0 like 1 dislike
14.5k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 14.5k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
* ** * ***********
**** ** *** * ** *

int main() {
** * *** * * * ** **** * ** ***
* * * **** ** * ***** * ** * * ** %f * * &a, &b, * ** ***
* * *** ** * *** *
* **** * * * * * ***** * ** ** * {
* *** * ** ********* *** ** * **** * * ** ** ** * * **** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * ** = * * = * *** * **** ** a, b, c, (-b)/(2*a), ** * (-b)/(2*a), ** * *
** *** * * * *** ** *
* * * * * * ** * **** *** if(d==0) {
***** **** * * * ** *** * **** * ** *** * * **** *** * * **
* * ***** *** ** **** * * **** * ******* * * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** * * ** a, b, c, x1);
* **** * ** ****** * *
* * * * * * ***** ** * * * ** {
* ** * * ** * *** * *** * * *** * * ** * ** ****
* ** ** *** ** * * ******** * * ** * * * * * * * **
* **** * * * * * *** * ** * * * * ** * *** * * ****** ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * * *** = %.2f\nx2 = ** * * ** * a, b, c, x1, x2);
***** ** * *** *** * * ** * * * *
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** *** * * *
**** ** ** * ** *
#include ***** **

int main()
{
* * ** **** ** * * * * *
** *** * * ** * * * * * ** %f ***** ** * * * * ** **
** * *** ** * * * ** ** * ***
* * * * * * * ***** ** * *
* * *** **** * **** ** **** * *
* * ** ** * ** * ***
* ** ** * * ** *** *** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and * *** * = %.2f\nx2 = *** ** ** *
* * * ***** * * ** *** ** * if(D==0)
*** * **** ** * **** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * ** * ***
* ** * * ** **** * * **
* * ** ** * * * * ** * *** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * ** * ** = * * * * * = * * ** ** **** * **** *** * * **** *****
** *** ** *** * * * ** ** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include *** * * **
*** * * ** * ** ***
*** ** ** ** * * *

int main()
{
**** * * * ** **** **** * *** * * * *
* * * * ** * ****** **** * * * %f * * * * ** * ** *****
** * ** * * ** *
** * * * ** * ** ** ******* * **
******** *** * ***** * ** *** ***
** ** ** * *** ** * ***** * ** ***
*** * *** **** * * * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and *** * = %.2f\nx2 = *** * * *** **** **
* *** * ** * **** * * * *
** ** * ** * ***** ******** *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * ** * **
* ** * * * * ***
* * ** * ** * ** **** ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * *** ** = %.2f + *** = %.2f - * * * *** *** ***** *** * * * **** *
* * * * ******* ** *** ***** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
*** ** **** * *** * * ** ** * a,b,c,x1,x2,D;
* * ****** ** **** * * ** %f **** * * * * ***** ****
*** * * * *** * * ****** **
* ** * * * ** * * ** = (-b + sqrt(D))/(2*a);
**** ****** * *** ** = (-b - sqrt(D))/(2*a);
********* ***** * * * * ***** **
***** * * * ** *** **** *** ** * ** * ***
* * *** ***** * * *** * * * * *** ** * ** * * *** **** * ** ** *** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\n",a,b,c);
* * **** ** * ** *** ** *** * * * * * * ** * ** *** * * ** *** ** * * = %.2f\n",x1);
** * ******* **** * * * * *** *** *** * ******* ** ** ***** **** * ** = %.2f",x2);
** ** **** * ** **** *** **** ** * ** * ** * * *
**** ** *** * * * * * *** * ** if(D==0)
* ** * ** * * * ***** * **** * ***
** ** * * *** *** *** ** * ***** **** **** * ********* * *** * * *** * **** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** ** ** * * * *** *** **** * * * * **** *** **** * ** * * = x2 = %.2f",x1);
* ** **** ** * * * ** * * ***** **** *
** ** **** ***** * ** *
*** * * ** * ** *** ** ** * * ********
** * ** ** ** * * ** ** * * * *** * * * *** ** * * * ***** * * * * ******* of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\n",a,b,c);
*** ** ** * * * ** *** * * **** *** * * ** * * *** * *** * **** * * * = * * * * * ** ** * **
********* *** *** ** ** * * * * * ** ** * **** * * ** ***** * **** * * * * = ** * ******* **
****** * * ** * *** ** * ** * * **** * *** ***
**** ** ** * * ** * * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
* * * ** * * **** **** a,b,c,x1,x2,D;
* *** * * **** *** * *** *** * * %f * ** ****** * * * * * ** * **
*** **** * ******* * **
** ** *** * * * * * * ** = (-b + sqrt(D))/(2*a);
* ** ** ****** * * * = (-b - sqrt(D))/(2*a);
* * ** * ** * * * * *
*** ** ** *** *** ** ** **** ** ***** *** * *
** *** * * * * * **** ** * * *** *** * **** **** * **** ** * * *** **** ** ** * of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
* ** ** * * ** * * * *** * ** * ** * ***** ** *** ** * * * *** = %.2f\n",x1);
* * * * *** ** * * *** ***** * ***** ** * **** ** ** *** *** ** *** * * ******* = %.2f",x2);
**** * * ** ** *** * ** *** * ******* * *
* *** * * * ** * * ** if(D==0)
*** *** * ** * ***** ** * * * * * **** *
** *** * * * * * * ** ** **** * ** * ** * * * * * ** * **** * of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
** * ** ***** *** *** * * * * * *** *** **** ** * *** * ** * * *** ** = x2 = %.2f",x1);
* *** ***** ***** * ** ** ** ** ******
** * *** * ** *
****** *** * * * *** *** ***** ** **** ** * **
**** * ** * *** **** * *** * ** * ** * * * * *** ** * * * * *** of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
*** **** *** *** * ** ***** * ** ** * ** ** ** ** * * ** * * ** * ** * ** *** = * ******* ** * * * * **
** * ** *** * * * * * ** ** * ***** *** * * * *** *** *** * ** **** = * ** * *** * **** ****
* ****** * * * ** ** ***** * ** ** ** *
* * ** * *** ***** * **** ** 0;
}
answered by (-258 points)
0 0
prog.c: In function 'main':
prog.c:13:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:19:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:24:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
0 like 0 dislike
Hidden content!
*** ** * *** *
* ** * * ***
int main()
{
**** * **** * *** * a,b,c,D = 0,x1 = 0,x2 = 0;
* ** * * * ** ****** * *** ***** * **** * *** * ****

********* * * ** * * * *** ******* * of %.2fx^2 + %.2fx +%.2f = 0 * * ** *
* *** * * ** ** ** ** = (b*b-4*a*c);
* ** * *** * * ** * ** (D < 0)
**** * *** *** *** * **
**** *** *** ** * * *** * complex and * * * ***
** *** ** *** *** * * * * * ** ** * * = *** * ** **** *** * * * **
** * ** ** * * * * *** ** *** = * *** * * * *** **** * *
*** ** ** ** ** * *
** *** ** * ** * * * ** ** *** (D > 0)
* ***** * *** ****** **
** ** * ****** *** ** ** * real and **
* **** * *** ** * * ** ** * = ** * + sqrt(D))/(2*a));
* * ******* * * ** * * ** ** * * * = %.2f",(-b - sqrt(D))/(2*a));
* * ***** * * ** *
** * * * *** ***** * * * (D == 0)
*** ** * * * * * ***
* * ** ** ** ** * * ** * real and same\n");
******** * * * * * * = x2 = %.2f",(-b + sqrt(D))/(2*a));
* * * **** *** ** **** **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
your output lack of 1 space at line 8 when print out "Roots of ..."
0 like 0 dislike
Hidden content!
* ** * *** *
* * ** *
int main()
{
* ***** *** ** * ** * *** * * * a,b,c,D = 0,x1 = 0,x2 = 0;
**** * * ****** ** *** * * * ***** * *** ** ** * ** **

**** * **** * *** *** *** * ** * of %.2fx^2 + %.2fx +%.2f = 0 * ******* **
* ** * * * * ** = (b*b-4*a*c);
* *** * *** ** * *** * (D < 0)
*** *** * * ***** * **
*** ** **** ******* ** * * complex and ***** ****
* *** ** * *** * * * ** = **** ** * * * ********** **
** ** ** * ** ***** * = * ** ** ** * * * * * ***
** * **** * ** ** **** *
* ***** * * *** *** ** (D > 0)
* * * * * * **** ** *
** * ** ***** * ** *** *** * * real and ** * ** *
* ** * * *** *** ** ** ** ** = * ** * ** + sqrt(D))/(2*a));
* **** * * *** * * * *** * *** = %.2f",(-b - sqrt(D))/(2*a));
***** ** * *
* ***** * ***** * * * * * * * (D == 0)
*** **** ** ** ****
* ** ** ** * * ** * real and same\n");
* * **** * ****** * **** * = x2 = %.2f",(-b + sqrt(D))/(2*a));
*** ** **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** * * * ** *
* * * * ** ** *** ***
int main()
{
*** *** * **** * * *** a,b,c,D = 0,x1 = 0,x2 = 0;
* * * * * * ** ****** * * * **** *** * * * * * *****

**** * * ** * * *** * * ** ** ****** of %.2fx^2 + %.2fx +%.2f = 0 * **** * *
*** ** ** ** **** *** * * = (b*b-4*a*c);
*** ** * **** ** * * ** (D < 0)
** * * * * *** ** ** * ** **
**** * * *** * ** * ** ** complex and * ** ** * *
** * ***** * * * * *** * ** * **** = * * * ** * ** * * *
* ***** * **** *** * *** ** ** = * **** * * ** * ** ** *****
** ****** * ** * ** ** *
*** ** * ** ** * (D > 0)
** * * * ** * * * ***
** * **** * ** ** * ** * * real and ** * ** ***** **
*** * * * ** * ** ** * ***** *** = * * ****** + sqrt(D))/(2*a));
* ** ** * * * *** * *** ** *** * = %.2f",(-b - sqrt(D))/(2*a));
** **** ** * * * * * *
* * * * * ***** * ** ** * (D == 0)
** ** * ***** * **
* * * * * ** ***** * * * * * ****** real and same\r\n");
**** * * * ** * * * * = x2 = %.2f",(-b + sqrt(D))/(2*a));
***** * ** * ** ** **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
*** * * * ** * **** *
* * **** * * ** **
int main()
{
* **** * * ** * * ** a,b,c,D = 0,x1 = 0,x2 = 0;
* ** ** * ** * * * * ***** ** * * ** *** * *** *** * * ** *

** * ** ** ** * **** **** * *** * of %.2fx^2 + %.2fx +%.2f = 0 * * * * *
* * * * ** * * * *** = (b*b-4*a*c);
**** * * * * * (D < 0)
***** * ** ** * *
* * *** ** * * ** * * *** * *** * complex and ** * **** * **
** * * * *** * * ***** *** * = ** *** * *** * * ****
* *** *** * *** * * * ** *** * * * ** * = *** ** * *** ** * * *** ** *
* * ** * * * ** * *
* **** * * *** * **** * (D > 0)
******** * ** * **** *
* * ** * * *** ** * * real and ** * *** * ******
*** * ***** **** * *** ***** ** ** = * * *** *** + sqrt(D))/(2*a));
* * * * ** *** **** * * * = %.2f",(-b - sqrt(D))/(2*a));
** ** * * * **
* * *** * ** * ** ** ** * (D == 0)
** ** * *** ** **
****** *** * * ** ** **** * real and same\r\n");
* ** * * * * ***** * **** * * = x2 = %.2f",(-b + sqrt(D))/(2*a));
* * * *** ** **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * * * ** **
* ** * **** * *
int main()
{
* ** * **** * * **** a,b,c,D = 0,x1 = 0,x2 = 0;
****** * ** *** * * * * * ** * ** * ********* *** * ** *

*** *** *** * * *** **** ** *** **** of %.2fx^2 + %.2fx +%.2f = 0 are",a,b,c);
* ** ** * ** ** *** *** = (b*b-4*a*c);
***** **** ***** ** * ** * = (-b + sqrt(D))/(2*a);
**** **** * **** * * = (-b - sqrt(D))/(2*a);
** ** * *** * * ** ** (D < 0)
* ** * ** * *** ** **
* ** *** **** * *** * ** *** complex and ****** *
** * ** *** *** ** * * * * * * *** * * = * ** * *** *** * **** * ** **
* ** ** * * * * ** * * * = **** * * ** * *
*** ** ** * **** * ***
* *** ** * ** **** ** * *** ** (D > 0)
**** * * *** * *****
* ** * ** * * ** * ** * * * ** real and * ** * *
***** ** *** ** ** * ** ** = ** *** ** * ** *
** ** ** ** ** ** ** ** ** * *** = %.2f",x2);
** ** * * * ** ** * * * *
** * ******** * * * * (D == 0)
* *** ** *** ******* *
* * *** * * ** *** ******* real and same\r\n");
* * *** * *** * * = x2 = %.2f",x1);
****** * ******** * * **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.17
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users