0 like 1 dislike
6.7k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 6.7k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
** * * * ** * ** *
* *** ** * **

int main() {
** * *** * * * * * ** ** ** * **
** ** * * ** ** *** *** * *** %f ** ** * &a, &b, ****
* * * ***** ****** ** *****
* ** *** * ** * * * * * {
* * * * *** * ** ** * * * ** * * *** **** ** ** ** ** ** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** * * = *** * * = * * * a, b, c, (-b)/(2*a), *** (-b)/(2*a), * *
* * * ** * ** * **
* * * *** * ** *** ** * if(d==0) {
* * ** ** ** ******** * ** ** ***** * *** ** **
** * *** ** *** ** *** * * *** * ** **** * * *** ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * * a, b, c, x1);
* ******* ***** ** *****
* * **** * * * ** ** ******** *** ** {
*** * * * * * ** **** ***** * *** * * ** * * ** * * ** *
* ** **** * * * ** * * * * * ****** * **** ** * * ***
** * * ** ********** * * *** * * **** ***** * of %.2fx^2 + %.2fx + %.2f = 0 are real and * * * * * = %.2f\nx2 = * * a, b, c, x1, x2);
* * *** * *** ** * * **
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** * * ** **
* ** ** ** ** **** *
#include * ** * ****

int main()
{
** * ** ***** *** ***** ** ** * ** **
* * * * * * * ***** ** *** %f ** * * * *** ***** *** ** *
* * * * * *** ** * *** * * *
*** * **** *** **** * * * ** ** ****
* * ** ***** *** ** * **** **
*** ** ** ** ** **** ** * * ****
* ***** * ** * * * * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** *** = %.2f\nx2 = ******** ** * **
* ** * ** ** * * * * ** ** if(D==0)
** * * *** ** **** * *** ** * * * * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** * * ** *
* **** **** ****** * ****
** ** * ****** * ** **** **** ** * **** of %.2fx^2 + %.2fx + %.2f = 0 are complex and **** * = *** **** = *** *** *** * *** * * * * ** **
*** ** * ** * * * * ** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ***
** ** * * ** ** ** *
** * * * **

int main()
{
** ** * ** * ******* * ** * *
*** ** ** ** * *** ** * *** %f ** * ** ** ** *** ** **
** * * *** *** *** *** ** *** *
* * * * * * * * *** **
** *** * * * * ** ** **** *
* * * * * ** * * ** *******
* ** ******** * * *** ** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and ** * * = %.2f\nx2 = * *** * *** *
* * * * ******* * **** * *
****** ** * * * * *** *** ** **** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * *** * * *
* ** *** * * * * * ******
* * * ****** * **** * * * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** * = %.2f + * * * = %.2f - *** * * *** * * * ** *** * *
** ** * * **** * ** * * * *** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
** * * * ** ** ***** **** a,b,c,x1,x2,D;
* ** * ** *** * *** ** * %f ***** ****** * ** **
* * * *** * ** *** ** ** *
* ** * ** *** ** * = (-b + sqrt(D))/(2*a);
* * ** * ** ** ** *** = (-b - sqrt(D))/(2*a);
** ** *** * * ** ** *** * *** **
** ** *** ** ** ** *** * *** ** ***** *
* ** * * * ** * * * **** * * * ****** * * * * * * * *** * **** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\n",a,b,c);
* ** * *** *** ** * **** * **** ** ** ** **** ** ** * * * ** * ** * * * = %.2f\n",x1);
** ** * *** * **** * * * * * ***** * * * *************** * * * * * ** ***** * * = %.2f",x2);
* * * * *** * *** * * * ** ** * ***
* * *** *** *** ** ** * if(D==0)
* * ** *** *** * *** ** * * ***** *** ***
* ** **** *** ****** ******* *** * **** ** **** * ** * **** * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** ** * *** * ** **** *** * ** * * ** ** * ** ** * ** *** ** * ** * = x2 = %.2f",x1);
** * ** *** ** ** ** * * ** * *** * *
***** ***** * ** ***** *** *
***** * ***** * * ** * **** ** * * * **
*** * ** ******** ** * ** * **** * ** ***** ***** ** * ** ****** * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\n",a,b,c);
** * *** ** * * * * ** * * *** ** ** * *** * ******* * **** * * *** ** *** * = * ** *** **** * * *** * * *
* ** **** **** ** * ** * ** * ***** * *** *** *** * * *** ******** = * * * *** *** * **
** * ** * ** ** ***** ****** **** * * *
** * *** * ** * ** *** 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
** ** ** **** ** ** * * ** * a,b,c,x1,x2,D;
* * * * ** * ** * ** * * * * * %f ** **** ** * * ** ** *
* ** *****
***** * *** * ** * **** = (-b + sqrt(D))/(2*a);
* * *** ** ** * *** ** = (-b - sqrt(D))/(2*a);
* **** ** *** * *** **** * *
*** * * * *** ** **** ** ** ** *** * **
**** * * * * * * ** **** *** *** ** ***** * * **** * * * of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
** ** * ** **** * *** * **** ** * **** * ***** * * ** ** ** ** **** * * ** * ****** = %.2f\n",x1);
* * ****** * * * **** * ** ** *** ** * *** * * ** * * *** * * * * ** * *** * ** = %.2f",x2);
* ** * * * * ** * * *** ** * **
** ***** * * *** ** if(D==0)
******** * * * ** * * ** ***** ****** * * **
* * * * * * ** ** ** * * * ** ****** *** * ** *** ** * * * ******** *** ** * of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
** ** * * * *** * * * *** **** * ** * ** *** ** * * * * * * ** * **** * = x2 = %.2f",x1);
** ** *** ** ** ** ** *** *** * ** ***
* * * ****** *** *****
***** ** ***** ** * * * * ** ** * ** * ****
*** * * ** ** * ** * *** ** ** * * ** *** ** * *** * *** * ** * * **** of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
* ** ** *** ** ** * * * * ** ** * **** ** ***** *** * ** * ** * * = ***** **** * * ** * * * * *
* **** **** ***** * * ** ** **** * * *** ** ** ** *********** = *** *** * * ** * * * *
** * * **** ** ** ** ***** * * ** * **
** * *** * * * * * * * * *** 0;
}
answered by (-258 points)
0 0
prog.c: In function 'main':
prog.c:13:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:19:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:24:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
0 like 0 dislike
Hidden content!
* ** * * ** *
* *** * ** *
int main()
{
* * ** * * * ** * * a,b,c,D = 0,x1 = 0,x2 = 0;
* ** ***** * ** * *** ***** * ** * * *** * * ** * * ** ***

** * * **** ** ** * * *** * * * * * * of %.2fx^2 + %.2fx +%.2f = 0 **** * * ** *
*** ****** **** * * * * = (b*b-4*a*c);
***** * ** * ** ** ** * ** (D < 0)
** * * * ** * ** ***
** * * *** * ** ** *** * complex and **** * * * **
* * *** ** * *** * ** *** = * ** ******* ** ***** *****
* * * *** **** * ***** * * * * = * * * ** * * ** *** * ** *
** *** ** * ** ****** *** *
* * * * * **** ** * (D > 0)
* ** * ** ** ***** *
* * * * * ** * ** *** * ** * * * * ** real and **** * ** *
* * * **** ** * *** * * * * * * *** = ** ** ** + sqrt(D))/(2*a));
* * * ** * *** **** ****** * ** * = %.2f",(-b - sqrt(D))/(2*a));
** ** *** *** * **
*** * *** **** * ** * (D == 0)
* *** * ** ** *
* ** * ** *** * * * **** real and same\n");
*** ** ** * * * * *** **** ** = x2 = %.2f",(-b + sqrt(D))/(2*a));
* * *** * * ** ***
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
your output lack of 1 space at line 8 when print out "Roots of ..."
0 like 0 dislike
Hidden content!
*** ** ***** ** *
** * ****
int main()
{
* * * **** ********* a,b,c,D = 0,x1 = 0,x2 = 0;
* * * ** * **** * **** *** ***** * * *** * ** * **** *****

*** * ***** ** ** * * ********* * of %.2fx^2 + %.2fx +%.2f = 0 * * * ***
**** ***** ****** ** * * * = (b*b-4*a*c);
* ****** **** *** * (D < 0)
* * ** **** ** * **
* * ** * ** **** complex and **** ***** ** **
******* ********** ** ** * * * = **** ** *** * * * * *
* * *** ***** * * ** * * * **** * = **** ** ** ** * ** * **
**** **** *** * * **** **
* *** *** ** * ******* (D > 0)
* ** * * ****** * *
*** * * ** * ** ** ** * real and * **** *** * *
* * ** * ** ** *** * * ** ***** * = * * ** ** * + sqrt(D))/(2*a));
*** * * * ** ** ******** ** = %.2f",(-b - sqrt(D))/(2*a));
* *** ********* ** ** *
*** * * ** * * * * * ** * (D == 0)
** ** ** * ** * ****** ****
** ** ** *** *** ** **** * ** * real and same\n");
* * *** ** * *** **** ** ** *** * = x2 = %.2f",(-b + sqrt(D))/(2*a));
** * * *** * ******
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** * ** **
** *** ***** ** **
int main()
{
* * * ***** * ** ** * **** a,b,c,D = 0,x1 = 0,x2 = 0;
* * *** *** * ** * * * ** ** * **** ** *** * * ** ** * **

** ** ** * *** ******* ** ** of %.2fx^2 + %.2fx +%.2f = 0 ** * ** **
* * **** * * * = (b*b-4*a*c);
* *** ** * **** *** * *** (D < 0)
* * * * *** ** ***
****** * * ****** ** * complex and ** * * *** *
*** ** ** ** * *** * *** *** ** * ** = * * *** ** *** * * * * **
** ***** * * ** * ******* *** = * ** * * ** *** *** * ** *
* * ****** ** *** *
**** * * **** ** ** * *** * (D > 0)
****** * * * ********* *
* * * ********** ** * ** * * real and * ******
* *********** * ** * ** * * = * * * ** * ** + sqrt(D))/(2*a));
* ** * * * * * ** * ** * ** = %.2f",(-b - sqrt(D))/(2*a));
* * * ** ****
** * *** ***** * **** * * (D == 0)
** * * * * *** * * *
** ***** *** * *** * * * ** ** real and same\r\n");
* * ** * * ** * * *** ** = x2 = %.2f",(-b + sqrt(D))/(2*a));
* *** ** * * * **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * * *** *** *
* ***** * * *
int main()
{
** ** *** *** ** ** ** a,b,c,D = 0,x1 = 0,x2 = 0;
* *** * **** ** * ** * * * ** * * ******* * ******* * *

** * **** * * * * *** * * * *** * ** * of %.2fx^2 + %.2fx +%.2f = 0 *** **** **
* **** *** ** * **** * = (b*b-4*a*c);
* ** ****** * * ** * (D < 0)
****** * * *** * ****** * ***
***** * * *** **** ** * * * ** complex and *** * * ** ***** *
*** **** ** *** ** * = ** * * * * ** * ******* *
* **** *** * * * *** ** * * = **** *** * * * * *** ** * *
** ** * *** **
* * ** ** * * * * ** (D > 0)
**** * * * ** * * **
* * **** * *** *** ** * real and *** * * * ** *
***** ** ** * ** *** * ** ** * ** = ** ** *** *** + sqrt(D))/(2*a));
** ** ** **** * ** ** *** * **** * = %.2f",(-b - sqrt(D))/(2*a));
*** ** * **
* **** *** * * * * (D == 0)
* ** **** * * * * *
* * * ** * *** *** ** *** * * ** real and same\r\n");
** ** ** ** ******* *** ** ** = x2 = %.2f",(-b + sqrt(D))/(2*a));
**** * ***** * * * **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * **** * ** *
* **** ** * ***
int main()
{
** * * * ***** ******* a,b,c,D = 0,x1 = 0,x2 = 0;
* * ****** * * ** ** * ** ** * * * ** *** **** ** * ***

* * ****** * ******** ** ** * * *** of %.2fx^2 + %.2fx +%.2f = 0 are",a,b,c);
* *** * ** * * * = (b*b-4*a*c);
*** * * * * ** ** = (-b + sqrt(D))/(2*a);
* * ** * * * ** = (-b - sqrt(D))/(2*a);
* * * * * **** * * * (D < 0)
** * *** * * ** * **
* *** *** ***** * ***** ** * complex and **** ** *
* ** ****** * *** * ****** *** * = ** * * *** * * ** **
**** * * ** * * * * * * * = ** **** * ****** *** *
* * * ** ** ****
** * * *** ***** * (D > 0)
* * * ** **** **** *
* * * **** * ** **** * ** *** * * real and ****** *
* **** * ******* * * * ** * = ** ** ** ***** *
* **** * ***** * * * ***** * * ** * = %.2f",x2);
* ** ** ** * **
*** * * * * * ** * * (D == 0)
* ** * **** *
** ***** * ** ** * ***** ** * * ***** * real and same\r\n");
* ** ** * *** * * *** *** = x2 = %.2f",x1);
* *** * * ** ** *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.164
©2016-2025

No related questions found

12,783 questions
183,443 answers
172,219 comments
4,824 users