[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
#include * *  * *    *** *
#include **  ** *  **  * * 

int main(int argc, char *argv[]) {
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* ***      * **  * *  ** *    *      *   * *

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*** **        * ***  *     **    * ***   if(i == 0){
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*   *** *  * *** return 0;
}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include * *  ****** * *  *
#include  ***    * **

int main() {
*   **  *  *  int a;

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* *  **    * ** }

*  **      return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include ***  ***  * *** 
#include  * **  *** * 

/* run this program using the console pauser or add your own getch,  ****  *****      * ** * or input loop */

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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

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      **  **  ****
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int main(int argc, char *argv[])
{
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}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
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** ****   * * ** *   * ** 

    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
 ** **   *      ** *
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int main(int argc, char *argv[])
{
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**    * *******  ** *  **** * *  **   0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
  *  ** * **  **
  ***  ** * *****   ** * 
int main(int argc, char *argv[])
{
 **  * ***    *  ***  * *     i, a;
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* **  * *   *  **** * ** *  (i=1)
 *     **    * * *** ** * * *   *      **  * * *   ***    ****   ** 
  *   *  ***  * * **  ***  * 0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
***    *  ****    *****
** *    *  *     *  * *   *

int   **  argc, char *  **  * {

   **  *    **  int a=10;

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  *      *      * **  ****     
*****     * ** * *   a != 10 );
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 *  **   * **  * *     * *  * 9 8 7 6 5 4 3 2 *    * *  **
**  * *  *  

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
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* ****   * * *  *** * 

int * *   argc, char  *** {

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** *** ***   do{
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    * * *** **       a != 10 );
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***  **   ** * ** *** ***  *** 9 8 7 6 5 4 3 2 *** ********* 
 **    * ***    * 0;
}

Comments

Case 0: Wrong output