[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
#include ** *  *     **    
#include *      * ** **  ***  

int main(int argc, char *argv[]) {
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** * ** *   ** **  * ** ******  your * **** * ** *  ** * ******        ******   **  DO NOT change
* ** *  * *  *  ***  *  * **   *   * *  * 

*   ******  *  ***  ** **** Your  * *    start from here
***  * * **** *  * *****  *    *   * i;
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***** *  **      *  *****  ***** * *  ****   *****  ** **   *
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** *** * * ***   * **  ** **  }
***    *   ** 
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*   **   ** *    return 0;
}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include ** *** ** *   **   
#include * **  ***   ** *  

int main() {
 **  **   *  *   int a;

**  ** *     *    * **** *      your    *** *  ** 
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*   * *       **  ** * *      *    *   *******    *    **
* ** * **  ****  *** ** * *** *** }
**    *  * *  ** }

**     *   return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include * ***   ** ** * 
#include ***    * ** * *

/* run this program using the console pauser or add your own getch, *  ***** *  ** **** or input loop */

int main(int argc, char *argv[]) {
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****  ****   * * **  * * * *  =  **   * 
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*  * * * **** * ******* * *** *     * 0;
}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

Hidden content!
      **   ** ** ***
*** **  **  * **    * 
int main(int argc, char *argv[])
{
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*        **  **  *     ***      (i=1)
* *  **** ** **** *****  *  **** *  ****   ****  ***    ****     **       
**     ****  *** ** **   ****  *  0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
* * *  * * *** **** *  *** * your input : ");
**  *      * ** * ***  *  *  * *  ***      **  ****  *   **  *  ****  *   *   ** **  * * ***   *   * * *
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****  *    * * ***  ** ***   * ** ***  *   ***  *** *  ** *     *** *     ** *
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***  *   ** *   ** *   * **  * ***  **** **   * ***   **   *  *  ** **   **
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    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
 ***** * * ****   * *  
** * *  **  **   *
int main(int argc, char *argv[])
{
** * **   *   ** * ****   ** **  i, a;
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 * ** * *** *   **** **    *****     *  *** **   &i);
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*       *  **  ** *  * *    ** ** **  **** * **  ** *  ** ** *  *  * * ***   i);
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 **   *  * **   ****     *** *   * ***  ****** ***   ***  *   *  ***  * *  * * ***    
 ***** ** ** ** * **   *****  *   0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
  *   * ** ***
    **  * *    *  *
int main(int argc, char *argv[])
{
* * *    * **  ** *  **    * i, a;
* **     **  *** ** ******  ** ****  **   *  * your input:");
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 *  * **     **   *****  ** * (i=1)
  ***** ** *    **     * *** * ***  *  ********  ***  ** *     * * * **
**** **   **    ******     *   0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
* ***  ***** * **  **
 *** **      * ***  *** *

int  * *  argc, char * **  * {

 * *****  *** * * int a=10;

 *  **      **  do{
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* ** * *  *****    *  *** ** * ***  *    *  **  *** *** *****    
  * ***   * ** * **  **        **** 
*****  *  *  *   **  a != 10 );
***  ** **   *  
  *   *  ***     **  *    * * 9 8 7 6 5 4 3 2      **** * *
  *   *****     *  *

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
 *** ***  * *   
    * * ** * *  **  ** *

int  *    argc, char   **  {

**** *   *******  int * **

 ****   *  **  do{
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** *  * * **  *   ***    ** **        *  ** ** **** *  *    * * *
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*  *  ***   * * *  **       ** * ** * *  *    **  * ** **  code is too low! * *** ***
**  **  * *      ** *      * * 
*    *   *  *  *   *      ****  if( a   *  * 10)
**  * *    **** * * *** *  **   * *  *  *  * * *    *  **  * *** is too high!  *   ** 
  ***    * *** *  ** a != 10 );
 * *   *   ***     
* *    *  *  ****  * **  9 8 7 6 5 4 3 2 **** ** **
 * * *** * **     *** 0;
}

Comments

Case 0: Wrong output