0 like 1 dislike
18.4k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 18.4k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
** ** ** *** * *
***** * * * * ***

int main() {
** * * *** *** ***** ****
** *** ***** *** *** * **** ** * * %f ** * &a, &b, * * *
** ***** ** * * ** * ** * *
* *** * * ****** * * * {
* * * *** *** * ** * * ** * * * * ** * ** *** ********* of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** * *** = * * *** = *** *** a, b, c, (-b)/(2*a), * * * (-b)/(2*a), * * * *
** ** * * **
** **** * * * * ***** if(d==0) {
*** * * *** * ** * * *** *** * * ** * ** ** ** ** * * * **
** ** * * ** ** *** *** * * * * ** ** ** * * ** * **** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** ** a, b, c, x1);
* *** ** *** *** ** * *
* * * ********** ** * ****** *** * {
* * ** * ***** * *** * ** *** ***** * * * * * *** ** * *
*** ** ***** * * *** **** ****** ** * * *** *** * *
*** * * ** * ** * ** *** * * * * * * * ** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and * * *** = %.2f\nx2 = * ** *** a, b, c, x1, x2);
* * * * * ***** **
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** ** * *
* * * * * * ** **
#include *** * ****

int main()
{
* * * **** * ** *** *** * * * * ***
*** * * * * * *** * * * * ** * %f ** ** * *** ** * * *
* *** *** *** * * **
* * *** ******** ** * ** *
* ** ** **** ** * ** ** *** ***
***** ***** **** * * *** ******
* ** **** * ***** * * ** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and ** * * = %.2f\nx2 = ** ** * *
* * *** ** ** *** * *** if(D==0)
**** ** ***** * ** * * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** ** * * *** **
* *** ** ** * * * ** **
* ** * * *** ** * ** **** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * ****** = ** * * = * * * * * *** **** ** ** *** ** **** *
** *** ** * * * * * * * * *** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** **** * *
*** **** * * * * ** *
* * * * ** * *

int main()
{
* * ***** ** * * *** * * * *
* * * ** ** * *** * ** * %f * * * *** *** * * **
** ** * ** **** * **** * * ***
******** *** *** ** * **** * ***
* **** *** * *** * * ** ***
*** ** ** * * * **** * **** **
** ** ** ** * *** ** * * * * ** ** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * ** * = %.2f\nx2 = ** **** * * ** *
** * * ** * * ** ** *
* * * ** ***** * * *** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** ** * * * *
*** * ** *** ** ***** **
* * ** * ** * ** * * *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * *** = %.2f + * ** = %.2f - * ** ***** *** * **** * * * ***
* ****** ** ** ****** * * ** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
* * * ****** ** ** * * a,b,c,x1,x2,D;
* ** * ** * * ** * * *********** %f *** ** * *** * * ****** *
* *** * **** * * ***
* * * ****** * *** * = (-b + sqrt(D))/(2*a);
*** ** * * ***** ** * *** * = (-b - sqrt(D))/(2*a);
** * *** ** * ** ** * ***** *
*** * *** ** * *** * ** * *** ** * *** *** * **
* ***** ***** * ** *** * * ** ** * **** * * ******** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\n",a,b,c);
****** ** ** ******** *** ** * ** * * **** *** **** * ** **** = %.2f\n",x1);
* ** ** * * *** ** * ** * * *** * ** ******* ** * ** **** *** ** * ** = %.2f",x2);
****** *** * * * * ** ******* ** * * ***
* * * * ** * **** * * * if(D==0)
**** ** * * * ** * *** * * *** * ** * * **** ****
* * **** * **** ** * *** ** * * * ******* * *** ** * * * *** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
**** * ** *** * ** **** ** ******* *** ****** ***** * * ** *** * ******* * = x2 = %.2f",x1);
*** * ** * * * * * ** * * * * ** * ***** *
* ** *** * ** **** ** **
* ****** * * * * * * *** ***** * ***** *
** * * * * *** ** * *** * ** ** *** ** ** * *** ** **** ** *** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\n",a,b,c);
**** *** * * ** * * ** *** *** * * * ** * **** * *** * * **** * = * * *** ** * * *
* ** * * ** ** * ** * ** *** ** ** * **** * *** * ** * ** * * * *** * * = * * * * ** * **** * *
* **** ** ** * ** **** * ** * ***** ***
*** ** * * * ** * * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
** ** * * * * * ** ** a,b,c,x1,x2,D;
* **** ****** * ******* %f * **** ** ** *** * * * **
* *** * ** ** ****** *** ***
***** ** **** *** * * * * = (-b + sqrt(D))/(2*a);
****** * * *** **** * *** = (-b - sqrt(D))/(2*a);
*** * **** ******* * *** ***
** * ** ***** ** ** * *** * ** * * * * ** ***** **
** *** * ** ** * ***** * ** *** **** * ** ** * * * * **** * * *** of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
* * ** * * ** * **** ** * **** * * ********** * ** ** * * * * * ** ** **** ** * = %.2f\n",x1);
** *** * ** ** * **** * **** ** ** **** **** * **** *** ** ** * * = %.2f",x2);
* * *** *** ** ** * * * * **** ** *** **
* * ** * ** ** *** * if(D==0)
** * ** *** * * * ** *****
* * * * **** ** ** * ** *** *** * ** ***** * *** * *** *** * ** ** of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
* * ** * ** * * * ** *** * * *** * * * * ** * = x2 = %.2f",x1);
** * ****** ******* ** ** * ** ****
* ** ****** * ******* *
*** * ** ******* ** * * * ***** * * *** * * * * ****
* ** * * ** * ****** ** * **** * * * * ** * * ** *** * * * *** ****** * * * ** * of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
*** ** ** * ** ** *** * * **** ** * **** ** * * * ** * *** ** * * *** * * = * * * ** * * * *** ****
*** * * * * ******* * *** *** * ******* **** * *** ****** **** *** * ** ** = *** * * * *
* ** * **** * * * ** * ** * * * * ***
**** * * *** * *** **** 0;
}
answered by (-258 points)
0 0
prog.c: In function 'main':
prog.c:13:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:19:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:24:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
0 like 0 dislike
Hidden content!
**** * ** ***
*** * *
int main()
{
*** * ** * ** ** * *** **** a,b,c,D = 0,x1 = 0,x2 = 0;
*** ** * * ** * * ***** ** * ** * ***** *** * * *** *

** * * * * *** ** ** *** ** ** ** of %.2fx^2 + %.2fx +%.2f = 0 * * * *** * *
*** * ** ** *** ** = (b*b-4*a*c);
* *** * *** * * ** ** (D < 0)
* * ***** ****** * * * *
**** ** * **** * * ** *** **** ** complex and * * **** **
*** * * ** ** * * * * * * ** * = * ********** * * * ***
* ** * ** ** * *** * * ** * * ** = * * * * ** ** *** *** *** ***
* *** ** * * * **** **
*** * *** *** ***** * * (D > 0)
*** **** *** * *
* ** ** * * * ** **** * real and ** * ** * *
******** * ** * * * ** *** = ** ** ** + sqrt(D))/(2*a));
**** *** * * *** *** * ** * ** ** = %.2f",(-b - sqrt(D))/(2*a));
* * * * * ** * ** *******
** * **** * * ** * (D == 0)
* * ***** ** * * ** * **
** ** ** ** * ***** **** ** ***** ** real and same\n");
*** **** * ** *** *** * ** *** * = x2 = %.2f",(-b + sqrt(D))/(2*a));
**** * * * ****** *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
your output lack of 1 space at line 8 when print out "Roots of ..."
0 like 0 dislike
Hidden content!
* *** ** *** **
* *** * ** *** * *
int main()
{
* ** * * ** *** ** *** a,b,c,D = 0,x1 = 0,x2 = 0;
*** ** ** ****** *** * ** ***** * ** * *** * *** * * *

** *** * *** ** * * **** ** of %.2fx^2 + %.2fx +%.2f = 0 ****** * * ***
* * ** * ** * * *** ** * = (b*b-4*a*c);
** * * *** ** **** ** (D < 0)
*** * ** ** *** **** *
** ***** ** * * * ******* * ***** complex and * *** *** **
** ** ***** ** *** ******* **** * * ** * = ** * **** ** * **** **** * ***
******* *** ******** ** * * *** = * *** ***** ** * * *
****** * * * ** * * **
* * ** ** * * * * (D > 0)
* * * * ** ****
***** * **** * ** * ** * * real and * * * * ****
* * * ** ** * *** ** ***** *** * ** = * * * + sqrt(D))/(2*a));
* ** ** * * *** ** ** * ** ** * = %.2f",(-b - sqrt(D))/(2*a));
* * * * * *
*** **** * * * * * * (D == 0)
**** * * ** * *** **
**** ** * * ** *** ***** * * real and same\n");
** ** ** ** * * ******* ** * * ** ** = x2 = %.2f",(-b + sqrt(D))/(2*a));
* *** ** *** *** * * ** **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** * ** ** * ** *
** * *
int main()
{
** ** ** * * * *** ** ***** a,b,c,D = 0,x1 = 0,x2 = 0;
** * ******** *** ** *** ** * ** ******** *** *** * *

* ***** * * *** * *** ******** * of %.2fx^2 + %.2fx +%.2f = 0 * * * *
* * * * * **** *** * ** = (b*b-4*a*c);
** *** ** ** * * (D < 0)
** * * ** * ******
**** ** ** * * ** * *** *** * * complex and ** * **** * *
*** ******** ** * * ** * * ** * = *** * * * ** * ** * *****
* * ** *** * * ** * * **** * ** ** = * * * **** *** * ** **
***** * ** * ** ***** * ****
** * ** * * ** ***** ** (D > 0)
* * ** * ** ***
** *** *** ** * * ** * * ** real and * * *** * ***
* * * * *** * * * * * *** * = * *** *** * + sqrt(D))/(2*a));
** ** ** * ** * ** **** ******* = %.2f",(-b - sqrt(D))/(2*a));
**** ** ** * * ** * **
*** **** **** *** * (D == 0)
* * ** ****** * *** *
* *** * ********* *** * * * * real and same\r\n");
****** *** * * ** ** * ** * * **** = x2 = %.2f",(-b + sqrt(D))/(2*a));
* * **** ********
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
***** ** ****** *
******** * ** *
int main()
{
**** ** * * * * *** * *** a,b,c,D = 0,x1 = 0,x2 = 0;
*** * *** **** * ** * ** ** * *** * ** ** *** ** ** * *** * *

** * * **** ** *** ******* of %.2fx^2 + %.2fx +%.2f = 0 * * ***** * *
* ** * ** * ** * * *** = (b*b-4*a*c);
* ** *** * * ** (D < 0)
* * ** * * *** * **
* *** *** ** * ** * ** * complex and ** ** ******* *
* * * * * *** * * ** ** *** * = ** * ** * * *** * *
** ****** * ** ** ** ****** ****** * * = * * *** ** * * ****** * * *
* **** * * * * ** **
** * *** * ** **** * *** *** (D > 0)
** * * * *** * ******
* * * ** * * ** real and ** ** * * *
** * * * ****** * * * = * ** ********** + sqrt(D))/(2*a));
* ** ******** * * * ** * * * ** * = %.2f",(-b - sqrt(D))/(2*a));
** *** * * **** ** * * *
* * ** *** *** ** *** * (D == 0)
* * ** ** * * *
* * * * ** * * ******* ** ** real and same\r\n");
* * *** ****** *** *** * = x2 = %.2f",(-b + sqrt(D))/(2*a));
* * *** * * ** * **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
****** * *** * *
***** ** * * *
int main()
{
* ** * ** * **** a,b,c,D = 0,x1 = 0,x2 = 0;
* * * ** **** * ** * * ** * *** ***** * ** *** *** *

** **** * *** * ** ** * * * *** of %.2fx^2 + %.2fx +%.2f = 0 are",a,b,c);
* * ** * * *** * ***** = (b*b-4*a*c);
* * **** * * ** ** * *** = (-b + sqrt(D))/(2*a);
** ** * * ** ** * * = (-b - sqrt(D))/(2*a);
* * ** ** * ** *** * * * (D < 0)
* * ** * *** * ** **
**** *** * **** ** *** * **** ** ** complex and * * * * * *
**** **** ** * * ** *** ** * = **** **** ******* * ******* **
* ** *** ** * ****** ** ** * = * ** *** * ** **
*** ** * *** ***
* * ** * **** *** * *** * * (D > 0)
****** ** * ** * ** **
* ** * *** *** ** *** * *** * real and ** * * ***** **
** *** * ** * * * * * * * * = ***** **** **
* * * *** * ** * * * = %.2f",x2);
* * ** * * * * ** * *
* **** * ** * * (D == 0)
*** * * * ***** * *
* ** * * ****** * ** * **** ** real and same\r\n");
* ** * **** * ** *** * * = x2 = %.2f",x1);
* * ** * * *** * *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.109
©2016-2026

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users