[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
#include *  *  **** * *  **
#include   * ** * ** 

int main(int argc, char *argv[]) {
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* *   ***  ** ** ****   Your ** **  *  start from here
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**  *   ** * *   * * *   ***** * * *  ** * ***  **
* *   **       ** ** ** * **  }
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   * * *   ** return 0;
}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include *   * ****  ***   *
#include ** ***  *  * ***

int main() {
*** ** ** int a;

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*   *  *    **  *** **    * *   }
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*      return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include ***  **   *
#include *  *  ** * ***  *  

/* run this program using the console pauser or add your own getch,  *    * ****  **     or input loop */

int main(int argc, char *argv[]) {
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***  *** **    *  * ***  ** = *     **
*  *****  *  ***   *   *** = getchar();
** * **    * **  *  ****  = getchar();
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*  * ** ** *** *  **    *  *   =  **     
** *    **  *** *  **** = getchar();


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   **  *  **  ***  ***   **
**  ** *  *** *   ** *   *  0;
}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

Hidden content!
   * * **  ***  **  * 
*  **    ** *  * *  ** *
int main(int argc, char *argv[])
{
*** **     ***     ** ** * *** ** i, a;
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* **  * ******** **   *** **  *** ***** * * * ** * &i);
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*   *** *** ** ** **** ** * * ***   *       *     *   **   *  ** ***  *      ** i);
 *** *** *   *  ** *   ** * * (i=1)
 ** *   ** * ****    ******* ** ****           *  ******  *******  ** ** *
   **  * **  * * *    **  ****   0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
***  **     ** * *  **** ******    your input : ");
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**** *** *** *  *   *   * *    * *  **   * **  ****   *  *   * *  ** ** * **  
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* *  * ***    *  *  * *   ***   **** * ***   * *  *     *   *      *   ***  **  **  **     * ** * ** *     * ***    **
*** **   ** * ** *     **   *  ** * **  * *  *    * *   ** *** *  * ** **  *
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     **  * * *  *  * * 

    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
 ** ** * *** **
 **  *** *  ***** 
int main(int argc, char *argv[])
{
*     ****   *  *    *   **  **** i, a;
** **    *   ** *** *****    * ** ***** **   ** your input:");
 * *****    ********   ***  * ** **  *  ***    * ** *    &i);
** ** *****  *** ****  **   * * * a<i; i--)
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*  ***  *** *   *   *   * **  (i=1)
* *  ***** **** * *      ***  *   **   ** * *  *** ** * *  ***  ***      **
   * ** ******* ***   * * ** *  * 0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
 *  *  * **  * *  **   * 
*   *  * *  ** * * *   *  
int main(int argc, char *argv[])
{
** ****   ** ***   ****  *      ** i, a;
    ***   * *  ** ** *  * *** ** **  ***  *  your input:");
     ***  *   * * * ******   **   **  *    *     * &i);
  * **         * *    * ** ** a<i; i--)
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 * * * *  *   ** * *  *  * **   ** (i=1)
* * ******  * **   *  ** ** *  * *  ***** ****** ** *  ***** **  *  * *****
*  **    * *** * *  *    * 0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
 * *     **  ***  *  **
 * **    * * *** 

int ***   argc, char   * {

** * ** *   **   int a=10;

 *  *  * ***   do{
*** * * *    *** *** ******* * **** *  *  ***  your **  *  *  ** 
**** * **  *  *         ***** * *  * *  *   ** * **  *  * * 
*  *     * *  *  **  **  ** 
* **     **  *  a != 10 );
 *****  **** * 
**   *     ***  * **    *   **  9 8 7 6 5 4 3 2 ** * ***      *
*   **      * ****

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
*   **   * * *   * * * ***
 * *        **  ***  

int   * argc, char ***  {

*   **  *  *  int  **  

  ****  * *   do{
** **  *  **  * ** *** **    *  ** ***  * * *  your ** * ** **  
*  * ** ***  **    ** *  ****  ** ** * *****  *  ****   
*   **  * ** * *     ** * * *    if( a *     10)
*  **   *   * *** *  ** ** *  *  * *  * *    **** *   *   * * code is too low!  *    *
  **    * *   *    **  *  * * *    
** * ***     **  * *** ***   ** * if( a * *  * 10)
* *  * *    *  *  * ***  ***   ***  **   **  * *  ***     *  * *  *  * is too high!  * * * *
     *   **      *  * a != 10 );
* ** *   ** **** 
*  ***   *   ** ***  *  **** * 9 8 7 6 5 4 3 2    * *    *  
* **     *  ** *  *  0;
}

Comments

Case 0: Wrong output