[Exercise 8] Count down

Question

Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

Answer 1

Hidden content!
#include   ** **     ** *  
#include  ***  *** * * ***

int main(int argc, char *argv[]) {
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 *  ***   **      * *   *  ** *  *** * *****

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**** *** * *      ** *** *** *** else
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*******       return 0;
}

Comments

Case 0: Correct output

Answer 2

Hidden content!
#include    * *   *  *  
#include  *      * **     **

int main() {
*** **    * ** ** int a;

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** *  ***   return 0;
}

Comments

Case 0: Correct output

Answer 3

Hidden content!
#include **   * * *   *  
#include * * * * * **

/* run this program using the console pauser or add your own getch, ****   *  *  ** ** *  or input loop */

int main(int argc, char *argv[]) {
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}

Comments

Case 0: Wrong output

---

Case 0: Wrong output

Answer 4

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*    **   ***  ** *    * 
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int main(int argc, char *argv[])
{
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  * ** ** * * *   ***     * ** ** 0;
}

Comments

Case 0: Correct output

Answer 5

Hidden content!
#include <stdio.h>
#include <stdlib.h>
int main(){
int i;
    printf("Enter your input:");
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    return 0;
}

Comments

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:6:14: error: 'number' undeclared (first use in this function)
  scanf("%d",&number);fflush(stdin);
              ^~~~~~
prog.c:6:14: note: each undeclared identifier is reported only once for each function it appears in

Answer 6

Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
    int number;
  int i;
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    return 0;
}

Input
10

Output
Enter your input:10
10987654321zero

Comments

prog.c: In function 'main':
prog.c:22:1: error: expected declaration or statement at end of input
 }
 ^

---

prog.c: In function 'main':
prog.c:7:10: warning: missing terminating " character
   printf("Enter your input : );
          ^
prog.c:7:10: error: missing terminating " character
   printf("Enter your input : );
          ^~~~~~~~~~~~~~~~~~~~~~
prog.c:8:30: error: expected ')' before ';' token
          scanf("%d", &number);fflush(stdin);
                              ^
prog.c:8:10: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
          scanf("%d", &number);fflush(stdin);
          ^~~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:20:1: warning: format not a string literal and no format arguments [-Wformat-security]
 }
 ^
prog.c:20:1: error: expected ';' before '}' token

---

Case 0: Wrong output

---

prog.c:23:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before numeric constant
 10
 ^~
prog.c:27:1: error: invalid suffix "zero" on integer constant
 10987654321zero
 ^~~~~~~~~~~~~~~

Answer 7

Hidden content!
*  **** *  * ****  *
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int main(int argc, char *argv[])
{
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***    ** * *** *  * (i=1)
*** ** **  ** *  *** ** **  * *   * *** *  **      ** * * **   * 
*** **  * *** ** *** * *  * 0;
}

Comments

prog.c: In function 'main':
prog.c:8:18: error: 'a' undeclared (first use in this function)
     for( i=0; i>=a; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

prog.c: In function 'main':
prog.c:8:18: error: 'i' undeclared (first use in this function)
     for( a=0; a>=i; a--)
                  ^
prog.c:8:18: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Wrong output

---

prog.c: In function 'main':
prog.c:8:21: error: 'a' undeclared (first use in this function)
     for(int i=0; i>=a; i--)
                     ^
prog.c:8:21: note: each undeclared identifier is reported only once for each function it appears in

---

Case 0: Correct output

Answer 8

Hidden content!
* * **     *  ****
* ** **  **  *       
int main(int argc, char *argv[])
{
   *** **    *  *     ** * *** i, a;
 * **** * * ** *  ***  *   **    * * * *  **  your input:");
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***   *** *****  *   *   *  * ****  *     ***** *** * *    *    * *    * ** *  *  
 * * **  *  ***  **** ***   * ** 0;
}

Comments

Case 0: Wrong output

---

I recommend you use loop run numbers from 10 to 0, then use 'if' to change 0 into 'zero'

---

Case 0: Correct output

Answer 9

Hidden content!
  *    * ** * ***** ***
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int  * * * argc, char ***   {

  **   *  ** * ** int a=10;

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*   * **    *      *   *  *  *   *** **  * * ** *** * ****  
**  *  *    **  **   ***     * ***** 
 * * **  ** *  *  **  a != 10 );
 **  *  * **** 
 ****** * **  ** *** ***  * 9 8 7 6 5 4 3 2  **  **   *  
 *****  *     * ** ***

Comments

prog.c: In function 'main':
prog.c:15:2: error: expected expression at end of input
  return
  ^~~~~~
prog.c:15:2: error: expected declaration or statement at end of input

Answer 10

Hidden content!
*  *   **  * **    * * 
* ***    ****  ** *    

int  *    argc, char    *   {

*       * ** * int *  **

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* * * ***  *  * **  * *   **   if( a * *   10)
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** *  * **** *   ** a != 10 );
* ** *   * * *  
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 **    * *    * * *  0;
}

Comments

Case 0: Wrong output