[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
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#include  *    * * * **

int main(int argc, char *argv[]) {
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*** *  *      * * 
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      **    return 0;
}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include * ***     **   
#include  ** * ****  *

int main() {
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** ***    return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include ** ********* ** *
#include * *  * *   

/* run this program using the console pauser or add your own getch, **** * ** *  **  ** or input loop */

int main(int argc, char *argv[]) {
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

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int main(int argc, char *argv[])
{
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*   *** *  * * * ***  *  * ** **  **  ** ** *  **** * *** *   ***** ***** * ****
  ** *  ** * ******* ****  ** 0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
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*   **     *     **** *   *  *    *    * **     ** **  * 
*** ***   *     **

    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
 * ** **   *** *  * *
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int main(int argc, char *argv[])
{
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*   ** * *** * ** *  ** *   (i=1)
      *  **  *** **        *  * ** **  **** * *   *****   *  **   *** * 
**  **   **    * *   *****   * *   0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
* *** **  *  *   **
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int main(int argc, char *argv[])
{
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***     *  * ** *  *** * ** * * *** ** * * *   * * &i);
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*  *  * ** ****  *****    ***** ** ** *    *  ** * *   ** * **** ***  * * 
**  **  ****  ** ** * * * ****  0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

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* *** * ***  *   **
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int ** *  argc, char **   {

 * ***    *  int a=10;

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*   *  *  *  *  * ***  * ***   
  *  ***   *****  *   * a != 10 );
*   ** *    **  
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  **** **  * *    

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
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*  * *     **   *    *   * *

int   ** * argc, char **** {

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**** * *  *  * *     **   * *  if( a   **    10)
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*  **  *     ** *** ** *    *   *  *   *  **  ** *****     **   is too high! *** ** 
* ****      * *   *** a != 10 );
**  *   **  *  
  **       ** **   * **** * *   *** 9 8 7 6 5 4 3 2 *** * * *
  *  *    ** ** ** 0;
}

Comments

Case 0: Wrong output