[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
#include *  ** * ***    **
#include   * ** ***   * 

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* *   * ** **  *     ** ** * ******* *  *  **

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* *****     *   * ****   **  }
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      **  *  *  * return 0;
}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include ** **         *  
#include ***** * **    ***

int main() {
* **    ** * * int a;

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* ****** *   return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include  ** *****   
#include  **  * * *** ** *

/* run this program using the console pauser or add your own getch, **     *   *  * ** *  or input loop */

int main(int argc, char *argv[]) {
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

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******* **  
* ** *** ** * ** *****
int main(int argc, char *argv[])
{
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** * **      * *     *** * *   (i=1)
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*  *  * * ***** ******   **  0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
*  **** *** * * ****      *   *  your input : ");
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    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
** ******* * *   **  
 *   **      **    *  * *
int main(int argc, char *argv[])
{
* *        **       *    *   i, a;
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         *  ** ***  *     *     0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
 ***       *   ***  *
***** *   ** ***   
int main(int argc, char *argv[])
{
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  * ***   ** * *  **  * *****   * * * **   **    * **    *      ** * ***  *
 **   * *******  * *  * *** 0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
*  *  ****  * *   ***
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int ***   argc, char  *** {

 *****  ***  * int a=10;

*   * **  * ** do{
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* ****** **  *  **   *   ** **   **  **    ** *   * *   *   
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* * *  **   * **  * * a != 10 );
 * * ***      * 
* *   * * **    *  ******  ***  9 8 7 6 5 4 3 2 *  **   ** 
 *** ** *  ****  ** 

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

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    *   **  *   **     **
*        **    * *  *

int  ****  argc, char   **  {

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****   *** *       * **   
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*** * * ***  * *** ** a != 10 );
**   *    ** ** *  
*      ***  *   **  * * ** 9 8 7 6 5 4 3 2  ** * * ****
*    *   *   *  *  0;
}

Comments

Case 0: Wrong output