[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
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#include * * *      ****  

int main(int argc, char *argv[]) {
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**      * ** *   **     **  **  *      * if(i == 0){
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**  ** *  * 
* *  *  * *  



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}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include *  ***  *  *  *
#include  **     * ****

int main() {
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*** ***  *** **  }

* * *   return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include *    ** * * *
#include  ***  * ** * 

/* run this program using the console pauser or add your own getch,  *       ** **  ** * or input loop */

int main(int argc, char *argv[]) {
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

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int main(int argc, char *argv[])
{
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}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
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** * **  ***          

    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
 * *** * *         
 * ***    *** **  * *
int main(int argc, char *argv[])
{
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**  *  **  ** *  ** ** *  **  ***         your input:");
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*  ** ****       **  **  *** *   **** * ** * * ** ******* * * ** * *     *
 * * *** *** ***   *   * ***      *    0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
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  * *      *  ** ***** 
int main(int argc, char *argv[])
{
*    ******** *   **       i, a;
*  ** ****  * * * *   * * *  ** ** * *  *  your input:");
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** *  *** *    *  *  **  *    a<i; i--)
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****      * **  ** * *** * * (i=1)
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  * **   *  *** ******  **  **   0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
    **  **    ** *****
  * * **       *     ***  

int *  **** argc, char  *    {

 ***    *  *** ***** int a=10;

*  * * *** * ** do{
***   * *  *   **** ***    ****  ****     your  ** *   **  
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*   *  *   **** * *   ** * 
  ***   **  ** *   * *  a != 10 );
  * *   *   *  *** 
****   *    ** * ** *    * **  9 8 7 6 5 4 3 2 **  *  * ***
 * * * **    * *     * 

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
          * ***   ****
* *      * *   * *  ***

int      argc, char  ****  {

  ** * ******* int ** 

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*    ** *  *   * ** *   *   *   if( a     10)
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 ****     **               
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****  *  ***   ** *** ** **   * *     ****  *  *  * * **           is too high! *   *  * * 
    ** * ***  *  *    * a != 10 );
  **   *       * *   
**** *   ****   *  ** ** * ****** 9 8 7 6 5 4 3 2 **  * *     
**** *** *  * *** 0;
}

Comments

Case 0: Wrong output