[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
#include  ****  *     *  ** 
#include  ** ** **   **

int main(int argc, char *argv[]) {
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** **  * **  **  * *      *  ** your   ***  * *  **   * * ***  **** *  ** **  * *****  ** ** * DO NOT change
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**  * **** * *  * * *   *   * Your    * *  start from here
**     ****          ***   ** i;
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**   *    ***   * * **    * * ** * * *  ** if(i == 0){
   **   * ***** * ***   ***    * *  *    *    **
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* **       *   *   **  * *      * }
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*** ** ** *  *  return 0;
}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include **       **   * 
#include * ** **  **** *** 

int main() {
   **     **** int a;

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*** *  *   *   }

     *  **    return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include ***  *   ** **
#include ****  *******     

/* run this program using the console pauser or add your own getch, * * ** *     ****  or input loop */

int main(int argc, char *argv[]) {
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*  *** * * *      * * *** * = getchar();
***** *  *   **  ***   = ** * * 
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* *** *  * * **  **** **** *   = getchar();


* ** *   **  **   **   **
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***   ** *** *  ** * * **  * q >= 'a'    **  * *** q <= 'z' )
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* * **   ***   ** ***       *
****   * **** ** * **** * ** * 0;
}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

Hidden content!
   ***  ** * 
* * * * *    *    * ** * 
int main(int argc, char *argv[])
{
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*     ***** *** ***** * ********  * your input:");
***  *  ***  **  ***    *** ***  **  *    &i);
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*****  *        *    *** ** **    * **    ** *   ******  *** **** *  ***** i);
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* * * * **   *   **** * ***     *   * *  ** * *    **  **  *******  ****** **  ** * **
** ** * ** ** ** * * **     * 0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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**** ** *      *** *   ** *  * * * ** * *  * * * *   *    ****   *  ** *****  * *
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
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*   *   ****  * ** **  *   **** * * *  **  ** *   *  *  ***** *** ***   ******    *   * * *  ** * * *
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 * *    *     *****    

    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
  *   **** *   ** **
****  ***  ****  ***
int main(int argc, char *argv[])
{
     ****   **  * **  ****   i, a;
*  *** ** * **  *   *  *  **      ** * your input:");
**** *  ** *  **    **  **  *******  ****** * &i);
* ** ** * *  * **  **  *   **  *** * a<i; i--)
** **    *   *** *    *** *     *** ** * ** *    ***   *   *  *  *  i);
     *   **        **  *     * (i=1)
*  **  ** *  * * * *  * *  *      ******  ** *      *  * ***** *  *  *
**     ** **   *  *** **  0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
 **    * *** * * 
*  *  **   *    *   **
int main(int argc, char *argv[])
{
******  *   ***  *** **  * *  *    *  i, a;
   *** *       *      * *    * *      *****  your input:");
 *  * *  ***     *     ******    * *  * ** * *  *** &i);
**  ** ****     *    * ** ** *  a<i; i--)
 **   ** **    * * ***** ***    **   *   ** * *****    **    * *** *   ****** i);
*  * * ****** *   ** *   (i=1)
     ***   *  ***** **  * ** *   *  ** * * **  * *  ***  **  **   **         
  **** **  * **   *  ***** ***    0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
    *   ** **  *** * 
 *  *   *  *** * ***  *

int        argc, char  ** * {

*  *     * * *  int a=10;

*****  * *   do{
* * ***   ** ***      ***   **  ***  * *   * * ** * your  * * ***  *
* **     *  *** * *   ** ** *   * ** * * *   **  *   **  ***
 ***  ** **     *   *    **  
*** ** * *   **  a != 10 );
   **   * ** 
 * **  *      *   ** **   *  *  9 8 7 6 5 4 3 2  **  *   *  **
 *  *       **    * *

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
  *** *  *   *  **** *
*  * ** *   **   ****  *** 

int **   argc, char  **  *  {

  *** * *  *  *   int    

*** * **  *  ** * do{
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* *  *   ****  ** * *    *** **   *   ***** *** ** *  * ***
 **** * *    ** * *  **    * **  if( a **  ** 10)
 ******  *     * * *     * **    ** *   * ** *  **** * ** * code is too low!   ****  
  *   *   * * ** **     * *  * 
****  ** * **  ** *  ** * **   if( a **** 10)
* *   * ****  * ***    ***   *  * **  **  *  *** **   * ** *   *  is too high! ***  *** *
   **  *     * * * a != 10 );
  *     * *   
 ** ** *  ** *  *** *   **   9 8 7 6 5 4 3 2 * ** * *   *
 *** **   ** * *   *** 0;
}

Comments

Case 0: Wrong output