[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
#include   *  **  * 
#include *  ** **** ** ****

int main(int argc, char *argv[]) {
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*** ** **   *  return 0;
}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include  **** * *  *  ** 
#include * *   *  *** * *

int main() {
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*  * *      return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include * *   *   * ** 
#include * ***** * * * * 

/* run this program using the console pauser or add your own getch,   **   **** ***  ** ** **     or input loop */

int main(int argc, char *argv[]) {
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

Hidden content!
* *   **   * ******
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int main(int argc, char *argv[])
{
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** *** **  * * * * **     ** 0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
* **   * *    *   *** * *   your input : ");
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    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
**  *  *  ***  **   **
** ** *  **  *  * * ** * *   
int main(int argc, char *argv[])
{
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*** * **     *** * *    (i=1)
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*  *    *  *  * **   ******   0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
   **  **  *******   
***** * **  * *** *  
int main(int argc, char *argv[])
{
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*  * * * ** ** **   **** *** * ***** **  *** * * ******     *    **  * *******    ** 
* * **** *     * *      *     **    * 0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
***   *     **  ** *   *
   *      *  * * * ****

int ****   argc, char    {

 *   * **** ** int a=10;

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  **  *     ***     ** ** ***   
*         *    *  a != 10 );
*  *** *       * 
   * * * ** *   ** *  * * 9 8 7 6 5 4 3 2 * **   *  * *
* ** *  ***  ***  ** 

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
* *   *    * * * * ** 
     **   **   *  ** **

int     * * argc, char *      {

*  ***  *  * int   *

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*   * * *   *     ** *   * **  if( a   ** 10)
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*** * * * ***  *  ** *     
**  *    *  *  **  * ** *  ** *   if( a ** *  10)
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** *        * *   **  a != 10 );
   *   **  **    ** 
 * *  ***    * * *   * *  9 8 7 6 5 4 3 2   ***    * *
* **   *  *  * * 0;
}

Comments

Case 0: Wrong output