[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
#include *   ***  **  
#include  ***  ** 

int main(int argc, char *argv[]) {
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* ** **   * * * **   **   * *  * *  * ******  if(i == 0){
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***  *       *  *     * *  else
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***   ***   
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 *  **  ***  ** return 0;
}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include  *   * ** *     * 
#include *** *  ** ** **  

int main() {
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** ***    return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include * * ****   *  * *
#include  * * **    *** ** 

/* run this program using the console pauser or add your own getch, *   * * *     * * *** or input loop */

int main(int argc, char *argv[]) {
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

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   *  *  * *  ** *   
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int main(int argc, char *argv[])
{
***  * ***    ***** ***  * *    * i, a;
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   *    *  **** * *****    *  *** 0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
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**** *  ****     **

    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
 * *****  *  * * ***   *
***    ******* **    
int main(int argc, char *argv[])
{
** * ** ** ** * * ***   *   * ** *  i, a;
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* *  *** *   * *  ** **  **  * (i=1)
   ***    ** * *** *  **  ** * **  *   * ***** ** **  * * ***    ** *   * ** 
 ***  ***** **   *   * **  *   ** 0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
*****  *  ***   **** *  
    ** * ** *  ****   *
int main(int argc, char *argv[])
{
*  * *  * * ** *** ** * **    *  i, a;
*   *  **** * ***   *   **  * **    ****  your input:");
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**  *  *     **  **   * *  * (i=1)
  *    *  *   **   **  * * **  **** ***    *  *** **  *     **** **   
 *** ** *      * ***** **** *   * 0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
   * **   * *   * * *  * * 
* * ** *  * ** *   *     *

int   * ** argc, char **   {

 *  *  ***   **** int a=10;

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* * * **   *  *  * ***       *  
  * *** *   ** ***  * a != 10 );
 *    **   ** *  
    *    *      * *******  9 8 7 6 5 4 3 2 * ****  * 
 * *    ** *  * 

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
**   *   ** *  *
*  * * *   *****  

int ** ** argc, char   * *  {

  *   *   ** * * int   

*  * * *  * * * * do{
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*     ****   **     *  ** *  if( a     *    10)
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****       **  * ****     *   if( a  *  *  10)
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***    ***     a != 10 );
   * * *   ** * 
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 ** *    ** *   *** 0;
}

Comments

Case 0: Wrong output