0 like 1 dislike
13.1k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 13.1k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
** ***** ** ***
** * *** * * *

int main() {
** * * * * **** ** ** * ** * *
* *** * ******* * * * ** ***** ** *** %f * ** &a, &b, **
* ** *** *** * ***
*** * * ** * * ** * * {
** * * *** * ***** *** ** ** * ** *** * ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * *** * * = * *** = * **** a, b, c, (-b)/(2*a), **** ** (-b)/(2*a), * * *
** ** * * ** * **
* **** * ******** ** *** if(d==0) {
**** ** ***** **** ** * ** * * * * ******* ******** *** * * ** *
* * * * ** * *** **** * * ** *** * *** ** ** ** *** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** **** a, b, c, x1);
* * *** *** **** * *
* * * *** ** * ** * * * {
* * *** * * * ** * * * * * ** * **** * **** ** *** **
*** * * * * * * *** * **** **** ** * * *** * * * * ** *
* *** ** * *** ******* * *** ****** * ******* ** ***** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * **** = %.2f\nx2 = *** *** a, b, c, x1, x2);
* * * * ** **** * ***
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** ** **** *
*** * * * ** * * **
#include * *** * **

int main()
{
** **** ** * * **** ** *** * *
**** ** * * ** ******* * * * %f * ** ** * * * * * *
* * * ***** * **** * ** ** *
*** *** *** ** *** * ******* ***
** * * *** * ******* * *** * * * **
**** *** * * ***** * * * *
* * **** ** *** ** * * * * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and * * * = %.2f\nx2 = * **** * * *
****** * * ** * ** * * if(D==0)
** ** ******* **** * * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** * * * *
* * * * * **** ** * * *
* ***** ** ** *** * * * ** ***** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * ** = * * * = **** * ** *** * *** * ********* * **
**** *** * * * ** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** * * * ***
* * * ** * * ** *
** * ** ** *

int main()
{
* ** ** * * ** *** ** * * ***
* * * * *** ** * *** *** * * ** %f * ** *** *** **
* *** * ** ******** *
* *** **** ** * ***** ** ** ** ***
* *** * * ***** ** ***** *** **
*** * * * * * ** ** ***
*** * * * *** * * **** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and **** **** = %.2f\nx2 = ** * *** ** ** *
* * * * ** * * * *** * *
** * * * ** * ** * * ** * ** * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * ** * ** *
* ** ** * *** * *
****** ** * *** *** *** * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** * ** = %.2f + * ** = %.2f - ****** * ** * * ** * * *** * ** **
*** * **** *** ** *** ** * 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
***** **** ** * * * * ** * ** a,b,c,x1,x2,D;
** * ** ** * *** *** ** ***** %f ** ** ****** * ** ** ***
* * ** ** *** * * * **
* ** * * **** * = (-b + sqrt(D))/(2*a);
** * * *** ** * **** * = (-b - sqrt(D))/(2*a);
*** * ** * ** * ** * ** * *** ** *
***** ** * **** ** * * * * * *** * * *** * **
* **** ** ** ** * *** ** *** * **** * * ** ** ***** ** ** * * ** ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\n",a,b,c);
*** ** ** ** * * * *** * * *** * * * ** * * * * * * ** * *** * * * ** * ** * ** * * = %.2f\n",x1);
* * ** * *** ** ** * **** * ** ****** * ** ** * * ** *** ** **** * * = %.2f",x2);
* * * ** ** * * *** * * * * ** * * **
* * ** ** * **** * ** * * if(D==0)
*** * ** * ** * *** * * * * ** * * *****
** *** **** *** ** * *** * * **** * * * ** * ** **** * ****** * ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** ** * * * ***** ** * * * ** * * * ** ** ** *** * *** * * * **** ***** = x2 = %.2f",x1);
* * * ** * * ** *** ***** ** *** * * * ***
******** ** * *** *
* * * * **** * ** * * * * * * * ** * *
***** * * ***** * * * * * * * * * * * * ** * ** **** *** *** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\n",a,b,c);
* * * ** * *** ** ** ** * ** *** *** * * *** * ** * ** ** = ** * * * ** *** ******
* ** * *** *** *** ** ** * * * * ** ** ***** *** * * * * *** *** ** * * = * ** * * **** ** ***
* * * * **** ** *** * ******** ** * ***** * *
** * **** * ** ** ** 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
** ** * ** * ** ***** * a,b,c,x1,x2,D;
* * * * * * ** * ** ** * *** * %f ** * *** ** * * ** * * **
* * **** ** ** * *
* * ** * ** *** * * ***** = (-b + sqrt(D))/(2*a);
***** * * * ** *** ** = (-b - sqrt(D))/(2*a);
* ** ** ** * * * *
* * ** *** **** ** **** *** * *** *
* * ** ****** **** *** ******* * *** * ** *** ** * ** ***** * * *** ** * of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
* *** *** * * * ******* * ** ** **** * * * ** * ** * **** * * **** * = %.2f\n",x1);
*** * ** *** * ** * * ** **** **** * **** * * ** * * *** * ** * *** ** = %.2f",x2);
* ** ** ***** * * * * * * * ** *** * * ** *
** * ** *** ** *** if(D==0)
* * *** ** ** ** ** * * ** * * * ** * ****
* *** ** **** * * * **** ** ** * * * ***** * * * ** * * * *** * **** * of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
***** ******** ***** * * * * * * ** * ** * * **** * ** * *** * * * = x2 = %.2f",x1);
**** * ** * * * * * *** * ** ** *****
** * ** ******
** ** **** **** * ** **** **** ** ** * ** * *
** * ** * * ** *** * **** * * * *** * * * ***** ** ** * *** * * of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
** ** * ** * * * * ****** * ** * ** * **** * * *** * * ** ** *** = * ** ** ****** * ***** *
****** * * * ** * * * ** * * * *** **** ** ** ** * ** * * * *** * ** * = * * * * * ** ** * * *
*** ** * ** **** * ** * *** ** * *** * *
*** *** ** * * ** * **** 0;
}
answered by (-258 points)
0 0
prog.c: In function 'main':
prog.c:13:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:19:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:24:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
0 like 0 dislike
Hidden content!
** * * * *
**** * * ** * * *
int main()
{
* **** ** * * * * * ** **** a,b,c,D = 0,x1 = 0,x2 = 0;
** **** * * * ** ** * * * ** * ** ** * * ** * * * *** **

*** * * * *** *** *** * ** * * of %.2fx^2 + %.2fx +%.2f = 0 * ** ** *
* ** ** ** * ** = (b*b-4*a*c);
* * * ** *** ** ** ** (D < 0)
**** * ***** *** ** *
* * * * *** * * * ** * * complex and * ** ** * ***
* * * ** * * * * ** ** * * = ****** * * ** *** * *
* * **** * **** * * * * *** * = * * * *** * * * **** *
******* **** ****** * ** * * *
** ****** ** ** * * (D > 0)
* * * * * * * **
* ** * * ****** * * ** ** ** real and * **** * *** *
* ** * ** ** ** * ** **** = * ** ** + sqrt(D))/(2*a));
**** *** * *** ***** * *** * ** ** = %.2f",(-b - sqrt(D))/(2*a));
** ** ** * ** *
***** **** * *** *********** (D == 0)
*** ** ** * * ***
***** ** ** *** *** * **** * * **** real and same\n");
* * **** ** ** * **** ****** = x2 = %.2f",(-b + sqrt(D))/(2*a));
* * * ** ****** ** * *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
your output lack of 1 space at line 8 when print out "Roots of ..."
0 like 0 dislike
Hidden content!
* * ** ** * * *
** * * ****
int main()
{
******* * * ** * **** ** * a,b,c,D = 0,x1 = 0,x2 = 0;
* * ** * * ** ** ** * * * * *** * * * * ** * * *** *

***** ** **** * * * * * * ** * of %.2fx^2 + %.2fx +%.2f = 0 * ** *** **
* **** * * *** ** * = (b*b-4*a*c);
*** * **** * ** **** (D < 0)
* **** ** * *** ***
* ** *** * ** **** ** complex and * *** * **
* * * * * * * * *** * ***** = * ***** * ** * * * * * *
*** **** * ** ***** * * *** ** * ** = * ** ***** ** * *
* *** * * *** ** ***
* * ** * **** *** (D > 0)
* * * * *** * *
* ****** * ** * * *** * * ** ** real and * * * * *** *
** ** ** ** **** * * * *** ** **** = * * * * + sqrt(D))/(2*a));
** *** * ** * * ** *** ** * * * * = %.2f",(-b - sqrt(D))/(2*a));
* * ** * * * * ** *
* ** * *** ** * * * ** * (D == 0)
** ** ******** **
** * ** * ***** * * ** real and same\n");
** ** ** * **** * *** * * ** * * = x2 = %.2f",(-b + sqrt(D))/(2*a));
** * ** * ***** *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
**** ** * ***** *
* ** ** *** *
int main()
{
** *** *** ** *** * ** a,b,c,D = 0,x1 = 0,x2 = 0;
* ** * ***** * * ** * * * * ****** * * *** **

** * ** ** * ** * ** ** **** * * ** of %.2fx^2 + %.2fx +%.2f = 0 * * * * * *
* ** ** ** * *** ** = (b*b-4*a*c);
**** * * * * **** ** ** *** (D < 0)
** * * ** * *
* ** * ****** ** ** * ** * complex and * **** **** **
* * * ** * *** *** * * **** * = *** *** **** * ** *** *
** ** ** ****** ** * * *** = * ** * * * * ***** ** ** **
* * * * *** * ******** ** ******
** * ** * *** *** (D > 0)
** * **** * *
* ** * * *** * ******* ******* real and * ** * * **
**** ** * ** **** *** * * = ** * * * + sqrt(D))/(2*a));
****** *** * * * ** *** * ** = %.2f",(-b - sqrt(D))/(2*a));
* * **** * * **** *
** * ** * * *** ***** (D == 0)
* * ** * * * * * *** ** *
* ***** ** ** **** ** * * ****** * real and same\r\n");
* * ***** ** *** ** *** * = x2 = %.2f",(-b + sqrt(D))/(2*a));
* ** ** * * ** *** * * *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** * * * ** ***
** * * * * * * ** **
int main()
{
* *** * * * ***** *** ********* a,b,c,D = 0,x1 = 0,x2 = 0;
***** **** * *** ** * * * ** *** * * * *** * ***** *** **** *

* * ** ** * *** ******* * of %.2fx^2 + %.2fx +%.2f = 0 * * ** * **
** * * * * *** ** * ** = (b*b-4*a*c);
* * * *** ** ** * * * (D < 0)
* ***** ** * *** *
* * ** * ** * ** *** ****** complex and * *** **
*** ** * ** ** **** * * * * = * ** * *** * * *** *** ** *
** * * * *** ***** ** ** ** *** * = *** *** *** ** ** **** ** *
* ****** *** * *
** ** ***** * * * * *** (D > 0)
** ** ** ** * * ***
* * ** *** * * *** * * * * ** real and * ** ****** ****
* * * ** **** ******* * ** * ** = * * ** * * + sqrt(D))/(2*a));
**** ** *** * * **** * **** * * *** = %.2f",(-b - sqrt(D))/(2*a));
**** *** ** *** ** ** ***
** * * *** * * * ** ** (D == 0)
* *** * * * *
* * ** * * * * ** * * * real and same\r\n");
* * * **** *** * * *** ** * ** *** = x2 = %.2f",(-b + sqrt(D))/(2*a));
***** *** ** * * **** **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * *** ** * ** * *
* ** *** *** * ****
int main()
{
* * * *** *** ** * ** a,b,c,D = 0,x1 = 0,x2 = 0;
***** * ** ****** * *** ****** ** **** * * *** * * ****

* ****** **** * * * ** **** * ** * * *** ** of %.2fx^2 + %.2fx +%.2f = 0 are",a,b,c);
** * * ** * ** ** * * = (b*b-4*a*c);
****** * * *** * ** * * *** = (-b + sqrt(D))/(2*a);
* *** * * ** *** *** = (-b - sqrt(D))/(2*a);
** ** * * ****** ** * * (D < 0)
* * *** ***** * *
* * * **** * * ** ** *** * * ** * complex and * ** **
* ** * ** *** * * * ** ** * * ** = * * * * * * * * * ** ***
* *** ***** ** * ** ** * *** * = * * ** * * *** ** * * * ** *
* ** *** ** **** *
* ** ** *** *** * * ** ** (D > 0)
** * ** ** * ***** *
* * * *** * ***** * ** ** * ** real and *** * **** *
* * * *** *** ** ***** * = ** * ***
*** * * ** *** *** * *** = %.2f",x2);
***** * **** * * * * *
* * * * ** * ****** (D == 0)
* * * * ** **** * * * ***
* ** * ** *** * *** ** * * * real and same\r\n");
* * * *** ** * ** ** ** **** * = x2 = %.2f",x1);
** * ** ** * ***
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.178.45
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users