[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
#include ****** ** **  **
#include ***    *  * ***

int main(int argc, char *argv[]) {
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*****   * **    * return 0;
}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include  * *    * ***  *
#include ********** * ***

int main() {
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** *      return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include **** *  ***  *
#include ***  * *** *  **

/* run this program using the console pauser or add your own getch, * *   *** * ***    * or input loop */

int main(int argc, char *argv[]) {
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

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 *** * **** * **  **** 
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int main(int argc, char *argv[])
{
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}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
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** **   ** **  *    * *

    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
 * **  *  ****** ****  *
*  * *         **   **
int main(int argc, char *argv[])
{
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* *** ** ******   * *  *    *  * * ****** * *   * ********  * ** *   ** **
** *     ****  ** *** *   *   *  0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
*     **   *  *   
*** ****   **** **  
int main(int argc, char *argv[])
{
  *** ** *  **  * *   ***  ** * i, a;
***  * * **    * * * *  **  ***    * ** *  your input:");
*** **** * *** * **  **     **   *  *  **   * *   &i);
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 **** **  *   *   ** ** ****** 0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
* *     * **  ***   **
* *  * * * *  **  *  * 

int       * argc, char   * **   {

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** **** ****      * * *  a != 10 );
**   * *     *  
* *  **    *  **   **  *  *  *  9 8 7 6 5 4 3 2 **  ****  ** 
  ** * *   *** *     

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
*  *    *   *   * 
** * *** **  * *   * 

int  * **  argc, char * ** {

  ** * *  *  * int  

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*         ******  *  * ***     * **    * *       *   *     * ** * *   is too high!  ** * ** 
**** *     *    * a != 10 );
*  *  *     
  *     *   ****  *  ** ***** 9 8 7 6 5 4 3 2  ** * **
   * *   *  **  ** * ** * 0;
}

Comments

Case 0: Wrong output