0 like 1 dislike
17.5k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 17.5k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
* * * *** ** ***
** ** ** ** ** *

int main() {
* * * ** * * * * ** ** **
*** ***** * ** * ** * ** ** ** *** %f * * &a, &b, * *
** * ** * * ** ** ***
* *** * * ******* * ** * * {
*** * ** * *** **** *** * * **** * ****** * **** ***** of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** = * *** * = * ** * * * a, b, c, (-b)/(2*a), * *** * * (-b)/(2*a), * ** *
* * * ** ** * ** * * **
** * **** *** ** **** if(d==0) {
** ** ** ** * *** * * *** * ** ***** * ** *
****** *** ** * * ** *** ****** ** ** * * * **** ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * a, b, c, x1);
***** ** * * * *
** *** ******* ******* * ** ** * {
* * * ** * * **** ** ***** * * ** * * ***** *** ** *
* ** *** ** * * ** * * * * * * ** **** *** ***
* * * ** **** * * ** ** ** **** ** * * * ** * *** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and * * * ** = %.2f\nx2 = ** * ** * a, b, c, x1, x2);
* * *********** * *** ***
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** * ** * *** *
** ** *
#include *** ** *

int main()
{
* * *** * * * ** ** *** * * **
**** * * * * * ** *** * %f ** **** *** ** ******
**** * ** * ** ******** * *
* * **** * * * * * ** ** ** *****
* **** **** ** *** ***
* ***** * ** *** ** * * * * **** *
* * ** * * * ** ** *** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and ** = %.2f\nx2 = * * *** **** *
* * * **** ** **** ***** ** if(D==0)
* ******** * **** * ** * *** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** *** *** *
**** ** * **** * ***
* * * ** * * * **** ** *** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and *** ** = * *** = ** * * * * * ***** * * ** ** ** *
** * * * * * * ** * ** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** * *
*** * ** * ** * **
** ** * ** *** **

int main()
{
*** ******** * **** ** ***
* * ** * * * * * *** * * **** %f * * * * * **** * *
** ** * ** * * * ******* * ****
*** * * * * * *** ** **** ** ** * **
** ** *** *** * **** * ** ** **** *
* * ** * * *** * *** ** * ***
* * * ** ** ** * * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * **** * = %.2f\nx2 = * * *** ** * **
* ** ** * * ** * ** ** **
***** * ** **** * ***** ** ** ** * **** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * **** *** ** **
* * *** * * ** * * *
** * * * * **** * * * *** * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** * * = %.2f + ** *** = %.2f - *** * ** * ** **** ** * * ** ** *** * **
** * *** * ** * ** * * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
* ******** ** ** ** * a,b,c,x1,x2,D;
*** ***** * * * * *** ******* * * %f * * * **** * **** ***
** **** ** * * * * *** *****
* * * **** * = (-b + sqrt(D))/(2*a);
** *** * *** ***** * * = (-b - sqrt(D))/(2*a);
* ** * * * ** ** * * * *
**** **** * * * * * * *** *** * ** *
** ** * ** **** * * ****** * ** * * ** *** * * * * *** ** *** * ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\n",a,b,c);
*** **** * ** * ** *** * * * * * * * *** ** * * *** * * ** * ** * = %.2f\n",x1);
* ** ****** * ** * * * *** * * * * * * ***** * * * *** * *** * * *** = %.2f",x2);
* ** ** * ** ** **** * * * *** * *** ** * **
* * * ** * * * *** if(D==0)
* ** ** ** ***** * * ** ** * ****
* * * * * * *** ** ** * * * ******* ** ** *** * * *** * * * * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * * * * ** ** ** *** * * ** * ** ** ** ** * ** ****** * * **** = x2 = %.2f",x1);
**** * * ******** **** ** * * * **** * *
** * * *** * ** * *
** ******* ** ** ** * ** * ** **** * * ** * ** * *****
** * **** ** ** **** *** * * ***** * * * ** * ******* ** ** * ****** * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\n",a,b,c);
**** * * * * * * ***** * *** * ** ** * ****** * * *** * * * * * ** * * * * * = * * **** * ***** *
* ****** ** *** ** ** *** *** ** ****** * * *** *** ***** * ** * * * * *** = * * ** ** *** * *** **
** * * ** * *** * * * **** * **** ** *** *
* ** * *** * ** ******* * ** ** * ** 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
* ** ** * ***** * * ** a,b,c,x1,x2,D;
***** * ** * **** *** ** * ** * %f * * **** ** * * ******
* *** * * **** * *** **
** ** * ** ** ** * = (-b + sqrt(D))/(2*a);
* ** * * * = (-b - sqrt(D))/(2*a);
* * ** ** ** * * * * * *
*** * *** ***** * * * * * ** * ****
** **** ** * * * *** ** **** **** * * * * **** ** * * * * * * * *** ** of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
** * *** ***** * * * * ******** * **** * * *** * * * ** *** * ** * * = %.2f\n",x1);
******* ** ** ** * ** ***** * * * * * ** ** **** ** ** **** * ** ** * = %.2f",x2);
**** * *** ** * * * *** * ** *** **** * * * *
* *** * *** **** **** if(D==0)
* * ****** *** ** * * *** **** ** *
* ** * ** * ** * ** * * * * ** **** ******** ** * *** * ** **** * of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
* * * *** * * *** ** * ** *** * ** *** * ** * * ** * * ***** * *** * = x2 = %.2f",x1);
* **** * * * *** ** * * ** ******** ** *
** ** ** **** * * *** *
** * ** * * ** * * ** *** * * **** * * ** ****
* * * *** * ***** **** * **** ** * * * * **** * ** * ** * ** of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
*** *** ** * ******* * ** ** * * * ** ** * ** ** *** *** ** * * *** * = ****** **** ** * * * * * * *
*** * ** * * *** ** * * ****** ** * * * *** *** * ****** * * **** * = * ** * ** ** ****** *
*** *********** **** *** ****** * * * * * ** ***
* *** * **** ** * * 0;
}
answered by (-258 points)
0 0
prog.c: In function 'main':
prog.c:13:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:19:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:24:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
0 like 0 dislike
Hidden content!
* **** * * * *** *** * *
*** * ** ***** * *
int main()
{
** * ****** **** **** a,b,c,D = 0,x1 = 0,x2 = 0;
* **** **** * **** ***** * * ** * ** * ** ** * ***

** * * * * * ********* * ** ** * of %.2fx^2 + %.2fx +%.2f = 0 *** * *
*** * * * ** * ** *** * = (b*b-4*a*c);
** * ** *** * * * *** ** * (D < 0)
*** * **** * * * *
* *** * * *** * * ** ** * ** complex and * * *** * * *
* * * ** *** *** ** * ** * * = ** *** * * * ** * * ***
* **** * ** ** ** * *** * ** = * *** ******* * * ** * ****
*** * **** * * * ** *
******* ** * * * (D > 0)
**** ** *
* ** ** * *** ** * *** * real and * * ****
** ** * * * *** *** * * * = * ** ** + sqrt(D))/(2*a));
*** ** ** ** ** ** * * * * = %.2f",(-b - sqrt(D))/(2*a));
*** *** * *** * * * * *
* ** * * * ** * (D == 0)
* ** * *** ** * *** * * ****
* * ** ***** * * **** *** * ** * real and same\n");
** * ** * **** * ** * * **** ** = x2 = %.2f",(-b + sqrt(D))/(2*a));
*** *** ** * * ***** **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
your output lack of 1 space at line 8 when print out "Roots of ..."
0 like 0 dislike
Hidden content!
**** ** * ** * *
* * * ***** **
int main()
{
** ***** * * ** * ** * a,b,c,D = 0,x1 = 0,x2 = 0;
** ** ** * * ** * ** * **** * * * * * * ******** * **

* * * * **** * **** ** * ** of %.2fx^2 + %.2fx +%.2f = 0 ** *** *** *
* * * **** *** ***** ** * = (b*b-4*a*c);
**** ** * * ** ** (D < 0)
** ** ********* * ** * * *
* ** * * * ** * ** * * * ** complex and * *** **** *****
* * **** * * ***** ** * * = ******* * * *** *** * *** *
* **** * *** ***** * **** ** ******* = * ****** * ***** ** ****
* ** * * * ****** **
* *** * *** *** ** * (D > 0)
** * *** * * ** **
** * *** * ** * ** * * **** * real and * ** * ** *
* * * * * * ** * * * * *** ** = ** * **** * * + sqrt(D))/(2*a));
*** ** ** * * * ** **** = %.2f",(-b - sqrt(D))/(2*a));
* ** *** *** * **
* ** * * **** **** ** (D == 0)
** *** **** * ** ** ** ***
* * ********* ** ***** *** * *** * * * real and same\n");
** ** * * ** ** **** ** * ** * * ** = x2 = %.2f",(-b + sqrt(D))/(2*a));
* * * * * * *** * **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* *** **** **
*** *** ****
int main()
{
* * *** ** * ** ** ** * a,b,c,D = 0,x1 = 0,x2 = 0;
* ** ** * *** ** * * ** * * * * *** * ** ** **** * * ** ***

*** ** * ** * **** * ** **** * * * ** * of %.2fx^2 + %.2fx +%.2f = 0 * ***** *** ***
***** *** * ** ** ** * = (b*b-4*a*c);
* ** * * ** ***** ** * (D < 0)
* ** ** * * ****** ** *
* * *** ** ** * * ** ** ** complex and **** *
* * ** * * * ** * ** ** * = ** * * * * ***** ** * **
* * * * * **** *** * * * * * = * * * * * * ** ****
** ** ** * ** * *****
** ** * *** ** * *** (D > 0)
** * * **** ** * **
*** * * ** * * ***** * * ** real and ** ** *** ** * *
* * * ** * ** * ** * * = * ** *** *** + sqrt(D))/(2*a));
******* *** ** * ** * **** **** = %.2f",(-b - sqrt(D))/(2*a));
**** * *** * * *****
* ** ******** ** * * (D == 0)
* *** * * * *
** *** ** * * * ** ** * * real and same\r\n");
* *** *** * * *** * * ** * = x2 = %.2f",(-b + sqrt(D))/(2*a));
***** * ****** *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** * ** ** *
*** *** ** * *
int main()
{
*** * ** * * ** * * * a,b,c,D = 0,x1 = 0,x2 = 0;
* ***** * * * * * * * * * *** **** ** *** * *** * *

*** * *** * ***** * ****** ******* * of %.2fx^2 + %.2fx +%.2f = 0 * ***** **
* * ** ***** = (b*b-4*a*c);
** * ** * * ** *** * (D < 0)
* *** *** * * ** *** *
***** *** * * *** * * * * *** ** complex and * * ***** **
*** * ** * ** **** * *** ** = * **** **** ** ***** ** * **
** **** ** * ***** ***** *** * *** = *** * ** *** * *
* * *** ***** * ** *****
* * * *** **** * * ****** * (D > 0)
** *** ** * * **** * **
* ** ** ** * * * * * * * ** real and ** ****
** ****** * * * ** = * * * * **** + sqrt(D))/(2*a));
** ** *** * ** ** * *** ** * = %.2f",(-b - sqrt(D))/(2*a));
* * * * ** * * ** *
* * ****** * ** * ** (D == 0)
* ** *** * ****
* ** * * **** * *** * ** * ** real and same\r\n");
* * ******* * * ** * ** = x2 = %.2f",(-b + sqrt(D))/(2*a));
*** **** * * *** * ** *****
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
*** * *** * *
* *** * *** * *
int main()
{
**** ** ***** * * * * * ** a,b,c,D = 0,x1 = 0,x2 = 0;
*** * * ** ** * * * ** * **** *** **** * * * * * * * * ** * **

* **** * * * *** *** **** * ** * of %.2fx^2 + %.2fx +%.2f = 0 are",a,b,c);
* * ** *** * * * * = (b*b-4*a*c);
* ** ****** ** ** **** ** = (-b + sqrt(D))/(2*a);
**** * * * * * ** * ** * = (-b - sqrt(D))/(2*a);
*** * * * **** * *** ** (D < 0)
**** * * * ** * *
* ** * * ** **** * ** * ** * *** * complex and ** * * *
** ** ********** * * * * * * * = * ** ** * ***** ** ** ****
* ** ** *** * *** ** ** * ** ** ** = * ****** * * *******
* ** * ** * * *
*** ** * ** * ** * *** **** * (D > 0)
** * * ****** * *
* * ** ** * * * * *** * * ** **** real and * ** *
* **** ** * *** ** **** *** = ** ** *** ** **
** * *** ** *** * *** *** * * ** = %.2f",x2);
* ** ** * ***** * **
* ** * * * * *** * * (D == 0)
* * * ** * ** * *** *****
** * * *** ** * * * * * **** real and same\r\n");
* ** * * **** * ** ** * = x2 = %.2f",x1);
* *** * * *****
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.94
©2016-2026

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users