0 like 1 dislike
13.1k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 13.1k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
* * *** * *
** * * * * ** * *

int main() {
* ** * * * *** * * * * ***
*** *** * ** ** * * ** * *** %f * * * &a, &b, ** * * *
*** * **** * * **** ** * * * *
* * *** ** * ** ** ** ** {
* * *** * * * * *********** ** ****** ** ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * *** = * * = * * ** a, b, c, (-b)/(2*a), *** ** *** (-b)/(2*a), ****
*** * **** * * ** * * *
* * * ******* * ** ** ***** if(d==0) {
** *** * * *** ** ** * *** * * ** ** ** ** ***** ** ***
* ** ** * **** * ** *** *** * ** ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * *** *** a, b, c, x1);
** *** * *** *** **
**** ******* ** ** * * * * {
* * *** * ***** * * * ** *** **** * * * * ****
** ** **** * ******* * * ** * * * **** * *** * *
* ** ** ** * * ** * **** ** * * **** * * * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and **** = %.2f\nx2 = * * ** a, b, c, x1, x2);
***** ** * * * * *** **
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** * * * *
* * *****
#include * ** **

int main()
{
* ******* * * ** * ** ******
* * **** ** ** * * %f * *** ** ** **** * ** * * * *
* * * * *** * * * ** ***
* **** * * ** * * * * * * * **
**** * *** * * * * *** ****
*** * ** * * *** * * * ** ***
****** *** *** ** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and * = %.2f\nx2 = ** ** * ** * **
** * ** * * * * ****** if(D==0)
** *** ** * ** * ** * * ***** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * *
**** * * * * *** *
** *** * * * * * * * *** **** of %.2fx^2 + %.2fx + %.2f = 0 are complex and *** * = * * = ** * ** * ** * ** * ** *** * * * *
* ** *** ** ** * * *** * **** 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * *** ** **** ***
** *** ***** **
**** * ** * * * *

int main()
{
* ** * **** * * ******** **
* ** ****** ** * *** ****** ** %f ** **** ***** ** *
* * * * * * * * ** ** * *
***** ** * * **** *** * * * * **
* ** ** **** * * * * * ** ** * ***
**** * **** *** * ** ** ** *** **** *
* * * *** ** * * ** *** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and ** *** = %.2f\nx2 = * * ** ** *
* *** ** * **** *** * * ** ** * * *
* ** *** * * **** * *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * ******* * * * *
* * * * * * * * ***
***** *** * * ** *** * ***** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * ** * = %.2f + = %.2f - ** ** ** * ** * * * * *** * * *
** * * * * * ********* 0;
}
answered by (-498 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
**** *** * * * ** * * * ** * a,b,c,x1,x2,D;
** * * *** ****** ***** * ** *** * %f * * *** ***** ****** ****
**** ***** * ** * * * **** * *
** * ** ** * ******** * = (-b + sqrt(D))/(2*a);
** * ** ** * * * * = (-b - sqrt(D))/(2*a);
* * ** * ** *** ** * **
* **** * ** * * * ***** **** ** ** ** ** ** *
*** ** ** ****** * ** ** ** *** * * * * * * ** ** ** ** * *** * ***** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\n",a,b,c);
** ** ** ** ** * * ** * * * * ** ** ** ** ***** * ** *** * *** = %.2f\n",x1);
* *** * * **** * * * **** * * * *** * * * *** * *** * **** * ** * * ** * * = %.2f",x2);
* ***** * ****** ***** * ** *** * * **
*** * *** * * * ** *** if(D==0)
* * *** *** **** ** * * **** ** *** *** * *
** * *** ** * * *** * * * * * * * *** ** * * * ** * ***** * ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * * * * * ** * ** * *** * * **** *** ** ** *** ** ****** ** * ** ** **** * ** = x2 = %.2f",x1);
** ** * * * * ** ** * **** * ** *** **
* ***** * * * ** * * * *
* * *** * * * ** ** * * **** ** ** ** * **
*** * *** * ******** * * * * * * * * * * * *** **** * * *** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\n",a,b,c);
* * **** * **** ** * ** ** ******** ** * ** *** ** ** ** * ** ** * * * = * * ** ***** * * * * **
*** ** ***** * *** * * * ** **** ******** ** * ** * * * * ** *** *** ** *** ** = * * * *** ** *** * *
*** ***** * * ** * *** * ** ****** **** * * ** *
** * ****** *** * * **** * * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include<math.h>
int main()
{
* * * ** * * a,b,c,x1,x2,D;
*** ** *** ** ** ** **** ** ** ** ** * %f * ** * * * ** * * *
** * * * **** * *** *
* * * **** * ** ** * = (-b + sqrt(D))/(2*a);
* * * * * ** * * * * * * = (-b - sqrt(D))/(2*a);
* *** *** **** * * * **
* * * ** *** *** ** **** *** *** **** * * **
*** **** ** ** * *** ****** **** * ** * **** ** ** **** * ** * * * of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
* * * ** * * * * * * * * * * ** *** **** **** * ** **** ** ** * * * ** = %.2f\n",x1);
* * ** * ***** * * *** ** ** * * * * *** ** *** * * * * * * = %.2f",x2);
** * ** **** * * * * * * * * * * * * **
* ** ** **** **** ** if(D==0)
** *** ** * * **** ****** * * ** ****
*** **** * * **** ** * * **** ******* * ** * * * ** ** ********** ****** *** of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
* ***** * ** * *** ******** *** * *** *** * ** *** ** **** **** * * * **** * = x2 = %.2f",x1);
*** * * ** ********* ** *** * * * **
* ** * **** * * * *** *
* * * ***** ** * * * ** * **** *
* * * *** **** * ** ** * ** **** *** * * * ** * ** **** **** * ** **** * * ** ** * of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
* ** *** * *** * **** ******** ** * * ** ******* * ***** ** *** * * *** * ** *** = * * ** ** * * * * ** ** *
** *** * ** * * **** * * * *** ** * * ** **** * ** ****** ** = * *** *** ** * * * **
* ** **** ***** * ***** * * * ** **
* * * * * * ***** **** 0;
}
answered by (-258 points)
0 0
prog.c: In function 'main':
prog.c:13:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:19:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are real and same\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:24:20: warning: too many arguments for format [-Wformat-extra-args]
             printf("Roots of %.2fx^2 + %.2fx + 1.00 = 0 are complex and different\n",a,b,c);
                    ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
0 like 0 dislike
Hidden content!
* ** * * * * * * *
*** ** * *
int main()
{
**** ***** *** ***** * * a,b,c,D = 0,x1 = 0,x2 = 0;
** * * *** **** ** * * * * ** * * ** * ** * * ** ** *

** **** *** * * **** * ** * * of %.2fx^2 + %.2fx +%.2f = 0 ** ** * ****
** *** * *** * *** ** * = (b*b-4*a*c);
*** ** ** ** * * ** (D < 0)
* * * ** * ** *** * * **
* ** * **** * * * * * * *** * complex and ** *** *****
** ** ***** * * ***** ** * = *** ** **** * ** *** ** * **
** * * * * ** **** * * * = ****** *** * * ** *** * **
* ** * **** * *** *
* * ** ** * ** * *** (D > 0)
** *** * *
** * ** ** * * * ** ** * * real and ** * ** **
** ** * *** * * * * * *** **** = * * ** + sqrt(D))/(2*a));
* **** * * * * *** * *** = %.2f",(-b - sqrt(D))/(2*a));
** ** **** * ** * ** *
* * * * * ** * ** * ** ** * * (D == 0)
** * * *** * **** ** *
* * * * * ***** * ** *** * * real and same\n");
* ** * ** * ** *** * ** * = x2 = %.2f",(-b + sqrt(D))/(2*a));
* *** * ** * ***** *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
your output lack of 1 space at line 8 when print out "Roots of ..."
0 like 0 dislike
Hidden content!
** *** * **** * *
********* * *****
int main()
{
*** ** * ** ** * **** ** a,b,c,D = 0,x1 = 0,x2 = 0;
** * ** *** ** ** * * *** * ** *** ***** ** ** ** * *** *

* **** *** **** * * ** * * * * of %.2fx^2 + %.2fx +%.2f = 0 * ******* ***
*** ** **** **** * ** = (b*b-4*a*c);
* * *** * ** * ** (D < 0)
** ** *** ** * * * ***** * **
*** ** * * * * *** complex and * * **
* ** * ** *** ** ** ** = ** ** ** ** * * * * *******
* * * * ** * * * **** = * * ** ** ** *** ***** **
** ** * * **** * * *
* **** ** **** ** * * *** (D > 0)
***** ** ** * * ** ****
* ** ** ** ** * * * real and *** * * * ** *
***** * * * * *** * ** * * *** ** = * ** ** * * * + sqrt(D))/(2*a));
* ** * ** ** *** * ** ***** = %.2f",(-b - sqrt(D))/(2*a));
** * * ** *** **
*** * ** * * (D == 0)
*** **** **** ** * *
** ******* * * * * ** * * * real and same\n");
**** ** ** * * * * * **** ** **** * = x2 = %.2f",(-b + sqrt(D))/(2*a));
* * *** **** ** ** * **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* *** ** * * ** * **
*** *** ***
int main()
{
* * ** * ** * * a,b,c,D = 0,x1 = 0,x2 = 0;
* ** ** ** ** **** * * * *** * ** * * * * ****** * **

* ***** ** **** ** ****** ** ***** ** * of %.2fx^2 + %.2fx +%.2f = 0 * *** * ***
* ** ****** ** * ***** = (b*b-4*a*c);
*** ***** * * * *** ** * * ** (D < 0)
**** * * * * **
** ** * ** *** * * * **** ** * * complex and *** **** ** *
* * *** ** * * * * *** * * *** = ** * * * * * * *
* * * *** *** * **** ** **** ** = * ** * **** * * * * ** * *
* ** **** *** *
** * ***** * ** * * * (D > 0)
** * * ** * ***** * * * **
** **** ** *** * ** ***** real and ***** *** ***
***** * * * ** * ** ** ** *** * * * ** ** = * * * + sqrt(D))/(2*a));
**** * * * * * ****** ** ** *** ** ** * = %.2f",(-b - sqrt(D))/(2*a));
* ** * ** * * *
* * * ** * * *** * (D == 0)
* ***** ** * * * **** **
* ** ** ** **** * ** * *** ** real and same\r\n");
** ****** * * * * * ** * ** = x2 = %.2f",(-b + sqrt(D))/(2*a));
* *** ** * * *** * * **
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * * ** * ** *****
** * * ** *** ***** **
int main()
{
** * * ** ** * a,b,c,D = 0,x1 = 0,x2 = 0;
* * ****** ** ** ** * ** * **** * * ** * ** * * * * * * * *

* * *** * * *** **** ** * * **** * of %.2fx^2 + %.2fx +%.2f = 0 * **** ** * *
* **** * ** * * *** ****** = (b*b-4*a*c);
** ** * * *** ***** ** ** (D < 0)
***** * ** **** * * **
****** * * *** * * *** * *** * * ***** * * complex and * * * **
* ** * ***** ***** **** *** *** * * * = * * ***** * * * * **** * * *
** * * * * ***** * * * ** *** * = ** * ** *** * * * ** *
* **** * * *** ** ***
** * * ***** * * *** (D > 0)
* * * ** **
* * ** ** ** * * * ** * ** * * real and * ** * * *
* ** ** * * * ** * * * * * * * * = * ** + sqrt(D))/(2*a));
* * * * ** ** ** * * * * * = %.2f",(-b - sqrt(D))/(2*a));
****** ** * ** *** * ** **
* **** * * * * * ** * (D == 0)
****** ****** ****
** ** ** * * * ** * ** *** **** real and same\r\n");
* ** * * * * * * **** * ** * *** = x2 = %.2f",(-b + sqrt(D))/(2*a));
** ** ** ** * *
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** * **** *** * * **
** ** ** * ** * **
int main()
{
* ** ***** ** ** ** *** a,b,c,D = 0,x1 = 0,x2 = 0;
*** **** ****** * *** * * * **** ***** * **** ** *** * ** *

* **** *** * *** **** * * ** **** of %.2fx^2 + %.2fx +%.2f = 0 are",a,b,c);
** ** * * * * ** *** ** = (b*b-4*a*c);
***** * ** *** *** * ** = (-b + sqrt(D))/(2*a);
** * ***** * * * * * = (-b - sqrt(D))/(2*a);
** ** ** *** ** * * (D < 0)
* ** * ** ** ** * ** ** **
* *** * * ** ** ** * *** ***** complex and * **** **** ***
********* ** * * * ** ** *** * = * ***** **** *** * ** ****** *
* ** **** ** * * * * * ** * ** * = * ** * ** * **** ***
****** ** * * ** * *
*** * * * * ** ** * * (D > 0)
****** *** * *
** * * * ** * * * * ** ******* * real and * * *** ******
*** ** ** ** * ** *** * ***** * = * *** **** ** *
*** * ** *** ** **** * * ** * * * = %.2f",x2);
* * *** * ***** *** * ***
* ** ********** * ** **** (D == 0)
* ***** **** * ***
**** * * ***** * *** * * ** * * * real and same\r\n");
* * ** ** * * ** ** *** ** *** * * = x2 = %.2f",x1);
* * * ***** * ****
}
answered by (-214 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.241.160
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users