[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
#include  * * ** ******  * ** 
#include  **     *    

int main(int argc, char *argv[]) {
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* *** *   * * * * 
** * *    * ** 



  * *** ** *** return 0;
}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include  *  * ***** *   ***
#include ** * * **   *  ** *

int main() {
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*  *****   return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include * *   *****   *
#include *** **** **   

/* run this program using the console pauser or add your own getch, ****  **   ** ****    or input loop */

int main(int argc, char *argv[]) {
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

Hidden content!
  **  **  ******  
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int main(int argc, char *argv[])
{
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*  *** ** ** ** ***** *   *  0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
* ******  ****    * * * * * your input : ");
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* **  ****** ** * *   

    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
  *  * **  ** ** *
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int main(int argc, char *argv[])
{
***   *       *** *  ** * * * * i, a;
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*   * ** *** * **   **** * ****   * * ** **** &i);
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*    ** *  * * * * * ***   * * (i=1)
* * *  *  * * *  * *     * **     *  ********* ***    ***  * * * * ***
*** ***  ***  **  ** ***      0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
** * ***         *  *
 * ******  ** **       
int main(int argc, char *argv[])
{
 ***   ***** *** * * ** *     * i, a;
* **  ***   *     *  ****  *****   ** *   your input:");
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* *** * *   ****    **** *   * ***     a<i; i--)
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****    *****  ** **       * (i=1)
   * ***  **   *** ** **** * **  *** *   ******  ** **  ** **  **** * 
*  **  ** *       ** *  **  * *** 0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
*      **  *  ** **
* *    *   ***** *** 

int   * ** argc, char * ****** {

**   *  * * * int a=10;

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** * * ** * ** ** ** * **** 
* *  *   *****     a != 10 );
*  * * ***   *   * * * 
 *     * **  ******  *** 9 8 7 6 5 4 3 2   *** **** 
  * * *  * **   *  *

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
 **** *    ** ** *** ** 
 *  *   **    **     **

int  **  argc, char *****  {

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*  ****     *  *      **  *   * **  ** *  ** *  **  * *      *** is too high!  ** ***
*    *** **  **   * *  a != 10 );
 *    **     * * 
   ** * *  **   *    *  ***   9 8 7 6 5 4 3 2 ** *** *
* ****  *  ***   ** 0;
}

Comments

Case 0: Wrong output