
int main()
{
** ** * ** ** * * * ** *** * a,b,c,D = 0,x1 = 0,x2 = 0;
**** * *** *** *** ** * ** ** ** ***** * *** *** *** ***** *

* * ** ********* * **** * * * *** of %.2fx^2 + %.2fx +%.2f = 0 are",a,b,c);
* * ** * ** * * = (b*b-4*a*c);
** ** **** * * * = (-b + sqrt(D))/(2*a);
** *** ***** * * * = (-b - sqrt(D))/(2*a);
*** *** ** ** * * * * (D < 0)
** ** ****** ** ** ***
* **** * * * ** * * ****** * complex and * ** * **
* * ** **** ** * * *** * ****** * = * * ** * ** * ** ** ** * *
* * *** *** * ** *** *** *** ** = * ** ** * ******* ** ***** ** *
* ** * * * * ** ** * * *
* *** **** ***** * * * (D > 0)
* * ********** * **
*** * * ** **** *** * * real and * * * * **
** * ** ** ***** * ** ** = * * ** ****
* *** * ******* * ** * * ** = %.2f",x2);
** * * * ** *** **
**** **** * ** ***** * ** (D == 0)
* * * ****
** * * ******* ** ** * * ** ** real and same\r\n");
* **** * * * ** * ****** * = x2 = %.2f",x1);
* * *** ** ** * * ***
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.255.105
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users