0 like 1 dislike
7.7k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 7.7k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
* *** * * **
* *** * *** * **

int main() {
* * ****** * * ** * *** * **** * * * *
** ** * * * *** * * ** %f ** * * &a, &b, * * * *
*** ***** ******* **** * * ***
** *** * ** ** ** ***** *** {
* * ** * *** *** ** * * ***** ** ** *** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * *** = ** *** *** = ** * * * ** * a, b, c, (-b)/(2*a), ** ** (-b)/(2*a), * ****** *
* *** ** ** **** * **** * * **
* *** * *** ******** * * if(d==0) {
*** * * * * ******* ** * * *** **** ** * * *
* ** ** * ***** * ** * * * * * ** * **** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * * a, b, c, x1);
** * ** * * ** * *
* *** * **** * *** ** * * *** * {
* ** ** ** *** ** **** * * * * * ***** ** ********** ***
* ** ** ** *** ***** * **** **** * * * * * * * * * *
*** * ** * * ***** * *** ** * * ** ******* **** * ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and ** = %.2f\nx2 = * * ** * a, b, c, x1, x2);
* * * * * * **** ****
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * *** * * ** ** *
* ** * *
#include ** * * ***

int main()
{
** * **** * *** * * * * ** **
* ** * **** * **** * * * ** %f *** ** * * * **** ** *
* ** *** ** * ** * * ** * *
** * ** ** *** * * * * **** ***
**** * ** * ** * * ** *** * **
***** * ** * * * * ** * *** * *
** *** * ** *** * * ** * ** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and ****** = %.2f\nx2 = * ** ** * *****
** * * * ** ** * **** * * if(D==0)
* * * * * *** * ** *** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** *** * * **
* ** *** ** * * * * **** ***
* * ** *** ** * * * *** * *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and *** *** * = ** ** = * ** * * ****** *** * * *** * ** ** * *
* ***** ** * * * ** * ** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * **
** ** * * * *** * *
* * *** ** **

int main()
{
** * * *** * * * **** ** * * *
* *** ** ** * *** * ** * * * * %f * * * * ********* *** * *
* ****** * ** *** * *
* * ****** ** * * * * *
* * * * **** * ********* *** ** ** *
****** ** *** *** * ** * **
** ** * * **** **** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and ** ** = %.2f\nx2 = ****** * *
* ** * * ** *** *** * ** * * **
* * *** * **** *** ******* * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** ** ** ***** *
* **** * * *
********** ******** ** * ** * * **** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * ** = %.2f + ** ** = %.2f - * **** * ** * * ** *** * * ** *
* * ** * * * * * * ** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
* * *** * ** ** * ** * a,b,c,x1,x2,D;
* * * * ** ** *** ** * * **** %f * ** * ** * * * * **
***** ** * *** * ****** * * *
* ** * * * * ** * ** * = (-b + sqrt(D))/(2*a);
** *** * * * * *** * * = (-b - sqrt(D))/(2*a);
* * *** ** ** * ** ** *
** * *** **** * ***** *** ** * * ***
** ** ***** * * *** * * * * ** ** ** ***** * * * * *** *** ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\n",a,b,c);
* * *** **** * * * * ** ** **** * * * * * ** * * ** *** ** ** * *** * = %.2f\n",x1);
* * * * * **** ** ****** * * * *** * *** *** ** ** * ** * *** * ******** * * ** = %.2f",x2);
* ** ** ** ** *** ** * * ** **
*** ** * * if(D==0)
*** * * * * * ** * * ** * ** * * * * * **
*** * * * * **** **** * * * **** * ** * ** **** * * ***** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ** ** * ** * ** **** ** * ** * *** * *** *** ** *** *** *** * = x2 = %.2f",x1);
**** * * * * * * * ** ** ** * * ** *
* * * * * * * * **
* * ** * ** *** *** * * *** ** ***** **** *
** * *** ****** **** * * * *** ** *** *** * * *** ** **** * * * * * * * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\n",a,b,c);
* ** * **** ** *** * * * * * *** *** * *** * * ** * ** ** *** * ** * * = * * *** ** * ** * * * ***
* *** ** ** * **** *** ****** * **** * * * * * * ** * * *** * ** ** * * *** * * = * **** ** ** ** * *
*** ** * **** * * * ** * * * * * * * *
** ** * * ** *** ** * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
***** ** * ** ** *** * ** * a,b,c,x1,x2,D;
** ******* *** * * * * * *** ** * %f ***** ** ******** *** ** * ** *
** * * * *** * *** * *
* * **** * *** ** * ** *** * = (-b + sqrt(D))/(2*a);
* *** * * * * ** * * * * * * = (-b - sqrt(D))/(2*a);
** *** *** * ***** ***** ** * *
* ** ** * ** ***** * ***** * * ** * * *
* * *** ** * * ** * * * * * * * * *** ***** ** ** *** * * * *** **** of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
* * * ****** * ********* ** ** ** * * * * ** *** ** * * ** * = %.2f\n",x1);
*** **** *** **** ******* ** * ****** * * ** **** * * ****** **** **** *** * ** = %.2f",x2);
*** * ** * *** ***** **** * *** * * ***
* *** * * * *** * ** *** if(D==0)
* ** *** ****** **** *** ***** ** * * * * * *
** * * * * * **** *** * * * ** * ** * *** * * ** ** ** *** *** * of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
* ** * * *** ** ***** ***** * * *** ***** *** ** * ** * *** * ** ** * = x2 = %.2f",x1);
* * * * *** * ***** *** ** * * * ** * *** ***
** ** *** *** ** * * * *
* * * ******* * * * *** ** ******** * **** **
* * * * **** ** * *** * * * ** ** * ** ** * * ** * * * * *** ** ** * of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
****** * ** * *** *** *** * * *** *** ** ** **** *** ***** * ***** *** ** * = * ** * * * * * ** *
* * * * ** * ** * ** * *** ** ** *** * ***** * ** * * ** *** * * * *** ** ** *** = *** * ** ** ** ***
** *** *** *** *** ** ** * * *** **
*********** ** **** * 0;
}
answered by (-258 points)
0 0
prog.c: In function 'main':
prog.c:13:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:19:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:24:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
0 like 0 dislike
Hidden content!
* * ***** ** *
* * *** *** *
int main()
{
** ** * ***** *** * *** * a,b,c,D = 0,x1 = 0,x2 = 0;
***** ** *** * * *** * * ** ** * * * * * * * ** * * *

* ***** *** ** ** * *** * *** * * of %.2fx^2 + %.2fx +%.2f = 0 *** **** * ***
* * * * ** ** ** * **** * = (b*b-4*a*c);
**** ** * ** * ** **** (D < 0)
* ***** ********* * ** ***
** * *** * ** ** * * * * * complex and **** ** **
* **** * ** *** ***** ***** ** * = * * * * ** * * ** * *
** * ***** *** **** * * ** ** = * ******* ** * *
**** **** ** * * * **** *
*** *** * ** * * * (D > 0)
*** *** ** **** * *
* * * ** * * **** * real and *** * * *
* ** * ***** *** **** **** * = *** * + sqrt(D))/(2*a));
** *** ** * * * ** * *** *** ** *** = %.2f",(-b - sqrt(D))/(2*a));
**** *** ** ** * * * **
**** * ** ** ** ***** (D == 0)
* ** ** * * ** * ** *
*** ** ** *** *** ** ** * * * real and same\n");
* * * * ** **** * **** ** = x2 = %.2f",(-b + sqrt(D))/(2*a));
** ** *** * ** ******
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
your output lack of 1 space at line 8 when print out "Roots of ..."
0 like 0 dislike
Hidden content!
* * * * ** * * *
**** * * * * *
int main()
{
* ** * * * * *** *** * * ** a,b,c,D = 0,x1 = 0,x2 = 0;
* * * * * * ** ****** ***** * * ** * * ** *** * * * * **

* * * * ** ** **** ** ** ** ** * of %.2fx^2 + %.2fx +%.2f = 0 * * * * *
* ** * *** * ** ** = (b*b-4*a*c);
* ** ** * * * * ** * (D < 0)
*** * * *** * * * ** *
* ** ** * ** **** ** * ** complex and ****** * *
* * **** *** * * * * * * *** = ** **** ** * ** ***
* * *** * * ** ** ******** ** = *** ** * * * *****
* ** ******* * *** * * *
*** * * * * * * * ******* ** (D > 0)
**** ** * *** ** ** *
* * * * *** * **** * **** * real and * * * *
** *** *** * **** *** ** = *** ** + sqrt(D))/(2*a));
* * * ** * ****** ** ** = %.2f",(-b - sqrt(D))/(2*a));
****** * ******** **** *
* *** * * * ** ** **** (D == 0)
* * ** * * * ****** * *
* ** * * * ** ** ** real and same\n");
** ** * * * * ***** ** **** ** = x2 = %.2f",(-b + sqrt(D))/(2*a));
** * * * ** ** * *** *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
**** **** *** * * *
* * ***** * *
int main()
{
* *** * ** ** ** * * * * * * a,b,c,D = 0,x1 = 0,x2 = 0;
** ** * ** * * * * * * **** * *** ****** * * *** ** **** **

*** * * ** **** * ** * ** * ***** of %.2fx^2 + %.2fx +%.2f = 0 ***** **** * *
** * * ** * ** *** ** * = (b*b-4*a*c);
* * * ** *** *** *** * (D < 0)
*** * ***** **** ** **
* ** **** ** *** ** * *** ** complex and ***** ***** *
* ****** * ** ** **** ** *** = * ** ** *** ******** **** *** *
* * * * ** **** *** * * * *** ****** = ****** *** * * *
* * ** **** ***** ** **
*** * ** *** ***** * (D > 0)
** * **** * * *****
* * * *** * * * * ** * ** * real and *** * ** *
* * * * * **** * ** *** *** = ** * ***** * * * + sqrt(D))/(2*a));
* **** * * * * * * * * * *** *** = %.2f",(-b - sqrt(D))/(2*a));
**** ** *** * * ****
* ***** * ******** ** * * (D == 0)
* ** * * **** *** ***** * *
* ********* * * * * ***** ** real and same\r\n");
* * *** *** ** ** * = x2 = %.2f",(-b + sqrt(D))/(2*a));
* * ** **** * ***
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* *** * * ** ****
** * *** ******
int main()
{
**** * * *** *** *** * a,b,c,D = 0,x1 = 0,x2 = 0;
* * ** * *** *** ****** ** * ** * * * * ** *** **

* **** * * * ** ** * *** *** of %.2fx^2 + %.2fx +%.2f = 0 * * * *** ** *
** *** * * * ** * * ** * = (b*b-4*a*c);
** **** **** ** ** ******* (D < 0)
** * * ** * * * * *** *
** * * * * * ** ** * * complex and ** * **
* ** * * * * * ** * ** *** * = * * * * * * ** ** *
** *** ** * ********** * ****** = **** ** * * *** ** *** *
** ** * *** * * ** *
****** * * * * * ** * (D > 0)
** ** ********* * *
** * ** *** ** * ** *** * *** real and ****** ** * ** *
* ****** ** ** * * * *** * ** ** = * * ** ***** + sqrt(D))/(2*a));
* *** * * * * * * ** * * * * * * = %.2f",(-b - sqrt(D))/(2*a));
** * * * * ***** *
***** * * *** ** ** * *** * ** (D == 0)
* ******* * ** ***
*** * ** ** **** * ** * ** * real and same\r\n");
** ** ******* *** ****** ** * * = x2 = %.2f",(-b + sqrt(D))/(2*a));
* * ** *** * * * **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** ** ** * *
* ** * * *
int main()
{
*** ** *** * ** ** a,b,c,D = 0,x1 = 0,x2 = 0;
* **** * *** ** **** ** ** * ** ****** *** ** * * ** **

**** *** **** ***** * * **** ** * * ** of %.2fx^2 + %.2fx +%.2f = 0 are",a,b,c);
** * **** * ** * * = (b*b-4*a*c);
* * * ** = (-b + sqrt(D))/(2*a);
** * **** ***** * = (-b - sqrt(D))/(2*a);
* ** * **** (D < 0)
* * ** **** * * **** * **
* *** **** * ** *** *** ** * complex and * * *
** * ** * *** * * *** * *** ** = * **** ** *** * * **
* ** ** *** ** * * * **** * * * = ****** ** ** * *** * ***
*** * * ** * *****
**** ** * ** ** * (D > 0)
*** ** * *******
**** * * *** ****** ***** *** ****** real and ****** ****
* **** * ****** * * ** ** ** * **** = *** * **
** ******** * *** * * * **** *** = %.2f",x2);
* ** **** ** ** ******
*** * ****** * (D == 0)
** * * * * ** * ** * *
* ***** **** * ** *** ** * * * real and same\r\n");
* ******* ** ** **** * * * = x2 = %.2f",x1);
* * * * * ** * * *** ** *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.127.168
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users