[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
#include  * *    *   ** 
#include  *   * *  *  *  **

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* * ****   *** **   ** ***   Your  * *    start from here
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* ***  * *   *    ****     * }
*** **   ** *  
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}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include *  ***  *** *  *
#include   ** *   **** ****

int main() {
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  *  ****   return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include   **  ** ** *  **
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/* run this program using the console pauser or add your own getch, * * **    **   *  or input loop */

int main(int argc, char *argv[]) {
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

Hidden content!
  * *  *******  *    ***
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int main(int argc, char *argv[])
{
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 *   ****** * *  ***  ***    0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
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***   ** *  * *    * *   *   * *** ** ** **   ** *     ***    
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    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
**  * **   ***  ** 
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int main(int argc, char *argv[])
{
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* **** *  **  *** ****  *** 0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
*   ** * *     * ** *** 
** *    ** * * * **    
int main(int argc, char *argv[])
{
 * ** *** **** *   *  ** *  i, a;
*** ** *   ** * ***  ***   **   **** *  your input:");
  **    **   **** ** *  *** **  ** * *     **  ** &i);
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*** *    ** *  *** **  ***    *   *  (i=1)
*   ** ***   **  **      *     *  *  *  * ** * *   ***   **  *   *  **
 **  ******* *  *  *** *** *  *    0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
*    * *** **** ** ** *** 
*** *   * * * **** *** * *

int  *    argc, char   ***  {

 * * *  *  **** int a=10;

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 ** **  **** *    *      *    ** ** *** *** *   ** **
*     *  *   ***  * ****     * * 
    *     ***   * * a != 10 );
 ****     * *** 
* *  * * *  *      * * * ****** 9 8 7 6 5 4 3 2    *  ** **** *
 * *   *   * ** ** * *

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
*  * *  *   * **  **   *  
     *  * ** * ****  

int **** argc, char *  *   {

* *  ** *     int *****

*   ******  *** * * do{
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**  **  *   * * **   ** * *** **** ****   *   * **   
  ** *  ******  *  *         *  if( a  * **  10)
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*     *  *    ** ***  *   **   ** 
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*   *   ** * *** *    *  **  ***  **    ***    *   * * ***   ** * is too high! * *  * 
*  * *  *   **  ***    *  a != 10 );
**  * *  **  ** 
   ** ** **   *  *   **  ** 9 8 7 6 5 4 3 2  **  * *   *
 **  *  ******* *  ** 0;
}

Comments

Case 0: Wrong output