[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
#include **  ****  *  ****
#include ***  *   *****

int main(int argc, char *argv[]) {
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* ****     *     ** ** *      your        **   *   ** *    * * ** *** *  * *  ** * DO NOT change
***    *  * **  * *  * * ** *      ** * *

*** * *  ****   **     Your   **  *** start from here
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*  * * * *    ****  *  *** **  ****   *  * if(i == 0){
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*      * ****   * **   *  *   }
    *    * *  
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*     * **  * * return 0;
}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include    ******   * **
#include **  * *   **  ***

int main() {
 ****  * * * * int a;

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  * *****   return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include ** ** *  **   * ** 
#include **  ****** * * 

/* run this program using the console pauser or add your own getch, *  **** **  *  * **  * * or input loop */

int main(int argc, char *argv[]) {
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*** * **  * *  ** ******* = getchar();
*  **** * **  *   *   ** ** =  *     
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* ****** * *** **   * *** = * * ***
** ***  **  ** * ** * = getchar();


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*  *******   **  *   **** * ***  ** * *   * ** *  *   *  * ****   * * *   q +  * ** * * - 'a'));
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*      ***  * *   * *  *** *   0;
}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

Hidden content!
**  *  * *    *  **** 
 *****  *   *** * *  *
int main(int argc, char *argv[])
{
 *******     ****  *   **    * i, a;
* * ***  **   *   *  *** ****  ***  * * your input:");
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* *   *  ****** * *  **  *****  ***  * **** * * *   * * **   *  *  *   * i);
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**  ***  *** ** * *   ****   * *  0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
    ** **  **  ****** **     * ****     *** * *
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*** *  **  ***     *    ** * *  * ** * **  *  ***** ***** *** **  ********  ***
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
  ** ***   * **  *  *** **  your input : ");
  *   *  ***    * **   * * *  *  * ***      *   ** * ***  *** * *  *** ***       * **   * * *** *      *  
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*   * ****   **** * *  ** *  **  *  * *    ***  *  **  * ** * **  ***   
***  *** ** **  *    *  *  *  *  *  * *** * *      *  *     * * ** ******* ** ******** *    * **  *
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*   *****  ***  ** * ***   * * *  **   * * **  *   * * *  *  
***  *   *** *  * *  

    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
*  ***   *******  * *  
**   **      **   ** 
int main(int argc, char *argv[])
{
*** ** * * * * *******    i, a;
*    ***  ** * *** * ***** ***    *  ** ** your input:");
  * **    **** ** ** ** * *  * **  **   *  **     &i);
** ****  **  * * *     **** * *  ** a<i; i--)
*** *** *     **     ** *  **   **  *   *****   *  ****  * *     ** *  *   *   **  i);
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* *  * *    ** **** *****   * * *** * *   * **   ***** *    * **** *  *
**  ** *** * * **   ** ****   ** **** 0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
***  ** *  ** ******** *
*** *     *   *** **** 
int main(int argc, char *argv[])
{
*** *  * **          **   * * * i, a;
*     * * **** * *  ** ****    * *   ** * your input:");
**  ******    *** ** * ***** * *  *** * ** * &i);
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  **    *  ******* ***  ****  * ***  * ** * **  * **    **          * *** *     i);
****  ** *** **  ***** ** (i=1)
  **  *  ** **  *  * *  * *  *    * * ****  *** **  ************   *** **  * *
  ***   ***** *   ****  **** 0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
*****  *   *****   ***
 ***  * * **  *   ***    

int  * *  argc, char     * {

  * * ***    * * int a=10;

*  ****  *  **  ** do{
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*** *   **    *  * *** **  *  ***    * * **  * ** *   * ** *
  * * *       * * *     * *** 
** *** **   **  * * * a != 10 );
* *  ** ****  * 
*  * * *  ***   *****  *  **** 9 8 7 6 5 4 3 2  *   * *  
 * *    ***  *    * 

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
****  *    * ***   * * *
** ** *  ** ***   **** **

int **   argc, char * *** {

**  ***        * int ** *

**** *  *       do{
* *  * ***    *  *   *    *****      *    ** *    your ***    
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**     **   *   *  *     *  *  if( a  ** *  10)
* *         **  **    * ***  ***** *  *   * **     **    *   *** code is too low! *****    *
* *    * *** *     * *  *   ****  
***** ** ** **  **   * *   if( a * *** 10)
*   *   ***  * * *  *****     ** ***    ***** *       *  *  * *  * is too high! *** **
*** * *   * **  *  **  a != 10 );
 * *    * * *  
      * **      * *  ** *  9 8 7 6 5 4 3 2 *** ** 
 *  **   ***** ** 0;
}

Comments

Case 0: Wrong output